The **initial velocity **of the car with the** mass** of 3000kg before the inelastic collision is** 1.347m/s**.

For two objects, the **relative speed** between them equals the change in distance between them divided by the change in time.

In an** inelastic collision**, the** momentum** of the bodies remain constant even after collision. This works on the principle of **conservation of momentum**.

**p = m.v**

where, p = momentum of the body,

m = mass of the body,

v = velocity of the body

Here,

**m₁. u₁ + m₂. u₂ = m₁. v₁ + m₂. v₂**

Therefore, the **velocity **of 3000kg car (m₂) can be calculated by this **formula**:

m₁ = 2100 kg

u₁ = 10m/s

m₂ = 3000kg

u₂ = ?

v₁ = v₂ = 4.91 m/s

Therefore,

**m₁. u₁ + m₂. u₂ = m₁. v₁ + m₂. v₂**

(2100kg × 10) + (3000 × u₂) = (2100 × 4.91) + (3000 ×4.91)

21000 + 3000u₂ = 10,311 + 14730

3000u₂ = (10311+14730) - 21000

3000u₂ = 25041 - 21000

3000u₂ = 4041

u₂ = 4041/3000

**u₂ = 1.347m/s**

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If an object is at rest or stopped, what is its velocity, acceleration, or speed?

**Answer:**

Thus, even though the velocity of an object at rest must be zero, acceleration can clearly be non-zero for objects at rest. A particle that is thrown vertically upwards stops momentarily at the highest point of motion.

**Answer:**

Everything is zero. Because it's at rest.

What is the frequency of light when the energy of a single photon is 2. 23 × 10-21 j?.

When a single** photon** has an energy of 2.23*10-21, light has a frequency of *E=hv 2.23 10-21 J = (6.626... 3.03 10-19 J (6.022*1023 photons).

A photon is a tiny energy packet of **electromagnetic radiation**, also referred to as a light quantum.

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Consider a toy made out of a ball attached to a 7 inch string attached to a pole. the pole is motorized so that the ball at the end of the string moves in a circle clockwise around the pole. the stand is located on origin of an x and y axis and the speed of the ball is constant (22 in/s). find the magnitude and direction.

The ball swings around the pole while maintaining its angular momentum because its angular **velocity **rises with decreasing radius and mechanical energy falls.

Think about the board at the top of the circle and the speed the bull is traveling at. We converse, and the **velocity **is the same when the board is at the base of the **circle**. According to Newton's Second Lawyer Motion, we are aware of this. the overall force applied to an item that is equal to the acceleration of a mustang underneath the object.

Therefore, a minimum velocity is necessary. Keep the board rotating in a **circle**. If not, the ball will drop to the ground. Therefore, the ground national wait that is acting on the circular's top board.

Additionally, for the minimal **velocity**, the centripetal force pressing on the kid must be equal to the gravitational weight acting under effort. Additionally, centripetal force can be expressed as fc = M. The bull is at the top of the **circle **with the lowest velocity, so according to Newton's Second Law of Motion, M. G. must be equal to him.

From the beginning, we debated in a minimum square. Find the least velocity at the circle's top using that expression. Therefore, by rearranging, we can cancel em from both sides of the minimal square G. R., making it equal. taking the highway. The group of G. R. will have the lowest velocity.

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Matt likes to get from the second floor of his house to the first floor by sliding

down the banister that is inclined at an angle of 30.0°to the horizontal. If Matt

has a mass of 50 kg and the coefficient of sliding friction between Matt and the

banister is 0.20, what is the force of friction impeding Martin's motion down the

banister?

The force of** friction **impeding** Matt's** motion is 49.05 N.

**What is friction?**

When two surfaces move relative to each other, **friction** between them turns** kinetic energy** into **thermal energy** (that is, it converts work to heat). As demonstrated by the utilisation of **friction** caused by rubbing pieces of wood together to start a fire, this feature can have severe repercussions. When motion with** friction **occurs, such as when a viscous fluid is churned, kinetic energy is transformed to** thermal energy**. Another significant effect of many types of **friction** is wear, which can lead to performance degradation or component damage. The science of **tribology** includes** friction.**

The force of** friction** impeding Matt's motion down the banister can be calculated using the equation:**Ff = μN**

where μ is the **coefficient** of sliding **friction** and

N is the normal force.

The normal **force** can be calculated using the equation:**N = mg sinθ**

where m is the **mass** of the object, g is the acceleration due to **gravity**, and θ is the angle of incline.

Plugging in the known values, we get:

Ff = μN

Ff = (0.20)(50 kg)(9.81 m/s2)(sin 30.0°)

Ff = 49.05 **N**

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the acceleration due to gravity on the surface of a planet is four times as large as it is on the surface of earth. the mass density of the planet is known to be eight times that of earth. what is the radius of this planet in terms of earth's radius?

The **radius **of the **planet **is √2 times radius of earth or 1.414 times the radius of Earth.

According to **Newton's law of universal gravitation**, every object in the universe attracts each other with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them.

F = GmM/R²

where;

G is universal gravitation constantm, M are the massesR is the distance between the objectsThe **acceleration **due to **gravity **on surface of **Earth **is given as;

g = GM/R²

G = gR²/M

For a **planet **whose **acceleration **due to gravity is 4 times of Earth and **mass **is 8 times of earth, the **radius **of the planet is calculated as;

(4gR_p²)/(8M) = (gR²)/(M)

where;'

R_p is the radius of the planet(4R_p²)/8 = R²

4R_p² = 8R²

R_p² = 8R²/4

R_p² = 2R²

R_p = √(2R²)

R_p = R√2

R_p = 1.414 (R)

Thus, the **radius **of the **planet **is root two times radius of earth or 1.414 times the radius of Earth.

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Please select the best answer from the choices provided

**Answer:**

u got to provide all info in order to be answered

**Explanation:**

You’re driving a car East on the 91 fwy for a total distance of 230 km. If it took you 2.3 hours to reach your destination, then what was your speed?

What was GIVEN?

**Answer:**

**Explanation:**

Given:

S = 230 km

t = 2.3 h

_________

V - ?

**Speed:**

V = S / t

**V = 230 / 2.3 = 100 km/h**

the bottom profile normal to the shore off a section of the coast has the following average depths (in m) at the given segment distance lengths (in nautical miles): 2.7 m (3 n.m.), 3.8 m (7 n.m.), 4 m (10 n.m.), 11 m (20 n.m.), 12.2 m (30 n.m.), 15.5 m (40 n.m.), 27 m (50 n.m.), 48 m (60 n.m.), 73 m (70 n.m.), and 200 m (80 n.m.). there is a sustained wind blowing directly onshore at an average speed of 72 knots. calculate the wind-induced setup at the shore. note: to solve this problem you can assume a flat bottom in each segment (we covered this solution in class) and march your solution from offshore to onshore through each segment just like a simple computer storm surge model would. keep in mind that as you march your solution shoreward, the water level in each segment is influenced by the water level from the previous one.

Entering 20 35 4 is not a valid value. This is the same as 27.6 at 50 frames per second multiplied by nine.16 Two plus one thus. Why I visited the buying **power**. 10 60 x 10 to the power is equal to the required speed of 20.5 mph.

He had utilized equal to allow the **power **of 0.16 to take over. U. **Cuban **is equivalent to two. What 4.16 is used for. First late invitation. U. Cuban is equivalent to one. wherefore in light of part.16.

As a result, **Cubans **find it difficult to offer you what you desire. Why 2 30? Power 300.16. Why? I continued to solve it up to a power of 0.16. Why do I purchase one at a power of 10.16 30?

The third major issue. Do not enter the value 20 35 4. This is equal to 27.6 at 50 frames per second nine to the power.16

Part B. As a result, two equals one. Why I went to the **power **to buy.4. The needed speed of 20.5 mph is equivalent to 10 60 x 10 to the power.4.

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two charges have a force of 8 n between them when the distance between them is suddenly increased by a factor of 2. the new force will be _________ n

When the distance between them is suddenly increased by a factor of 2. the new **electrostatic force** will be **2 N**.

We need to know about **electrostatic force** to solve this problem. The **electrostatic force** is a force caused by two charges separated at a distance. It can be determined as

F = k . Q1 . Q2 / r²

where F is force, k is coulomb's constant (9 x 10⁹ Nm²/C²), Q is charge and r is radius.

From the question above, we know that

F1 = 8 N

r1 = r m

r2 = 2r1 = 2r

For this question, we can apply the ratio of initial and final force

F1 / F2 = k . Q . Q / r1² / k . Q . Q / r2²

F1 / F2 = r2² / r1²

F1 / F2 = (2r)² / r²

F1 / F2 = 4r² / r²

F1 / F2 = 4

F2 = 1/4 . 8

F2 = 2 N

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If a force of 10 newtons acts on an object and an additional force of 6 newtons acts in the same direction, what will be the net force on the object?.

Two forces 10N and 6N acts on an object in same direction , then the **net force** will be:

**16N **.

So here net force : F= F1 + F2.

Here,

F1 = 6 N

F2 = 10 N

F = 6N + 10N

F = 16N

∴ **Net force = 16N **.

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why is chlorophyll green? why is chlorophyll green? it absorbs wavelengths in only the blue and red parts of the visible spectrum. it absorbs wavelengths only in the red portions of the spectrum (680-700 nm). it absorbs wavelengths only in the blue part of the visible spectrum (450-480 nm). it absorbs all wavelengths in the visible spectrum.

chlorophyll is green because It absorbs wavelength in only the **blue and red parts** of the visible spectrum

The pigment **chlorophyll** is what gives green plants their **green color**. A portion of the visible light spectrum is absorbed by **chlorophyll**. **Chlorophyll **is a pigment that absorbs visible light in the red (long wavelength) and blue (short wavelength) portions of the spectrum. The plant appears green because it reflects rather than absorbs **green light.**

The chloroplasts of plants contain **chlorophyll**. Plants have **chlorophylls **a and b, though there are other forms as well. Only one side chain's makeup distinguishes these two forms of **chlorophyll** from one another.

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ASAP:You live on a part of Earth where the angle of the sun's rays are very high, and the latitude is low. Which temperatures do you experience quite often?'

You would experience high temperatures

Your area is exposed to high radiation of sunlight because of the high angle of the sun's rays, which is a sign of a hot climate. The question also mentions the low latitude of this region. Low latitude places are those near the equator where it is often warmer than in areas near the poles. Therefore, based on the given description, it may be claimed that you frequently encounter high temperatures.

Your area is exposed to high radiation of sunlight because of the high angle of the sun's rays, which is a sign of a hot climate. The question also mentions the low latitude of this region. Low latitude places are those near the equator where it is often warmer than in areas near the poles. Therefore, based on the given description, it may be claimed that you frequently encounter high temperatures.

The question is in the picture please answer problem 8Thank you

According to the second law of Newton, the acceleration is directly proportional to the net force acting on the object:

[tex]F=m\cdot a[/tex]From this formula, we can also see that the acceleration is inversely proportional to the mass: For the same force, if the mass increases, the acceleration decreases.

Therefore **the correct option is d.**

How can manipulation of a model be done

A** model** can be altered in a number of ways, by importing a database, combining information, or erasing data.

The term "scientific** manipulation**" in behavior analysis describes the methodical organization of a variable under research in order to enable the objective analysis of the effects of the variable presence or absence on some other measurable behavior.

To **manipulate** data, build a database with information from many sources, clean and rearrange the content of the database, combine and remove redundant information, and then do an analysis to uncover important information.

Understanding your needs and goals, utilizing automation tools, filtering your data, and researching various **manipulation** tools are some strategies for manipulating data.

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Users in motion, wireless connectivity, and a cloud-based resource are the elements in a ________ system.

Users in motion, wireless connectivity, and a cloud-based resource are the elements in a** ****mobile system.**

Smartphones, tablets, 2-in-1 PCs, smart speakers, smart watches, and smart eyewear all use **mobile operating systems**. Because they were originally developed for desktop computers, which historically did not have or require specific mobile capability, the operating systems that are used on "mobile" machines, like ordinary laptops, are often not referred to as mobile operating systems.

The distinction between mobile and other forms has become more hazy recently as a result of current **hardware** becoming more compact and portable than earlier equipment. This distinction is being muddled by the introduction of tablet computers and lightweight laptops, two major advancements.

Mobile operating systems combine desktop operating system elements with additional **functionality** that is useful for handheld or mobile use. For telephony and data connectivity, these systems typically have a wireless integrated modem and **SIM tray**.

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Users in **motion**, wireless connectivity, and a **cloud-based** resource are the elements of a **mobile** system which is the operating system used to run mobile devices like smartphones, tablets, etc.

A mobile system is a **computing** system with mobile entities. These can be hardware or software. The system runs on a mobile operating system such as android and iOS which are the two major mobile operating systems among others. A mobile **operating system** (OS) allows smartphones, tablet PCs, and other devices to run applications and programs.

Because **mobile systems** help in the real-time execution of several applications these must use wireless forms of connectivity and a cloud-based resource and storage system. Also, the fact that **users** can be in motion should be kept in mind and hence these are important **elements** in a mobile system

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An electic bulb is rated 60W, 220V. Calculate the resistance of its filament when it is operating normally.

**Answer:**

**Explanation:**

**We have to use the equation p = I^2 x R. But we do not have the current.**

**To work out the current, we look at what we have. We have the voltage and power, therefore we will use the equation P = IV and rearrange to find the current.**

**I = P/V**

**I = 60/220**

**I = 0.2727272727 or round it to 2 dp to get = 0.27**

**we now have to rearrange the first equation to find the resistance.**

**R = P/I^2**

**R = 60/0.2727272727^2**

**R = 806.6666665501**

**R = 807 ohms (3sig)**

The resistance of the filament is **806.67 ohms**.

**Electrical power** is defined as the rate at which electrical energy is transferred by an electric circuit. The SI unit of power is Watt, 1 joule per second ( 1J/S).

The formula of **electrical power** is

**P = V^2/R**

where,

P = power

V = volts

R = resistance

from the above formula

60 = 220x220/R

R = 220x220/60

R = 806.67

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a spotlight on the ground is shining on a wall away. if a woman 2m tall walks from the spotlight toward the building at a speed of 0.6 m/s how fast is the length of her shadow on the building decreasing when she is 2m from the building?

The answer is dy/dt is equal to -(20/7)(1/14)(0.6) = **-0.12245 m/s.**

The negative sign shows that the rate is falling as y **gets shorter**

.Woman Height/ Distance** Light To Woman** equals

Shadow Height/Distance** Light To Wall.**

**explanation?**

Think of a huge triangle with the origin as the spotlight, a base of 20, and the height of the shadow on the wall as y. Inside the larger triangle, a comparable triangle that is** x meters** from the spotlight and** 2 meters **

tall—the woman's height—can be seen.

Woman Height/ Distance Light To Woman equals

Shadow Height/Distance Light To Wall.

The shadow height is y. Let x be the distance from the woman to the light.

**xy = 40 or y/20 = 2/x**

Take both sides' derivative:

**XDY + YDX = 0** based on the product rule.

Solve for the desired result, dy/dy:

dy/dt = -(y/x)dx/dt, where **dx/dt = 0.6 m/s.**

The woman is 20 - 6 meters from the light when she is 6 meters from the wall, which is** 14 meters, or x.**

Keep in mind that y/20 = 2/x = 2/14 --> y = 40/14 = 20/7 from the related triangles.

So, dy/dt is equal to** -(20/7)(1/14)(0.6) = -0.12245 m/s.**

The negative sign shows that the rate is falling as **y gets shorter.**

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a 77 kg man is riding on a 32 kg cart traveling at a speed of 3.8 m/s. he jumps off with zero horizontal speed relative to the ground. what is the resulting change in the cart's speed, including sign?

**Answer:**

See below

**Explanation:**

Using conservation of momentum:

Initial momentum = (77+32 kg)* 3.8 m/s = 414.2 kg m/s

Jumping off with zero speed relative to ground (I think this is what zero horizontal speed MEANS) means all of his momentum is given to the cart ( think about jumping off of a skateboard)

final momentum of the cart

mv = 414.2

v = 414.2/32 = 12.94 m/s for a + 9.13 m/s change

be sure to answer all parts.an fm station broadcasts classical music at 94.5 mhz (megahertz, or 106 hz). find the wavelength (in m, nm, and å) of these radio waves.

Thus, the **wavelength **is **3.21 m** when the frequency fm station broadcasts classical music is at 93.5 mHz.

A waveform signal's **wavelength** is defined as the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or along a wire. This length in wireless systems is typically expressed in metres (m), centimetres (cm), or millimetres (mm) (mm). It is more common to specify the wavelength in nanometers (nm), which are units of 10-9 m, or angstroms (), which are units of 10-10 m, for infrared (IR), visible light (VL), ultraviolet (UV), and gamma radiation ().

**Frequency**, or the quantity of wave cycles per second, is inversely related to wavelength. The wavelength of a signal decreases in length as its **frequency** increases. An electric field and a magnetic field vibrate together, producing an electromagnetic wave. A wavelength can be determined by dividing a wave's velocity by its **frequency**.

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at midday, solar energy strikes the earth with an intensity of about 1000. w/m2. what is the area of a solar collector that could collect 150 mj of energy in 1 h? this is roughly the energy content of 1 gallon of gasoline.

41.67 m² is the **area **of a solar **collector **that could **collect **150 mj of **energy** in 1 h.

Power received per unit surface is the definition of intensity.

[tex]I=P/A=1kW/m2(1)[/tex]

**Power **is simply defined as the rate at which energy changes over time.

[tex]P=\Delta E/\Delta t(2)[/tex]

ΔE = 150 MJ

Δt = 1 hour = 3600 sec.

[tex]P=150 MJ/3600 s=41.67 kW(3)[/tex]

Replacing (3) in (1), and solving for **Area**, we get:

Area = 41.67 m²

The **measurement **that indicates the size of a region on a plane or curved surface is called **area**. Surface area refers to the area of an open surface or the border of a three-**dimensional **object, whereas the area of a plane region or plane area refers to the area of a form or **planar lamina**.

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Object starts from rest. Dots are placed every second. What is the acceleration of the object?

The **acceleration **of the object is 4.48m/s².

From the graph we can see,

There are **5 dots** placed over the line, it means that the object has moved for** 5 seconds**. The distance which the object has covered in 5 seconds is equal to about 56 meters.

As we know, the object is starting from rest, so the** initial velocity** is 0m/s.

Now, to find the acceleration a of the object, we can use the equations of motion.

So,

Using,

S = ut + 1/2at²

Where,

u is initial velocity,

S is the **distance covered,**

and t is the time period of motions of the object.

Putting all the values,

56 = 1/2a(5)²

(56 x 2)/25 = a

a = 4.48m/s²

Hence, the **acceleration **is 4.48m/s².

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When electricity to an electromagnet is stopped, what happens to the strength of the magnet?.

When **electricity** to an electromagnet is stopped the magnetic strength of the magnet will be lost.

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the speed of car increase if the car's

Any of these are correct

- velocity is constant

- acceleration is zero or constant (depending on rate of change)

- distance covered increases

- velocity is constant

- acceleration is zero or constant (depending on rate of change)

- distance covered increases

a mouse of mass 27.0 g falls 200 m down a vertical mine shaft and lands at the bottom with a speed of 8.1 m/s. during its fall, how much work (in j) is done on the mouse by air resistance?

**Work **is done on the mouse by air resistance 25.574 Joule.

**Work **is done every time a **force **moves something over a **displacement**. you can calculate the electricity transferred, or paintings done, by using multiplying the force via the gap moved in the course of the force. strength transferred = work achieved = pressure x distance moved within the direction of the pressure.

Work to be accomplished, a force must be exerted and there must be motion or **displacement **in the route of the pressure. The work done by way of a force appearing on an object is the same as the significance of the pressure **accelerated **by way of the space moved within the route of the **force**.

given,

mass = 27.0 g = 0.027 kg

Height H = 200 m

initial speed u = 0 m/s

final speed V = 8.1 m/s

force = mg

= 0.027 × 9.8

= 0.2646 N

1/2mu² + mgh = mgh + 1/2mv²

0 + 0.027×9.8 ×100 = 0 + 1/2×0.027× (8.1)² + air reesistance

initial energy = 26.46 J

final energy = 0.886 J

air resistance = 26.46 J - 0.886 J

= 25.574 Joule

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a current density of 4.50 10-13 a/m2 exists in the atmosphere at a location where the electric field is 133 v/m. calculate the electrical conductivity of the earth's atmosphere in this region.

This measurement demonstrates the **conductivity **of a certain material. When compared to rubber, which has poor electrical conductivity and high electrical resistance, metal, for instance, has high electrical conductivity and low electrical resistivity.

Electrical resistivity's physical opposite is electrical conductivity. This measurement demonstrates how well a certain material can conduct an **electric **current.

Rubber has a poor electrical **conductivity **and a high electrical resistivity, whereas metal has a high electrical conductivity and a low electrical resistance.

We are aware of the following thanks to the values that have been provided:

J = 6.00 10 13 A / m 2 and E = 100 V / m

The following equation provides the current density in terms of the **electric **field:

J = σ E

Here, E is the electric field, J is the current density, and is the electrical **conductivity**.

σ = J / E

The known values are then substituted.

σ = ( 6.00 × 10 − 13 A / m 2 ) / ( 100 V / m )

σ = ( 6.00 × 10 − 15 / m ) / ( 100 V )

The corresponding unit for V / A is.

Condense the units.

σ = 6.00 × 10 − 15 Ω − 1 m − 1.

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There are several methods of extrasolar planet detection currently in use. Which properties of a planet does each method discover? sort the following methods into the appropriate categories.

The complete box as per methods of extrasolar **planet detection**

Diameter of the

Mass of the planet

Microlensing methodRadial velocity methodThis is further explained below.

What are the methods of extrasolar planet detection?Generally, The techniques for finding planets beyond the** solar system**

Microlensing caused by gravitational forces occurs when a star that contains a planet moves in front of another star. This causes the light to bend in a peculiar manner.

The transit method takes into account the varying luminosities of the stars. When a **planet **passes in front of a star, the star's apparent brightness decreases, which provides information about the **planet's **radius or diameter.

The radial velocity method analyzes the Doppler shift of a star to determine whether the star is moving closer or farther away from us.

Method of astronomy that is based on variations in the positions of stars in the sky.

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a boy is running north with a speed of 5 m/s on a large, horizontal frozen lake. the coefficient of friction (both kinetic and static) between his shoes and the ice is ?

The **coefficient** of** friction **between the boy's shoes and the ice is **0.65**.

The coefficient of **static friction** for ice is 0.65, so this means that 65% of the **force** needed to move an object from one place to another must be applied in order to get it moving across the ice at all—once it starts moving, however, there will be a lot less **work** required because we have already accounted for the initial force required to start moving it.

This means that if we want our boy running north at** 5 meters **per second across this large, flat lake with no wind or waves or anything else going on that might cause him trouble (or even help him), he'll need 10 meters per second or more just to get started.

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electricity iii goals define the concept of obstacle determine how obstacles combine when in series and in parallel. expand model of electricity to include effects of obstacle size

A circuit is necessary for **electricity **to flow. The same materials can be used in multiple ways to create a complete circuit.

**Diffraction **is the interference or bending of waves via an aperture into the area that is geometrically in the shadow of the obstruction or aperture. Effectively, the wave's secondary source is the **diffracting **element or aperture. The term "diffraction" was created by Italian scientist Francesco Maria Grimaldi, who also made the first precise observations of the phenomena in 1660.

The Huygens-Fresnel principle, which views each point in a propagating wavefront as a collection of unique spherical wavelets, describes the diffraction phenomenon in classical physics. [3] As seen in the enclosed figure, the distinctive bending pattern is most obvious when a wave from a coherent source (like a laser) comes into contact with a slit or aperture that is roughly the same size as its wavelength.

A circuit is necessary for **electricity **to flow. The same materials can be used in multiple ways to create a complete circuit. Electric circuits of various types exhibit varying behavior (parallel and simple circuits) Light, heat, and music can all be produced with the use of **electricity **electrical conductors and insulators.

This results from the addition or interference of various wavefront points (or, alternatively, each wavelet) that follow pathways to the registering surface of varying lengths. Multiple, closely spaced apertures (like those in a **diffraction **grating) can produce a complicated pattern with different intensities.

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Two objects in a closed system collide. After the collision, one object has lost speed, but the other object has gained speed. Explain what has happened. A. Total momentum in a closed system is conserved. B. Gravitation potential energy converts to kinetic energy. C. Kinetic energy converts to gravitational potential energy. D. Mass is conserved

A. Total momentum in a closed system is conserved

the law of momentum conservation states that The total amount of momentum before the collision is the same as the total momentum after the collision. Regardless of the change of momentum of each object.

the angular area of the entire sky is about 41,250 square degrees. how many pictures would the hst have to take with its camera to obtain a complete picture of the entire sky?

It will takes **years **of **time **to obtain a complete picture of the entire sky of **angular area** is about 41,250 square **degrees**.

Divide 41250 by 0.0036 , we will get 11458333 and 1/3 image. but to take image for all of the sky it will takes years of time.

An **angular distance** used to describe how big a sphere or circle seems from a certain point of view is known as the **angular diameter**, angular size, apparent **diameter**, or apparent size. It is known as the visual angle in the vision sciences and as the angular **aperture **in optics (of a lens).

The **angular diameter **may also be thought of as the angle that a camera or eye must spin around in order to view from one side of an apparent circle to the other. Humans are able to distinguish sizes of up to around 1 arcminute (about 0.017° or 0.0003 radians) with their unaided eyes.

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