0.0351mol/L is the **equilibrium constant**, Kc of the given chemical **reaction**.

The value of a chemical reaction's **reaction **quotient at chemical equilibrium, a condition that a dynamic chemical system approaches when enough time has passed and at which its composition has no discernible tendency to change further, is the **equilibrium constant** for that **reaction**.

Given:

Initial no. of moles of NOCl = 2.5 moles

NOCl dissociated = 28%

total volume = 1.5 L

To find:

Equilibrium constant, Kc = ?

Formula:

Kc = [products] / [reactants]

Calculations:

(28/100) x 2.5 = 0.7 moles

[tex]2NOCl (g) \leftrightarrow 2NO (g) + Cl_2 (g)[/tex]

According to the above equation,

2 moles of NOCl will give 1 mole of [tex]Cl_2[/tex] and 2 moles of NO

Therefore, no. of moles of NO = 0.7 mol

No. of moles of [tex]Cl_2[/tex] = 0.35 mol

No. of moles of NOCl remaining after dissociation = 2.5 - 0.7 =1.8 mol

Molarity = no. of moles / volume

Therefore, Molarity of NO = 0.7 / 1.5 = 0.466M

Molarity of [tex]Cl_2[/tex] = 0.35 / 1.5 = 0.233M

Molarity of NOCl = 1.8 / 1.5 = 1.2M

Kc = [tex]([NO]^2 [Cl_2]) / [NOCL]^2[/tex]

Kc = [tex][(0.466)^2 (0.233)] / (1.2)^2[/tex]

Kc = 0.0351mol/L

Result:

The **equilibrium constant**, Kc of the given chemical reaction is found to be 0.0351mol/L.

The complete question is:

A 2.50 mol quantity of NOCl was initially in a 1.50L reaction chamber at 400℃. After equilibrium was established it was found that 28.0% of NOCl had dissociated.

[tex]2NOCl (g) \leftrightarrow 2NO (g) + Cl_2 (g)[/tex]

Calculate equilibrium constant Kc for the reaction.

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Which elements are represented by the following electron configurations:

7 1s²2s²2p 3s²3pº4s¹

1s²2s22p 3s 3p 4s² → (add all of the exponents) → 20-Ca

8 1s²2s²2p 3s²3p 3d³4s²

Which elements are represented by the following shorthand notation:

9 [Ne]3s²

10 [Ne]3s 3p6

[He]2s²2p3→ (write the electron configuration of the element inside the brackets & then add

what you see outside of the brackets)→→ [1s²]2s22p³→ (add all of the exponents)

7- Nitrogen

1s²2s²2p° → 3s² → 3p6 →4s²3d¹04p6 → 5s² →

4d¹05p6

5p6s²4f¹4

6s²4f45d¹0

6d ¹0

6p7s²5f¹4 ->>

**Electron configurations**, the **atomic number** of the above element is 2+2+6+2+3=15. The atomic number of the element below the given element is 15+18=33.

Titanium, Nitrogen (N), Phosphorus, Sulfur (S)

What is Electronic configuration ;The arrangement of an atom's or molecule's electrons in atomic or molecular orbitals is known as the **electron configuration** in atomic physics and quantum chemistry.

**Electron configurations** written down. The energy level (the period) should come first when writing an **electron configuration**, followed by the subshell that needs to be filled and the superscript, which indicates how many electrons are in that subshell. The atomic number Z represents the total number of electrons.

In other words, we adhere to the **Aufbau Principle,** Pauli-exclusion Principle, and Hund's Rule, which are the three key rules.

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A piece of aluminium foil is 8.0×1^-5cm thick . what is its thickness in micrometers?

**Answer: 80000 micrometers**

**hope i helped**

abs plastic is a polymer consisting of three monomer units: acrylonitrile (c₃h₃n), butadiene (c₄h₆), and styrene (c₈h₈). a sample of abs plastic contains 14.9% n by mass. it took 1.56 g of br₂ to react completely with a 2.00 g sample of abs plastic. bromine reacts 1:1 (by moles) with the butadiene units in the polymer and nothing else, so bromination is a method for determining the quantity of butadiene in the polymer. what is the percent by mass of styrene in the polymer?

The **ABS plastic** is a **polymer **which has styrene 28.5% by mass.

A **polymer **is a substance or material made up of macromolecules, which are very big molecules made up of several repeating subunits.

Styrene and acrylonitrile are polymerized with polybutadiene to create ABS, a terpolymer. Since **ABS plastic** is amorphous, it lacks a proper melting point.

A **polymer **called a terpolymer is created when three distinct monomers are copolymerized.

Let the mass of sample ABS plastic = 100 g

Given, mass of Nitrogen (N) in ABS plastic = 11.9 g

Moles of Nitrogen (N) in ABS plastic = 11.9 / 14 = 0.85 mol

1 mole of N is present in 1 mole of acrylonitrile

0.85 mol of N is present in acrylonitrile = 0.85 mol

Moles of acrylonitrile = 0.85 mol

Mass of acrylonitrile = 0.85 mol X 53 g/mol = 45.05 g

Moles of [tex]Br_2[/tex] reacted = 1.56 g / 159.8 g/mol = 0.0098 mol

As given, [tex]Br_2[/tex] and butadiene react in 1:1 by moles

So, moles of butadiene = 0.0098 mol

Mass of butadiene in 2g ABS sample = 0.0098 mol X 54 g/mol = 0.529 g

Mass of butadiene in 100g ABS sample= 0.529 / 2 x 100 g = 26.45 g

Mass of styrene in 100g ABS Sample = mass of sample - mass of butadiene - mass of acrylonitrile

Mass of styrene = 100 – 26.45 – 45.05 = 28.5g

% Mass of styrene = 28.5%

Result:

28.5% of styrene is present in 100g **ABS plastic**, which is a **polymer**.

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At the end of the video, the man getting interviewed provides an analogy about meditation and states of matter. Create your own analogy that explains the differences between the behavior of molecules in different states of matter. Explain.

**Marathon runners** well exhibit the differences between the behavior of molecules in different **states of matter**.

At the starting point before the start of the race, the runners would gather in a common place before the starting line. They would be close to each other and are **tightly packed** like solid molecules.

After the race was started, some players would start to move fast and some remain in a group for a certain period. They were **loosely packed** compared to solid.

As the game reaches the end point, the players would be more spread out based on their stamina. They would be more **loosely packed **compared to solid and liquid.

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need help on this for science

**Answer:**

For part A : Length = 3

Width = 3

Height = 4

For part B : on multiplying 3 × 4 × 3 = 36

For part C : Answer = 36

27. Sample of gas is electrically charged so that it glows red. The red color is emitted when

The** red color** is emitted when **electrons **in the gas return to **ground state.**

From the** Bohr model,** we know that an **electron **in atom could be found in its lowest energy state. The electron could receive energy in this lowest energy state and move to a higher energy state called the excited sate. The lower energy state that the electron was at the first is called the ground state of the electron.

As the electrons return to** ground state**s, photons of light of a characteristic wavelength is emitted. The color of the light shows the **wavelength **of the light emitted.

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Which statement describes the

distribution of charge in an atom?

-A neutral nucleus is surrounded by one or

more

negatively charged electrons.

-A neutral nucleus is surrounded by one or more

positiVely charged electrons.

-A positively charged nucleus is surrounded by one

or more negatively charged electrons.

-A positively charged nucleus

is surrounded by one

or more positively charged electrons

**Answer:**

-A positively charged nucleus is surrounded by one

or more negatively charged electrons.

i will give 100 points for help

**Answer: Hope this helps! **

**Explanation:**

Oxygen has the atomic number 8; its atoms contain 8 protons and 8 electrons. Uranium has the atomic number 92; its atoms contain 92 protons and 92 electrons.

I don't know if this is what your looking for but i think it should help!

part a a solution is prepared by dissolving 0.69 mol of mgcl2 in 0.40 kg of water. how many moles of ions are present in solution? express your answer to two significant figures and include the appropriate units. n

The **moles **of ions present in the solution when a solution is prepared by dissolving 0.69 mol of mgcl2 in 0.40 kg of water is 2.0 moles.

0.69 moles of MgCl2 in 0.4 kg water

MgCl2 disassociates as Mg2+ + 2Cl-

So 1 MgCl2 from 3 moles

Moles of ion present is 3x0.69=2.0 moles

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5. Describe A ruler is on the table with the

higher numbers to the right. An ant

crawls along the ruler from 6 cm to 2 cm

in 2 seconds. Describe the ant's distance,

speed, and velocity

The** distance** the ant would have covered crawling from 6 cm to 2 cm on ruler scale would be 4 cm and the speed would be 2 cm/s.

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how might the process of making paper from wood be changed to produce paper that is not so acidic

During the production of paper, use a **mild base** such as **calcium** or **magnesium** **bicarbonate** to neutralize the** natural acids** occurring in wood pulp, and prevent the formation of additional acids.

**Acid-free paper **is paper if soaked in water, gives a **neutral** or basic pH. The production of such paper can be done from any cellulose fiber as long as the **active acid pulp** is removed during processing. Acid-free paper is a solution to the problem of **preserving** documents and preserving artwork for long periods.

The **wood pulp paper** becomes to be acidic from alum-rosin sizing which, generates** sulfuric acid **in the presence of moisture. Acids also are formed in a paper by the **absorption** of **pollutants** such as mainly sulfur and nitrogen oxides.

The addition of **bicarbonate** is in excess, to provide the paper with an alkaline reserve to offer **protection** from further attack by **acids** remaining in the paper.

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Donald rides his bicycle 12 km north, turns around, and then rides the bicycle 9 km back toward his starting point.

**starting point. **

He rides total **21 km **.

An object, a concept, or a collection of data that can be utilized to start a process or conversation. The essay provided a good place to start for our conversation.

Your **beginning point **is the location from where you **begin a journey**. Safaris into northern Tanzania's game parks and reserves depart from the recently constructed airport. From their **starting position,** they had already traveled a few miles or more on foot.

A **baseline **is a beginning or the beginning of something.

The **baseline **line is always crucial and can be used as a basis for comparison.

In many fields, including medicine, the baseline data—which is the **data discovered** at the start of a study—is employed.

Every person's **base line** or start up is equally important and significant, and it's frequently taken seriously to avoid mistakes that might not be **readily rectified.**

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problem 3 how many rearrangements of are there in which no two adjacent letters are also adjacent letters in the alphabet? for example, no such rearrangements could include either or .

There are 2 **rearrangements **of abcd in which no **two adjacent **letters are also adjacent letters in the alphabets.

Here's the **Complete **question:

How many rearrangements of abcd are there in which no two adjacent letters are also adjacent letters in the alphabet? For example, no such rearrangements could include either ab or ba.

(A) 0

(B) 1

(C) 2

(D) 3

(E) 4

Using XXXX

We can't put B in either of the middle positions, as there would only be the far end at which to put both A and C and we can't put two things in one slot. That is, XBXX would require A and C to both be in the red X in order to avoid putting them next to **B**...can't do that, so B can't go in the middle.

Similarly, we can't put C in either of the middle positions, as there would only be the far end at which to put both B and D and we can't put two things in one slot.

So, B and C must go on the ends.

BXXC can only be filled in as BDAC.

CXXB can only be filled in as CADB.

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3. There are 2 questions about isotopes.a) If an element has three isotopes with the following characteristics, what is theaverage atomic mass of the element?Isotope #1 is 10.0% abundant and has a mass of 23.8 amu. Isotope #2 is40.0% abundant and has a mass of 24.6 amu. Isotope # 3 has a mass of25.8 amu.b) An isotope has a half life of 5 minutes. How much of a 100 gram sample ofthis isotope is left after 20 minutes?

**Question a**

**Step 1**

*The average atomic mass of the element is calculated as:*

--------------------

**Step 2**

*Information provided:*

Isotope 1:

10.0 % abundant and 23.8 amu.

Isotope 2:

40.0 % abundant and 24.6 amu.

Isotope 3:

25.8 amu, the % abundant = 100 % - 10.0 % - 40.0 % = 50.0 %

-----------------------

**Step 3**

*Procedure:*

Average atom mass = (10.0% x 23.8 amu + 40.0% x 24.6 amu + 50.0 % x 25.8 amu)/100 = 25.12 amu

**Answer: 25.12 amu**

whats the wavelength of the radiation with a frequency of 6.00 x 10^15 Hz

Given Data:

Frequency of radiation = 6.00 x [tex]10^{15}[/tex] Hz

The relationship between frequency and wavelength is expressed by the formula , c = λν, where λ is the wavelength of the radiation,

ν is the frequency of the radiation, c is the velocity of light in free space.

c =3 x [tex]10^{8}[/tex] m/s , ν = 6.00 x [tex]10^{15}[/tex] Hz

Then , wavelength of the radiation is , λ = [tex]\frac{c}{v}[/tex] = [tex]\frac{3X10^{8} }{6X10^{15} }[/tex] = 0.5 x [tex]10^{-7}[/tex] m

= 50 nm.

Hence, the radiation with a frequency will have a wavelength of 50 x [tex]10^{-9}[/tex] m = 50 nm.

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an orbital is described by combining the n quantum number with the quantum number, for example, 1s and 3p are descriptions of orbitals. group of answer choices true false

Yes, the given statement is** true** that an** **orbital is described by combining the n quantum number with the l quantum number, for example, 1s and 3p are descriptions of **orbitals.**

**Quantum numbers** are those numbers that are used to identify and describe the distribution and position of an electron in an atom.

In general, quantum numbers are classified as principal (n), angular (l) and magnetic (m) and consist of integers starting from 0, 1, 2, 3 and so on.

The estimated values for the principal quantum i.e. 'n' are 1, 2, 3, 4, and so on.

Similarly, for angular quantum numbers i.e. 'l' the values range between 0 and n - 1.

**Orbitals** are found in sub-shells and are made up of these quantum numbers i.e. n and l.

A two-digit code is assigned to an orbital e.g. 2p or 4f. Here 'n' is the shell whose value is 2 and 4 and 'p' and 'f' are subshells.

If we combine the abovementioned quantum numbers then we see that for shell n= 3 there will be three subshells 3s, 3p, and 3d orbitals.

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if a star close to earth si 6.78 light years away, how many years does it take for this star's light to reach earth

The **time (in years)** taken for the star's light to reach the earth, given it is 6.78 light years away is 6.78 years

From the definition 6.78 light years speed, we can obtain a formula to calculate **time**. This is illustrated below:

Speed = distance / time

Cross multiply

Speed × time = distance

Divide both side speed

Time = distance / speed

With the above formula, we can determine the **time.**

The following data were obtained from the question give above:

Distance = 6.78 light yearsSpeed of light in space = 3×10⁸ m/s = 1 Light year/yearTime = distance / speedTime = distance / speed

Time = 6.78 / 1

Time = 6.78 years

Thus, we can conclude that the **time** required is 6.78 years

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How can you use different properties and changes to identify a chemical substance? Choose all that apply.

Specific pure substances have their own unique properties.

When separating mixtures, you can use their properties to determine what separation technique is needed.

You can compare properties and changes of an unknown substance to a known one to see if they are the same or different.

Different substances will have different properties and will change in different ways.

You can create classifications of substances based on their properties and/or changes.

We can use different properties and changes to identify a **chemical** substance through the following below:

This is referred to as a type of substance which has a definite **composition** and **properties** and it is based on different factors.

**Pure** substances have their own unique properties and a mixture can be separated by using the right **techniques** through this which is why all is the correct choice.

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In a titration, acetic acid is used as the analyte and sodium hydroxide is the titrant. At the equivalence point, will the ph be higher than, lower than, or equal to 7?.

In a** titration**, acetic acid is used as the analyte and sodium hydroxide is used as the titrant. At the **equivalence point**, ph be higher than 7.

The **equivalence point** of the titration is that point at which enough titrant has been added to react with all of the substance being titrated. A **strong acid** with a weak base gives a slightly acidic salt. Likewise, a strong base with weak acid gives slightly basic salt.

When** acetic acid** react with NaOH then a salt **sodium acetate** and water is formed. Acetic acid, CH3COOH react with sodium hydroxide, to produce sodium acetate, CH3COONa and water

CH3COO- + H2O ---> CH3COOH + OH-

This reaction of the acetate ion makes the ph **greater than 7.**

At the equivalence point, **moles **of acetic acid is equal to the moles of sodium hydroxide. The solution will turn pink as more of** sodium** **hydroxide** is added.

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ANSWER QUICKLY calcium carbide reacts with water to form calcium hydroxide and acetylene gas according to the reaction below what mass of Cac2 is used when 2.00 moles of water react

**Answer: Calcium carbide (CaC2) reacts with water to produce acetylene (C₂H₂):. CaC2 (s) + 2H2O (g) → Ca(OH)2 (s) + C₂H₂ (g).**

a 71.0 ml portion of a 1.50 m solution is diluted to a total volume of 258 ml. a 129 ml portion of that solution is diluted by adding 149 ml of water. what is the final concentration? assume the volumes are additive.

The **final concentration **assuming the volumes are additive when a 71.0 ml portion of a 1.50 m solution is **diluted** to a total volume of 258 ml. a 129 ml portion of that solution is **diluted** by adding 149 ml of water is 0.191 M

This can be solved by using the **dilution factor.**

So the dilution factor for the first dilution is 71.0 ml to 258 ml

DF1=258/71=3.63

For the first solution, the dilution factor is

3.163, refers that the concentration is decreased by a factor of 3.163.

The concentration of **diluted solution **is

c(diluted)=1.50/3.63=0.413

Now, you take a sample of 129 mL of this **diluted solution** and add another 165 mL of water. So,

V(final)=129ml +149 ml=278 mL

The concentration of the 129 mL sample is equal to the concentration of the first diluted solution, i.e. 0.413 M

So,

DF2=278/129=2.155

So, the final concentration is

c(final)=0.413/2.155=0.191 M

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1) An alloy called nichrome contains the elements chromium and nickel. 100g of nichrome contains 20g of chromium. How much nickel does it contain?

2) Why does bronze not rust?

3) Complete the equation: iron + copper sulphate = ____ + ____

Assume that the given **alloy** nichrome is pure of nickel and chromium then, if 100 g of nichrome contains 20 g of **chromium** , remaining is nickel thus, it contains 80 g of **nickel**.

**Bronze** hardly rust because the iron content in this alloy is very less. The reaction iron + copper sulphate gives iron sulphate + copper.

An** alloy **is a metallic substance made of two or more metals. For example nichrome is a combination of nickel and chromium and brass is a combination of copper and **zinc**.

If the 100 g of nichrome with 20 g of **chromium **purely contains nickel and chromium then, it contains 100-20= 80 g of nickel.

Bronze is an alloy of copper and tin. Rust is iron oxide and since bronze contains only traces of iron hence, it hardly undergo corrosion and form rust.

Iron and **copper sulphate** reacts to form iron sulphate and metallic copper: iron + copper sulphate [tex]\rightarrow[/tex]** iron sulphate**+ Cu.

Hence, the **mass **of 100 g of **nichrome** with 20g chromium is 80 g. Bronze does not rust because of the small **iron** content and iron and copper sulphate reacts to give iron sulphate and **Cu**.

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in the chlorine monoxide molecule, chlorine has a charge of 0.167 e-. if the bond length is 154.6 pm, calculate the dipole moment of the molecule in debyes. a. 3.11 d b. 2.30 d c. 0.167 d d. 1.24 d e. 1.65 d

The correct option is option** d 1.24**

**What is dipole moment?**

A **dipole moment **forms in any system where the charges are** dispersed**. A **dipole moment** could be created by both covalent and **ionic bonding**. The development of the **dipole moments **is caused by the difference in **electronegativity**.** Electronegativity** describes the **chemical bonding **between these two atoms.

A bond dipole moment measures the polarity between two atoms in a molecule. Bond **dipole** and the concept of **electric dipole moment** are connected. It evaluates how effectively a system separates positive and negative charges. The bond dipole moment has **magnitude **and **direction** because it is a vector quantity.

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a 0.755g sample of hydrated copper (ii) sulfate, cuso4 x h2o was heated carefully until it had changed completely to anhydrous copper (ii) sulfate, cuso4, with a mass of 0.483 g. determine the value of x.

The value of **x is 5. **

We know that,

Molar mass of CuSO4 = 156.609g/mol

Molar mass of H2O = 18.015g/mol

So ,Molar mass of CuSO4 .xH2O = **molar mass of CuSO4 +X**(molar mass of H2O)

Molar mass of CuSO4.xH2O=[( 156.609) + (18.015)X] g/mol

mass of CuSO4.xH2O = 0.755gmass of CuSO4 = 0.483g

And if we change 4.895 to a whole number or one significant figure,

then we get

**x = 5 **

chemical formula is = **CuSO4.5H2O (Blue Vitriol)**

**What is molar mass?**

The molar mass of a chemical compound is determined by dividing its **mass **by the **quantity** of that compound, expressed as the number of moles in the sample, measured in moles.

Therefore the value of** x is 5. **

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(a) what fraction of the neutron's kinetic energy is transferred to the carbon nucleus? (the mass of the carbon nucleus is about 12.0 times the mass of the neutron.)

There is the neutron's total kinetic energy. E is the same as the final **kinetic energy** of the EF-2 carbon nucleus. Okay, I'm down one from k E F one. In other words, Jews, this is 1.3 incremental -13 -4, -3.69 into 10 to the Power -14. 1.3 into a power of 10 to the -13th Minour.

Two will equal twelve in one if we subscribe one river to the neutron and another to **carbon**. Okay. EI one, which is a brand-new drone's first kind of technology, is equivalent to one three into ten to thirteen. For the first support, no. Half of Mnu square is equal to E I and E F, respectively, as well as one V squared. Additionally, if you apply the law of conservation of momentum, M 1 - M 2 will equal 1 + M 2 into Vi, giving you v = 2 and M 1 - M 2. And to you, multiplied by M1 + M2, is mmhmm.

As a result, if you substitute, the answer to the second equation will be K E F 1, which is equal to half of M 1, which is divided by M 1 plus M 2 entire square to give you square. We make this much simpler. And if we divide KEF one by KEI one, we get four, which is equal to M1 plus M2 divided by M1. Cool square, can you divide 4 M1 12 by M 1 + 12? My father has all this. One divided by M. They were by 1 69, which is equal to 40.

This serves as the first support's response. The final **kinetic energy** is provided by k e F one as a result of the neutron's current technology being transmitted to **carbon **during the collision's second support. That is equivalent to 3.69 into 10 and 48 x 1, respectively, and to 1.3 into 10 to the power of 13 and 69. Jews, to the Power -14. There is the neutron's total **kinetic energy**. E is the same as the final kinetic energy of the EF-2 carbon nucleus. Okay, I'm down one from k E F one. In other words, Jews, this is 1.3 incremental -13 -4, -3.69 into 10 to the Power -14. 1.3 into 10 to the power -13 Minor of the original solution.

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Cadmium (Cd) is a solid at room temperature, forms an ion that has a +1 or +2 charge, is a less reactive metal, and forms more than one unique compound with a given nonmetal. Because of these properties, cadmium (Cd) could also be identified as

a halogen.

an alkaline earth metal.

a transition metal.

an alkali metal.

Because of these properties, **cadmium **(Cd) could also be identified as a **transition metal**.

**Cadmium **(Cd) is a solid at room temperature, forms an ion that has a +1 or +2 charge, is a** less reactive metal**, and forms more than one unique compound with a given nonmetal.

**Transition metal,** any of various chemical factors which have valence electrons i.e., electrons that can participate inside the formation of chemical **bonds **in two shells as opposed to simplest one.

**Transition metals **are determined within the periodic desk among the s-block and p-block elements. Hence, they are known as **d-block **elements. Transition metals are unstable metals that display transitional conduct between s and p block elements, therefore their name.

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The hydrochloric acid utilized in this experiment can often discolor gloves if it is spilled on them during use. If this does occur, what should be done in order to remedy this potentially hazardous situation?.

There are many applications for **hydrochloric acid**. It is used for the production of chlorides, fertilizers and dyes, as well as in galvanic plating and in the **photographic**, textile and rubber industries.

Eyes, skin and mucous membranes are corroded by **hydrochloric acid.** In humans, acute (short-term) inhalation exposure may cause eye, nose, and **respiratory** tract irritation, as well as inflammation and pulmonary edema. Acute oral exposure can cause mucosal, esophageal, and stomach burns, and dermal contact can cause severe burns, ulceration, and scarring in humans. Gastritis, chronic bronchitis, dermatitis, and **photosensitization** have all been associated with chronic (long-term) exposure to hydrochloric acid. Long-term exposure to low concentrations can also cause tooth discoloration and **erosion**. Hydrochloric acid has not been classified as a carcinogen by the EPA.

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During a phase change, the temperature remains constant although heat is still being added. What is the best explanation for what the heat energy is being used to do?

A) Breaking chemical bonds to form new substances.

B) Moving the particles closer together.

C) Weakening or breaking the intermolecular forces.

D) Increasing the movement of particles.

A **phase change** is a physical change involves no bond making or breaking. The **heat energy** is used to weaken the intermolecular forces of attraction and moves the molecules apart. Thus option **C** and** D** are correct.

A **phase change** is the change in phase or state of the substance. For example, solid to liquid, liquid to gas conversions etc. are phase changes.

During a phase change, no** chemical bond **is breaked or maked but the **intermolecular force** of attraction holding the molecules together weakens and moves the molecules apart.

Consider the phase change of solid to liquid. The closely packed molecules in solid uses** heat energy **to to move apart by weakening the intermolecular force and form the liquid state.

Therefore, during a **phase change**, heat is used to weaken or break the **intermolecular force** and increasing movement of particles. Thus options **C **and **D** are correct.

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whats the molarity of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL

The **molarity **of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL is 11.85 mol/L.

**What is molarity?**

The number of moles of solute divided by the number of liters of solution is the definition of **molarity**, a concentration unit in chemistry. **Molarity **is measured in moles per liter (mol/L).

Number of moles of phosphoric acid whose molar mass is 98:

[tex]Number of moles = \frac{mass}{molar mass}[/tex]

n = 20/98

n = 0.204 mols

[tex]Volume = \frac{mass}{density }[/tex]

V = 20/1.22

V = 17.85 ml

**Molarity **is the number of moles of solute per liter of solution.

[tex]M = \frac{n}{V}[/tex]

Where, M = **molarity**, V = volume of solvent in liters, n = no. of moles of solute.

So, [tex]M = \frac{0.204}{17.85} \times \frac{1000}{1}[/tex]

M = 11.85 mol/L

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at the low temperatures found in some interstellar molecular clouds (around 100 k), molecular oxygen emission is strongest at a wavelength is 0.2521 cm. determine the speed (in km/s) of a low temperature molecular cloud containing molecular oxygen if its strongest emission is at a wavelength of 0.1835 cm

By using the **Doppler effect**, - 81634.27km/s is found to be the **velocity **of the cloud.

The **Doppler effect** can be used to solve this problem. When an observer travels in relation to the wave source, the frequency or wavelength changes from the viewpoint of the observed. The Doppler Effect is commonly used to calculate the **velocity **of the origin of waves or the velocity of the viewer. The generic waveform and frequency equations are used to derive the **Doppler Effect** velocity equations. The source velocity may then be calculated by setting the observer **velocity** to zero.

The Doppler shift in wavelength or frequency is calculated using the following relationship:

Δλ / λne = ν / c

where,

Δλ = wavelength shift

λne = wavelength of stationary source

ν = velocity of source

c = velocity of light = 3 x [tex]10^5[/tex] km/s

Given:

Initial wavelength, λini = 0.2521cm

New wavelength, λnew = 0.1835cm

Calculation:

Wavelength shift,

Δλ = λnew - λini

Δλ = (0.1835cm) - (0.2521cm)

Δλ = - 0.0686

On substitution of the known values in the above equation, we get:

Δλ / λne = ν / c

- 0.0686 / 0.2521 = ν / 3 x [tex]10^5[/tex]

ν = - 0.0686 x 3 x [tex]10^5[/tex] / 0.2521

ν = - 81634.27km/s

Result:

- 81634.27km/s is found to be the required **velocity **of the cloud moving towards us.

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the template code provided is intended to check whether an integer entered by the user is outside of the range 50-59 (inclusive). if it is outside of this range the program should print a warning and change the number to 55. however, when using de morgan's law to simplify this code, the programmer has made some mistakes. can you correct the errors so the code functions as intended?
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