**Answer:**

J = 3.564 N.s

**Explanation:**

From the given information:

angle θ = 27°

mass = 0.0200 kg

speed = 33.0 m/s

To determine the impulse applied using the equation:

J = m(2V cos θ)

J = 0.0200 (2 × cos (27.0))

J = 0.0200 (2 × 0.8910)

J = 0.03564

J = 3.564 N.s

A wave has a frequency of 2 Hz. Find its period

It’s period would be 0.5 seconds or 1/2. I think

T=1/f where f=2Hz => T=1/2 or 0,5 seconds.

A turntable, with a mass of 1.5 kg and diameter of 20 cm, rotates at 70 rpm on frictionless bearings. Two 540 g blocks fall from above, hit the turntable simultaneously at opposite ends of a diameter, and stick to it.

Required:

What is the turntable's angular speed, in rpm, just after this event?

**Answer:**

The turntable's angular speed after the event is 28.687 revolutions per minute.

**Explanation:**

The system formed by the turntable and the two block are not under the effect of any external force, so we can apply the Principle of Conservation of Angular Momentum, which states that:

[tex]I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}[/tex] **(1)**

Where:

[tex]I_{T}[/tex] - Moment of inertia of the turntable, in kilogram-square meters.

[tex]r[/tex] - Distance of the block regarding the center of the turntable, in meters.

[tex]m[/tex] - Mass of the object, in kilograms.

[tex]\omega_{o}[/tex] - Initial angular speed of the turntable, in radians per second.

[tex]\omega_{f}[/tex] - Final angular speed of the turntable-objects system, in radians per second.

In addition, the momentum of inertia of the turntable is determined by following formula:

[tex]I_{T} = \frac{1}{2}\cdot M\cdot r^{2}[/tex] **(2)**

Where [tex]M[/tex] is the mass of the turntable, in kilograms.

If we know that [tex]\omega_{o} \approx 7.330\,\frac{rad}{s}[/tex], [tex]M = 1.5\,kg[/tex], [tex]m = 0.54\,kg[/tex] and [tex]r = 0.1\,m[/tex], then the angular speed of the turntable after the event is:

[tex]I_{T} = \frac{1}{2}\cdot M\cdot r^{2}[/tex]

[tex]I_{T} = 7.5\times 10^{-3}\,kg\cdot m^{2}[/tex]

[tex]I_{T}\cdot \omega_{o} = (2\cdot r^{2}\cdot m +I_{T})\cdot \omega_{f}[/tex]

[tex]\omega_{f} = \frac{I_{T}\cdot \omega_{o}}{2\cdot r^{2}\cdot m +I_{T}}[/tex]

[tex]\omega_{T} = 3.004\,\frac{rad}{s}[/tex] ([tex]28.687\,\frac{rev}{min}[/tex])

The turntable's angular speed after the event is 28.687 revolutions per minute.

Which of the following is true of the

thermocline layer of the ocean?

A. rapidly decreases in temperature

B. warmest and least dense of the ocean layers

C. is the bottom layer of the ocean

D. is the top layer of the ocean

**Answer:**

d is trueeeeeeeeeeeeeeeee

What is the equation for frequency?

a. number of cycles +unit of time

b. number of cycles - unit of time

c. number of cycles ×unit of time

d. number of cycles/ unit of time

D. Number of cycles/ unit of time

**Answer:**

d

**Explanation:**

It is almost as if each outer planet is a solar system in its own right.

True or False

False there are many planets in our solar system

False.... planets like venus / mars is in our solar system

Which of the following is NOT true about

newspaper weather maps?

A. They report the temperature of the area in degrees

Fahrenheit.

B. They let you know how much precipitation to expect.

C. They provide more detail than weather service maps.

D. They tell you about the warm and cold air fronts.

It’s obviously C since all the rest of the answers make sense except for C.

Can anybody help in number 6? <3

**Answer:**

5.4 will be the weight in illustrate form

g A velocity selector consists of crossed electric and magnetic fields. The electric field has a magnitude of 480 N/C and is in the negative z direction. What should the magnetic field (magnitude and direction) be to select a proton moving in the negative x direction with a velocity of 3.50 cross times 10 to the power of 5 m/s to go un-deflected

**Answer:**

B = 1.37 mT

**Explanation:**

Given that,

The magnitude of the electric field, E = 480 N/C

The speed of the proton, [tex]v=3.50 \times 10^5\ m/s[/tex]

We need to find the magnitude of the magnetic field. In a velocity selector, the electric field is balanced by the magnetic field. So,

[tex]qE=qvB[/tex]

Where

B is the magnetic field

[tex]B=\dfrac{E}{v}\\\\B=\dfrac{480}{3.5\times 10^5}\\\\B=1.37\times 10^{-3}\ T\\\\or\\\\B =1.37\ mT[/tex]

**So, the magnetic field is equal to 1.37 mT. **

PLEASE HELP NO LINKS NEED HELP FAST

Use the scenario to answer the question.

An astronomer discovers a new galaxy using a telescope. The astronomer wants to investigate how the galaxy is moving relative to the Milky Way galaxy.

In one or two sentences, make a hypothesis about the movement of the galaxy and explain at least one way to test the hypothesis.

**Answer:**

The galaxies outside of our own are moving away from us, and the ones that are farthest away are moving the fastest. This means that no matter what galaxy you happen to be in, all the other galaxies are moving away from you

**Explanation:**

The hypothesis about the **movement** of the **galaxy** is that galaxies are **moving** far from each other continuously.

The milky way galaxy is a **galaxy** that contains over a hundred billion stars and it also includes our **solar system**. Its name describes its appearance when viewed from the earth. All the individual stars in the whole sky are a portion of the** Milky Way Galaxy,** the term "**Milky Way**" is because of the band of light.

The **astronomer** has discovered a **new galaxy** which means our universe is continuously **expanding**. This is because the universe encloses everything that exists.

**Galaxies** are moving in space and since the **universe** space is continuously expanding so the galaxies continuously move from each other. The farther the galaxy is from the** milky way** which is an **observable part**, the faster will be moving the galaxy and the closer the galaxy is to the milky way, the slower will be **movement** of the galaxy.

Learn more about** the milky way galaxy**, Here:

https://brainly.com/question/2905713

#SPJ5

Select all the correct answers.

Which statements about our solar system are false?

Our solar system is made up of the Sun and other objects that orbit the Sun.

The Sun is the only star in our solar system.

Dwarf planets have several other bodies in their path orbiting the Sun just as they do.

The Kuiper Belt is between Uranus and Neptune.

A large number of irregularly shaped comets are located in a vast ring between the orbits of Mars and Jupiter.

D and E are false.

A, B, and C are true.

Answer:

- Our solar system is made up of the Sun and other objects that orbit the Sun.

- The Sun is the only star in our solar system.

- Dwarf planets have several other bodies in their path orbiting the Sun just as they do.

Explanation:

plato

Which of the following is an example of heat transfer by conduction?

A. Heat is transferred to the air above a candle flame.

B. Heat is transferred to the soil on a sunny day.

c. Heat is transferred to your hand from a warm cup.

D. Heat is transferred to the air from a warm lightbulb.

**Answer:**

*option** c*

* ** ** ** **Heat **is **transferred** to** **your** **hand **from** **a **warm** **cup *

*conduction** **is **the **process** of** **transferring** of** heat** **from** **one **material** **to **another** **when** **they **are **in **contact** *

*hope** it** helps*

It’s option c.

Conducting need contact

Conducting need contact

Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic collision. Momentum is conserved. Object A has a mass of mA = 16.7 kg and an initial velocity of = 7.26 m/s, due east. Object B, however, has a mass of mB = 29.3 kg and an initial velocity of = 4.39 m/s, due north. Find the (a) magnitude and (b) direction of the total momentum of the two-object system after the collision.

**Answer:**

a) v = 3,843 m / s, b) 46.7º North- East

**Explanation:**

Moment is a vector quantity, so one of the best ways to solve this problem is to solve each component separately.

The system is formed by the two vehicles so that the moment is preserved during the crash

Direction to the East

initial instant. Before the crash

p₀ = mₐ vₐ₀

final insttne. After the crash

p_f = (mₐ + m_b) vₓ

p₀ = p_f

mₐ vₐ₀ = (mₐ + m_b) vₓ

vₓ = [tex]\frac{m_a}{m_a + m_b} \ v_{ao}[/tex]

let's calculate

vₓ = [tex]\frac{16.7}{16.7 + 29.3} \ 7.26[/tex]

vₓ = 2,636 m / s

direction north

initial p₀ = m_b v_{bo}

final p_f = (mₐ + m_b) v_y

p₀ = p_f

m_b v_{bo} = (mₐ + m_b) v_y

v_y = [tex]\frac{m_b}{m_a+m_b} \ v_{bo}[/tex]

let's calculate

v_y = [tex]\frac{29.3}{16.7 + 29.3} \ 4.39[/tex]

v_y = 2.796 m / s

the final speed of the two two vehicles is

v = (2,636 i ^ + 2,796 j ^) m / s

a) the magnitude of the velocity

let's use the Pythagorean theorem

v = [tex]\sqrt{v_x^2 + v_y^2}[/tex]

v = [tex]\sqrt{2.636^2 + 2.796^2}[/tex]

v = 3,843 m / s

b) let's use trigonometry to find the direction

tan θ = v_y / vₓ

θ = tan⁻¹ v_y / vₓ

θ = tan⁻¹ (2,796 / 2,636)

θ = 46.7º

This direction is 46.7º North East

Describe the formation of the land, the atmosphere, and the oceans of earth

Land: Tectonic plate movement under the Earth can create landforms by pushing up mountains and hills. Erosion by water and wind can wear down land and create landforms like valleys and canyons. ... Landforms can exist under water in the form of mountain ranges and basins under the sea.

Atmosphere: (4.6 billion years ago)

As Earth cooled, an atmosphere formed mainly from gases spewed from volcanoes. It included hydrogen sulfide, methane, and ten to 200 times as much carbon dioxide as today's atmosphere. After about half a billion years, Earth's surface cooled and solidified enough for water to collect on it.

Ocean: After the Earth's surface had cooled to a temperature below the boiling point of water, rain began to fall—and continued to fall for centuries. As the water drained into the great hollows in the Earth's surface, the primeval ocean came into existence. The forces of gravity prevented the water from leaving the planet.

Atmosphere: (4.6 billion years ago)

As Earth cooled, an atmosphere formed mainly from gases spewed from volcanoes. It included hydrogen sulfide, methane, and ten to 200 times as much carbon dioxide as today's atmosphere. After about half a billion years, Earth's surface cooled and solidified enough for water to collect on it.

Ocean: After the Earth's surface had cooled to a temperature below the boiling point of water, rain began to fall—and continued to fall for centuries. As the water drained into the great hollows in the Earth's surface, the primeval ocean came into existence. The forces of gravity prevented the water from leaving the planet.

TIME REMAINING

15:56:15

A plant root is an example of

Type here to search

**Answer:**

h

**Explanation:**

1.

is the rate that velocity changes

O Acceleration

O

Time

O

Distance

O

Mass

**Answer:**

a) acceleration

**Explanation:**

Acceleration is, by definition, the change of an object's velocity.

A belt of negligible mass passes between cylinders A and B and is pulled to the right with a force P. Cylinders A and B weigh, respectively, 5 and 20 lb. The shaft of cylinder A is free to slide in a vertical slot and the coefficients of friction between the belt and each of the cylinders are µs = 0.50 and µk = 0.40. For P = 3.6 lb,

Determine:

(a) Whether slipping occurs between the belt and either cylinder,

(b) The angular acceleration of each cylinder.

**Slipping** doesn't occur between the belt and **cylinder B **because the **force** of **static friction **is greater than **force** exerted on **cylinder B**.

Given the following data:

Mass A = 5 lb to kg = 2.27 kg.

Mass B = 20 lb to kg = 9.02 kg.

Force = 3.6 lb to N = 16.02 Newton.

How to calculate angular acceleration.In order to calculate the **angular acceleration **of each **cylinder**, we would take moment about the two **cylinders**.

For **cylinder A**:

[tex]\sum M_G=\sum (M_G)_{eff}\\\\I_A\alpha _A = F_A (0.1)\\\\(\frac{m_Ar^2}{2}) \alpha _A = F_A (0.1)\\\\(\frac{2.27 \times 0.1^2}{2}) \alpha _A = F_A (0.1)\\\\0.1F_A=0.01135\alpha _A\\\\F_A=\frac{0.01135\alpha _A}{0.1} \\\\F_A= 0.1135\alpha _A[/tex]

For **cylinder B**:

[tex]\sum M_G=\sum (M_G)_{eff}\\\\I_B\alpha _B = F_B (0.2)\\\\(\frac{m_Br^2}{2}) \frac{\alpha _A}{2} = F_B (0.2)\\\\(\frac{9.02 \times 0.1^2}{4}) \alpha _A = F_B (0.2)\\\\0.1F_B=0.02255\alpha _A\\\\F_B=\frac{0.02255\alpha _A}{0.2} \\\\F_B= 0.1128\alpha _A[/tex]

For the **belt**, we have

[tex]\sum F_A =0\\\\P-F_B-F_A=0\\\\16.02-0.1128\alpha _A-0.1135\alpha _A=0\\\\16.02=0.2263\alpha _A\\\\\alpha _A=\frac{16.02}{0.2263} \\\\\alpha _A=70.79 \;rad/s^2[/tex]

Also, we would determine the **angular acceleration** of cylinder** B**:

[tex]0.1\alpha _A=0.2\alpha _B\\\\0.1 \times 70.79 = 0.2\alpha _B\\\\7.079= 0.2\alpha _B\\\\\alpha _B=\frac{7.079}{0.2} \\\\\alpha _B=35.40\;rad/s^2[/tex]

Next, we would calculate the **forces** acting on the **cylinders**:

[tex]F_A = 0.1135\alpha _A\\\\F_A = 0.1135 \times 70.79\\\\F_A = 8.04 \;Newton[/tex]

[tex]F_B = P-F_A\\\\F_B = 16.02 - 8.04\\\\F_B = 7.98\;Newton[/tex]

Next, we would determine the **force** of **static friction**:

[tex]F_s = \mu_s N = \mu_s m_B g\\\\F_s = 0.50 \times 9.02 \times 9.8\\\\F_s=44.198\;Newton[/tex]

From the above calculation, we can deduce that the **force** of **static friction **is greater than **force** exerted on **cylinder B**. Therefore, slipping doesn't occur between the belt and **cylinder B**.

Read more on **angular acceleration** here: https://brainly.com/question/6860269

An electromagnetic wave has a frequency of 5.0 x 1014 Hz. What is the

wavelength of the wave? Use the equation 2 = and 3.0 x 108 m/s for the

speed of light.

A. 1.7 x 10-8 m

О

B. 6.0 x 1022 m

O C. 6.0 x 10-7 m

O D. 1.7 x 105 m

**Answer:**

c

**Explanation:**

wavelength = speed of light/ frequency

= (3x 10^8 m/s)/(5.0 x 10^14 Hz)

= 6.0 x 10^-7 m

A student hangs a block from a light string that is attached to a massive pulley of unknown radius R, as shown in the figure. The student allows the block to fall from rest to the floor. Which two of the following sets of data that could be measured or determined should the student use together to determine the final angular velocity of the pulley just before the block hits the floor? Select two answers. Justify your selections.

**Answer:**

The mass of the block, the distance of the block above the floor, and the time it takes the block to reach the floor, because these quantities can be used to determine the acceleration of the block.

The radius and the mass of the pulley, because these quantities can be used together to determine the rotational inertia of the pulley.

**Explanation:**

If the motion starts from rest, the** initial angular velocity** will be zero and the **final angular velocity** can be determined with the product of **angular acceleration** and** time** of motion of the **pulley.**

**Angular velocity **is defined as the change in the angular displacement per change in time of motion. This can be expressed mathematically as follows;

[tex]\omega = \frac{\Delta \theta}{\Delta t} = vr[/tex]

where;

Ф is the angular displacementt is the time of the motionv is the linear velocityr is the radius of the circular path.In a **circular motion** that starts from rest and ends with final velocity, the equation is given as;

[tex]\omega_f =\omega_i + \alpha t[/tex]

Where;

[tex]\omega_f[/tex] is the final angular velocity[tex]\omega_i[/tex] is the initial angular velocity[tex]\alpha[/tex] is the angular accelerationThus, if the motion starts from rest, the** initial angular velocity** will be zero and the **final angular velocity** can be determined with the product of **angular acceleration** and** time** of motion of the** pulley**.

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A rod that is 96.0 cm long is made of glass that has an index of refraction equal to 1.60. The rod has its ends ground to convex spherical surfaces that have radii equal to 8.00 cm and 19.1 cm. An object is in air on the long axis of the rod 19.9 cm from the end that has the 19.1-cm radius.

(a) Find the image distance due to refraction at the 19.1-cm radius surface.

(b) Find the position of the final image due to refraction at both surfaces.

(c) Is the final image real or virtual?

your answer is B! find the position of the final image due to refraction at both surfaces

A 41.6-kg person, running horizontally with a velocity of +4.21 m/s, jumps onto a 14.6-kg sled that is initially at rest. (a) Ignoring the effects of friction during the collision, find the velocity of the sled and person as they move away. (b) The sled and person coast 30.0 m on level snow before coming to rest. What is the coefficient of kinetic friction between the sled and the snow?

**Answer:**

a) v = 3.116 m / s, b) μ = 1.65 10⁻²

**Explanation:**

a) to find the velocity of the set, let's define a system formed by the person and the sled, so that the forces during the collision are internal and the moment is conserved

initial instant. Before the crash

p₀ = M v₀

final instant. After the crash

p_f = (M + m) v

the moment is preserved

M v₀ = (M + m) v

v = [tex]\frac{M}{M+m} \ v_o[/tex]

let's calculate

v = [tex]\frac{41.6}{41.6 + 14.6} \ 4.21[/tex]

v = 3.116 m / s

b) for this part let's use the relationship between work and kinetic energy

W = ΔK

as the body has its final kinetic energy is zero

the work of the friction forces is

W = - fr x

the negative sign is because the friction forces always oppose the movement

let's write Newton's second law

Y axis

N - W_sled -W_person = 0

N = mg + M g

N = (m + M) g

X axis

fr = ma

the friction force has the expression

fr = μ N

fr = μ g (m + M)

we substitute

- μg (m + M) x = 0- ½ (m + M) v²

μ = [tex]\frac{1}{2} \ \frac{v^2 }{g \ x }[/tex]

let's calculate

μ = [tex]\frac{1}{2} \ \frac{3.116^2}{9.8 \ 30.0}[/tex]

μ = 0.0165

μ = 1.65 10⁻²

Two points on a progressive wave are out of phase by 0.41 rad.

What is this phase difference?

[1 mark]

A 23° [e]

B 47° [e]

C 74° [e]

D 148° [e]

The p**hase difference **between **two points** on a progressive wave are out of phase by** 0.41 rad** is **23°.**

An equation is an expression that shows the** relationship** between two or more **numbers and variables**.

The two points on a progressive wave are out of phase by 0.41 rad.

Hence, Phase difference = **0.41 rad**

But:

**Rad to degree = (rad * 180/π)°**

Hence:

**0.41 rad **= (0.41 rad * 180/π) =** 23°**

The p**hase difference **between **two points** on a progressive wave are out of phase by** 0.41 rad** is ** 23°.**

Find out more on ** equation** at: https://brainly.com/question/2972832

an object is acted by force of 22 newtons to the right and a force of 13 newtons to left

**Answer:**

**Explanation:**

I'm going to guess that you want the net force.

These two forces are acting in opposite directions. Therefore the forces are subtracted in effect.

F = F1 - F2

F1 = 22N to the right

F2 = 13N to the left

F = 22 - 13 = 9 N to the right.

Specifying the direction is very important. Forces do have directions and you must specify what that is. Otherwise, the question should be marked incorrect.

stainless steel, tell us about its properties and what should be taken into account when using it?

It has low maintenance Which is long lasting, and environmentally friendly which means it’s recyclable

On a perfect fall day, you are hovering at low altitude in a hot-air balloon, accelerated neither upward nor downward. The total weight of the balloon, including its load and the hot air in it, is 20,000 N. a. Show that the weight of the displaced air is 20,000 N. b. Show that the volume of the displaced air is 1700 m3 .

**Explanation:**

Since the balloon is not accelerating means that the net force on the balloon is zero. This implies that the weight of balloon must be equal to the buoyant force on balloon.

Hence, the buoyant force equals the weight of air displaced by the balloon, also 20,000 N.

Weight of the air displaced = density of air × volume

The density of air at 1 atm pressure and 20º C is 1.2 kg/m³

the volume V = 20,000/(1.2×9.8) = 1700 m³

A cylindrical diving bell is open at the bottom and closed at the top, and is 5m tall. The bell is open to atmospheric air until it is placed in the water, but the bell remains upright (open end facing down, closed end facing up). The pressure of the air inside the bell will naturally increase by 105 Pa for every 10m of depth the bell descends within the water. Assume the temperature of the air remains constant for this process, and that the air can be approximated as an ideal gas

Required:

a. If the bell is lowered 40 meters below the surface, how many meters of air space are left inside the bell?

b. Explain why water doesn't completely flood the bell as it enters the water V (m).

**Answer:**

a) y = 0.35 m, b) hydrostatic balance

**Explanation:**

a) For this fluid mechanics exercise, let's use that the pressure at a given level is the same, let's set a level on the bell shape.

The pressure inside is

P_interior = P₀ + ρ g h ’

The pressure outside

P_exterior = Pₐ + ρ g h

as the point is at the same level the pressures are equal

P_interior = P_exterior

P₀ + ρ g h ’= Pₐ + ρ g h

h ’= (Pₐ- P₀) + ρ g h

To calculate P₀ they indicate that the pressure increases 10⁵ Pa for every 10 m, we use a direct rule of proportions or rule of three

P₀ = 10⁵ (40 + h ’) / 10 = 4 10⁵ + h’ 10⁴

the positive sign is because the water inside the hood also increases the air pressure.

we substitute

(4 10⁵ + h’ 10⁴) + ρ g h’ = Pₐ + ρ g h

h’ (ρ g + 10⁴) = Pₐ - 4 10⁵ + ρ h h

h’ (1000 9.8 + 10⁴) = (1 10⁵ -4 10⁵) + 1000 9.8 40

h' (1.98 10⁴) = -3 105 + 3.92 10⁵

h’ = [tex]- \frac{0.92 \ 10^5 }{1.98 \ 10^4 }[/tex]

h ’= -4.65 m

as the hood is only 5 m high, the free air space is

Y = 5 - 4.65

y = 0.35 m

it is very little free space

B) The pressure outside and inside the hood is the same, the water rises inside the hood until the pressures equalize and at this point the force is equal and in the opposite direction, which is why the system is in hydrostatic balance.

The rollercoaster is near the

bottom of the hill after the first big

drop. Which best describes the

potential and kinetic energy?

A. It has mostly kinetic energy.

B. It has mostly potential energy.

C. The kinetic energy is decreasing.

D. The potential energy is about 50%

and increasing.

**Answer:**

A. It has mostly kinetic energy

**Explanation:**

Kinetic energy refers to movement. Potential energy refers to height. In this case, the big drop just got over. So, when the coaster is at the bottom, it has more kinetic than potential energy . Potential energy is still present but kinetic is more at the bottom.

Please help me someone !

**Answer:**

**The object is moving at constant speed.**

**Explanation:**

The spaces between the dots are equal.

A 1.8 kg book has been dropped from the top of the football stadium. Its speed is 4.8 m/s when it is 2.9 m above the ground. How high is the stadium?

**Answer:**

**the height of the stadium is 4 m **

**Explanation:**

The computation of the height of the stadium is shown below:

but before that total mechanic energy should be determined

**E = PE + KE **

where

**PE = mgh**

**and, KE = 1 ÷2 mv^2**

Now

E = mgh + 1 ÷2 mv^2

= (1.8) (9.8) (2.9) + 1 ÷ 2 (1.8) (4.8)^2

= 71.9J

= 72J

Now the height of the stadium is

**TE = mgh**

72 = (1.8) × (9.8) × h

So, h = 4 m

Hence, **the height of the stadium is 4 m **

Humans impact the Earth in good AND bad ways.

A) True

B) False

**Answer:**

True

**Explanation:**

yes we can see that we are helping animals but we create pollution which is very bad

The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is applied in the same direction to each steering wheel. What is the ratio of the torque produced by this force in the truck to the torque produced in the car

**Answer:**

[tex]\frac{T_t}{T_c} = 1.32[/tex]

**Explanation:**

The torque applied on an object can be calculated by the following formula:

[tex]T = Fr[/tex]

where,

T = Torque

F = Applied Force

r = radius of the wheel

For car wheel:

[tex]T_c = Fr_c\\[/tex]

For truck wheel:

[tex]T_t = Fr_t[/tex]

Dividing both:

[tex]\frac{T_t}{T_c} = \frac{Fr_t}{Fr_c}[/tex]

for the same force applied on both wheels:

[tex]\frac{T_t}{T_c} = \frac{r_t}{r_c} \\[/tex]

where,

rt = radius of the truck steering wheel = 0.25 m

rc = radius of the car steering wheel = 0.19 m

Therefore,

[tex]\frac{T_t}{T_c} = \frac{0.25\ m}{0.19\ m} \\[/tex]

[tex]\frac{T_t}{T_c} = 1.32[/tex]

A triangle is shown in the image.What is the area of the triangle represented?A: 204 in2B: 216 in2C: 408 in2D: 432 in2
MPH. Test-5 Question 1 Choose the incorrect answer. Clinical data sources include: hospital data diseases treated in special clinics immunization records of pupils in school data from physicians' records Question 6 An abrupt drop in mortality due to a specific disease from one year to the next is most likely due to: Answers: incorrect listing of cause of death by the physician on the death certificate coding mistake when using the International Classification of Disease (ICD) system A and B a change in the International Classification of Disease (ICD) system fewer older persons dying from chronic diseases each year Question 8 Descriptive epidemiology characterizes the amount and distribution of disease within a population and enables the researcher to: make direct tests of etiologic hypotheses generate testable hypotheses regarding etiology evaluate trends in health and disease within a population All of the above B and C only Question 9 What data source has the advantage of being almost nearly complete in the U.S.? Reportable disease statistics Mortality statistics Birth statistics B and C Question 10 Age-specific and age-adjusted mortality rates by sex in the United States generally show the following sex differences: Answers: Rates for males are higher than rates for females from birth to age 85 and older. Rates for females are higher than rates for males from birth to age 85 and older. Rates for males are higher than rates for females from age 6 to age 85 and older. Rates for males are equal to rates for females during the first 5 years of life. C and D
1. Suppose thereare 4 people and 9 different assignments. Each person should receive oneassignment. Assignments for different people should be different. How many waysare there to do it?
g with a and c being arrays of double precision floating point numbers with each element being 8 bytes. no element of a or c is in the cache before executing this code. assuming that the cache is large enough to hold both a and c, and has a cache block size of 64 bytes, determine
Which resource management involves the administrative tasks that address the hiring and compensation of a company's employees?
What is the correct formula for wavelength as a function of energy?
What type of data analytics is used to get the answer of what will happen in the future?
Assign a molecular geometry to each interior atom in cytosine Drag the appropriate labels to their respective targets. Reset Help H tetrahedral HC C trigonal planai HC, Z trigonal pyramidal bent NH2 Assign a hybridization to each interior atom in cytosine. Drag the appropriate labels to their respective targets. SP H N. HC =O sp? HC Sp N
Are there persons who are dominantly right-brained or left brained?
What is the difference between Indian and western education?
If you tossed two coins simultaneously 400 times, would you expect the deviation to be greater or less than it was in tossing them 40 times? Explain.
What happens in chapter 9 of among the hidden?
how many grams of magnesium must react with phosphoric acid to produce 100 L of hydrogen gas
What is the mode of 2 6 5 3 0 3 4 3 2 4 5 2 4?
Why are some genetic diseases common?
4 adults took their 5 children to a movie. The price for the 9 people was $160. The 5 children recieved a 20% discount on their tickets. The cost for a child ticket is how much less than the cost of an adult ticket?
The core value of ____________________ reveals the independent american spirit.
What are Plato's views on slavery?
compare and contrast between bacterial cell division and eukaryotic cell division in terms of length of time it takes.
Why does Swift dehumanize people in A Modest Proposal?