The value of the Acceleration at the given** speed** of** 262 m/s **will be** 0.245 m / s²**

Throughout time, the **velocity** is shifting. In actuality, the velocity is changing by a fixed rate of 10 m/s every second. An object is considered to be accelerating if its velocity is changing; it has **acceleration.**

Given that:

Mass of car = 2 Tonnes = 2000 kg.

Wheel's power transfer = Efficiency * b.P.

Power = 0.9 * 57000

Therefore, **Power = 51300 W**

Wheel's angular velocity = (2[tex]\pi[/tex]N / 60) * (1 / rear-axle ratio)

Angular Velocity = (2[tex]\pi[/tex] * 4000) / 60 * (1 / 4.4)

Therefore, **Angular Velocity** = **95.15 rad / sec**

**Wheel:**

Power = Torque * Angular Velocity

P = F * Tyre Radius * W

⇒ 51300 = F * 0.33 * 95.15

F = 51300 / (0.33 * 95.15)

F = 51300 / 31.4

Therefore, **Force = 1633.76 **(by the engine)

**Resistance:**

Rolling Resistance (Fr) = 180 N/tonne * 2 = 360 N

**F₁ = 360N**

**Gradient Resistance: **

tanθ = 1 / 25

θ = 2.2906°

Fg = mg * sinθ

Fg = 2000 * 9.84 * sin (2.2906)

**Fg = 783.37 N**

**Acceleration (a):**

Net force = Mass * Acceleration

F - (Fr + Fg) = 2000 * a

1633.76 - (360 + 783.37) = 2000 * a

a = 490.39 / 2000

Therefore, **Acceleration = 0.245 m / s²**

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suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. the first child exerts a force of 74.0 n, the second a force of 89.0 n, friction is 8.00 n, and the mass of the third child plus wagon is 23.0 kg.

The wagon and the child inside it make up the system of interest, **acceleration **equals **0.13 m/s²** in the direction of child 1 and Zero** **acceleration if friction is 15.0 N.

When two things are moved against one another, instant **friction **results. The motion will be opposed by the friction, who will also be working against it. When an item is in motion and its velocity changes, the concept of **acceleration **takes place. **Friction**, which opposes motion, always lowers acceleration. An object and a surface come into contact and cause friction. The features of the surface and the item, as well as whether or not the object is moving, determine its magnitude. Always, friction works in the opposite direction of motion. As a result, **friction **cancels out some of the force driving motion when it is there. Therefore, there will be less acceleration and net force.

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At a gas is in a container with a constant temperature pressure change cause the volume to decrease based on the relationship between pressure and volume what must happen to the pressure

At constant** temperature pressure **is inversely proportional to volume, so pressure will increase.

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When we see saturn going through a period of apparent retrograde motion, it means.

In its orbit, **Earth **is passing** Saturn,** with both planets on the same side of the Sun.

**What is apparent retrograde motion?**

When a planet appears to be moving backward relative to other bodies in its solar system when viewed from a certain angle, this is known as **apparent retrograde motion.** Motion in the same direction as other bodies is referred to as direct motion or prograde motion.

Mars typically looks to be traveling to the left of the stars. **Mars**, however, moves right in relation to the **stars **during** "retrograde motion"** periods. Truth be told, that is only an illusion that lasts for around two years. In reality, **Earth** is orbiting the **Sun** and is currently passing past Mars. **Mars** is only occulted by Earth once every 26 months since it orbits the Sun more closely and moves quicker than Mars. **Mars** typically moves from west to east in the sky, but when Earth passes in front of it, we see it move from east to west, creating the impression that it is going backward.

Hence, the earth is passing **Saturn** in its orbit, with both planets on the same side of the Sun.

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Ask Tutor a question about your assignment

The current in each **branch** of the circuit is **9.5 A** and** 0 A**.

Point B, according to Kirchoff's** junction** law equation is

**i = i₁ + i₂ ** ......equation 1

Now, according to Kirchoff's **Loop** law,

Loop 2 is anticlockwise, calculates the current i₂ equation is

21.4 - 50i₂ - 6 - i - 100i₂ = 0

**150i₂ + i = 15.4** ......equation 2

Loop 1 is clockwise, calculates the current i₁ equation is

20.5 - 30i₁ - 6 - i - 40i₁ - i₁ = 0

**80i₁ + i = 14.5 ** ........equation 3

substitute equation 1 in equation 3 for the value of i,

81i - 80i₂ = 14.5 .....equation 3

Upon, subtracting equation 3 from equation 2, we get **i₂ = 9.5 A **

substituting the value of i₂ in equation 3, we get i = 9.5A

Hence on substituting value for i₁, in equation 1 , we get **i₁ = 0 A **

Hence, the** current **in each branch of the circuit is **9.5A, 9.5A, 0A**

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One tank of goldfish is fed fish food once a day. A second tank is fed twice a day, and a third tank is fed food four times a day during a six week study. The weight of each fish is recorded daily.

The dependent variable in the experiment in which the **weight of each fish** is recorded daily is the fish' weight.

A **dependent variable** is the variable that cannot be controlled in an experiment. An independent variable is the controllable variable/factor in an experiment.

In this experiment, the amount of food fed and how often the food fed can be controlled. The **fat gained** by the fish and the weight of fish cannot be controlled.

Therefore, in this experiment the dependent variable is **weight of fish.**

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we will explore more this equation. we need to solve this for all masses! you should recognize now that this system of linear equations can be written in a matrix form. we will define the variable

The coefficients of the variables in each equation can be arranged in a row to create the coefficient **matrix**. A constant term should always be written on the right in standard form for each equation.

A coefficient matrix, a variable matrix, and a constant **matrix **can all be used to describe a system of linear **equations **in matrix form.

Think about the system,

2x+3y=8

5x−y=−2

X and Y are the variables that we have. As a result, the variable **matrix **can be written as [xy].

The constant terms from the equations, 8 and 2, are on the right side of the equivalence. The first and second rows of the constant matrix are occupied by the two integers in that order since they are the ones that correspond to the first and second **equations**. The matrix then takes the form [82].

The system is now represented by the equation [2531] [xy] = [82].

Now, the system is denoted as [2531] [xy]=[82].

You can see that the matrix representation is identical to the system of **equations **using matrix multiplication.

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Which of the following statements is most true regarding the use of testimony on hair samples in courts today?

We may not consider the use of** hair samples **today because **DNA **analysis is more modern.

The term **DNA **refers to the molecule that contains the** genetic material **of the living things. Hence, we could use the DNA sample to be able to solve very difficult cases. This is because the DNA sample can be able to tell the exact identity of the person that involved,

Before the advent of the DNA, the hair sample was one of the very reliable ways be which evidence could be gathered to solve crimes. Hence; Modern** DNA analyses** have made testimony using hair samples obsolete.

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Missing parts;

Hair samples are replacing DNA as an easily available, go-to source for identifying suspects

Modern changes in the discipline mean that any police officer can provide testimony on hair samples

Modern DNA analyses have made testimony using hair samples obsolete

There’s solid research that should lead us to be skeptical of testimony based on hair samples

5.12 ** consider a simple harmonic oscillator with period r. let ( f ) denote the average value of any variable f (t), averaged over one complete cycle: 1 f (f)

considering simple** harmonic oscillator** with period r E=1/2mw²A² , T= 1/4mw²A² V = 1/4mw²A² therefore **T=V=E/2.**

A model with numerous significant applications in both conventional and quantum mechanics is the **harmonic oscillator**. It acts as a model for the mathematical analysis of a wide range of phenomena, including elasticity, acoustics, AC circuits, molecular and crystal vibrations, electromagnetic fields, and the optical characteristics of matter. A body is referred to be a linear harmonic oscillator or a simple harmonic oscillator when it oscillates about its location along a linear straight line under the influence of a force that is directed towards the mean location and is proportionate to the **displacement **at any moment from this location. Periodic motion is best demonstrated by this type of oscillation. The period is completely independent of the initial **displacement **from equilibrium (amplitude of oscillation). The period is unaffected by how far the cart is moved from its equilibrium location. the greatest **displacement **from the mean position, is the angular speed of the body rotating around in a circle, and t is the duration.

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A 750 resistor in a circuit has a current flowing through it of 2.0 A. What is

the power dissipated by the resistor? (Use P=OVI = /²R= VR)

OA. 300 W

B. 150 W

C. 38 W

D. 450 W

The **power **dissipated by the resistor is** 3000W.**

**Electrical power**, or (P), in a circuit is a unit of measurement for the rate at which energy is consumed or produced inside a circuit. The energy produced or delivered by an **energy source**, such as a **voltage**, is absorbed by the associated load.

In physics, power is referred to as the rate of **energy conversion **or transfer over time. The unit of power in the** SI system, **often known as the **International System **of **Units**, is the** Watt (W).** A single joule per second is one watt. Power was formerly referred to as activity in some research. A **scalar quantity** is **power.**

The resistor's **power **dissipation can be computed as P = I²R

here ,

I = 2 A

R = 750

Therefore P= **2² x 750 W**

**= 3000W**

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Q2. A stone leaves a slingshot horizontally with an initial speed of 15.2 m/s from a

height 1.1 m above the ground. Determine the stone's:

a) total air time

b) maximum height

c) range

d) final velocity

Horizontal

VX =

dx = ?

t = ?

Vertical

dy = -1.1m

v1y =

v2y= ?

a =

t = ?

**Answer:**

Assume that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex]. Also assume that that the air resistance on this stone is negligible.

The total air time of this stone is approximately [tex]1.5\; {\rm s}[/tex].

The maximum height of this stone is [tex]1.1\; {\rm m}[/tex], same as the height of the slingshot.

The range of this stone is approximately [tex]23\; {\rm m}[/tex].

The final velocity of this stone is approximately [tex]21\; {\rm m \cdot s^{-1}}[/tex].

**Explanation:**

If the air resistance on this stone is negligible, this stone will accelerate towards the ground with a **vertical acceleration** [tex]a_{y}[/tex] of [tex]a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex].

At the same time, the **horizontal velocity** [tex]v_{x}[/tex] of this stone will stay the same during the entire flight: [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex].

The stone was launched from a height of [tex]1.1\; {\rm m}[/tex] above the ground. Therefore, the **vertical displacement** [tex]x_{y}[/tex] of the stone will be [tex]x_{y} = (-1.1)\; {\rm m}[/tex] when the stone hits the ground.

The **initial vertical velocity** [tex]u_{y}[/tex] of this stone would be [tex]u_{y} = 0\; {\rm m\cdot s^{-1}}[/tex] since the stone was launched horizontally.

Let [tex]v_{y}[/tex] denote the **final vertical velocity** of this stone right before landing. Apply the SUVAT equation [tex](v_{y})^{2} - (u_{y})^{2} = 2\, a\, x[/tex] to find [tex]v_{y}\![/tex]:

[tex](v_{y})^{2} - (u_{y})^{2} = 2\, a\, x[/tex].

[tex](v_{y})^{2} = (u_{y})^{2} + 2\, a\, x[/tex].

[tex]\begin{aligned}v_{y} &= -\sqrt{(u_{y})^{2} + 2\, a\, x} \\ &= -\sqrt{0^{2} + 2\, (-9.81) \, (-1.1)}\; {\rm m\cdot s^{-1}} \\ &\approx -14.6908 \end{aligned}[/tex].

(Final vertical velocity [tex]v_{y}[/tex] is negative since the stone is travelling downwards toward the ground.)

Let [tex]t[/tex] denote the duration of this flight. Apply the SUVAT equation [tex]t = (v_{y} - u_{y}) / (a)[/tex] to find [tex]t\![/tex]:

[tex]\begin{aligned} t &= \frac{v_{y} - u_{y}}{a} \\ &\approx \frac{(-14.6908) - 0}{(-9.81)}\; {\rm s} \\ &\approx 1.49753\; {\rm s} \end{aligned}[/tex].

In other words, this stone was in the air for approximately [tex]1.5\; {\rm s}[/tex].

Also because the stone was launched horizontally, the vertical velocity of this stone started at [tex]u_{y} = 0\; {\rm m\cdot s^{-1}}[/tex] and became negative (toward the ground) immediately after.

Hence, this stone would not have travelled upward during the entire flight. The height of this stone would be maximized immediately after the stone was launched: [tex]1.1\; {\rm m}[/tex].

Multiple the horizontal velocity [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex] of this stone by the duration of the flight [tex]t \approx 1.49753\; {\rm s}[/tex] to find the **range** (horizontal displacement) of this stone:

[tex]\begin{aligned} (\text{range}) &= v_{x}\, t \\ &\approx (15.2\; {\rm m\cdot s^{-1}})\, (1.49753\; {\rm s}) \\ &\approx 23\; {\rm m} \end{aligned}[/tex].

Right before landing, the stone would be travelling with a vertical velocity of [tex]v_{y} \approx (-14.6908)\; {\rm m\cdot s^{-1}}[/tex] and a horizontal velocity of [tex]v_{x} = 15.2\; {\rm m\cdot s^{-1}}[/tex]. Apply the **Pythagorean Theorem** to find the overall velocity of this stone at that moment:

[tex]\begin{aligned} v &= \sqrt{{(v_{x})}^{2}\, {(v_{y})^{2}} \\ &\approx \sqrt{(15.2\; {\rm m\cdot s^{-1})^{2} + (-14.6908)^{2}}\; {\rm m\cdot s^{-1}} \\ &\approx 21\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

a plane circular coil of radius 0.77 m lies in a horizontal plane. it carries a current of 4.38 a. the coil is in a uniform horizontal 1.157-t magnetic field. what is the magnitude of the magnetic torque on the coil? calculate the torque in the units of n.m. write your answer in decimal form with three digits to the right of the decimal point (e.g. 5.374); do not write any units.

The **magnitude** of the magnetic **torque **on the coil is 9.435 Nm.

A **magnetic field **exerts a **torque **that tries to align the normal vector of a loop of current with the magnetic subject. the size of the torque on a loop

The **magnetic torque**, τ, skilled by using a unmarried particle of quantity V and domain magnetization Md whose moment is oriented at attitude θ to carried out induction B is given by means of τ=mHsinθ where m=MdV is the magnetic second of the particle.

This is the **torque **on a modern-wearing loop in a uniform **magnetic field**. This equation can be proven to be valid for a loop of any form. The loop includes a modern I, has N turns, every of area A and the perpendicular to the loop makes an angle θ with the field B.

Calculation:-

τ = μ×B

= I A B sin90°

= 4.38 × 3.14×(0.77)²× 1.157

= 9.435 N m.

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use letter B below to explain what is wrong with the orbital diagram for beryllium

Electronic Configuration:

Normally, the electronic configuration will be written through the atomic number of the particular element. The electrons fill in this accruing to the energy level and orbitals like s, p, d, and f

The atomic number for the Beryllium is 4. So, the electronic configuration of beryllium is

[tex]1s^22s^2[/tex]In option B, the s block has two electrons and both are having an upward spin orientation. This is incorrect, as one must be in the upward orientation and the other will be in the downward orientation

a typical insulation resistance of equipment rated 480v is . select one: a. 10 m ohms b. 50 megohms c. 100 megohms d. 1,000 megohms

All different kinds of electrical wires and cables are routinely tested by measuring **insulation **resistance. This test is frequently used as a customer acceptance test in production settings.

This **test **is frequently used as a customer acceptance test in production settings, with the customer frequently defining the minimum **insulation **resistance per unit length.

In contrast to a real HIPOT **test**, the results of the IR **Test **are meant to provide information on the quality of the bulk insulation material rather than being helpful in identifying specific insulation flaws.

Many wire and cable manufacturers use the** insulation **resistance test to track their insulation manufacturing processes and identify emerging issues before process variables stray outside of permitted limits, even when it is not needed by the end customer.

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True or false Condensation occurs with the removal of thermal energy.

true. condensation is when gas converts to liquid. the molecules move slower because of a loss of thermal energy, so it forms liquid

What distance will a car traveling at a speed of 50 km/hr cover in 0.25 hr?

**Answer: 12.5**

**Explanation: 50 x 0.25 = 12.5 km**

To do this you would multiply 50 by 0.25 and end up with 12.5 as your answer

a 40.0-kg child and an 8.40-kg sled are on the surface of an icy lake 15.0 meters apart. the child exerts a 5.20 n force on the sled towards them via a rope they’ve attached.

**Acceleration** of the sled is 0.62m/s^2

Acceleration of the **child** is 0.13m/s^2

They **met** at 2.6m from the child's initial position

The question is incomplete, the complete question is given below:

a 40.0-kg child and an 8.40-kg sled are on the surface of an icy lake 15.0 meters apart. the child exerts a 5.20 n force on the sled towards them via a rope they’ve attached.(a) What is the acceleration of the sled? m/s2(b) What is the acceleration of the child? m/s2(c) How far from the child's initial position do they meet? m

Part a

Acceleration of the sled:

Mass of sled=8.40kg

**Force=**5.20N

Acceleration=F/m

=5.2/8.4

=0.62m/s^2

Part b

Acceleration of the child

Mass of the child=40kg

Force=5.20N

Acceleration=F/m

=5.2/40

=0.13m/s^2

Part c

Distance from the child's initial position they met

They accelerate towards each other at =0.62+0.13

=0.75m/s^2

The time to meet is given by:

We use **kinematic **equation to find this,

s=ut+1/2at^2

u=0m/s^2

a=0.75m/s^2

s=15m

t=?

15 =0*t+ (1/2) (0.75) t^2

15=(1/2)*0.75t^2

t=6.32 sec

The child moves:

s=ut+1/2at^2, u=0, a=0.13, t=6.32

=(1/2) (0.13) 6.32^2

=2.6m

Hence they met at 2.6m from the child's original position

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Help! A car is traveling at 60 km/h. It accelerates to 85km/h in 5 seconds. What is the acceleration of the car?

A Car is travelling at a speed of 60 km/h and then **accelerates** to the velocity 85 km/h than **acceleration** in 5 sec is given by 18000 km/h² .

**Acceleration** of body is defined as rate of change of the **velocity** with respect to the time. **Acceleration** is a vector quantity it have magnitude as well as direction.

**Acceleration** = (final **velocity** - initial **velocity** )/ time

**Acceleration **= change in velocity / change in time

Given that in the question that the **velocity** changes from 60 km/h to 85 km/h in 5 sec =( 0.00138 h ) then the **acceleration** of the car is given as,

**Acceleration **of the car = (60 - 85)/0.00138

**Acceleration **of the car = 18000 km/h²

**Acceleration** of the car travelling with the **velocity **60 km/h to final the **velocity** 85 km/h in time 5 sec is given by 18000 km/h².

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what is the power of 600 joules of work done in 4 seconds?responses 150 watts 150 watts 240 watts 240 watts 600 watts 600 watts 2,400 watts

**150 Watts **is the **power** of 600 J of** work** completed in 4 seconds.

The **rate** at which **work** is completed is referred to as **power**. It has the following **mathematical** expression:

[tex]Power = work/time[/tex]

The **power** can be obtained using the above **formula**.

From the mentioned query, the following **information** was observed:

**Work** = 600 J

**Time** = 4 s

**Power** =?

[tex]Power = Work/Time \\Power = 600/4[/tex]

**power** = 150 watts

Thus, 150 **Watts** are generated by 600 J of **work** completed in 4 seconds.

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a gun with a muzzle velocity of 100 m/s is fired horizontally from a tower. neglecting air resistance, how far will the bullet fall 1 second later (vertical distance) ? * 1 point a) 5 m b) 50 m c) 100 m d) 490 m e) none of these

option c A gun is fired horizontally from a tower with a muzzle **velocity** of 100 m/s. The bullet will arrive **100m **away and arrive 1 second late if air resistance is ignored.

That is not to argue that there isn't a **velocity **increase. It absolutely depends on the specific firearm, cartridge, and loading in question. The reason for an increase in velocity is that the **pressures **are slightly higher, which causes the bullet to move less before engaging the rifling.

However, a significant improvement in accuracy is what many handloads will discover. A smaller distance to the rifling reduces the possibility of any bullet tipping and the variation in breech **pressures **that exists between different rounds. From round to round, slightly variable **pressures **can and will be produced even with equal powder loads, down to less than 1/10th of a grain. It's a simple reality.

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A man pulls a crate with a rope. The crate slides along the floor in the horizontal direction (x direction). The man exerts a force of 50 N on the rope, and the rope is at an angle . Describe how the force components change as the angle increases from 0° to 90° and use your graph to explain your answer. Give a detailed explanation of the forces at . Show a sample calculation at one angle for both components.

The 50 N force applied at an angle to the **crate** may be broken down into horizontal and vertical force components. As the angle created by the rope, e, increases from 0° to 90°, the horizontal component, Fx, drops and the vertical force component, Fy, increases.

The **components** of a force are the force parts acting in perpendicular directions, horizontal and vertical, that combine to give the specified force.

The **direction** the crate is sliding = The horizontal, x-direction

The force exerted by the man = 50 N

The angle of the rope

The components of the force are therefore:

Horizontal component, Fx = 50 × cos(8)

Vertical component, F₁ = 50 x sin(0)

The value of cos(e) and sin(e) as the angle the rope makes with the horizontal,

e, increases from 0° to 90° are as follows:

Therefore, the horizontal component of the force exerted by the man, Fx has a maximum value at = 0, and decreases to 0, as increases from 0° to 90°.

The vertical component of the force exerted, Fy, has a minimum value of O at → = 0°, and the value of sin(e) and therefore Fy, increases to a maximum of (sin(90°) 1) 50 N as increases to 90°.

Please find attached the graph showing the components of the force, Fx, and Fy, exerted by the man as the angle formed by the rope increases from 0° to 90°

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an electron of mass 9.11 3 10231 kg has an m initial speed of 3.00 3 105 m/s. it travels in a straight line, and its speed increases to 7.00 3 105 m/s in a dis- tance of 5.00 cm. assuming its acceleration is constant, (a) determine the magnitude of the force exerted on the electron and (b) c

a. The magnitude of the **force **exerted on the electron F = 3.64*10^-18N

b. The force F is 4.08*10^11 times the weight of the electron

a. In order to calculate the magnitude of the **force **exerted on the electron you first calculate the acceleration of the electron, by using the following formula:

v: final **speed **of the electron = 7.00*10^5 m/s

vo: initial **speed **of the electron = 3.00*10^5 m/s

a: acceleration of the electron = ?

x: distance traveled by the electron with certain **speed**= 5.0cm = 0.05m

you solve the equation (2) for a and replace the values of the parameters:

[tex]a=v^{2} - V^{2} /2x[/tex]

a=4×10^12 m/s²

to calculate the force we now use the second Newton law :

F=ma

m: mass of the electron = 9.11*10^-31kg

F=3.64*10^-18N

The magnitude of the force exerted on the electron is 3.64*10^-18N

b. given weight of electron is :

Fg=mg

Fg = 8.92*10^-30N

The Division between the force electron and the weight of the electron F is:

F/Fg=4.08*10^11

The force F is 4.08*10^11 times the weight of the electron

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With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in ____________ twitches per stimulus.

With low-frequency stimulation, the muscle relaxes fully between contractions, resulting in **identical twitches** twitches per stimulus.

**Alpha motor** neurons are the** motor neurons** that innervate the fibers of the skeletal muscle. A number of branches, each innervating a different muscle fiber, are formed as the alpha motor neuron enters the muscle. A motor unit is made up of one** alpha motor** neuron and all of the muscle fibers it innervates. Small motor units with 3-5 muscle fibers per** motor neuron** are found in muscles that are involved in delicate, coordinated control. Our hand and eye muscles, as well as those that control eye movement, have very small motor units.

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what is the speed of the book when it reaches the hands? (b) if we substituted a second book with twice the mass, what would its speed be? (c) if, instead, the book were thrown down, would the answer to (a) increase, decrease, or remain the same?

Anything thrown from a structure, you have a downward velocity if you throw it down correctly. Additionally, you have little G, thus the ball will keep **accelerating**. As a result of the acceleration, your final velocity will undoubtedly be much higher.

At the bottom of the structure, a book is currently being dropped; a man is standing nearby with his hands extended in a very linear motion. The height of these arms is also determined, de Unlike this book, which stands at a specific height Big D The weight of this book has increased to two kilograms. two kg. This small D is equivalent to one point five meters on the issue whereas this enormous D is equal to ten meters of wire. seeks to know the speed at which it will reach this person's grasp.

We have a starting **energy **and a finishing energy. We also have one more energy. We only have gravitational potential energy, after all. What is our final energy, then? The book is falling, so we have kinetic energy, and since Cromwell is not written in it, we have gravitational potential energy. really easy Therefore, we have M g Big D, followed by 1/2 em, the last square, and M g Little T. What should we do next, then? really easy As a result of our velocity solution, the final square's mg big d minus m g tiny d is equal to 1/2.

Therefore, the final square is equal to two times mg big D, minus mg small D, and you merely need to solve for V divide. I divide by an, you square root it, and the result is equal to two mg large D minus two mg little D all over.

Because if you thought about this properly, your speed would increase. You must simply consider anything. anything falls from a structure. If you throw it down correctly, it will move downward at a speed. Furthermore, since you have little G, the ball will keep **accelerating**. Because it is **accelerating**, it follows that your final velocity will be much higher.

Both your initial kinetic energy and your gravitational potential energy would be present, as would your final kinetic **energy **and gravitational potential energy. Because it is at its highest point, you would have a 1/2 M V initial square plus M g Big D and he would have a 1/2 em final square plus M g tiny. +00 It's not a huge D or small D now that it's in their palm. Therefore, the answer would alter. Your speed would actually rise, in my opinion, if you give this some careful thought. You only need to consider anything.

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What test may be used to determine if a stain is a blood or not?

**Answer:**

Kastle-Meyer Color Test is used to determine if a stain is blood or not.

**Explanation:**

which color is bent the least by prism

The red light is the least refracted by the **prism.**

Each beam of light with a particular wavelength is slowed differently by the glass. Since violet light has a shorter** prism **wavelength, it is brake more than the longer wavelengths of red light. accordingly, violet light is bent the most while red light is bent **prism** the least.** Prism** on dispersion, the light rays with longer wavelengths bend less than ones with shorter wavelengths. Since red has the longest wavelength, it bends the least.** prism** Among the 7 constituent colors of light, violet light has the least wavelength and hence it deviates the most, and red light having the largest wavelength deviates the least. Hence, **prism **the required order is violet, indigo, blue, green, yellow, orange, and red.

So we can conclude that in a **prism**, the red light is less refracted.

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a system of diatomic ideal gas contracts from a volume of 4.1 m3 to a final volume of 1.3 m3. if the process proceeds at constant pressure of 148 kpa, calculate the energy in kj transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system.

A system of **diatomic ideal gas** contracts from a volume of 4.1 m3 to a final volume of 1.3 m3. if the process proceeds at constant pressure of 148 kpa. The energy transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system is(Q)= 1450.4 KJ

**Energy** is a physical term that means if a force is applied on a object and the object move some distance that means there is some energy is generate in that object. It is a vector quantity. It can be measured in Joule.

To calculate the energy we using the formula,

Q = nCp AT

Or, Q = nCp(T₂-T₁)

Or, Q = nCp[P(V₂ - V₁) /nR] ....eq(1)

Here we are given,

V₁ =Initial volume = 4.1 m³

V₂= final volume = 1.3 m³

Process is isobaric so,

p= Constant pressure= 148 kP = 148 x 10³ P

n = Number of moles = 1

Cp= specific heat at constant pressure.

For diatomic molecule Cp = 7R/2

we know, AT = T₂-T₁

From ideal gas equation

PV = nRT

T = PV/ nR

T₁= PV₁/nR

And T₂ = PV₂/nR

Now to calculate energy = Q in KJ transferred by heat at constant pressure.

Substitute all these values in eq (1)

Q = n(7R/2) [P(V₂ - V₁) /nR]

Or, Q = 7P(V₂ - V₁)/2

Or, Q = 3.5(148 × 10³ P) (4.1- 1.3) m³

Or, Q = 1450.4 x 10³ J ........(P.m3 = J)

Or, Q = 1450.4 KJ

From the calculation we can say that, The energy transferred by heat, where positive is energy transferred into the system, and negative is energy transferred out of the system is(Q)= 1450.4 KJ

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A) assume the object moves with a constant acceleration as it rolls down the incline. write an equation that includes acceleration and quantities that can be measured or obtained from measurements by using the available equipment in the list.

1 point for an equation that includes **acceleration** and is conceptually relevant to the procedure described in part b.

1 part is earned for stating or implying that the** initial speed** of the object is 0 when released from the top of the incline.

example response: x = 1/2 at^2

The **acceleration** of a sphere on an inclined plane can be analyzed to a first approximation ignoring** frictional forces**. In this case without rotation, the sphere has no torque to rotate so it just slides down the slope with an acceleration of a = g sin θ. The greater the angle, the greater the acceleration of the object. The description for this refers to the component we drew.

As the angle increases the** force** component parallel to the slope increases, and the force component perpendicular to the slope decreases. **Acceleration** is the change in velocity divided by the change in time. A car traveling freely up and down a ramp has constant acceleration. The object then accelerates down the inclined surface due to the presence of an unbalanced force. The parallel component of gravity causes this acceleration.

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What is an ellipse?

an elliptical shape

a perfectly round circle

an undefined shape

**Answer: In geometry, an ellipse is a two-dimensional shape, that is defined along its axes. An ellipse is formed when a cone is intersected by a plane at an angle with respect to its base. **

**Explanation:**

When engineers consider the forces that can act on a structure, they must think about all parts of the structure. Describe three different places on a bridge that would experience very different forces.

Any **bridge** is subject to three different types of **forces**: the **dead** **load**, the **live** **load**, and the **dynamic load**. The weight of the bridge itself is discussed in the first of these words.

Any of the four fundamental forces in physics—gravitational, **electromagnetic**, strong, and weak—that control how objects or particles interact as well as how some particles decay—is referred to as a **fundamental** **force**, also known as a fundamental interaction.

**Compression** and **tension** are the two main forces that are ever-present on a bridge. A **force** that compresses or shortens the object it is acting on is known as a **compressive** **force**. A force known as tension or tensile force works to stretch or expand the object it is acting on.

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A motorbike and its rider have a mass of 261 kg. If they experience an acceleration of 4.7 m/s2, what force was exerted on them?

**Answer:**

1226.7

**Explanation:**

force=ma

261×4.7=1226.7N

Circumference of 2 circles =220m and 286m find area! Helppp!!!!
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