The **final speed **of the motorcycle is 67m/s

The first equation of motion deals with final velocity or **speed**, initial velocity (velocity of the object before the effect of acceleration), acceleration (the** rate **of change of velocity with respect to time) and time. To find out the final speed or velocity of the motorcycle we will use the first equation of motion v = u + at , where

v = final velocity

u = initial velocity

a =** acceleration**

t = time, put the given values in the equation,

v = 25 + 7.0(6.0)

v = 25 + 42

v = 67 m/s

Thus the final speed of the** motorcycle** is 67m/s.

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if you are on top of mount Everest and do a small hop without moving forward, would you still be pulled down by gravity? explain it and also answer my other newest question.

**Explanation:**

Gravity would still pull you down although it wouldn't affect you as much because there is less gravitational pull in high places such as Mt. Everest.

a stunt pilot in an air show performs a loop-the-loop in a vertical circle of radius 2.88 103 m. during this performance the pilot whose weight is 845 n, maintains a constant speed of 2.25 102 m/s.

We calculated that the pilot's apparent weight at the maximum point was 3 70.5 **Newton**. Additionally, the circular portion's lowest point is equal to 1598.5 Newton.

A stunt pilot performing a loop during an airshow has been described to us. the vertical circle's loop. During his performance, he gives us the radius of the circle as 3.08 into 10 to the power three m.

We are provided the weight of the **pilot**, which is 614. For one second, **Newton **maintains a speed of 2.2 into tend to the bar at a distance of 2 m. We need to know the pilot's apparent weight in newtons while he is at the highest point of the loop. Now, the formula for the pilot's mass can be expressed as being equal to the pilot's weight divided by the acceleration caused by gravity. adding the values together results in 614. too unexplored by exploration.

You get the mass of the **pilot**, which is 62.65 kgs Hill, when you add gravity. The apparent weight of the pilot will be equal to the normal force generated by the airplane seat. At this point, we may use the formula M to determine the apparent weight off the pilot at the highest point in the circular journey. N in this case stands for the pilot's apparent weight. We find the apparent weight of Mars to be 62.65 kgs multiplied by velocity, which is 2.2 and 2 10 to the part two m for a second, by adding the pilot's speed and the circular portion's radius, r. entire square.

The normal force of the seat on the **pilot **will be zero since the apparent weight of the pilot at his or her highest point throughout the circle in the case of weightlessness is **Newton**. With the numbers we have divided by Mars being She took 165 and shoes as replacements, we get the speed of the pilot at weightlessness state equal to 173.7 meters per second. As a result, its speed at this point will be equal to root of wait, multiplied by Baridis divided by mass.

Now your parent wait of the pilot at the lowest point can we given us Baron, well being equal to and we square r plus right, substituting the values, we have 62.65 Kgs to point to entertain the part to the whole square divided by yes, 614. Newton solving which we get the apparent weight of the pilot, the lowest point equal to 1598 0.5. Newton which is the apparent weight of the pilot at the lowest point of the circular what therefore Therefore we determined the apparent weight of the pilot at the highest point being equal to 3 70.5 Newton. And at the lowest point of the circular part being equal to 1598.5 Newton.

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A 11.0kg ball traveling at 13.0m/s is crashed into from behind by a 14.0kg ball traveling at 22.0m/s in the same direction. What is the velocity of the first ball if the second slows down to 16.2m/s after the collision?

Let **p **be the total linear momentum of the system before the collision and **p'** the total linear momentum of the system after the collision. Let **p₁₁** and **p₁₄** be the linear momentum of the 11.0kg ball and the 14.0kg ball before the collision, and let **p₁₁'** and **p₁₄' **be their linear momenta after the collision.

According to the **Law of Conservation of Linear Momentum**, the total linear momentum of the system before and after the collision remains the same. Then:

Let **v** be the unknown speed of the 11.0kg ball after the collision. Find the value of **p₁₁, p₁₄, **and** p₁₄'**. Find an expression for **p₁₁'** in terms of **v** and replace all the values into the above equation. Solve for **v**.

The linear momentum of a particle with mass **m** and velocity **v** is:

Then:

[tex]\begin{gathered} p_{11}=(11kg)(13.0\frac{m}{s})=143kg\cdot\frac{m}{s} \\ \\ p_{14}=(14kg)(22.0\frac{m}{s})=308kg\cdot\frac{m}{s} \\ \\ p^{\prime}_{11}=(11kg)\cdot v \\ \\ p^{\prime}_{14}=(14kg)(16.2\frac{m}{s})=226.8kg\cdot\frac{m}{s} \end{gathered}[/tex]Then:

[tex]\begin{gathered} p_{11}+p_{14}=p_{11}^{\prime}+p_{14}^{\prime} \\ \\ \Rightarrow143kg\cdot\frac{m}{s}+308kg\cdot\frac{m}{s}=(11kg)\cdot v+226.8kg\cdot\frac{m}{s} \\ \\ \Rightarrow143kg\cdot\frac{m}{s}+308kg\cdot\frac{m}{s}-226.8kg\cdot\frac{m}{s}=(11kg)\cdot v \\ \\ \Rightarrow224.2\cdot\frac{m}{s}=(11kg)\cdot v \\ \\ \Rightarrow v=\frac{224.2kg\cdot\frac{m}{s}}{11kg}=20.381818\ldots\frac{m}{s} \\ \\ \therefore v\approx20.4\frac{m}{s} \end{gathered}[/tex]**Therefore, the velocity of the first ball after the collision is 20.4m/s.**

the current in a single-loop circuit with one resistor r is 8.400 a. when an additional resistor of 9.00 ω is inserted in series with the existing resistance, the current drops to 6.384 a. what is r in ohms?

The initial resistance of one **resistor **r in ohms in **series combination** is** 28.5 Ω**.

The resistance depends on the used **combination**. The resistor combination can be combined in 2 ways which are **series combination **and parallel. In series combination, the resistance will be added up for each resistor. It can be written as

R = R1 + R2

where R is total resistance, R1 and R2 are the **series combination** of resistors.

From the question above, the given parameters are

R2 = 9 Ω

I1 = 8.4 A

I2 = 6.384 A

Hence, the current ratio of the initial and final condition is

I1 / I2 = V /R1 / V/(R1 + R2)

8.4 / 6.384 = (R1+R2) / R1

8.4 R1 = 6.384 R1 + 57.456

2.016R1 = 57.456

R1 = 28.5 Ω

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A frog leaps from flat ground at 6.32 m/s

at a 36.3 angle. What maximum height

does it reach?

(Unit = s)

At hmax, Vy=0

vy=v0y-gt

0=6.32sin(36.3)-9.81t

t=.381 seconds

Δy=v0yt-.5gt^2

Δy=6.32sin(36.3)*.381-.5(9.81)(.381)^2

maximum height=.714 m

If it takes 20 N to move a box, how much power will be needed to move the box a distance of 5meters in 5 seconds?

**Answer:**

It will need **20 Watts** power to move the box 5 meters in 5 seconds.

**Step-by-step explanation:**

The** power** is defined as the **work per** unit **time** or the rate of doing work:

W=dL/dt

Where de **work** L, can be calculated by multiplying the** force** by the displacement d:

L=F.d

To this example, F and D are known, therefore the work is:

L=20N . 5m=40 Nm

We know that the work is doing within a time of 5 seconds:

W= 40 Nm / 5s = 20 Nm/s = **20 Watts**

Hydrochloric acid and sodium hydroxide can be combined to form sodium chloride and water. Which best explains the reaction?

The mass of sodium hydroxide will result in the same mass of sodium chloride.

The total mass of hydrochloric acid and sodium hydroxide will result in a lower total mass of sodium chloride and water.

The mass of hydrochloric acid will result in the same mass of sodium chloride.

The total mass of hydrochloric acid and sodium hydroxide will result in the same total mass of sodium chloride and water.

THE ANSWER IS D

The statement that best describes the reaction is as follows: The total **mass** of hydrochloric acid and sodium hydroxide will result in the same total **mass** of sodium chloride and water (option D).

The **law** of **conservation** of **matter** states that matter can neither be created nor destroyed. This law means that the **mass** that enters and leave a system is accounted for.

The **law** of **conservation** of **mass** explains the input and output of **mass** in a chemical reaction such that the mass of the reactants must be equal to the **mass** of the products.

According to this question, hydrochloric acid (HCl) and sodium hydroxide (NaOH) can be combined to form sodium chloride and water.

This means that the total amount of **matter** of the **reactants** (hydrochloric acid and sodium hydroxide) must equate the total amount of **matter** of the products (sodium chloride and water).

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Heat waves are defined by the difference in temperature compared to the normal _________ typical of a region.

The difference in **temperature **from the average temperature for a region defines a **heat wave**.

A **heat wave **is an extended period of unusually hot weather that usually lasts longer than days.

**Heat waves **can occur in both low and high humidity conditions. They have the capacity to cover a wide area, exposing too many **people **to harmful heat.

An extremely dangerous weather event known as a heat wave occurs when **temperatures **rise considerably above 90° F. Due to the extreme heat and high **humidity **levels, an area becomes extremely warm for an extended period of time.

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a 115 kg lineman is working on tackling drills. if he is running at 2.8 m/s and hits a tackling dummy with a mass of 55 kg , what is the momentum of the tackling dummy after the hit assuming the lineman stops instantly after impact?

A 115 kg lineman is working on tackling drills. if he is **running **at 2.8 m/s and hits a tackling dummy with a mass of 55 kg, then the **momentum **of the tackling dummy would be 322 kg-m/s.

It can be defined as the product of the **mass **and the speed of the **particle**, it represents the combined effect of mass and the speed of any particle, and the **momentum **of any particle is expressed in Kg m/s unit.

As given in the problem a 115 kg lineman is working on tackling drills. if he is running at 2.8 m/s and hits a tackling dummy with a mass of 55 kg ,

By using the **conservation **of the momentum,

Momentum before the collision = momentum after the collision

The **momentum **of the tackling dummy = m × v

= 2.8 × 115

=322 kg-m/s

Thus, the **momentum **of the tackling dummy would be 322 kg-m/s.

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a cylinder of mass m slides down from rest in a vertical tube whose inner surface is covered by a viscous oil of film thickness h. if the diameter and height of the cylinder are d and l, respectively, derive an expression for the velocity of the cylinder as a function of time, t. discuss what will happen as t → [infinity]. can this device serve as a viscometer?

When there is relative motion between the fluid layers or between the fluid and solid surface, the fluid's internal property known as viscosity is created. This relative motion is being resisted by **viscosity**.

Derivations of the equations of motion—the connections for the conservation of mass and momentum—in rectangular,

coordinates that are spherical and cylindrical. The entire body of experimental data suggests that the fundamental equations of fluid mechanics are in fact those listed below, and that they apply to any circumstance where a Newtonian **fluid **is flowing, in theory.

**Viscosity**, a characteristic of fluids, is produced when there is relative motion between the fluid layers or between the **fluid **and solid surface. **Viscosity **prevents this relative motion from happening.

Unfortunately, due to their all-encompassing nature, their analytical solution is challenging or impossible unless the circumstances are quite straightforward.

However,

These "Navier-Stokes equations" must be understood for the following reasons.

reasons:

1. They result in the analytical and precise resolution of some basic yet significant problems.

issues.

2. They serve as the foundation for additional chemical engineering research in various fields.

3. A few reasonable simplification assumptions can frequently result in

for many engineering problems, approximation solutions are eminently acceptable purposes. Typical examples can be found in the study of boundary layers, the use of films to cover substrates, waves, lubrication, and inviscid (irrotational) flow.

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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.

Wave 1's intensity is nine times greater than Wave 2's. An **electromagnetic wave** carries both magnetic and electric energy when it moves.

An electromagnetic wave carries both magnetic and **electric energy** when it moves. Both waves contribute equally to the energy of electromagnetic waves. It is assumed that wave 1 has an electric field E that is three times greater than wave 2's maximal electric energy E'.

Thus, we can state:

E/E' = 3

We are aware,

The wave's intensity is determined by,

I = 1/2eE²c

Where,

I represents the wave's power,

e is a free space permittivity,

E represents the wave's energy.

The speed of light is c.

the strength of wave 1 right now

I1 = 1/2eE1²c

second wave

I2 = 1/2eE²c

Currently, dividing the two intensities,

I1/I2 = E1²/E2²

We are aware,

E/E' = 3

So,

I1/I2 = 9

I1 = 9I2

Thus, we can state:

Wave 1's **intensity **is nine times greater than Wave 2's.

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a singly charged positive ion has a mass of 3.3x10-26 kg. after being accelerated from rest through a potential difference of 933 v, the ion enters a magnetic field of 1.43 t along a direction perpendicular to the field. calculate the radius of the circular path of the ion in the field.

A singly charged positive ion has a** **mass of 3.3x10-26 kg. after being accelerated from rest through a** potential difference** of 933 v, the ion enters a magnetic field of 1.43 t along a direction perpendicular to the field. The** **radius of the circular path of the ion in the field is (r)= 1.982 cm.

Energy is a term that means the object is affected by some amount of force and move a distance. That is called the **energy**. It can be measured in Joule.

To calculate the radius we are using the formula here,

r= mu/Bq

Where we are given,

m = The mass of single positive charged ion.= 3.3×10⁻²⁶kg.

q= The charge of the single positive charged ion.= 1.602×10⁻¹⁹ C

B = The magnetic field for the electric field. = 0.92 T

But we don't know the term, u= the velocity of the single positive charged ion.

So we have to calculate the velocity of the single positive charged ion. To calculate the velocity we are using the formula,

(1/2)mu²=qv

Here we are given,

v= The potential difference of the electric field. = 933v.

We have to calculate the velocity=u, as Conservation of energy we know,

(1/2)mu²=qv

Or,(1/2)mu²=ev

Or, u²= (2×1.602×10⁻¹⁹×933)/(3.3×10⁻²⁶)

Or, u=91325.9 m/s.

So from this we know the velocity of the ion, u=91325.9 m/s.

Now, we have to calculate the radius in a magnetic field= r,

r= mu/Bq =mu/Be

Or, r= 3.3×10⁻²⁶×91325.9/0.92×1.602×10⁻¹⁹

Or, r=0.01982m

Or, r=1.982 cm.

So from the calculation we can surely say that, The radius of the circular path of the ion in the field is (r)= 1.982 cm.

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electromagnetic radiation with a maximum wavelength of 540 nm(5.4×10−7 m) is needed for the study of the photoelectric effect in potassium atoms. what is the approximate frequency that corresponds to this wavelength?

At a speed of two times ten to the eighth and violent. 5, 40 times 10 to the power -9 meters is written as. This leads to the conclusion that frequency F is equivalent to 5.6 times. Turn 14 times every second. Therefore, the given **electromagnetic radiation** requires this frequency.

In this problem, we have a given violent electromagnetic radiation, and we need to determine the frequency that corresponds to that **violent electromagnetic radiation**.

The chosen wavelength is lambda. I called at five minutes and forty nanometers—540 times 10 to the power—or nine meters. Considering that one nanometer equals 10 to the power -9 meters. Now, sea upon lambda finds frequency.

The value of C is three in 2, ten to the power eight meters per second, **violent**, and the speed of light in a vacuum. 5, 40 times 10 to the power -9 meters is written as. This leads to the conclusion that frequency F is equivalent to 5.6 times. Turn 14 times every second. Therefore, the given **electromagnetic radiation **requires this frequency.

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gas giants have many moons than terristcal planets due to having higher ___ ?

Gas giants have more moons than terrestrial **planets **due to having higher masses.

Giant **planets **are composed of low boiling point substances rather than other solid substances but massive solid **planets **can also exist. There are four giant **planets **in the Solar System i.e. Jupiter, Saturn, Uranus, and Neptune. They are composed of hydrogen and helium atom i.e. Jupiter and Saturn whereas Uranus and Neptune are composed of ice, rock, hydrogen, and helium.

The giant **planets **have more moons as compared to the terrestrial planets because of their big masses which leads to stronger gravitational fields. Giant **planets **also occupy greater space and have larger volumes of mass in their surrounding atmosphere.

So we can conclude that due to having higher masses, Gas giants have many moons as compared to terrestrial **planets**.

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Convection, conduction, or radiation??

**Answer: Conduction**

**Explanation: Radiation is the receiving of heat via waves from the air, Convection is the transfer via liquids. Conduction is the transfer of heat between two solids.**

If 2 balls of the same size and different masses roll down a ramp, which ball would be faster; the bigger mass or the smaller mass

**Answer:**

The bigger mass

**Explanation:**

This can be explained using F=ma

Let's say the acceleration is same on both balls 10m/s2 however we have different masses.

Pretend small mass ball is 0.5 kg and big mass is 1kg.

10 x 0.5 =5

10 X 1 =10

10 is bigger than 5

17. A ball rolls off a lab table at 5 m/s horizontally. The table is 1.2 meters tall.

a. How long is it in the air?

b. How far from the table does it hit the ground?

c. What are the x and y speeds just before it hits the ground?

The ball is in the air for 0.24 seconds, the ball hits the ground 2.46 meters far from the table and the** x speed** is 0m/s and** y speed** is 5m/s.

**Velocity **of the ball is 5m/s and the height of the table is 1.2 meters.

a. We know,

**Velocity = distance/time**

5 = 1.2/time

Time = 1.2/5

Time = 0.24 seconds.

The time taken by the ball to reach the ground is 0.24 seconds.

b. The ball after rolling of the table will behave like **Horizontal projectile.**

**Horizontal range R** formula,

R = V.√(2h/g)

Putting all the values,

R = 5.√(2×1.2/9.8)

R = 5×0.49

R = 2.46 meters.

c. When the ball reaches the ground,

**X speed** is 0m/s and **Y speed **is 5m/s.

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Suppose you are in a car that is going around a curve. The speedometer reads a constant 30 miles per hour.

Which of the following is NOT true?

a) Your velocity is constant.

b) You and the car are accelerating.

c) Your acceleration is constantly changing

d) Your direction is constantly changing.

e) Your speed is constant.

The true statement is "Your **speed** is constant".

An object is moving at a **constant speed** when its speed is constant, that is the speed does not increase or decrease.

**Constant speed** also refers to the movement of a body at a uniform rate in a fixed steady-state moving with an average speed.

If you are in a car that is going around a curve and the speedometer reads a constant 30 miles per hour, you will notice that the direction of your motion is changing and but the **distance** travelled in a given **time** does not change.

Thus, only the **speed** is constant but velocity and acceleration is not constant.

The correct option is E.

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anne is working on a research project that involves the use of a centrifuge. her samples must first experience an acceleration of 100???? , but then, the acceleration must increase by a factor of eleven. by how much will the rotational speed have to increase? express your answer as a fraction of the initial rotation rate.

if the final **acceleration** increases by a factor of 11, then the final rotation should be** 3.32**[tex]w_{1}[/tex]** times **the initial rotation.

The relation between the centripetal **acceleration** and rotation speed of the particle is given as

a=rω²

Where ω is the angular speed and r radius of the circle

Now, rearranging the above equation we will get

ω = √[tex]\frac{a}{r}[/tex]

The initial acceleration is given by

a₁ =100g

But then, the acceleration increases by a factor of 11. Which means the final acceleration of the particle is

a₂ = 11 (100g)

= 1100g

The final and initial rotation speeds are related as

[tex]\frac{w1}{w2}[/tex] = √[tex]\frac{a2}{a1}[/tex]

[tex]w_{2}[/tex] = √[tex]\frac{1100g}{100g}[/tex] x [tex]w_{1}[/tex]

[tex]w_{2}[/tex] = 3.32 [tex]w_{1}[/tex]

The **final rotation **should be** 3.32**[tex]w_{1}[/tex]** times **the initial rotation.

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Is the exoplanet like earth in terms of its distance from its star? Explain your answer

Every planet in the **solar** **system** orbits the Sun. Planets known as **exoplanets** orbit other stars. **Astronomers** search for exoplanets by observing the effects that these **planets** have on the **stars **they **orbit**.

Any planet outside of our solar system is an exoplanet. The **majority** of **exoplanets** orbit other **stars**, while rogue planets—free-floating exoplanets that are unattached to any star—orbit the galactic center.

Since **liquid** **water **is necessary for all known forms of life, an **exoplanet** that is too near or too far from its host star is less likely to support life. Additionally, some primordial compounds may require **ultraviolet** light to form, but a **hyperactive** host star can blast the nascent planet, removing its atmosphere.

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an athlete lifts a 350 n set of weights from ground level to a position over her head, a vertical distance of 1.90 m. how much work (in j) does the athlete do? assume the weights are moved at constant speed.

**Work** is measured in joules or newton-meters

It may be thought of as force * distance

If there were acceleration in this problem, the force would be more than the weight, but because the speed is constant force = weight.

given,

force= 350N

Distance= 2m

work= ?

**Work = Force * Distance**

= 2m * 350 N

= 700 j or 700 N*M

If you're looking at this from an energy standpoint, you can just consider the final PE as the energy required because there is no KE at the end. so,

PE = m*g*h

and m*g = 350N

h= 2m

PE = 700j or 700 N*M

Hence, the 700N*M work is done by athlete.

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How could infrared imaging be used to find a lost hiker? Answer in 2-3 complete sentences.

When you scan the **hiker's body**, you will notice a **warm spot**. Unless that person was dead, they would not be **emitting heat.**

What is hiking?According to

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how does Newton's third law describe the force affecting a rocket as it descends to

**Answer:**

**Explanation:**

Newton's Third Law states that "every action has an equal and opposite reaction". In a rocket, burning fuel creates a push on the front of the rocket pushing it forward. This creates an equal and opposite push on the exhaust gas backwards.

You are designing another dolly-sandbag system for a different actor in the performance. The mass of the dolly and actor combined is 76 kg, and the mass of the sandbag is 18 kg. The coefficient of kinetic friction between the dolly and the stage floor is 0.20. What is the acceleration?

**Answer: 0.30 m/s^2**

**Explanation:**

[tex](9.8m/s^{2} )[/tex] · [tex]\frac{(18kg)-0.20(76kg)}{(76kg)+(18kg)}[/tex]

The **acceleration **of the dolly-sandbag system is **0.29 m/s².**

The definition of **force **in physics is: The push or pull on a massed object changes its velocity. An **external force** is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

A spring balance can be used to calculate the **Force**. The Newton is the SI unit of **force**.

Given parameters:

The **mass **of the dolly and actor combined is: M = 76 kg

the **mass **of the sandbag is: m = 18 kg.

The **coefficient **of kinetic friction between the dolly and the stage floor is 0.20.

Let the **acceleration **is a.

Hence, From **Newton's **2nd law of motion, we can write that:

ΣF = (m+M) a

mg - μMg = (m+M) a

a = g (m- μM)/ (m+M)

= 9.8 ( 18 - 0.20×76)/(18+76)

= 0.29 m/s².

Hence, the **acceleration **of the dolly-sandbag system is** 0.29 m/s².**

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a rigid bar with mass m, length l, and a uniformly distributed positive charge q is free to pivot about the origin in the presence of a spatially uniform electric field e⃗

a. V(y)=V-E(y) b. U=vq-1/2QEL.cosФ c. V=EL/2 d. **angular speed** of the bar as it passes Ф=0° is W=[tex]\sqrt{3QE/ML}[/tex]

You were already familiar with the ideas of **velocity **and speed. The idea of** angular speed** and velocity, however, is what needs to be understood in terms of physical numbers. Angular motion is the term for when an item is expected to travel along a circular path while making a specific angle. The idea of angular speed and angular **velocity **is derived from the object's angular motion. Let's examine these ideas in greater depth. Assuming you are rotating a ball in a circular orbit, the angular speed can be defined as follows.

A body's rate of angle change over time as it rotates in a circular orbit is known as its angular speed. The definition of angular **velocity **is similar to that of linear velocity when an object is moving with some speed in a circular orbit.

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rank the capacitors on the basis of the charge stored on the positive plate. rank from largest to smallest. to rank items as equivalent, overlap them.

Capacitors on the basis of charge stored on positive plates become stable. Large ones should be more wild, smaller ones are less large an urgent. When overlapped, the plates collide causing earthquakes.

A 0.300 kg mass is attached to 26.6N/m spring.It is pulled 0.120 m and released. How much Potential Energy does it have when it is 0.0600 m fro

equilibrium?

**Answer:**

**Explanation:**

The elastic potential energy equation is EPE = (1/2) k x2, where k is the spring constant and x the distance from equilibrium. EPE = (0.5)*(26.6 N/m)*(0.0600 m)2 = 0.0479 Joules.

A rod pr is balanced on a pivot at the end r while a string is used to support the rod at p. the weight of the rod is 9n, acts at a point q where qr=30cm and pq=15cm. the tension in the string is

The **tension in the string** if a rod PR is balanced on a pivot at the end R while a string is used to support the rod at P is 6 N

**Moment = Force * Perpendicular Distance**

Let us consider the pivot side be initial point,

Since the rod is balanced,

CM = ACM

CM = Clockwise moment

ACM = Anticlockwise moment

F = 9 N

PQ = 15 cm = 0.15 m

QR = 30 cm = 0.3 m

PR = PQ + QR

PR = 0.15 + 0.3

PR = 0.45 m

**CM = W * QR**

CM = 9 * 30

CM = 2.70 N m

ACM = T * PR

ACM = 0.45 T N m

2.70 = 0.45 T

T = 6 N

Therefore, the tension in the string is **6 N**

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Among elements 1 to 18, which element or elements have the smallest effective nuclear charge?.

As we walk across a period from left to right, the effective nuclear charge rises, whereas it falls as we move down the group. The **element** with the lowest **effective nuclear charge** will be found on the left side of the periodic table. The periodic table's group 1 includes **H, Li, and Na.**

A **fluorine atom's nucleus** has a charge Z of 9, but the valence electrons are mostly screened by the core **electrons**—four electrons from the 1s and 2s orbitals—and to a lesser extent by the 7 electrons in the 2p orbitals. The **cation of sodium** thus has the highest effective nuclear charge.

In spite of being in the same period as **sodium** and **phosphorus**, chlorine has the most protons in its shell (the most inside the same period), giving it the highest **effective nuclear charge**.

The amount of **shielding** **electrons** may be calculated by deducting the amount of **valence electrons** from the overall number of electrons in the atom or ion.

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__________________________1. She is caught in a wind that blows toward the

equator from about 30° N and 30° S of the

equator. She is in the_______________

This is science

She is caught in a **wind** that blows toward the **equator** from about 30° N and 30° S of the equator. She is in the **trade wind**. This science is called **Hadley cell**.

It follows the movement of wind blows from one **direction** to the other such as the one which blow from north to **south** or **east** to west. The trade wind are produced by **warm moist air** rising near the equator.

Now, within the context of the task given above, when the movement wind which blows toward the equator from about 30° N and 30° S of the equator is known as the trade wind.

So therefore, the **movement** of wind from the same certain degrees from North and South is called **trade** wind.

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