For the moving car, if you double your driving **speed**;

a. the **tim**e required to come to a stop will increase by a factor of 2.

b. the distance needed to stop will increase by a factor of 2.

What is the formula relating acceleration, speed, time, and distance traveled?The formula relating to the **acceleration**, **speed**, time, and distance traveled of an object is a formula of the equations of motion.

The equations of motion are given below as follows:

v = u + at

s = ut + ¹/₂at²

v² = u² + 2as

where:

v = final speed

u = initial speed

t = time taken

s = distance traveled

a = acceleration

Considering the given scenario:

a. if the **speed **is doubled, the equation v = u + at applies for the time required to come to a stop;

t =2 * v - u / t

the time will be increase.

b. if the **speed **is doubled, the equation v² = u² + 2as applies for the distance needed to stop;

s = 2 * v² - u²

the distance will increase with an increase in **speed**.

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d. Use trigonometry to resolve the following vectors into component

Describe the vectors using vector notation.

**v ≈ (3.28512, 20.74146) (3.28512, 20.74146)**

In trigonometry, what is a vector?

Vectors can be used to depict motion between points in the **coordinate plane**. A vector is just a **line segment **in a specified location with an arrow designating its length and direction. The vectors in the following

**v** = 21 (cos (81°), sin (81°))

components for v (3.28512, 20.74146) (x, y)

Authors use different notations. You can write the vector as...

(r, θ) = (21, 81°)

r∠θ = 21∠81°

21 cis 81° = r cis

**v** = 21·e^(i·9π/20)

(x, y) ≈ (3.28512, 20.74146) (3.28512, 20.74146)

**v** = 3.28512i +20.74146j Maybe this is the **vector notation** you're looking for (i and j are unit vectors in the **x- and y-directions,** respectively)

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Set the cannon to have an initial speed of 15 m/s. For which situation do you think the cannon ball will be in the air for the longest time: if it is set at a 60-degree angle, or if it is set at a 70-degree angle?

Question 6 options:

60 degree

70 degree

The cannon ball will be in the air for the **longest time** if the the **angle** of projection is set at 70 degrees

How to determine which **angle** will result in **longest time**

Case 1:

Initial velocity (u) = 15 m/sT = 2uSineθ / g

T = (2 × 15 × Sine 60) / 9.8

T = 25.98 / 9.8

T = 2.65 s

Case 2:

Initial velocity (u) = 15 m/sT = 2uSineθ / g

T = (2 × 15 × Sine 70) / 9.8

T = 28.19 / 9.8

T = 2.88 s

From the above calculations, we can conclude that the ball will stay **longe**r in air if the **angle** is 70 °

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A 50-ω resistor is connected to a 9.0 V battery. How much thermal energy is produced in 7.5 minutes?1.2 102 J1.3 103J3.0 102 J7.3 102 J

The power consumed by the resistor can be expressed as,

[tex]P=\frac{V^2}{R}[/tex]Substitute the given values,

[tex]\begin{gathered} P=\frac{(9.0V)^2}{50\text{ }\Omega}(\frac{1\text{ W}}{1V^2\Omega^{-1}}) \\ =1.62\text{ W} \end{gathered}[/tex]The thermal energy produced in the given time can be expressed as,

[tex]E=Pt[/tex]Plug in the known values,

[tex]\begin{gathered} E=(1.62\text{ W)(7.5 min)(}\frac{60\text{ s}}{1\text{ min}}) \\ =729\text{ J} \\ \approx7.3\times10^2\text{ J} \end{gathered}[/tex]Thus, the thermal energy produced is 7.3*10^2 J which means fourth option is correct.

Jason is pulling a box across the roompulling with a force of 16 newtons and his arm is making a 68 anglet with the horizontal what is the horizontal component of the he is pulling with?

The horizontal component of a force is defined as follows

[tex]F_x=F\cdot\cos \theta[/tex]Where F = 16 N, and theta = 68. Let's use these values to find the horizontal component of F.

[tex]F_x=16N\cdot\cos 68\approx6N[/tex]Therefore, the horizontal component of the pulling force is 6 Newtons.A person walks 8 km east, turns and walks 5 km west, then turns back around and walks 3 km, east.

What is the distance traveled of the person from the initial point to ending point?

A person walks 8 km east, turns and walks 5 km west, then turns back around and walks 3 km, east.** Total distance traveled** of the person from the initial point to ending point will be 16 km

**Distance **is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.

total distance = 8 km + 5 km + 3 km = 16 km

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what does it mean to have a velocity of 10 m/s?

Answer: c'est le fait de parcourir 10 mètres par secondes

Explanation:

en une seconde, avec une vitesse de 10m/s, tu pourrais donc parcourir 10 mètre

en 10 secondes, 100 mètres

en une minutes (60s), 600 mètres

cela reviens également a une vitesse de 36km/h

Ou bien 22miles/h

Explanation:

en une seconde, avec une vitesse de 10m/s, tu pourrais donc parcourir 10 mètre

en 10 secondes, 100 mètres

en une minutes (60s), 600 mètres

cela reviens également a une vitesse de 36km/h

Ou bien 22miles/h

A pitcher claims he can throw a 0.145-kg baseball with as much momentum as a 3.00-g bullet moving with a speed of 1.50 x 103 m/s. What must the baseball’s speed be if the pitcher’s claim is valid?

**ANSWER**

**3.10 x 10⁴ m/s**

**EXPLANATION**

Given:

• The mass of the baseball. m₂ = 0.145 g

,• The mass of the bullet, m₁ = 3.00 g

,• The speed of the bullet, v₁ = 1.50 x 10³ m/s

Find:

• The speed of the ball, v₂, if it has the same momentum as the bullet.

The momentum of an object of mass m moving at a speed v is,

[tex]p=mv[/tex]So, in this problem, if both objects have the same momentum,

[tex]m_1v_1=m_2v_2[/tex]Solving for v₂,

[tex]v_2=\frac{m_1v_1}{m_2}[/tex]Replace the known values and solve,

[tex]v_2=\frac{3.00\text{ }g\cdot1.50\times10^3\text{ }m/s}{0.145\text{ }g}\approx3.10\times10^4m/s[/tex]Hence, **the speed of the baseball must be ****3.10 x 10⁴ m/s**.

Calculate the wavelength of a light that has an energy of 9.55x10^-19J.

**ANSWER**

**EXPLANATION**

To calculate the wavelength of light, we have to **apply the formula for the energy of light:**

h = Planck's constant

c = speed of light

λ = wavelength

Therefore, we have that:

[tex]\lambda=\frac{hc}{E}[/tex]The wavelength of the light is:

[tex]\begin{gathered} \lambda=\frac{6.626\cdot10^{-34}\cdot3\cdot10^8}{9.55\cdot10^{-19}} \\ \lambda=2.08\cdot10^{-7}m \end{gathered}[/tex]Josh has 12 blue marbles and 7 red marbles. Write the ratio of blue marbles to red marbles.

**ANSWER**

**EXPLANATION**

Josh has 12 blue marbles and 7 red marbles.

To **find the ratio of blue marbles to red marbles**, we have to write them in the form:

Therefore, **the ratio of blue marbles to red marbles is**:

A boat is moving across a 100 meter wide stream at 5 m/s. If the stream is flowing south at 10 m/s, how long will it take the boat to cross the river?

answer:

20 minutes for 5 m/s 10 minutes for 10 m/s

You observe that 34 crests of a water wave pass you each minute. if the wavelength is 12 m, what is the speed of the wave?

**ANSWER:**

6.8 m/s

**STEP-BY-STEP EXPLANATION:**

We must calculate the frequency, knowing that per minute (60 seconds) there are 34 crests, therefore:

[tex]f=\frac{34}{60}=0.57\text{ Hz}[/tex]Therefore, the speed of the wave would be:

[tex]\begin{gathered} s=f\cdot w \\ s\text{ =speed} \\ f=\text{ frequency = 0.57 Hz} \\ w\text{ = wavelength = 12 m} \end{gathered}[/tex]Replacing:

[tex]\begin{gathered} s=0.57\cdot12 \\ s=6.8\text{ m/s} \end{gathered}[/tex]The speed of the wave is 6.8 m/s

Wei drags a heavy piece of driftwood for 940 m along an irregular path. If Wei ends 710 m from where he starts, exerting a constant force of 625 N parallel to his path the entire time, how much work does he do?

**Answer:**

587500

**Explanation:**

Since Wei will still hit every point of the path even though it is irregular, you do not have to worry about the displacement in this problem, just the original path (940m).

W= F x D

587500 = 625N x 940M

A rectangular loop of wire with a cross-sectional area of 0.118 m2 carries a current of 0.679 A. The loop is free to rotate about an axis that is perpendicular to a uniform magnetic field strength of 0.179 T. The plane of the loop is initially at an angle of 22.09o to the direction of the magnetic field. What is the magnitude of the torque on the loop ?

**Given**:

The area of the rectangular loop is,

[tex]A=0.118\text{ m}^2[/tex]The current in the loop is,

[tex]I=0.679\text{ A}[/tex]The magnetic field is of strength

[tex]B=0.179\text{ T}[/tex]The plane of the loop is at an angle

[tex]\theta=22.09\degree[/tex]**To find**:

The magnitude of the torque on the loop

**Explanation**:

The torque on a current-carrying loop is,

[tex]\begin{gathered} \tau=IABsin\theta \\ =0.679\times0.118\times0.179\times sin22.09\degree \\ =5.39\times10^{-3}\text{ N.m} \end{gathered}[/tex]**Hence, the torque is**

if the mass of the paper is 0.003 kg, what force does the boxer except on it?

**Answer:**

1.15 N

**Explanation:**

You want to know the **force exerted** on a **mass of 0.003 kg** to accelerate it from 0 to **23 m/s** in a period of **0.06 s**.

The acceleration of the mass is the change in velocity divided by the change in time:

a = ∆v/∆t

a = ((23 -0) m/s)/(0.06 s) = 1150/3 m/s²

ForceThe force applied is the product of mass and acceleration:

F = ma

F = (0.003 kg)(1150/3 m/s²) = 1.15 kg·m/s² = 1.15 N

**The applied force is 1.15 newtons**.

thunder can make objects inside a room vibrate explain what causes the objects to vibrate

**Thunder **can make objects inside a room vibrate by which our house columns in **underground **that causes the objects to **vibrate**.

**Thunder **is caused by the rapid expansion of **air **around the path of **lightning**. It only takes a few millionths of a second for lightning to burst through the air from a cloud to a nearby tree or roof. The loud thunder that follows a lightning strike is generally said to come from the lightning itself. However, the **rumbling **and roaring heard during** thunderstorms **is actually due to the rapid expansion of air around the lightning.

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A gardener mows a lawn with an old-fashioned push mower. The handle of the i mower makes a 32° angle with the surface of the lawn.

a)If a 68N force is applied along the handle of the 17kg mower, what is the force exerted by the lawn on the mower? b）If the angle between the surface of the lawn and the handle of the mower is increased, does this force increase, decrease, or stay the same? Explain.

The **force** exerted by the lawn on the mower is 202 N when applied 68N force along the handle.

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Which of the following statements is always true?

a.

Pressure always increases when force increases or the area acted on increases.

b.

Pressure always increases when force increases or the area acted on decreases.

c.

Pressure always increases when force decreases or the area acted on increases.

d.

Pressure always increases when force decreases or the area acted on decreases

The statement that is true is that **pressure** always increases when **force** increases or the **area** acted on decreases (option B).

**Pressure** is the amount of **force** that is applied over a given area divided by the size of this **area**.

The **pressure** applied to a surface can be calculated by dividing the **force** required by the **area** of the surface as follows:

P = F/A

The above shows that the **pressure** of a body is inversely proportional to the **area** but directly proportional to the **force**.

This means that as the **pressure** of an object increases, the **force** increases while the **area** acted on decreases.

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what is scientific knowledge

**Answer: Based on evidence**

**Explanation: Scientific knowledge is based on evidence and is included in scientific theories: consistent and deductively complete sets of propositions around a topic of scientific interest, which describe it and give it a verifiable explanation.**

16. On the moon, Bob weighs 160 N while on earth Fred weighs 882 N Who has thegreater mass?

We are given the weight of two people, one on the moon and the other on earth. To determine the mass we will use the following formula:

[tex]W=mg[/tex]Where:

[tex]\begin{gathered} W=\text{ weight,}\lbrack N\rbrack \\ m=\text{ mass,}\lbrack kg\rbrack \\ g=\text{ acceleration of gravity, }\lbrack\frac{m}{s^2}\rbrack \end{gathered}[/tex]Now, we solve for the mass "m" by dividing both sides by "g":

[tex]\frac{W}{g}=m[/tex]Now, for the case of the moon we have that the acceleration of gravity is:

[tex]g_{moon}=1.62\frac{m}{s^2}[/tex]Plugging in the values:

[tex]\frac{160N}{1.62\frac{m}{s^2}}=m[/tex]Solving the operations:

[tex]98.77kg=m[/tex]Now, for the case of the earth we have:

[tex]g_{\text{earth}}=9.8\frac{m}{s^2}[/tex]Plugging in the values:

[tex]\frac{882N}{9.8\frac{m}{s^2}}=m[/tex]Solving the operations:

[tex]90kg=m[/tex]Therefore, the greater mass is the mass of Bob.

3. Find for the total resistance of the series-parallel circuit below

In order to find the total resistance, first let's calculate the total resistance between R2 and R3, which are in series, so the total resistance is the sum:

[tex]R23=R2+R3=3+2=5\text{ ohms}[/tex]Now, let's calculate the total resistance between R23 and R1, which are in parallel, so we use the equation below:

[tex]R123=\frac{R23\cdot R1}{R23+R1}=\frac{5\cdot6}{5+6}=\frac{30}{11}=2.727\text{ ohms}[/tex]Finally, we calculate the total resistance between R123 and R4, which are in series:

[tex]RT=R4+R123=3+2.727=5.727\text{ ohms}[/tex]An object of 31.3 kg is at rest. You apply a constant force to this object and the object moves a distance of 103 m in 13 s. find the acceleration produced by your force.

The **acceleration** produced by your force is determined as 1.22 m/s².

What is the acceleration of the object?

The **acceleration** of the object is the rate of change of its velocity with time.

Apply the following kinematic equation to solve the **acceleration** of the object.

s = vt + ¹/₂at²

where;

s is the distance travelled by the objectv is the initial velocity of the object = 0t is the time of motion of the objecta is the acceleration of the objects = ¹/₂at²

103 = ¹/₂a(13)²

103 = 84.5a

a = 103/84.5

a = 1.22 m/s²

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number 16part b: what is the speed of the combined vehicles after the collison?

velocity = p/m

p = momentum= 51,000 kgm/s

m = mass = 3,000+2,000= 5,000kg

v= 51,000 kgm/s / 5000 kg = **10.2 m/s**

Find the y-component of this vector.

80.0°

B-18.6 m

0 = 170°

By = [?] m

The **y-component** of **vector B** is** 3.23 m.**

The** y-component** of a vector is the vertical component of the vector. It the vector that points in the y-direction.

The **y-component** of a vector is measured along the y-axis of the Cartesian coordinate.

Mathematically, the **y-component** of a vector is given as;

By = B sinθ

where;

By is the vertical or y-component of vector BB is the magnitude of vector Bθ is the angle of inclination of vector BThe **y-component** of **vector B** is calculated as follows;

By = 18.6 m x sin(170)

By = 3.23 m

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Provide an example of a situation that can be explained by each of Newton's Three Laws of Motion.

**ANSWER and EXPLANATION**

First, let us state Newton's three laws of motion.

The first law of motion states that:

The second law of motion states that:

The third law of motion states that:

Let us take an example of a ball that is stationary on a frictionless floor. As long as no force acts on the ball, it will continue to remain at rest but once a person kicks the ball, it begins to move and stay in motion (since the floor is frictionless, hence, no resistive force).

That is an application of the first law of motion.

The acceleration of this ball depends on the force with which it was kicked and the mass of the ball, as shown in the force equation:

[tex]F=ma[/tex]where m = mass, a = acceleration

That is an application of the second law of motion.

Assuming that this ball then comes in contact with a wall and stops moving. The force that the ball exerts on the wall is equal to the force that the wall exerts on the ball, but both forces act opposite one another.

That is an application of the third law of motion.

A force of 540 N keeps a certain ideal spring stretched a distance of 0.300 m.

A) What is the potential energy of the spring when it is stretched 0.300 m?

B) What is its potential energy when it is compressed 6.00 cm?

A **force **of 540 N keeps a certain ideal spring stretched a distance of 0.300 m.

A) The potential energy of the spring when it is stretched 0.300 m will be 81 J

B) The potential energy when it is compressed 6.00 cm will be 3.24 J

**Hooke's law**, law of elasticity discovered by the English scientist Robert Hooke in 1660, which states that, for relatively small deformations of an object, the displacement or size of the deformation is directly proportional to the deforming force or load.

To find spring constant , using formula

k= F/x

where

F = Force

k = spring constant

x = displacement

k = 540 / .300 = 1800 N/m

A) **Potential energy **of the spring when it is stretched 0.300 m

U = 1/2 * k * [tex]x^{2}[/tex] = 1/2 * 1800 * [tex]0.300^{2}[/tex] = 81 J

B ) Potential energy of the spring when it is stretched 0.06 m

U = 1/2 * k * [tex]x^{2}[/tex] = 1/2 * 1800 * [tex]0.06^{2}[/tex] = 3.24 J

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A truck with mass m has a brake failure while going down an icy mountain road of constant downward slope angle α (Figure 1). Initially the truck is moving downhill at speed v0. After careening downhill a distance L with negligible friction, the truck driver steers the runaway vehicle onto a runaway truck ramp of constant upward slope angle β. The truck ramp has a soft sand surface for which the coefficient of rolling friction is μr.

What is the distance that the truck moves up the ramp before coming to a halt? Solve using energy methods.

Express your answer in terms of m , α , v0 , L , g , β and μr .

((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ) is the **distance **that the truck moves up the ramp before coming to a halt.

Let the distance the truck moves up the ramp be by x.

The** kinetic energy** of the truck on an icy road is given by,

K1 = (1÷2)mv²

The potential energy of the truck on an icy road is given by,

U1 = mgLSinα

The kinetic energy of the truck on the tuck ramp is given by,

K2 = 0

The **potential Energy** of the truck-on-truck ramp is given by,

U2 = mgxSinβ

Work done is given by,

W(others) = -µ×mg×cosФ

Hence, by using the work-energy theorem,

W(others) = (K2 + U2)(K1 + U1)

Therefore, by putting the values we get,

((1÷2)mv² + mgLSinα)(0 + mgxSinβ) = -µ×mg×cosФ

x = (K1 + mgLSinα) ÷ (mg(Sinβ + µcosβ))

x = ((v² ÷ 2g) + LSinα) ÷ (Sinβ + µcosβ)

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What in the final position of a robot that starts from (0, 0) m and makes displacements of (4.4) * m (3.3) * m and (- 4, - 2) m?

Answer:

The final position of the robot is (3, 5) m

Explanation:The** initial position of the robot = (0, 0)**

The position of the robot after making a displacement of (4, 4)m = (0+4, 0+4)

The **position of the robot after making a displacement of (4, 4)m = (4, 4) m**

The new position of the robot after making a displacement of (3, 3)m

= (4+3, 4+3)m

The **new position of the robot after making a displacement of (3, 3)m =(7, 7)m**

The final position of the robot after making a displacement of (-4, -2)m

= (7-4, 7-2)

**The final position of the robot after making a displacement of (-4, -2)m **

**= (3, 5)m**

Therefore, **the final position of the robot is (3, 5) m**

A 2 kg mass hangs motionless from a spring with spring constant 8 N/m. Howfar will the spring stretch if the mass is motionless?

[tex]\begin{gathered} \text{Spring constant = K= 8N/m} \\ \text{mass}=\text{ m = }2\operatorname{kg} \\ \text{gravity = }g=9.81m/s^2 \\ stretch\text{ing = x =?} \\ \text{spring force = Kx} \\ Kx=mg \\ \text{Solving x} \\ x=\frac{mg}{K} \\ x=\frac{(2kg)(9.81m/s^2)}{\text{8N/m}} \\ x=2.4525m\approx2.45m \\ \text{The stretching is 2.45m} \end{gathered}[/tex]

Jake throws a rock downward from his deck at time t = 0 and it lands in his yard below.

Which of the following graphs best shows the velocity u of the rock until it hits the ground?￼

A graph of **velocity **vs **time **displays the change in an **object's velocity** in a straight line with regard to time.

A plot between speed and time is called a **velocity-time graph**. It depicts the motion of an object moving straight ahead. At any given time, the magnitude of velocity equals its **instantaneous speed**.

A graph of velocity vs time displays the change in an object's velocity in a **straight line** with regard to time. The x-axis is used to measure time, and the y-axis is used to measure velocity. For an item moving at a constant velocity, the **height **of the velocity-time graph does not change over time.

We can use a **velocity **vs. **time graph** to determine position and a time graph to determine velocity. We are aware that v = d/t. Rearranging the equation with a little mathematics reveals that d = v × t.

The complete question is:

Jack throws a rock downward from his deck at time t = 0 and it lands in his yard below. Make velocity-time graph of the rock until it hits the ground? Assume upward is the positive direction.

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Shiyon just received his first credit card in the mail. His mom reminded him that he needs to order a new pair of baseball cleats. In order to make sure his browser is secure for the transaction, he should

(A) use the same password for all accounts

(B) install Microsoft Excel

(C) enable pop-ups

(D) deactivate background scripts

**Answer:**

the answer is D

**Explanation:**

i got it right on the test

In order to make sure his browser is secure for the transaction, Shiyon should **deactivate background scripts**. Hence,** option (D)** is correct.

Without the **requirement **to create a trigger or script like a business row, a **background script** provides a free-form method of instantly running server-side code. When you want to clean a modest amount of data that doesn't call for a lot of intricate **adjustments**, we recommend using a **background script.**

You could get **around **that if you need to update records that may be subject to several **scripts **running on them—as long as they are small or decent in size, not excessive. You'll **discover **a few techniques to work around that.

Your transaction may run for hours when you run a **background script, **but this one will end it after four hours.

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(d) Find the domain of function R. Choose the correct domain below.
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Which of the following is incorrect according to Dalton's atomic theory?a) atoms of different elements can mix together and chemically combine to make new elementsb) atoms of the same element are identicalc) chemical reactions occur when atoms are rearranged in different combinationsd) all elements are made up of tiny particles called atoms
what is the acceleration of a car, moving along a straight line, that increases its velocity from 0 to 15 m/s in 10s?
What publication provides recommendations for forming patterns of eating that will promote health?.
Consider the vocabulary words from Walden.Select the word from the drop-down menu that correctly completes the sentence.Picturesnauseabecause of the astounding color combinations.
Find the length of the third side. If necessary, round to the nearest tenth.914
what was the final motive behind the federalist including the bill of rights?help pls