(in dollars), on the card after buying x prints is given by the following function.

B(x)=20.50-0.06.x

What is the remaining balance on the card if Boris bought 15 prints?

**Answer:**

$19.6

**Step-by-step explanation:**

B=20.50-0.06.x

B=20.50-0.06*15

B=20.50-0.9

B=19.6

please na solve it please please.

**Solution given** to both questions **below**, they reveal the given answers.

The steps are self-explanatory, let me know if anything is unclear.

Question 24[tex]\cfrac{2}{(x-2)(x-3)} +\cfrac{2}{(x-1)(3-x)}+\cfrac{1}{(1-x)(2-x)} =[/tex][tex]\cfrac{2}{(x-2)(x-3)} -\cfrac{2}{(x-1)(x-3)}+\cfrac{1}{(x-1)(x-2)} =[/tex][tex]\cfrac{2(x-1)}{(x-1)(x-2)(x-3)} -\cfrac{2(x-2)}{(x-1)(x-2)(x-3)}+\cfrac{x-3}{(x-1)(x-2)(x-3)} =[/tex][tex]\cfrac{2x-2-2x+4+x-3}{(x-1)(x-2)(x-3)} =[/tex][tex]\cfrac{x-1}{(x-1)(x-2)(x-3)} =[/tex][tex]\cfrac{1}{(x-2)(x-3)}[/tex]Question 25[tex](4x - 1)(x + 2) = 2 + 7x[/tex][tex]4x^2+8x-x-2=2+7x[/tex][tex]4x^2+7x-2=2+7x[/tex][tex]4x^2=4[/tex][tex]x^2=1[/tex][tex]x=\sqrt{1}[/tex][tex]x=\pm1[/tex]**Answer:**

[tex]\textsf{24.} \quad \dfrac{1}{(x-2)(x-3)}[/tex]

[tex]\textsf{25.} \quad x=1, \quad x=-1[/tex]

**Step-by-step explanation:**

Given expression:

[tex]\dfrac{2}{(x-2)(x-3)}+\dfrac{2}{(x-1)(3-x)}+\dfrac{1}{(1-x)(2-x)}[/tex]

When adding **rationals** with **different denominators**, make the denominators the same by finding the **least common denominator**.

Create a **common denominator** by:

[tex]\textsf{Multiplying the first fraction by $\dfrac{x-1}{x-1}$}.[/tex]

[tex]\textsf{Multiplying the second fraction by $\dfrac{-(x-2)}{-(x-2)}$}.[/tex]

[tex]\textsf{Multiplying the third fraction by $\dfrac{x-3}{x-3}$}.[/tex]

[tex]\implies \dfrac{2}{(x-2)(x-3)} \cdot \dfrac{x-1}{x-1}+\dfrac{2}{(x-1)(3-x)}\cdot \dfrac{-(x-2)}{-(x-2)}+\dfrac{1}{(1-x)(2-x)}\cdot \dfrac{x-3}{x-3}[/tex]

[tex]\implies \dfrac{2(x-1)}{(x-1)(x-2)(x-3)}+\dfrac{-2(x-2)}{-(x-1)(x-2)(3-x)}+\dfrac{x-3}{(1-x)(2-x)(x-3)}[/tex]

[tex]\implies \dfrac{2(x-1)}{(x-1)(x-2)(x-3)}+\dfrac{-2(x-2)}{(x-1)(x-2)(-3-(-x))}+\dfrac{x-3}{(-(-1+x))(-(-2+x))(x-3)}[/tex]

[tex]\implies \dfrac{2(x-1)}{(x-1)(x-2)(x-3)}+\dfrac{-2(x-2)}{(x-1)(x-2)(x-3)}+\dfrac{x-3}{(x-1)(x-2)(x-3)}[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{d}+\dfrac{b}{d}+\dfrac{c}{d}=\dfrac{a+b+c}{d}:[/tex]

[tex]\implies \dfrac{2(x-1)-2(x-2)+(x-3)}{(x-1)(x-2)(x-3)}[/tex]

Expand the **numerator**:

[tex]\implies \dfrac{2x-2-2x+4+x-3}{(x-1)(x-2)(x-3)}[/tex]

[tex]\implies \dfrac{x-1}{(x-1)(x-2)(x-3)}[/tex]

Cancel the **common factor** (x - 1):

[tex]\implies \dfrac{1}{(x-2)(x-3)}[/tex]

Question 25Given equation:

[tex](4x-1)(x+2)=2+7x[/tex]

**Expand **the left side:

[tex]\implies 4x^2+7x-2=2+7x[/tex]

**Subtract **7x from both sides:

[tex]\implies 4x^2+7x-2-7x=2+7x-7x[/tex]

[tex]\implies 4x^2-2=2[/tex]

**Add **2 to both sides:

[tex]\implies 4x^2-2+2=2+2[/tex]

[tex]\implies 4x^2=4[/tex]

**Divide **both sides by 4:

[tex]\implies \dfrac{4x^2}{4}=\dfrac{4}{4}[/tex]

[tex]\implies x^2=1[/tex]

**Square root **both sides:

[tex]\implies \sqrt{x^2}=\sqrt{1}[/tex]

[tex]\implies x= \pm 1[/tex]

Therefore, the **solutions **are:

[tex]x=1, \quad x=-1[/tex]

I WILL GIVE BRAINLEST 1+1

it is 2 becuase 1 plus 1 is two when you have an apple and a freind gives you an apple you have 2 appelapples

**Answer:**

1+1=2

**Step-by-step explanation:**

if you have one of me then you duplicate me or make a dopleganger than you now have 2

have a great day^^

Gloria is making flower arrangements for a wedding. She has a total of 112 flowers and 14 vases to fill. What is the unit rate of

flowers per vase? (1 point)

O 8 flowers

O 14 flowers

10 flowers

6 flowers

The answer is 8 flowers.

Aaron has two summer jobs. During the week he works in the grocery store, and on the weekend he works at a nursery. He gets paid $20 per hour to work at the grocery store and $21 per hour to work at the nursery. How much does he earn if he works 13 hours at the grocery store and 9 hours at the nursery? How much does he earn if he works gg hours at the grocery store and n hours at the nursery?

Total pay, 13 hours at the grocery store and 9 hours at the nursery:

Total pay, g hours at the grocery store and n hours at the nursery:

If he gets** paid** $20 **per hour** to work at the grocery store and $2 per hour to work at nursery,

Part a

He will** earn **$449 if he works 13 hours at the grocery store and 9 hours at the nursery

Part b

He will earn 20g + 21n, if he works g hours at the grocery store and n hours at the nursery

**The payment** at the grocery store per hour = $20

The payment at the nursery per hour = $21

**Part a**

**Number of hours** he works at the grocery store = 13 hours

Number of hours he works at nursery = 9 hours

Total pay = 13×20 + 9×21

= 260 + 189

= $449

**Part b**

Number of hours he works at the grocery store = g hours

Number of hours he works at nursery = n hours

**Total pay** = 20g + 21n

Hence, If he gets paid $20 per hour to work at the grocery store and $2 per hour to work at nursery,

Part a

He will earn $449 if he works 13 hours at the grocery store and 9 hours at the nursery

Part b

He will earn 20g + 21n, if he works g hours at the grocery store and n hours at the nursery

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Let f(x)=2x²+x-11 and g(x)=x-1. Perform the function operation and then find the domain.

(f+g)(x)

(f+g)(x) = (Simplify your answer.)

**Answers:**

[tex](f+g)(\text{x}) = \boldsymbol{2\text{x}^2+2\text{x}-12}[/tex]

Domain = **set of all real numbers**

========================================================

Work Shown:

[tex](f+g)(\text{x}) = f(\text{x})+g(\text{x})\\\\(f+g)(\text{x}) = (2\text{x}^2+\text{x}-11)+(\text{x}-1)\\\\(f+g)(\text{x}) = 2\text{x}^2+\text{x}-11+\text{x}-1\\\\(f+g)(\text{x}) = 2\text{x}^2+(\text{x}+\text{x})+(-11-1)\\\\(f+g)(\text{x}) = 2\text{x}^2+2\text{x}-12\\\\[/tex]

The domain of each f(x) and g(x) is "set of all real numbers" since we can replace x with any real number to get some output.

By extension, this means the domain of (f+g)(x) is also "set of all real numbers".

It turns out any polynomial will have this domain. We don't have to worry about things like applying square roots to negatives, or dividing by zero. This is why there isn't a restriction on x.

To write "set of all real numbers" in interval notation, we would say [tex](-\infty, \infty)[/tex] to indicate x is anything between negative infinity and positive infinity.

The area of a triangle is 1/2bh

1) rewrite the formula for b

2)rewrite the formula for h

**Answer:**

1. b = 2A/h

2. h = 2A/b

**Step-by-step explanation:**

All you have to do is isolate the variable.

1.

Isolate b:

A = 1/2 x b x h

Multiply each side by 2

2A = b x h

Isolate b by dividing both sides by h

b = 2A/h

2.

Isolate h:

A = 1/2 x b x h

Multiply each side by 2

2A = b x h

Isolate h by dividing both sides by b

h = 2A/b

Pls help asap I’ll give brainliest

Firstly **multiplication** operation will be performed and the value on **simplification** will be **-7.**

The expression will be solved based on the sequence in **order of operations.** In the mentioned expression, parenthesis and exponents are not there. Thus, firstly we will multiply the values followed by division. Then we will perform addition and subtraction **(PEMDAS)**.

Performing **multiplication** first -

Value = 27 ÷ 27 - 8

Performing **division** at second step -

Value = 1 - 8

We are left with **subtraction**, so performing it -

Value = -7

Therefore, **firstly multiplication** will be performed and the value is **-7**.

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In a pond, the ratio of toads to frogs was 3: 10.

9 more frogs then entered the pond, and the ratio of toads to frogs became

3:11.

Work out how many toads are in the pond.

**Toads **are in the **pond** is 27.

The **quantitative** relation between two **amounts **showing the number of times one value contains or is contained within the other.

"the **ratio **of men's jobs to women's is 8 to 1".

Given that,

The ratio of toads to frogs was 3: 10.

Let the number of **toads **= 3x

number of **frogs **= 10x

9 more frogs then entered the pond and the **ratio **of **toads **to **frogs **became 3:11.

[tex]\frac{3x}{10x+9} =[/tex] [tex]\frac{3}{11}[/tex]

[tex]\frac{x}{10x+9} = \frac{1}{11}[/tex]

11x = 10x+9

x = 9

number of **toads **= 3x = 3×9 = 27

Hence, **Toads **are in the **pond** is 27.

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f(n)=3.3n-1 for n ≥ 1

The first five terms of the given function is:

**f(1)** = 2.3

f(2) = 5.6

f(3) = 8.9

**f(4)** = 12.2

f(5) = 15.5

Functions: The core concept of mathematics calculus is **functions**. The unique varieties of relations are the functions. In mathematics, a function is represented as a rule that produces a distinct result for each input x. In mathematics, a function is indicated by a mapping or transformation. Typically, these functions are identified by letters like f, g, and h.

The given function is **f(n)** = 3.3n-1 for n>= 1

The first 5 terms of this function are as follows:

f(1) = 3.3(1)-1

= 3.3-1 = 2.3

f(2) = 3.3(2)-1

= 6.6-1 = 5.6

f(3) = 3.3(3)-1

= 9.9-1

=8.9

f(4) = 3.3(4)-1

= 13.2-1

=12.2

f(5) = 3.3(5)-1

= 16.5-1

= 15.5

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3. Given the perimeter of the figure is 76 ft, Find

the dimensions of the shape.

R

(4x-5) ft

(25-x) ft

(13 + x) ft

S

T

(3x+1) ft

All the** dimensions** of the **shape** is found as 19 ft.

For the given question, the dimensions of the shape is given as;

(4x-5) ft(25-x) ft(13 + x) ft(3x+1) ftThe perimeter of the shape = 76 ft.

The formula of the** perimeter **= sum of **length **of all sides.

Let 'P' be the perimeter.

P = (4x-5) + (25-x) + (13 + x) + (3x+1) ing

Simplifying

P = 4x - x + x + 3x - 5 + 25 + 13 + 1

76 = 7x + 34

7x = 76 - 34

7x = 42

x = 6

Thus, the **dimensions **of the shape is; Put x = 6

Thus, all the dimensions of the **shape** is found as 19 ft.

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The midpoint of segment AB is M. If the coordinates of M are (1/2,-2) and the coordinates of B are (6,1), what are the coordinates of A?

The **coordinates** of **A **are (-5, -5).

How to determine the **midpoint** of a **given segment**?

The **center point** of a straight line can be located using the **midpoint **formula. We can use this **midpoint formula** to determine the coordinates of the supplied line's midpoint in order to discover its location on a graph. Assuming that the line's endpoints are (x₁, y₁) and (x₂, y₂), the **midpoint** (a, b) is determined using the following formula:**(a , b) ≡ (((x₁ + x₂)/2), ((y₁ + y₂)/2))**

Given, the **line segment** under consideration is **AB **as endpoints.

And, the **co-ordinate** of **B** is = (6, 1)

Also, the **midpoint **of **segment AB** i.e. **M** is = (0.5, -2)

Let the **co-ordinate** of **A** be = (x, y)

Using the available literature and formula, we get

(0.5, -2) ≡ (((x + 6)/2), ((y + 1)/2))

Equating both parts in the given equation,

0.5*2 = x + 6 ⇒ 1 = x + 6 ⇒ x = -5

and, (-2)*2 = y + 1 ⇒ -4 = y + 1 ⇒ y = -5

Therefore, the **co-ordinates** of **A** are (-5, -5).

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PLEASE HURRY

Simplify:

**6m/m-3 + m/m+1**

Simplify

Identify the common factor

{6m/m-3 + m/m+1

(m+1) . (6-3) /(m+1) + (m-3)/ (m+1)

Add fractions with the same denominator together.

terms to put constants on the left and reorder them

Solution

**7m^{2}+3m / m^2-2m-3**

The answered are **7 3 2 3**

**What does the algebraic expression M mean?**

The slope of a line is represented by the letter "**m" in algebra**. A line's slope defines both its direction and steepness.

The order in which you perform operations in arithmetic and algebra is governed by a number of laws. The** Commutative**, **Associative**, and **Distributive** Laws are the three that receive the most attention. People have discovered over time that adding or multiplying doesn't depend on the order of the numbers

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IMAGE ATTACHED Help with this please.

Part of a full number and a means of dividing a number into **equal pieces **are represented by fractions.The denominator is the total number of parts in the whole, while the numerator is the number of equal portions being **counted. **

**Solve the problem ?**

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A bicycle has cash price $16 319.50. It can be bought on hire purchase with a deposit of $6 900 and ten monthly installments of $1 224.50 each.

a. What is the total hire purchase price for the bicycle? [3 marks]

b. Find the difference between the hire purchase price and the cost price for the bicycle. [1 mark]

c. Express your answer in (b) above as a percentage of the cash price.

a) **Total **purchase price for the bicycle is **$19,145**

b) The **difference **between the hire purchase price and the cost price for the bicycle is **$2,825.50**

c) The **percentage **of difference between the hire purchase price and the cost price for the bicycle is **17%**

**Percentage:**

Percentage means a **fraction **or a **ratio **in which the **value **of whole is **always 100. **

Given,

A bicycle has cash price $16,319.50. It can be bought on hire purchase with a deposit of $6,900 and ten monthly installments of $1,224.50 each.

Here we need to following:

a) Purchase price for the bicycle

b) Difference between the hire purchase price and the cost price for the bicycle

c) Percentage of the cash price.

The total purchase price is calculated by **adding **the deposit and the ten month installment.

So, the total purchase price is,

=> 6900 + (10 x 1224.50)

=> 6900 + 12245

=> 19145.

Therefore, the total purchase price is $19145.

Now, the **difference **between the hire purchase price and the cost price for the bicycle is calculated as,

=> 19145 - 16319.50

=> 2825.50

So, the difference between the hire purchase price and the cost price for the bicycle is $2,825.50

Now, we have to calculate the percentage by using the following **expression**,

x% of 16,319.50 = 2825.50

x% = 2825.50/16319.50

x% = 0.1731

x = 17.31.

Therefore, there is 17% difference in the hire purchase price and the cost price for the bicycle.

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if the total value of the coins is $5.50 and kayleigh has 17 quarters, how many nickels does she have?

Kayleigh have 25** nickels** with her.

Given,

The total value of **coins** Kayleigh have = $5.50

Number of quarters with Kayleigh = 17 quarters

We have to find the number of nickels Kayleigh with her.

Lets see:

1 dollar = 4 quarters

1 dollar = 20 nickels

Here, we have a total of 5.50 dollar

In this, 17 quarters are there.

So,

17 / 4 = 4.25

That is, the value of coins as **quarters** is $4.25

Now,

5.50 - 4.25 = 1.25

That is,

$1.25 is in the form of nickels.

Number of nickels = 1.25 × 20

Number of nickels = 25

Therefore,

Kayleigh have 25 **nickels** with her.

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If the area of a triangle is 2x^2-2x-4 and it has a height of x-2, write the base of the triangle.base of the triangle:_________________

Answer:

The base of the triangle = 4(x + 1)

Explanations:The Area of a triangle is given by the formula:

[tex]\text{Area = }\frac{1}{2}\times\text{ base }\times\text{ height}[/tex][tex]\begin{gathered} \text{Area = 2x}^2-2x-4 \\ \text{Height = x -2} \end{gathered}[/tex]Substituting these expressions into the formula for the area of a triangle:

[tex]\begin{gathered} 2x^2-2x-4\text{ = }\frac{1}{2}\times\text{ b }\times(x-2) \\ 2(2x^2-2x-4)\text{ = b (x - 2)} \\ 4x^2-4x-8\text{ = b (x-2)} \\ 4x^2-8x\text{ + 4x - 8 = b (x - 2)} \\ 4x(x\text{ - 2) + }4(x\text{ - 2) = b(x-2)} \\ (4x+4)(x-2)\text{ = b(x-2)} \\ b\text{ = }\frac{(4x+4)(x-2)}{(x-2)} \\ b\text{ = 4x + 4} \end{gathered}[/tex]b = 4 (x + 1)

The base of the triangle = 4(x + 1)

Did I get these right

**Answer:**

Almost!

**Step-by-step explanation:**

Problems 1-9 and 11 are correct, but not problem 10 or 12

For **problem 10**, 12/6 does equal 6/1, so it would just be the whole number of **6** as your final answer as it doesn't need to be simplified further.

For **problem 12**, -4/6 can be simplified further to **-2/3** by dividing by 2.

**Answer: Very close!**

**Step-by-step explanation:**

Problems 7, 8, 9, and 11 are correct but not 10 or 11, because they are not in simplest form.

2/1 can be simplified to 2, and -4/6 can be simplified to -2/3.

Which of the following proves these triangles are congruent?

A. neither

B. SAA

C. ASA

**Answer:**

**Step-by-step explanation:**

**Neither, they are not congruent.**

A. neither

Explanation:

they arent congruent

Explanation:

they arent congruent

bu sorunun çözümünü yazarmısınız çok acil lütfennnnn

**Answer:**

**Step-by-step explanation:**

i poopeyd in ma pants

the volumes of soda in quart soda bottles can be described by a normal distribution with a mean of 32.3 ounces and a standard deviation of 8.8 ounces. (a) what proportion of bottles will have a volume more than 32 ounces? 0.5136 correct: your answer is correct. (4 decimal places) (b) what is the 85th percentile for this distribution? 23.18 incorrect: your answer is incorrect. (2 decimal places)

a)The **percentage **of bottles expected to have a volume more than 32 oz is 33.60%

b) 85% of 0.3360 is 0.2856

a) The **volumes **of soda in quart soda bottles can be represented by a Nomal model with a= 32.3 oz

b=8.8 oz

Let S be the volume of randomly selected soda bottles

Y-score: S-a/b

For S=32 oz

Substitute the values of S,a and b into the equation

Y=32-32.3/8.8

Y= - 0.0341

Probability of bottles that have a **volume **more than 32 oz is

P(S>32)=P(Y>-0.0341)= 0.3360

**Percentage **of bottles that have **volume **more than 32 oz will be

0.3360×100%=33.60%

b) 85% of 0.3360 is 0.2856

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ABC has vertices at A(4,1), B(-3,-2), and C(-1,3). what is the perimeter of ABC?

If ABC is a **triangle**, which when plotted on the cartesian coordinate system, has it's vertices at A(4, 1), B(-3, -2), and C(-1, 3), then the **perimeter **of triangle ABC will be [√58/(√2 - 1)]

As per the question statement, ABC is a triangle, which when plotted on the **cartesian coordinate system**, has it's vertices at A(4, 1), B(-3, -2), and C(-1, 3).

We are required to calculate the **perimeter** of triangle ABC.

To solve this question, first we need to calculate the distances between AB, BC ad AC, which are the three sides of our concerned triangle ABC, and then add them up to obtain our desired answer. And to calculate the lengths of AB, BC ad AC, we will need to use the distance formula which goes as,

"The **distance** between any two points (x₁, y₁) and (x₂, y₂) can be given by

√[(x₂ - x₁)² + (y₂ - y₁)²]

**Considering** points A(4, 1) and B(-3, -2), we can say that [(x₁, y₁) = (4, 1)] and [(x₂, y₂) = (-3, -2)]. Therefore, distance AB = √[{(-3) - 4}² + {(-2) - 1}²]

Or, AB = √[{-(3 + 4)}² + {-(2 + 1)}²]

Or, AB = √[(-7)² + (-3)²]

Or, AB = √[(49 + 9)]

Or, AB = √58

Similarly **considering** points A(4, 1) and C(-1, 3), we can say that

[(x₁, y₁) = (4, 1)] and [(x₂, y₂) = (-1, 3)].

Therefore, distance AB = √[{(-1) - 4}² + (3 - 1)²]

Or, AC = √[{-(1 + 4)}² + (3 - 1)}²]

Or, AC = √[(-5)² + (2)²]

Or, AC = √[(25 + 4)]

Or, AC = √29

Finally considering points B(-3, -2) and C(-1, 3), we can say that

[(x₁, y₁) = (-3, -2)] and [(x₂, y₂) = (-1, 3)].

Therefore, distance BC = √[{(-1) - (-3)}² + {3 - (-2)}²]

Or, BC = √[{-(1) + 3}² + (3 + 2)²]

Or, BC = √[(3 - 1)² + (5)²]

Or, BC = √[(4 + 25)]

Or, BC = √29

Therefore, the **perimeter** of Triangle ABC = (AB + BC + AC)

Or, perimeter of Triangle ABC = (√58 + √29 + √29)

Or, perimeter of Triangle ABC = [√(29 * 2) + √29 + √29]

Or, perimeter of **Triangle** ABC = [(√29*√2) + √29 + √29]

Or, perimeter of Triangle ABC = √29(√2 + 1 + 1)

Or, perimeter of Triangle ABC = √29(√2 + 2)

Or, perimeter of Triangle ABC = (√29*√2)(1 + √2)

Or, perimeter of Triangle ABC = (√58)(1 + √2)

Or, perimeter of Triangle ABC = [tex]\frac{\sqrt{58} (1+\sqrt{2})(1-\sqrt{2}) }{(1-\sqrt{2})} =\frac{\sqrt{58} [(1)^{2}-(\sqrt{2})^2 }{(1-\sqrt{2})}}[/tex]

Or, perimeter of Triangle ABC = [tex]\frac{\sqrt{58} [(1-2) }{(1-\sqrt{2})}}=\frac{-\sqrt{58}}{(1-\sqrt{2})}}=\frac{\sqrt{58}}{(\sqrt{2}-1)}}[/tex]

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If 3/5 of Ellen’s class has brown eyes and there are 25 people in Ellen’s class, how many of them have brown eyes?

**Answer: The answer is 15**

**Step-by-step explanation: 25* 3/5 is 15 so 15 out of 25 is what percent of the class has brown eyes**

Given 4 1/10 -3 5/12 determine the product

The **product **of 4 1/10 and -3 5/12 is **-14 1/120**

**Fractions** are simply described as a subset of a whole or the **part** of a whole.

They are several types of fractions, some of which includes;

Mixed fractionsProper fractionsImproper fractionsSimple fractionsComplex fractionsSome examples of **mixed fractions**; 3 1/4, 5 1/2, 6 1/4

Some examples of simple fractions; 1/2, 1/4, 1/6

Some examples of proper fractions; 3/4, 4/5, 6/7

Some examples of improper fractions; 3/2, 4/3, 6/5

Given the mixed fractions;

4 1/10 × -3 5/12

convert to improper fractions

41/10 × - 41/12

Multiply through

- 1681/120

Find the ratio

- 14 1/ 120

Hence, the **value **is - 14 1/ 120

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Which of the following numbers is NOT equivalent to 40%? A 0.04 B 0.40 c.? D *I • 10

The option that is not equivalent to the given **percentage **of 40% is; A:0.04.

What is the correct percentage?

We are given the** percentage** as 40%.

Now, this percentage can be rewritten as a** proper fraction** as;

40% = 40/100

In **decimal form**, this is expressed as 0.40

Now, the proper fraction 40/100 can be broken down into;

40/100 = 4/10

Further more when we divide both **numerator** and** denominator** by 2, we will get the fraction 2/5.

Thus, the only option that is not equivalent to the given percentage is option A which is 0.04.

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The correct options are;

A) 0.04

B) 0.40

C) 2/5

D) 4/10

write 34,000 , 43,000,000 , 0.0000087 , 91,000,000 , 16.6 x 10^3 , and 0.00372 x 10^-3 in scientific notation

To write a number in scientific notation you must know:

1. A number in scientific notation is written as the product of a number (integer or decimal) and a power of 10

2. A number can be converted to scientific notation by increasing the power of 10 by one for each place the decimal point is shifted to the left.

Then so:

[tex]34000=3,4x10^3[/tex][tex]43000000=4.3x10^7[/tex][tex]0.0000087=8.7x10^{-6}[/tex][tex]91000000=9.1x10^7[/tex][tex]16.6x10^3=1.66x10^4[/tex][tex]0.00372x10^{-3}=3.72x10^{-6}[/tex]Please help for 50 points

Which of the following points are solutions to the given system?

3x-4y<10

2x+6y≥-8

Select all that apply

(0, 4)

(2, –1)

(2, –2)

(8, 2)

(–1, –1)

**Answer: (0,4) and (-1,-1)**

**Step-by-step explanation:**

**1) Plug in all of each equation**

**1a) (0,4)**

3(0)-(4)<10

0-4< 10

-4< 10

2(0)+6(4)>=-8

0+24 >= -8

24>= -8

**Works!**

**1b) (2,-1)**

3(2)-4(-1)<10

6+4<10

10<10

**Nope.**

**1c) (2,-2)**

3(2)-4(-2)<10

6+8<10

14<10

**Nope.**

**1d) (8,2)**

3(8) -4(2) < 10

24 - 8 < 10

16<10

**Nope.**

**1f) (-1,-1)**

3(-1)-4(-1) < 10

-3 +4 < 10

1 < 10

2(-1)+6(-1)>=-8

-2+-6 >= -8

-8 >= -8

**Works.**

1. PET CARE You buy a 6.3-pound bag of dry cat food

for your cat. The function c = 6.3-0.25p represents

the amount of cat food c remaining in the bag when

the cat is fed the same amount each day for p days.

Find the zero of this function. Describe what this

value means in this context.

The **zero **of the **function **is 25.6 and it means that the total number of days is 25.6

From the question, the **equation **of the **function **is given as

c = 6.4 - 0.25p

The **zero **of this **function **is when the function equals 0

This is represented as

c = 0

Substitute c = 0 in c = 6.4 - 0.25p

So, we have

6.4 - 0.25p = 0

The above equation becomes

0.25p = 6.4

Divide both sides by 0.25

p = 25.6

So, the **zero **is 25.6 and it represents that the total number of days

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Mrs Flores 'sixth grade class has 15 students 9 of which are boys .What is the ratio of boys and girl in Mrs flores classroom in the simplest form ?

It know it 3:2 but can you tell me why because I am confused

**Answer:**

see explanation

**Step-by-step explanation:**

there are 15 students , 9 of which are boys, then

number of girls = 15 - 9 = 6

ratio of boys : girls = 9 : 6 = 3 : 2 ← in simplest form

Taylor and her children went into a movie theater and she bought $81 worth of bags of popcorn and candies. Each bag of popcorn costs $9 and each candy costs $4.50. She bought 6 more candies than bags of popcorn. Graphically solve a system of equations in order to determine the number of bags of popcorn, x,x, and the number of candies, y,y, that Taylor bought.

**Answer:**

**Step-by-step explanation:**

You* *want to find the **number** of **bags of popcorn** (x) and **candies** (y) Taylor **bought for $81**, given that popcorn costs $9 and candies cost $4.50, and she bought **6 more candies** than popcorns.

The equations relating x and y are ...

6x +4.5y = 81 . . . . . . . . the total cost of the snacksx + 6 = y . . . . . . . . . . . there were 6 more candies than popcornsSolutionThe attached graph shows the solution of thees equations is ...

(x, y) = (4, 10)

**Taylor bought 4 bags of popcorn and 10 candies**.

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What is the

domain?

Ahh someone give me the answer plsss

**Answer:**

0≤x≤|**R**

**Step-by-step explanation:**

I'm not really sure but I think the domain is all positive real numbers including zero

Hmm thats not right. The graph does not continue to the right forever. It stops at x=3. If it was all positive numbers including 0, the notation would just x greater than, equal to 0.

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