some fhdf

djfsirsisdsjfsd

fdfjjjf9d094--djjf9939=3030395944./445335

hi for the second qn i’m not sure if the vol is referring to the entire object or js the pyramid

Solve for a.5a== ✓ [?]2aPythagorean Theorem: a2 + b2 = c2=

**ANSWER**

**a = √21**

**EXPLANATION**

This is a right triangle, so we have to apply the Pythagorean Theorem to find the value of a.

We know the length of the hypotenuse which is 5, and the length of one of the legs, which is 2. The Pythagorean Theorem for this problem is,

[tex]a^2+2^2=5^2[/tex]Subtract 2² from both sides,

[tex]\begin{gathered} a^2+2^2-2^2=5^2-2^2 \\ a^2=25-4 \end{gathered}[/tex]And take the square root to both sides,

[tex]\begin{gathered} \sqrt[]{a^2}=\sqrt[]{25-4} \\ a=\sqrt[]{21} \end{gathered}[/tex]Hence, the value of **a is √21**.

What is the probability of drawing a red card from a pack of cards and rolling an even number on a standard six-sided die?

Select one:

1/12

1/2

1/4

1/8

**Answer:**

**1/2 because half the cards are red and half the numbers are even**

The wholesale price for a chair is 194$ . A certain furniture store marks up the wholesale price by 35%. Find the price of the chair in the furniture store.

The** price** of the chair will be 261.9 $ .

One **percent** (symbolized 1%) is a hundredth part; thus, 100 percent represents the entirety and 200 percent specifies twice the given quantity. For example, 1 percent of 1,000 chickens equals 1/100 of 1,000, or 10 chickens; 20 percent of the quantity is 20/100 1,000, or 200.

If we say, 5%, then it is equal to 5/100 = 0.05.

To solve **percent problems,** you can use the equation, Percent · Base = Amount, and solve for the unknown numbers. Or, you can set up the proportion, Percent = , where the percent is a ratio of a number to 100. You can then use cross** multiplication **to solve the proportion.

Based on given conditions formulate

x = 194 ×(35%+1)

x= 194 ×1.35

x = 261.9 $ .

Thus The** price** of the chair will be 261.9 $ .

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URGENT!! ILL GIVE

BRAINLIEST!!!!! AND 100

POINTS!!!!!

If angle a measures 42 degrees, then what other angles would be congruent to angle a and also measure 42 degrees?

If **angle "a"** measures 42° the the other angles that will be** congruent** to angle "a" and also **measure 42°** will be angle d, angle e and angle h .

In the question ,

a figure is given ,

From the figure we can see that 2 parallel lines are cut by a** transversal** .

So ,

angle a = angle d .......because vertically opposite angles .

angle a = angle e ...because **corresponding angles** are equal in measure

also

angle e = angle h .... because vertically opposite angles .

Therefore , If angle "a" measures 42° the the **other angles** that will be congruent to angle "a" and also **measure 42° **will be angle d, angle e and angle h , the correct option is (a) .

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Hi, can you help me answer this question please, thank you!

**Given:**

The test claims that night students' mean GPA is significantly different from the mean GPA of day students.

Null hypothesis: the population parameter is equal to a hypothesized value.

Alternative hypothesis: it is the claim about the population that is contradictory to the null hypothesis.

For the given situation,

[tex]\begin{gathered} \mu_N_{}=\text{ Night students} \\ \mu_D=Day\text{ students} \end{gathered}[/tex]**Null and alternative hypothesis is,**

**Answer: option f) **

Need help answering all these questions for the black bird. Exponential equation for the black bird: g(x) = 2^x-8 + 1King Pig is located at (11,9)Moustache Pig is located at (10,4)

**Given:**

Exponential equation for the black bird is,

[tex]g(x)=2^{x-8}+1[/tex]**Required:**

To find the starting point of bird and graph the given function.

**Explanation:**

(1)

The bird starting point is at x = 0,

[tex]\begin{gathered} g(0)=2^{0-8}+1 \\ \\ =2^{-8}+1 \\ \\ =1.0039 \\ \\ \approx1.004 \end{gathered}[/tex](2)

The graph of the function is,

**Final Answer**

(1) 1.004

(2)

15 Which of the digits from 2 to 9 is 5544

divisible by?

**Answer:**

All of em, except 5

**Step-by-step explanation:**

5544 / 2 = 2772

5544 / 3 = 1848

5544 / 4 = 1386

5544 / 6 = 924

5544 / 7 = 792

5544 / 8 = 693

5544 / 9 = 616

Two cars start moving from the same point. One travels south at 24 mi/h and the other travels west at 18 mi/h. At what rate (in mi/h) is the distance between the cars increasing four hours later?

mi/h

The** rate** at which the **distance** between the two cars increased four hours later is 30 mi/h.

First of all, we would determine the **distances** travelled by each of the cars. The **distance** travelled by the first car after four (4) hours is given by:

Distance, x = **speed/time**

Distance, x = 24/4

**Distance**, x = 6 miles.

For the second car, we have:

Distance, y = **speed**/time

Distance, y = 18/4

**Distance**, y = 4.5 miles.

After four (4) hours, the total **distance** travelled by the two (2) cars is given by this mathematical expression (Pythagorean theorem):

z² = x² + y²

Substituting the parameters into the mathematical expression, we have;

z² = 6² + 4.5²

z² = 36 + 20.25

z² = 56.25

z = 7.5 miles.

Next, we would differentiate both sides of the mathematical expression (Pythagorean theorem) with respect to **time**, we have:

2z(dz/dt) = 2x(dx/dt) + 2y(dy/dt)

Therefore, the **rate** of change of **speed** (dz/dt) between the two (2) cars is given by:

dz/dt = [x(dx/dt) + y(dy/dt)]/z

dz/dt = [6(24) + 4.5(18)]/7.5

dz/dt = [144 + 81]/7.5

dz/dt = 225/7.5

dz/dt = 30 mi/h.

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**Answer:**

30 mi / hr

**Step-by-step explanation:**

First find out how far the cars are apart after 4 hours

24 * 4 = 96 mi = y

18 * 4 = 72 mi = x

Now use the pythagorean theorem

s^2 = ( x^2 + y^2 ) shows s = 120 miles apart at 4 hours

Now s^2 = x^2 + y^2 Differentiate with respect to time ( d / dt )

2 s ds/dt = 2x dx/ dt + 2y dy / dt

ds/dt = (x dx/dt + y dy/dt)/s

= (72(18) + 96(24)) / 120

ds/dt = 30 mi/hr

Solve the system [tex]\left \{ {{5x1 + 5x2 = 5} \atop {2x1 + 3x2 = 4}} \right.[/tex]

The** solution** for the given **system of equations** is **x[1] = -1 **and **x[2] = 2**.

A system of linear equations (or linear system) is a collection of **one **or **more linear** equations involving the **same variables.**

Given are the following equations as -

**5 x[1] + 5 x[2] = 5**

**2 x[1] + 3 x[2] = 4**

Assume that -

**x[1] = a **

**x[2] = b**

Then, we can write the equations as -

**5a + 5b = 5**

**2a + 3b = 4**

Now -

5a + 5b = 5

5(a + b) = 5

a + b = 1

a = 1 - b

So, we can write -

2a + 3b = 4

as

2(1 - b) + 3b =4

2 - 2b + 3b = 4

b = 4 - 2

**b = 2 = x[2]**

Then

a = 1 - 2

**a = -1 = x[1]**

Therefore, the** solution** for the given **system of equations** is **x[1] = -1 **and **x[2] = 2**.

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A

piece of ribbon

was cut into

three parts in the ratio of 1:3'5

If the shortest was 11cm how long was the ribbon

1:3:5

11:33:55=99

99cm

11:33:55=99

99cm

**Answer: Total Length of ribbon is 99 cm**

**Step-by-step explanation:**

** Here ribbon was cut into three parts in the ratio 1:3:5**

**let x be the common multiple of the above ratio**

**therefore, the lengths of the three parts of the ribbon is 1x,3x,5x**

**now, given is that the shortest part i.e 1x is equals to 11cm**

**i.e 1x=11 **

** x=**[tex]\frac{11}{1}[/tex]=11cm

now lengths of the ribbon will be

1x=11cm, 3x=3*11=33cm, 5x=5*11=55cm

now total length of piece of ribbon = 1x+3x+5x=9x=9*11=99cm

Write the equation of a Circle with the given information.End points of a diameter : (11, 2) and (-7,-4)

The form of the equation of the circle is

[tex](x-h)^2+(y-k)^2=r^2[/tex]Where (h, k) are the coordinates of the center

r is the radius

Since the endpoints of the diameter are (11, 2) and (-7, -4), then

The center of the circle is the midpoint of the diameter

[tex]\begin{gathered} M=(\frac{11+(-7)}{2},\frac{2+(-4)}{2}) \\ M=(\frac{4}{2},\frac{-2}{2}) \\ M=(2,-1) \end{gathered}[/tex]The center of the circle is (2, -1), then

h = 2 and k = -1

Now we need to find the length of the radius, then

We will use the rule of the distance between the center (2, -1) and one of the endpoints of the diameter we will take (11, 2)

[tex]\begin{gathered} r=\sqrt[]{(11-2)^2+(2--1)^2} \\ r=\sqrt[]{9^2+3}^2 \\ r=\sqrt[]{81+9} \\ r=\sqrt[]{90} \\ r^2=90 \end{gathered}[/tex]Now substitute them in the rule above

[tex]undefined[/tex]I really need help please!

**Answer:**

n < -15/4

**Step-by-step explanation:**

You want to use the **discriminant** to find the **values of n** for which the **quadratic 3z² -9z = (n -3)** has only **complex solutions**.

The discriminant of quadratic equation ax²+bx+c = 0 is ...

d = b² -4ac

The given quadratic can be put in this form by subtracting (n-3):

3z² -9z -(n -3) = 0

This gives us ...

a = 3b = -9c = -(n -3)and the discriminant is ...

d = (-9)² -4(3)(-(n-3)) = 81 +12(n -3)

d = 12n +45

Complex solutionsThe equation will have only complex solutions when the discriminant is negative:

d < 0

12n +45 < 0 . . . . . use the value of the discriminant

n +45/12 < 0 . . . . . divide by 12

** n < -15/4** . . . . . . . subtract 15/4

**There will be two complex solutions when n < -15/4**.

What point in the feasible region maximizes the objective function?

x>0

Y≥0

Constraints

-x+3≥y

{ y ≤ ½ x + 1

objective function: C = 5x - 4y

**Answer:**

(3, 0)

Maximum Value of Objective Function = 15

**Step-by-step explanation:**

This is a problem related to Linear Programming(LP)

In linear programming, the objective is to maximize or minimize an **objective function** subject to a set of **constraints.**

For example, you may wish to maximize your profits from a mix of production of two or more products subject to resource constraints.

Or, you may wish to minimize cost of production of those products subject to resource constraints..

The given LP problem can be stated in standard form as

Max 5x - 4y

s.t.

-x + 3 ≥ y

y ≤ 0.5x + 1

x ≥ 0, y ≥ 0

The last two constraints always apply to LP problems which means the **decision variables** x and y cannot be negative

It is standard to express these constraints with the decision variables on the LHS and the constant on the RHS

Rewriting the above LP problem using standard notation,

Let's rewrite the constraints using the standard form:

- x + 3 ≥ y

→ -x - y ≥ -3

→ x + y ≤ 3 [1]

y ≤ 0.5x + 1

→ -0.5x + y ≤ 1 [2]

The LP problem becomes

Max 5x - 4y

s. t.

x + y ≤ 3 [1]

-0.5x + y ≤ 1 [2]

x ≥ 0 [3]

y ≥0 [4]

With an LP problem of more than 2 variables, we can use a process known as the Simplex Method to solve the problem

In the case of 2 variables, it is possible to solve analytically or graphically. The graphical process is more understandable so I will use the graphical method to arrive at the solution

The feasible region is the region that satisfies all four constraints shown.

The graph with the four constraint line equations is attached. The feasible region is the dark shaded area ABCD

The feasible region has 4 corner points(A, B,C, D) whose coordinates can be computed by converting each of the inequalities to equalities and solving for each pair of equations.

It can be proved mathematically that the maximum of the objective function occurs at one of the corner points.

Looking at [1] and [2] we get the equalities

x + y = 3 [3]

-0.5x + y = 1 [4]

Solving this pair of equations gives x = 4/3 and y = 5/3 or (4/3, 5/3)

Solving y = 0 and x + y = 3 gives point x = 3, y =0 (3,0)

The other points are solved similarly, I will leave it up to you to solve them

The four corner points are

A(0,0)

B(0,1)

C(4/3, 5/3)

D(3,0)

The objective function is 5x - 4y

To find the values of x and y that maximize the objective function,

plug in each of the x, y values of the corner points

Ignoring A(0,0)

we get the values of the objective function at the corner points as

For B(0,1) => 5(0) - 4(1) = -4

For C(4/3, 5/3) => 5(4/3) - 4(5/3) = 20/3 - 20/3 = 0

For D(3, 0) => 5(3) - 4(0) = 15

So the values of x and y which maximize the objective function are x = 3 and y = 0 or point D(3,0)

7Lines a and bare parallel cut by transversal line t solve for the value of x25x + 4a3x + 14

These angles measure the same they are interior alternate angles.

3x + 14 = 5x + 4

Solve for x

3x - 5x = 4 - 14

Simplify like terms

-2x = -10

x = -10/-2

Result

** x = 5 **

4. Sean bought 1.8 pounds of gummy bears and 0.6 pounds of jelly beans and paid $10.26. He went back to the store the following week and bought 1.2 pounds of gummy bears and 1.5 pounds of jelly beans and paid $15.09. What is the price per pound of each type of candy?Directions: For each problem - define your variables, set up a system of equations, and solve.

Let

the price of gummy bears per pound = x

the price of jelly beans per pound = y

[tex]\begin{gathered} 1.8x+0.6y=10.26 \\ 1.2x+1.5y=15.09 \\ 1.2x=15.09-1.5y \\ x=12.575-1.25y \\ \\ 1.8(12.575-1.25y)+0.6y=10.26 \\ 22.635-2.25y+0.6y=10.26 \\ -1.65y=10.26-22.635 \\ -1.65y=-12.375 \\ y=\frac{-12.375}{-1.65} \\ y=7.5 \\ \\ 1.8x+0.6y=10.26 \\ 1.8x+0.6(7.5)=10.26 \\ 1.8x+4.5=10.26 \\ 1.8x=10.26-4.5 \\ 1.8x=5.76 \\ x=\frac{5.76}{1.8} \\ x=3.2 \end{gathered}[/tex]**price per pound of gummy bear = $3.2**

**price per pound of jelly beans = $7.5**

Andre was trying to write 7^4/7^-3 with a single exponent and write 7^4/7^-3= 7^4-3=7^1 Exploit to Andre what his mistake was and what the answer should be...PLEASE THE ANSWER IS URGENT!!

[tex]\frac{7^4}{7^{-3}}=7^7[/tex]

Here, we want to get what Andre's mistake was and correct it

To answer this, we are supposed to use the division law of indices

We have this as;

[tex]\frac{a^x}{a^y\text{ }}=a^{x-y}[/tex]Now, in the case of this question, x is 4 and y is -3

So, we have the expression as;

[tex]7^{4-(-3)}=7^{4+3}=7^7[/tex]His mistake is thus adding the exponents instead of subtracting

the number 0.3333... repeats forever; therefore, its irrational

The **statement** is** false**, the number can be rewritten as:

0.33... = 3/9

So it is a **rational number**, not irrational

Here we have the **statement**:

"the number 0.3333... repeats forever; therefore, its irrational"

This is **false**, and let's prove that.

our number is:

0.33...

Such that the "3" keeps repeating infinitely.

If we multiply our number by 10, we get:

10*0.33... = 3.33...

If we subtract the original number we get:

10*0.33... - 0.33... = 3

9*0.33... = 3

Solving that for our number we get:

0.33... = 3/9

So that number can be written as a **quotient **between two integers, which means that it is **a rational number.**

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What needs to occur for a geometric series to converge?

Given a Geometric Series:

[tex]\sum_{n\mathop{=}1}^{\infty}a\cdot r^{n-1}[/tex]Where "r" is the ratio.

By definition:

[tex]undefined[/tex]For people over 50 years old, the level of glucose in the blood (following a 12 hour fast) is approximately normally distributed with mean 85 mg/dl and standard deviation 25 mg/dl ("Diagnostic Tests with Nursing Applications", S. Loeb). A test result of less than 40 mg/dl is an indication of severe excess insulin, and medication is usually prescribed.

What is the probability that a randomly-selected person will find an indication of severe excess insulin?

Suppose that a doctor uses the average of two tests taken a week apart (assume the readings are independent). What is the probabiltiy that the person will find an indication of severe excess insulin?

Repeat for 3 tests taken a week apart:

Repeat for 5 tests taken a week apart:

Using the** normal distribution** and the central limit theorem, it is found that:

The **z-score** of a measure X of a normally distributed variable that has **mean **represented by [tex]\mu[/tex] and **standard deviation** represented by [tex]\sigma[/tex] is given by the following rule:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-scoreThe **mean **and the **standard deviation** of the glucose levels are given, respectively, by:

[tex]\mu = 85, \sigma = 25[/tex]

The **probability **of a reading of less than 40 mg/dl(severe excess insulin) is the p-value of Z when X = 40, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (40 - 85)/25

Z = -1.8.

Z = -1.8 has a p-value of 0.0359.

For the mean of two tests, the** standard error** is:

s = 25/sqrt(2) = 17.68.

Hence, by the Central Limit Theorem:

[tex]Z = \frac{X - \mu}{s}[/tex]

Z = (40 - 85)/17.68

Z = -2.55.

Z = -2.55 has a p-value of 0.0054.

For **3 tests**, we have that:

s = 25/sqrt(3) = 14.43.

Z = (40 - 85)/14.43

Z = -3.12.

Z = -3.12 has a p-value of 0.0009.

For **5 tests**, we have that:

s = 25/sqrt(5) = 11.18.

Z = (40 - 85)/11.18

Z = -4.03

Z = -4.03 has a p-value of 0.

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The sum of the squares of three consecutive odd numbers is 83. Find the numbers.

In order to represent three consecutive odd numbers, we can use the expressions "x", "x+2" and "x+4".

If we add the square of each number, the result is 83, so we can write the following inequality:

[tex]\begin{gathered} x^2+(x+2)^2+(x+4)^2=83\\ \\ x^2+x^2+4x+4+x^2+8x+16=83\\ \\ 3x^2+12x+20=83\\ \\ 3x^2+12-63=0\\ \\ x^2+4x-21=0 \end{gathered}[/tex]Let's solve this quadratic equation using the quadratic formula, with a = 1, b = 4 and c = -21:

[tex]\begin{gathered} x=\frac{-b\pm\sqrt{b^2-4a}c}{2a}\\ \\ x=\frac{-4\pm\sqrt{16+84}}{2}\\ \\ x=\frac{-4\pm10}{2}\\ \\ x_1=\frac{-4+10}{2}=\frac{6}{2}=3\\ \\ x_2=\frac{-4-10}{2}=\frac{-14}{2}=-7 \end{gathered}[/tex]If we assume the numbers are positive, **the numbers are 3, 5 and 7.**

(The other result, with negative numbers, would be -7, -5 and -3).

A parents' evening was planned to start at

15h45. There were 20 consecutive

appointments of 10 minutes each and a

break of 15 minutes during the evening. At

what time was the parents evening due to

finish?

C O 19h15

O 19h20

O 19h00

O 20h00

O 19h30

The **time** on which **parents** **evening **was due to finish was 19 hour 20 **minutes.**

**Time **is the ongoing pattern of existence and things that happen in what seems to be an irreversible order from the past, through the present, and into the future.

It is a component quantity of various measurements used to order events, compare the length of events or the **time **gaps between them, and quantify rates of change of quantities in objective reality or in conscious experience. Along with the three spatial dimensions, **time **is frequently considered a fourth dimension.

The International System of **Units **is built upon the seven base **units **of measurement stipulated by the Système International d'Unités (SI), from which all other SI **units **are derived. The primary **unit **of **time **is the second. The second can be shortened using either the letter S or the letter sec.

20 consecutive appointments of 10 mins = 20 × 10 mins

= 200 min

= 3 hours 20 mins

A break of 15 mins = 3 hours 20 mins + 15 min

= 3 hours 35 mins

The **time **that the parents evening due to finish = 15h 45 min +3h 35 mins

= 19h 20min

Thus, the **time **on which parents evening was due to finish was 19h 20min.

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HELP ME PLEASE !!!

REASONING An absolute value function is positive over its entire domain. How many x-intercepts does the graph of the function have?

● None

01

02

O Infinite

The **absolute value** function can intersect a horizontal **x-axis** at zero, one, as well as two points.

Thus, depending on the way the graph has indeed been shifted and reflected, it could or might not intersect the horizontal axis.

The absolute value function can intersect the** x-axis** at zero, one, or two points.

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20 >= 4/5 w

Solve the inequality. Grab the solution

Solve the inequality. Grab the solution

-8<-1/4m

In **inequality **20 >= 4/5 w, w is 25 or any real no. lower than< 25 and in **inequality **-8<-1/4m, m = any real no. greater than> 24 is are the **solution**.

An **inequality **compares two values and indicates whether one is lower, higher, or simply not equal to the other.

A B declares that a B is not equal.

When a and b are equal, an is less than b.

If a > b, then an is bigger than b.

(those two are called strict **inequality**)

The phrase "a b" denotes that an is less than or equal to b.

The phrase "a > b" denotes that an is greater than or equal to b.

We have give the **inequality **to solve

20 = 4/5w

w = 20 × 5/4

= 25 or any real no. lower than< 25

Let -8 = -1/4m

m = -8 × -4

m = 24

so m = any real no. greater than> 24

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Find all the values of x where the tangent line is horizontal.3f(x) = x³ - 4x² - 7x + 12X=(Use a comma to separate answers as needed. Type an exact answer, using radicals

Given the function:

[tex]h(x)=x^3-4x^2-7x+12[/tex]Find the first derivative:

[tex]h^{\prime}(x)=3x^2-8x-7[/tex]The first derivative gives us the slope of the tangent line to the graph of the function. When the tangent line is horizontal, the slope is 0, thus:

[tex]3x^2-8x-7=0[/tex]This is a quadratic equation with coefficients a = 3, b = -8, c = -7.

To calculate the solutions to the equation, we use the quadratic solver formula:

[tex]$$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$ [/tex]Substituting:

[tex]x=\frac{-(-8)\pm\sqrt{(-8)^2-4(3)(-7)}}{2(3)}[/tex]Operate:

[tex]\begin{gathered} x=\frac{8\pm\sqrt{64+84}}{6} \\ \\ x=\frac{8\pm\sqrt{148}}{6} \end{gathered}[/tex]Since:

[tex]148=2^2\cdot37[/tex]We have:

[tex]\begin{gathered} x=\frac{8\pm2\sqrt{37}}{6} \\ \\ \text{ Simplifying by 2:} \\ \\ x=\frac{4\pm\sqrt{37}}{3} \end{gathered}[/tex]There are two solutions:

[tex]\begin{gathered} x_1=\frac{4+\sqrt{37}}{3} \\ \\ x_2=\frac{4-\sqrt{37}}{3} \end{gathered}[/tex]A student rolled 2 dice. What is the probability that the first die landed

on a number less than 3 and the second die landed on a number

greater than 3?

So what’s the probability you ask?

So the first dice can get either 1 or 2 and the second dice can have 4 5 or 6

So we need any one of these outcomes

(1,4) (1,5) (1,6) (2,5) (2,6) (2,4)

Clearly total no of outcomes is 36 (6x6)

Thus probability= 6/36 = 1/6

So the first dice can get either 1 or 2 and the second dice can have 4 5 or 6

So we need any one of these outcomes

(1,4) (1,5) (1,6) (2,5) (2,6) (2,4)

Clearly total no of outcomes is 36 (6x6)

Thus probability= 6/36 = 1/6

what is the area of a circular pool with a diameter of 36 ft?

**Answer:**

**1,017.36ft^2**

**Explanation:**

Area of the circular pool = \pi r^2

r is the radius of the pool

Given

r = d/2

r = 36/2

r = 18ft

Area of the circular pool = 3.14(18)^2

Area of the circular pool = 3.14 * 324

Area of the circular pool = 1,017.36ft^2

Use the rules of significant figures to answer the following question:43.5694 * 22.07A. 961.58B. 961C. 961.577D. 961.7

we have that

43.5694 * 22.07=961.576658

therefore

the answer is

961.577 -----> 6 figures

(remember that 43.5694 has 6 figures)

option C

Which of the following expressions is equal to -x2 -36

OA. (-x+6)(x-6i)

OB. (x+6)(x-6i)

OC. (-x-6)(x-6i)

OD. (-x-6)(x+6i)

The **expression equivalent** to -x² - 36 is the one in option C.

(-x - 6i)*(x - 6i)

Which of the following expressions is equal to -x² - 36?We can rewrite the given **expression **as:

-x² - 36 = -x² - 6²

And remember that the product of a** complex numbe**r z = (a + bi) and its **conjugate **(a - bi) is:

(a + bi)*(a - bi) = a² + b²

Then in this case we can rewrite:

-x² - 6² = -(x² + 6²) = - (x + 6i)*(x - 6i)

= (-x - 6i)*(x - 6i)

The correct option is C.

Learn more about **complex numbers **at:

https://brainly.com/question/10662770

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Simplify completely.a.4x212 xwhen x +0.b. (2t)(3t)(t)c. (3x² - 4x +8)+(x² +6x-11)d. (3x² + 4x – 8) - (x² + 6x +11)

The expression in 4a) is given below

[tex]\frac{4x^2}{12x}[/tex]Collecting similar terms using the division rule of indices, we will have

[tex]\frac{a^m}{a^n}=a^{m-n}[/tex]The above expression therefore becomes

[tex]\begin{gathered} \frac{4x^2}{12x} \\ =\frac{4x^2}{12x^1} \\ =\frac{1}{3}\times x^{2-1} \\ =\frac{1}{3}\times x \\ =\frac{x}{3} \end{gathered}[/tex]**Hence,**

**The final answer = ****x/3**

Solve-2x-16=2x-20.

Ox=1

O no solutions

○ * = −1

all real numbers

x = 1

First, move the terms.

-2x - 2x = -2 + 20

Collect like terms

-4x = -20 + 16 —> -4x = -4

Divide both sides

x = 1

First, move the terms.

-2x - 2x = -2 + 20

Collect like terms

-4x = -20 + 16 —> -4x = -4

Divide both sides

x = 1

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