The two experiments that **Coulomb's** to show the relationship between electrostatic force and that law carries Coulomb's name today to include this relationship as a fundamental component.

**T****orsion balance**** **is used to study the repulsion and attraction forces of charged particles and found that the strength of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

A bar is suspended from the centre of the torsion balance by a thin fibre. The fibre functions as a flimsy torsion spring.

The torsion balance in **Coulomb's experiment** was a suspended metal-coated ball attached to one end of an insulating rod.

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9. A driver, driving a Bugatti Veyron, accelerates at 26.7 m/s² for 2.4 seconds. What change in

velocity did the driver experience?

The **change in** **velocity **experience by a driver, driving a Bugatti Veyron, accelerating at 26.7 m/s² for 2.4 seconds is** 64.08 m/s.**

**Change in velocity **is the difference between the final and the initial velocity of a body.

To calculate the **change **in velocity experienced by the driver, we use the formula below.

Formula:

Δv = at........... Equation 1Where:

Δv =From the question,

Given:

a = 26.7 m/s²t = 2.4 secondsSubstitute these values above into equation 1

Δv = 26.7×2.4Δv =Hence, the **change **in **velocity **experienced by the driver is** 64.08 m/s.**

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two ice skaters stand facing each other at rest on a frozen pond. they push off against one another and the 61 kg skater acquires a speed of 0.75 m/s. if the other skater acquires a speed of 0.89 m/s, what is her mass in kilograms?

The **mass **of the other skater who is pushed is 51.4 kilograms.

According to the** law of conservation of momentum,**

The total linear momentum is always conserved in a system if no external force is applied.

So. we can write,

**Initial momentum **=** final momentum**

Initial momentum is zero as both the skater are at rest.

So, Final momentum should be 0,

Final momentum = 0

M₁V₁ + M₂V₂ = 0

M₁ is the mass of first skater,

V₁ is the final speed of the first skater,

M₂ is the mass of the second skater,

V₂ is the final speed of the second skater, V₂ will taken as negative because the second skater is pushed into opposite direction,

Putting all the values,

61(0.75) = -M₂(-0.89)

M₂ = 51.4 Kg.

So, the **mass **of the skater is 51.4 kg.

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each of the following situations involves the flow of heat energy. for each scenario, specify the primary mode (conduction, convection, or radiation) by which the energy is transferred.

For each of these scenarios, the primary method by which heat energy is transferred is:

A) **Radiation ** B) **Conduction**

C) **Convection** D) Radiation

E) Conduction F) Convection

G) Radiation H) Convection

What are conduction, convection and radiation?

Conduction, convection and radiation are all methods of heat transfer. Conduction is the transfer of heat between two solid objects in contact. Convection is the transfer of heat by convection currents in fluids (liquids or gases). Liquids and gases on their own don't conduct heat, but when molecules of a fluid are heated up, they move within the medium and carry the heat energy with them. This phenomenon is called convection currents. Radiation is the transfer of heat in a vacuum. Unlike convection and conduction, radiation does not need a material medium for heat to be transferred, as heat is transferred through electromagnetic waves.

For each situation in the question, heat is transferred in one way or another. The methods are:

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Complete question:

Each of the following situations involves the flow of heat energy. For each scenario, specify the primary mode (conduction, convection, or radiation) by which the energy is transferred. a)What is the primary mode of energy transfer from hot coffee inside a Thermos bottle to the environment? b)What is the primary mode of energy transfer from your bare feet to a cold ceramic bathroom floor in the middle of winter? c)What is the primary mode of energy transfer from your body to your hands when you blow on them to warm them? d)What is the primary mode of energy transfer into your sealed car parked in the sun on a hot summer day? e)What is the primary mode of the flow of energy from your tongue to a metal railing if you happen to lick it on a cold winter day? f)what is the primary mode of energy transfer from a hair dryer to your wet hair? g)What is the primary mode of energy transfer from your body on a cold day with no wind? h)What is the primary mode of energy transfer away from your body on a very windy day?

A body weighs (i) 900N on the surface of earth how much will it weigh on the surface of

Mars whose mass is one ninth and radius is one half that of the earth take g on the surface

of earth to be 10 m/s2

The **weight **of the body on the surface of** mars** would be **333.9 Newtons**.

Weight is the force exerted by the **earth **on an object at the** surface** of the earth and this force is directed towards the** center** of the earth. Mathematically -

**W = mg**

where -

**[m] **is the mass of object

**[g]** is acceleration due to gravity

Given is a body that weighs **900N** on the surface of earth. Mars is a planet whose mass is **one ninth** and radius is **one half **that of the earth. The same body is now placed on mars.

Since the weight of the body is **900 N** on earth, we can write -

**W = mg**

900 = m x 10

m = 900/10

m = 90 Kg

Now, we know for a body of** mass [m] **on a planet of **mass [M]**, the **gravitational force** exerted by planet on the body will be -

**F = GMm/r²**

but

F = W = mg

So, we can write -

mg = GMm/r²

**g = GM/r²**

For the planet of **mars**, we can write -

g = GM[mars]/r[mars]²

g = (6.6743 × 10⁻¹¹ x 0.65 x 10²⁴)/(3185.5 x 10³)

**g = 3.71 m/s²**

So, the weight of the body on mars will be -

W = mg = 90 x 3.71

**W = 333.9 N**

Therefore, the **weight **of the body on the surface of** mars** would be **333.9 Newtons**.

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suppose that the resistance between the walls of a biological cell is 1.00 109 ω. (a) what is the current when the potential difference between the walls is 45 mv?

The **current** when the **potential** **difference** between the walls is 45 mv is 4.500×10⁻¹¹ A.

To find the current when the potential difference between the walls is 45 mv, we will Use **Ohm's** **law**.

V = IR ........................ Eqn 1

Where

V = Potential difference between the walls

I = current

R = Resistance between the walls

Make I the subject of the equation

I = V/R...................... Eqn 2

From the question, we are given that:

V = 45 mV = 0.045 V

R = 1.0×10⁹ Ω.

Substitute into Eqn 2

I = 0.045/(1.0×10⁹)

I = 4.500×10⁻¹¹ A.

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A charge of 15C has flowed past a point in the circuit with a current of 2A. How long has this charge been flowing through this circuit?

Round the answer to 2 decimal places.

The charge of 15 Chas been flowing through a circuit with current of 2 A for a **time period** of 7.5 s

**Q = I t**

Q = Electric charge

I = Electric Current

t = Time

Q = 15 C

I = 2 A

t = Q / I

t = 15 / 2

t = 7.5 s

**Electric current** is the rate of flow of charge. In a circuit the current always flows from the negative terminal to the positive terminal. Its unit is Ampere ( A ) which is C / s.

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a conductor consists of an infinite number of adjacent wires, each infinitely long and carrying a current i (whose direction is out-ofthe-page), thus forming a conducting plane.

The important Physics chapter "**Conductors **and Dielectrics in an Electric Field" focuses on the electric field and its interactions with different kinds of materials, such as conductors and dielectrics.

The significance of its components in the electrical circuit is explained in **Conductors **and **Dielectrics **in an Electric Field. is a crucial resource component that all students require in order to succeed in the Class 12 Physics exams and admission exams. It is one of the greatest ways to prepare for physics exams and practice problems in order to get good marks. Here, the questions are primarily centered on electric field, current, speed, voltage, and other related concepts.

In-depth explanations are provided for the behavior of **conductors **and **dielectrics**. The issues help to strengthen the applicability of the theoretical ideas in daily life and activities.

For clear knowledge and a firm grasp of the syllabus and concept, students aiming for a good mark in a competitive examination must solve every issue provided.

Based on each and every formula, equation, and procedure, there are a variety of difficulties that can be accessed. Each problem's solution is broken down into logical steps and supported with relevant data, formulas, graphs, and equations. All questions based on conductors and dielectrics are readily available to students. This aids in conceptual clarity and full knowledge for kids.

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A trebuchet is a compound machine. What individual simple machines is it composed of ￼?

It uses one main simple machine,** the lever**, to propel a projectile, making it both a **compound machine **(a device that employs a number of simple machines) and a** simple machine.**

A** trebuchet** is a form of catapult, a **weapon** that can launch things considerably farther than a person can. The usage of trebuchets is first recorded in **second-century China**, however catapults were in use far before the **Roman Empire.** Trebuchets are most known for their use in medieval castle raids because they could be placed so far away from the fortress that archers couldn't touch them and could launch practically anything.

which particular simple machinery

They are the most basic** techniques** that are now understood for using leverage (or mechanical advantage) to increase force. The wheel and **axle**, **inclined plane**, **lever**, **wedge**, **pulley**, and **screw **are examples of **rudimentary machines.**

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imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? view available hint(s)for part a imagine another solar system, with a star of the same mass as the sun. suppose a planet with a mass twice that of earth (2mearth) orbits at a distance of 1 au from the star. what is the orbital period of this planet? 2 years it cannot be determined from the information given. 6 months 1 year

1year is the **orbital period** of this planet.

The **orbital period** is the quantity of time a given astronomical object takes to complete one orbit around every other object. In astronomy, it generally applies to planets or asteroids orbiting the solar, moons orbiting planets, exoplanets orbiting different stars, or binary stars.

**Kepler's third law** - indicates the relationship among the length of an items orbit and the common distance that it's far from the issue it orbits. this could be used for something clearly orbiting round another factor.

Entire **revolution **is known as the orbital duration. At 200 km that is approximately ninety minutes. The orbital duration will increase with altitude for two motives. First, as the altitude increases, Earth's gravity decreases, so the orbital speed had to stability it decreases.

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A medium-sized jet has a 3. 8-m-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to the cylindrical fuselage, and aerodynamic shaping gives it a drag coefficient of 0. 37.

To travel at 230 m/s at an altitude where the** air density **is 1.0 kg/m3, the jet's engines must deliver** 111kN** of thrust.

**Air Density** is defined as the mass of an object, including air, divided by its volume.

Scientists measure density in terms of kilogrammes per cubic metre when using the metric system.

The density of the air is influenced by its **temperature**, pressure, and water vapour content. We'll discuss dry air initially, so just **temperature **and pressure will be a concern.

In addition to a fundamental explanation of air density, we will go into how humans are affected by decreased air density, such as that experienced at high altitudes, how humidity influences air density in unexpected ways, and how air density affects things like aircraft, baseballs, and even racing automobiles.

The density of the air in a free environment drops as **temperature **increases.

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HELP ILL GIVE BRAINLYIST Compare the interaction between light and two different materials: a reflective glass mirror and a transparent glass block. How did the light behave differently

**Answer: See Below**

**Explanation:**

A reflective glass mirror will reflect all the components of white light and not allow visible light to pass through.

A transparent glass block will allow light to pass through with some refraction.

NEED HELP URGENTLY FOR 10 POINTS

**Answer:**

Option 2

**Explanation:**

This is the definition of the plum-pudding model.

A BALL Is released from a hight of 20m calculate the time it taken to fall. The velocity with it hits the ground

A **ball** is released from a certain **height** of 20m then the time taken by the ball to **fall** is 2 sec and the **velocity** is 20m/s

Here: s (**height**) = h =20

a=g=±10m/s

a=10m/s (since it is **dropped**)

[tex]v^{2} -u^{2} =2as\\v^{2} =2*10*10\\v^{2}= 200[/tex]

(u=0; it is dropped not thrown)

v=20m/s

for calculating **time** we know,

v=u+at

20= 0+ 10xt

t=20/10

t=2seconds

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PLEASE HELP!!! WILL MARK BRAINLIEST

The environmental impact of the changes in the amount of **energy resources** is reduction in **air pollution.**

**Energy resources** are the materials that can act as sources of energy which is grouped into two namely:

From the given figures,

In 2014 renewable energy = 19%; while in 2015 it is = 25%

In 2014 non renewable energy when added = 79%; while in 2015 it is = 73%

This shows that there was reduction in the use of non renewable energy from 2014 to 2015 by 6%.

This would affect the environment positively as there would be **reduction** in **air pollution** caused by non renewable energy resources.

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a ball of mass m collides completely inelastically in one dimension with another ball of mass 3m that is initially at rest (the balls stick together after the collision). what fraction of the initial kinetic energy is lost in the collision

Fraction of the initial** kinetic energy** is lost in the collision f = 3/4.

Two balls of masses M and 3M **kinetic energy**

Initially before collision:

Speed of ball of **mass** M = −V0 (Right direction is taken as negative)

Speed of ball of** mass** 3M = +V0

Finally after collision: Speed of ball of mass M = v

Speed of ball of mass 3M = V02

[tex]Finding the fraction(f) of initial kinetic energy lost in the collisionf=1−Final Kinetic EnergyInitial Kinetic Energyf=1−12×M×(v02)2+12×3M×(v02)212×M×(−v0)2+12×3M×(v0)2f=1−v024v02f=1−14=34[/tex]

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what's the answer to this question?

**Answer:**

**Energy**

**Explanation:**

Some of the suns **energy **is converted into wind and water waves

you are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. you instantly start running toward the still-open door at 5.7 m/s.

a) It **takes** you 1.893s to **reach** the opened **door** and jump in.

b) The **maximum** time that you can wait before starting to **run** and still catch the **bus** is 1.27s

The time which the passenger can delay and still catch the bus must be less than this.

From the question:

**Distance** between the passenger and the door of the bus d = 9

Acceleration of the bus a¹ = 1.0m/s²

**Speed** of the passenger v = 5.7m/s

Time taken for you to catch up with the bus must occur at the exact position with the bus,

Let the position = y

The time taken for you to reach the point:

t = total speed/distance

t = y + 9/5.7 ..................... eqn 1

The time taken for the bus to reach the same point;

y = vt + 1/2at²

Initial velocity of the bus is zero

y = 0.5*(1)t²

y = t²/2

t = √2y .......................eqn 2

We solve eqn (1) and (2) together:

9 + y = 5.7 * √2y

81 + y² + 18y = 64.98y

y² - 46.98y + 81 = 0

y = 45.187m or 1.792m

Now we take the smallest distance: x=1.792 m

Time taken for both to reach this point: (put x in eq. (1))

t = 1.792+9/5.7

t = 1.893s

For the maximum waiting time we find have:

Relative acceleration, ar = -1m/s⁻²since the bus is moving away from the intended

The final relative velocity for the passenger to catch it, vr = 0m/s⁻¹

Using equation of motion:

s = 9 + 1/2 * (-1)t²

also the initial relative velocity:

vr = ur + ar.t

ur = 5.7 - t

and

vr² = ur² + 2ar.s

0² = (5.7 - 1)² - 2 * 1 * (9 - 0.5t²)

t = 1.27s

Here's the **complete** question:

You are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. You instantly start running toward the still-open door at 5.7 m/s.

How long does it take for you to reach the open door and jump in?

What is the maximum time you can wait before starting to run and still catch the bus?

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you need to determine the density of a ceramic statue. if you suspended from a spring scale, the scale reads 28.4 n. if you than lower the statue into a tab of water, so that it is completely submerged, the scale reads 17.0 n. what is the statue density?

The density of the ceramic statue is **"2495.5 kg/m³".**

This question involves the concepts of **density, weight, volume, and buoyant force.**

First, we will find out the **mass of the statue:**

W=mg

m=W/g

where,

W = hanging weight of statue = 28.4 N

g = acceleration due to gravity = 9.81 m/s²

Therefore,

28.4/9.81**m= 2.9kg**

Now, we will find out the **volume of the statue.**

The difference, in weight of the statue upon submerging, must be equal to the buoyant force applied by the water. This **buoyant force** is equal to the weight of the volume of water displaced, which is equal to the volume of the statue.**V = 1.16 x 10⁻³ m³**

Density= 2.9/1.16 x 10^-3

=**2495.5kg/m^3**

Therefore, the stature density is **2495.5 kg/m^3. **

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a dc 2-wire system is to be converted into ac 3-phase, 3-wire system by the addition of a third conductor of the same cross-section as the two existing conductors. calculate the percentage additional load which can now be supplied if the voltage between wires and the percentage loss in the line remain unchanged. assume a balanced load of unity power factor.

The **percentage **of additional power transmitted is 73.2%.

A **conductor **is an object or form of fabric that permits the flow of fee in a single or extra instruction. Materials **manufactured **from steel are not unusual **electrical **conductors.

A **conductor**, or electrical conductor, is a substance or fabric that allows energy to drift through it. In a conductor, electric rate carriers, typically electrons or ions, pass without problems from an atom to an atom when **voltage **is carried out.

IN DC 2-WIRE SYSTEM

If R is the resistance oper conductor,then the power transmitted is

P=VI

And power loss is = I²R

IN AC 3-PHASE 3 WIRE SYSTEM

P=√3VIcos φ

=√3VI [as unity power factor,cos φ=1]

power loss= 3I²R

The **percentage **of additional power transmitted in a phase 3 wire ststem is

(√3VI-VI )/ VI *100 =73.2%

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A pack of dogs are pulling a wooden sled and rider of combined mass

of 238 kg across dry snow. How much force do the dogs need to apply

to cause the sled to begin to move?

**Answer:**

FN=-Fg -> Fg=mg -> Fg = 238 kg*9.8 m/s^2 ->

Fg = -2432.4 so FN = 2432.4 -> FF = μs*FN ->

FF = 0.22*2332.4 N -> FF = 513.128 ->

Fapplied > 513.128 N

**Explanation:**

...

when the spectrum of light from a star is redshifted, the star must be when the spectrum of light from a star is redshifted, the star must be moving away from you moving toward you cooling off ready to explode

The distance traveled will therefore simply be equal to the original **velocity **multiplied by the time period. The result of adding these two numbers together is about 2.41, or 4 times 10 to the ninth meters.

Some star material, with an initial **velocity **of roughly 40,232,600 m/s, is accelerated outward in specific shock waves that are created by a star dying. Let's record that as beginning velocity, which is 40 million 233,600 meters per second. And we inquired as to how far it travels in a minute. Since we are in space, there are essentially no **accelerations **to take into account. Therefore, we don't need to think about any form of slowing down or speeding up of this velocity.

The distance traveled will simply be equal to the original **velocity **multiplied by the time interval because this is how long it has been moving. And when we combine those two figures, we get a result of around 2.41, or 4 times 10 to the ninth meters.

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2. Your household electricity system is labeled as 127V/30A. If each electricheater consumes 1600W. How many such heaters can be running at the sametime safely?

We can calculated the maximum power as follows:

[tex]\begin{gathered} P_{Max}=VI \\ so: \\ P_{Max}=(127)(30) \\ P_{Max}=3810W \end{gathered}[/tex]Since the heater consumes 1600W, we can write the following inequality:

[tex]n1600<3810[/tex]Where n is the number of heaters, so:

[tex]\begin{gathered} n<\frac{3810}{1600} \\ n<2.38 \\ so: \\ n\approx2 \end{gathered}[/tex]**Answer:**

**2 heaters**

a human expedition lands on an exoplanet. one of the explorers is able to jump a maximum distance of 18.0 m with an initial speed of 2.60 m/s. find the gravitational acceleration on the surface of the exoplanet. assume the planet has a negligible atmosphere. (enter the magnitude in m/s2.)

The **gravitational acceleration** on the surface of the exoplanet is **0.188 m/s²**.

**Gravitational acceleration** has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration (**gravitational acceleration**), t is time and s is displacement.

From the question above, we know that

h = 18 m

vo = 2.6 m/s

In this case, the final velocity should be zero. Hence,

vt² = vo² + 2a . s

vt² = vo² - 2g . h

0² = 2.6² - 2.g . 18

36g = 6.76

g = 0.188 m/s²

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If a man pulls a box with a force of 90 N at an angle of 45

degrees, then what are the X and Y components of the force?

**Answer:**

See below

**Explanation:**

x component = 90 cos 45 = 63.6 N

y component = 90 sin 45 = 63.6 N

a plane is flying horizontally with speed 198 m/s at a height of 3210 m above the ground, when the package is dropped from a plane. The acceleration of gravity is 9.8 m/s^2.

a second package is thrown downward from the plane with a vertical speed v1=78m/s. what is the magnitude of the total velocity of the package at the moment it is thrown as seen by an observer on the ground? answer in units of m/s.

The magnitude of the total **velocity** of the package at the moment it is thrown as seen by an observer on the ground is D = 193m/s 15.2s = 2934 m.

What is **velocity ?**

**velocity ** is the prime indicator of the position as well as the rapidity of the object

Sol-

1. 0.5gt^2 = 2010 m.

4.9t^2 = 2010.

t = 20.3 s. = Fall time.

D = Xot. = 193m/s 20.3s = 3909 m.

2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.

3. Vot + 0.5gt^2 = 2010 m.

58t + 4.9t^2 = 2010.

4.9t^2 + 58t - 2010 = 0.

Use the **quadratic ** formula we are get

t = 15.2 s. = Fall time

D = 193m/s 15.2s = 2934 m.

D = 193m/s 15.2s = 2934 m.

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Write a properly formatted hypothesis statement to answer this question: how does the amount of dissolved salt affect the boiling point of water? specify how you plan to change the independent variable by using terms such as increase or decrease. also, specify how the dependent variable will change in response by using terms such as increase, decrease, or stays the same.

The theory is that:

**H0**: The amount of **salt** added to ice has no bearing on how quickly it melts.

**H1**: The amount of salt added to ice will have an impact on how quickly it melts.

By altering the rate at which salt is introduced to the equation, the independent variable can be modified.

The ice, which is the dependent variable, will alter or melt in response because it will get smaller as the rate at which salt is injected rises.

The **boiling point **of water, or the temperature at which it may erupt, rises when salt is added to it. For every 58 grams of dissolved salt per kilogram of water, the temperature required to reach boiling rises by around 0.5 C. This is an illustration of an elevated boiling point, which is not just a property of water.

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at the instant a ball is thrown horizontally with 100m/s, an identical ball is dropped from the same height. which ball hits the ground first? (ignore air resistance) * 1 point a)the horizontally thrown ball b)the dropped ball c)neither - they both hit the ground at the same time d)the horizontally thrown ball never reaches the ground. it keeps circling earth.

option c When a ball is thrown horizontally at 100 m/s, a second ball is dropped from the same height at the exact same moment neither they both hit the ground at the same time .Here **gravitational force **plays role.

**Gravitational force **tells if** **Any two bodies' mutual attraction is directly proportional to the sum of their masses and inversely proportional to the square of their separation. As a "thought experiment," Newton proposed the Newton's cannonball, which supports the idea that gravity is a powerful force that affects planetary motion.

He assumed a cannon on top of a very tall mountain peak in this thinking experiment. If the cannon is loaded with gunpowder and fired, the following situations might occur.

If the cannon's **speed **is modest, it will fall to Earth in a projectile motion.

If the **speed **of the cannon is equal to the orbital **speed **at that altitude, the cannonballNo change in gravity affects the speed of light.

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Newton's First Law

A lantern of mass m is suspended by a string that is tied to two other strings, as shown

in the figure below. The free-body diagram shows the forces exerted by the three

strings on the knot.

F₂

Fy

0₂

¥

F₁

1. In terms of F₁, F2, and F3, what is the net force acting on the knot?

(Hint: The lantern is in equilibrium.)

2. Find the magnitudes of the x and y components for each force acting on the knot.

(Assume the positive directions are to the right and up.)

String 1 (F₁)

x component

y component

String 2 (F₂)

x component

y component

String 3 (F3)

x component

y component

3. In terms of F1, F2, and F3, what is the magnitude of the net force acting on the

knot in the x direction? in the y direction?

Fx net=

Fynet

=

. Assume that 8₁ = 30°, ₂ = 60°, and the mass of the lantern is 2.1 kg. Find,

F1, F2 and F3.

F₁=

F₂=

F3 =

**Answer:**

1. If the knot is in equilibrium - no net force acts on the knot.

2. F1x = 0 F1y = -F1

F2x = -F2 cos θ1 F2y = F2 sin θ1

F3x = F3 cos θ2 F3 = sin θ2

3. Fx net = 0

Fy net = 0 for equilibrium to occur

4. F2 cos θ1 = F3 cos θ2

F1 = M g = 2.1 * 9.8 = 20.6 N

F2 sin 30 + F3 sin 60 = 20.6 balancing forces in y-direction

or .5 F2 + .866 F3 = 20.6 (use this equation below ) (I)

F2 cos 30 = F3 cos 60 as stated above

.866 F2 = .5 F3 or F3 = 1.732 F2 substituting for θ

.5 F2 + .866 (1.732 F2) = 20.6 using (I) above

2.0 F2 = 20.6 and

F2 = 10.3 N

F3 = 1.732 * 10.3 = 17.8 N

Check:

10.3 * .866 = .5 * 17.8 using values above

8.92 = 8.9 forces balance

Also .5 * 10.3 + .866 (1.732 * 10.3) = 20.6

a 0.24 kg blob of clay is thrown at a wall with an initial velocity of if the clay comes to a stop in what is the average force experienced by the clay?

The - 60.6 N is the **average force** experienced by the clay.

The force applied by a body moving at a **constant velocity** (rate of speed) over a fixed time period is known as the average force. The magnitude and direction of force are both vector quantities. The term 'average' denotes that this velocity was not precisely measured or was not 'instantaneous.' As a result, the average force over a given time period is equal to the body's mass multiplied by its average velocity. The magnitude and direction of the average force are both vector quantities.

Average acceleration = Δv/t

We know F = ma,

We have m = 0.24

Δv = Final velocity - Initial velocity

Δv = (0 - 23) m/s

Δv = -23 m/s

t = 91 ms or 0.91 s

As we know **acceleration** (a) = v/t

So, a = -23/0.91

a = - 25.27 m/s²

Put the above value in formula F = ma.

F = (0.24 kg) × (-25.27 m/s²)

F = - 60.6 N

Therefore, the average force experienced by the clay is - 60.6 N.

To know more about **average force**,** **visit:**https://brainly.com/question/16344573**

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The complete question is:

"A 0.24 kg blob of clay is thrown at a wall with an initial velocity of 23 m/s. the clay comes to a stop against the wall in 91 ms, what is the average force experienced by the clay"

18. How might the cycling of matter in Earth’s atmosphere be related to to the movement of dust from the Sahara desert to the Amazon?

This is Science

The** cycling of matter** in Earth’s atmosphere is related to the movement of dust from the Sahara desert to the Amazon because the **biosphere **is a major ecosystem that connects all **ecosystems **around the world.

The **ecosystems **are specific geographic regions in which biotic factors (life) and abiotic factors (e.g. dust) interrelate to shape the environmental condition of the area, while the term biosphere makes reference to a major ecosystem that connects all these region in the world.

Therefore, we can conclude that ecosystems are interconnected to shape the **biosphere**, thereby the phenomena that occur in Sahara desert are able to modify the conditions in a Forest like Amazon.

Learn more about **ecosystems and biosphere** here:

https://brainly.com/question/605396

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