The mass of the given** iron sphere** of diameter 0.5 m is **510.9 kg**

**Density** of the iron sphere = 7890 kg/m³

**Diameter** of the iron sphere = 0.5 m

**Radius **of the iron sphere = 0.25m

The formula to find the mass of the iron sphere is

**ρ = m / v**

where ρ is the density

m is the mass

v is the volume.

So , to find the mass , we need to know the volume of the sphere

Volume of the sphere = 4/3 πr³

Let us substitute the value of r in the above equation,

V = 4/3 x 3.14 x (0.25)³

= 4/3 x 3.14 x 0.0156

= 0.196/3

** V = 0.065 m³**

So , now let us find the mass of the given sphere

ρ = m / v

m = ρv

m = 7860 x 0.065

** m = 510.9 kg**

Therefore , the **mass **of the given iron sphere is **510.9 kg**

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4. Betsy wants to use her own weight to lift a 1,500-newton box. She weighs 500 newtons. Suggest input and output arm lengths that would allow Betsy to lift the box with a lever. Draw a lever and label the input and output arms with the lengths and forces.

**Answer:**

**Explanation:**

Given:

F₁ = 500 N

F₂ = 1.500 N

____________

L₁ - ?

L₂ - ?

Moment rule:

M₁ = M₂

F₁*L₁ = F₂*L₂

F₂ / F₁ = 1.500 / 500 = 3

L₁ / L₂ = 3

L₁ = 3*L₂

If L₂ = 0.5 m

then L₁ = 3*0.5 = 1.5 m

Joshua rode his bicycle from his school to home. The total distance covered in this journey was 800 meters and the total time taken was 7 minutes. What is the average speed of joshuas bicycle in this journey

**Answer: 6,857.14m/h (6.86km/h or 1.90m/s)**

**Explanation:**

-%deviation from expected value (show calculations) in relation between frequency and radius.

When an object moves in a circular trajectory with a uniform speed, a centripetal force is needed to keep it in that trajectory. In the experiment, the hanging mass is used to keep the tension of the string constant. The tension is equal to the weight of the hanging mass, and it is responsible for keeping the rubber stopper in a circular trajectory.

The centripetal acceleration of a particle in a circular trajectory with radius **r** and frequency **f** is:

On the other hand, if the mass of the hanging object is M and the mass of the rubber stopper is **m**, according to Newton's Second Law of Motion, the relationship between the tension of the string and the centripetal acceleration is:

If we isolate **f** from that expression, we get a theoretical relationship between the radius and the frequency:

To find the expected value for the frequency for different values of **r**, replace **M=200g**, **m=15.3g**, **g=9.81m/s^2** and the different values of **r**:

On the other hand, we can find the experimental measurements for the frequency depending on the radius using the information provided in the table.

To do so, remember that the frequency is equal to the average number of spins from the three trials over the time.

The experimental values for the frequencies are:

[tex]\begin{gathered} f_{10cm-exp}=\frac{35+34+32}{3\times10s}\approx3.37Hz \\ \\ f_{15cm-exp}=\frac{31+29+27}{3\times10s}\approx2.90Hz \\ \\ f_{20cm-exp}=\frac{27+27+25}{3\times10s}\approx2.63Hz \\ \\ f_{25cm-exp}=\frac{25+23+24}{3\times10s}\approx2.40Hz \\ \\ f_{30cm-exp}=\frac{26+23+20}{3\times10s}\approx2.30Hz \end{gathered}[/tex]To find the percent deviation from the expected value, use the following formula:

[tex]\%dev=\frac{f_{exp}-f}{f}\times100\%[/tex]**Then, the percent deviations from the expected values are:**

The force diagram below is for a 10 kg object. Determine its acceleration.

As the buoyant force balances the weight of the object.

Thus, there is no motion of the object in the vertical direction.

Whereas, the force acting on the object towards the right is more than the drag force.

Thus, the net force acting on the object along the horizontal direction is,

[tex]F_{net}=F_T-F_{drag}[/tex]Substituting the known values,

[tex]\begin{gathered} F_{\text{net}}=35-10 \\ F_{\text{net}}=25N_{} \end{gathered}[/tex]According to Newton's second law, the net force acting on the object in terms of the acceleration of the object is,

[tex]F_{\text{net}}=ma[/tex]where m is the mass, and a is the acceleration,

Substituting the known values,

[tex]\begin{gathered} 25=10\times a \\ a=\frac{25}{10} \\ a=2.5ms^{-2} \end{gathered}[/tex]**Thus, the acceleration of the object is 2.5 meters per second.**

**H**

Gravitation always does negative work. Is this true or false?

The given statement 'Gravitation always does negative work' is false.

The work done by the gravitation depends upon the reference level of the system. Therefore, according to reference level it is taken as positive or negative.

- If we start an experiment with 191.3 g of a substance, how much should we end with?

More than 191.3 g

191.3 g

Less than 191.3g PLEASE NOW

If we **start an experiment** with 191.3 g of a substance, we should be ending with 191.3 g

We know that matter cannot be created out of nothing. So that is why the number of atoms of products must be equal to the number of atoms of reactants. That is why a chemical reaction is written as a balanced reaction equation. This is the law of **conservation of mass**.

During a combustion reaction or during decomposition reaction, the products mass might seem to be **different **than that of reactants either higher or lower. This is due to the involvement of environment. So while considering mass environment should also be included.

Therefore, if we start an experiment with 191.3 g of a substance, we should be ending with **191.3 g**

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Explain why planets orbit the sun instead of traveling off into space

**Answer:**

gravity

**Explanation:**

The gravity of the Sun keeps the planets in their orbits. They stay in their orbits because there is no other force in the Solar System which can stop them.

Two ice skaters stand facing each other at rest on a frozen pond. They push off against one another and the 49 kg skater acquires a speed of 2.10 m/s. If the other skater acquires a speed of 3.81 m/s, what is her mass in kilograms?

The **mass** of the** second skater** is equal to 27 Kg, which acquires a **speed** of 3.81 m/s.

According to the l**aw of conservation of momentum,** the sum of the **momentum** of the two objects before and after the collision must be equal.

m₁ u₁ + m₂u₂ = m₁ v₁ + m₂ v₂

where m₁ and m₂ is the **mass** of the collided bodies, u₁ and u₂ are the initial **speed** while v₁ & v₂ is their final speed.

The** linear momentum **can be described as the product of the mass times the velocity of the object. **Conservation of momentum **is a characteristic held by an object where the total amount of momentum remains the same.

Given the **initial speed **of the skaters is equal to zero so u₁ = u₂ =0

The **mass** of the one skater, m₁ = 49 Kg

The first skater acquires the **speed**, v₁ = 2.10 m/s

The **speed** acquired by the **second skater,** v₂ = -3.81 m/s

From the law of conservation of momentum, we can find the **mass** of another **skater**:

m₁ u₁ + m₂ u₂ = m₁v₁ + m₂ v₂

49 × 0 + m₂ ×0 = 49 × (2.10) + m₂ × (- 3.81)

m₂ = -49 × (2.10)/ (- 3.81)

m₂ = 27 Kg

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The steeper the slope of a current vs voltage graph, the _________ the resistance.A. Not enough infoB. LowerC. The sameD. Greater

The slope of the graph current vs voltage can be explained with the next

[tex]\begin{gathered} V=IR \\ I=\frac{V}{R} \end{gathered}[/tex]In this case, current vs voltage means that current is y axis, and voltage is x axis. Based n that, the equation is the second one

[tex]I=\frac{V}{R}[/tex]And the slope is the **inverse of the resistance.** Dont forget that current - voltage is different to voltage - current

When two coherent waves combine destructively to create a minimum, what is the smallest phase difference possible in Degrees and Radians?

180° or π Radians is the smallest **phase difference **possible When two coherent **waves **combine **destructively **to create a **minimum**

Two waves of the same **wavelength **that are entirely out of **phase **with one another might cancel one another out or interact negatively. When there is a 180 degree or larger radian** phase difference**, this happens. Only when the two **waves **have the same amplitude do they completely cancel out. Partially destructive **superposition **occurs when two waves that are entirely out of phase yet have different **amplitudes**. The intensity is 0.

**Superposition **is the phenomenon in which the combined **displacement **of two combining **waves **is equal to their vector sum.

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Monochromatic light of 605 nm falls on a single slit of width 0.095 mm. The slit is located 85 cm from a screen. How far from the center is the first dark band?540 mm5,400 mm0.5 mm5.4 mm

The wavelength of the monochromatic beam is given as,

[tex]\lambda=605\text{ nm}[/tex]The value of the width of the slit is,

[tex]d=0.095\text{ mm}[/tex]The distance of the slit from the screen is,

[tex]D=85\text{ cm}[/tex]Thus, the distance of the dark band from the center is,

[tex]y=\frac{(2m+1)\lambda D}{d}[/tex]For the first dark band,

m=0,

Substituting all the known values,

The value of the distance of the dark band becomes,

[tex]\begin{gathered} y=\frac{605\times10^{-9}\times85\times10^{-2}}{0.095\times10^{-3}} \\ y=540000\times10^{-8}\text{ m} \\ y=5.4\text{ mm} \end{gathered}[/tex]**Thus, the first dark band is 5.4 mm away from the center of the screen.**

**Hence, the correct answer is 5.4 mm.**

An Olympic diver is on a diving platform 8.40 m above the water. To start her dive, she runs off of the platform with a speed of 1.2 m/s in the horizontal direction. What is the diver speed, in m/s, just before she enters the water?m/s

**Given data**

*The given distance above the water is **s **= 8.40 m

*The given initial speed of the Olympic diver is **u** = 1.2 m/s

*The value of the acceleration due to gravity is a = 9.8 m/s^2

The formula for the diver speed, in m/s, just before she enters the water is given by the equation of motion as

[tex]v^2=u^2+2as[/tex]Substitute the known values in the above expression as

[tex]\begin{gathered} v^2=(1.2)^2+2\times9.8\times8.40 \\ v=12.88\text{ m/s} \end{gathered}[/tex]Hence, the diver speed, in m/s, just before she enters the water is **v** = 12.88 m/s

1) Prove that for the adiabatic process of gas pVr =const ; r=Cp/Cv *

2) Write down the expression for the number of molecules of N2 gas having speeds in the interval (100m/s ; 102m/s) for one mole of gas at T=300K

3) Demonstrate how to obtain the Boltzmann Distribution of Energies from the Maxwell-Boltzmann distribution of speeds.*

For an **adiabatic **process of gas PV(^r)= **Constant**, where r = Cp/Cv , Cp, and Cv are constants for a particular gas.

It is an imaginary **gas **for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an **ideal **gas is only the theoretical one.

Universal Gas **Equation **for the ideal gas,

PV=nRT

By differentiating on both sides: P.dV + V.dP = n.R.dT…. (1)

For the adiabatic process, the expansion or compression of gas occurs at a very fast rate which makes no **heat transfer**. Therefore, dQ= 0

A/c to First Law of TD: dQ=dU+ dW, implies dU= -dW=-P.dV ….. (2)

But dU= n.Cv. dT …. (3) Combining 2 and 3, we get: n.dT= -P.dV/Cv …..(3)

Using R= Cp-Cv, the gas law gives: from 1 and 3.

n.dT= (P.dV + V.dP)/(Cp-Cv) = -PdV/Cv

On rearranging terms we get, (dP/P)+((Cp/Cv)*(dV/V))=0

Cp and Cv are **constants **for a particular gas, hence integrating,

Ln(P)+ r.Ln(V)=constant (replacing Cp/Cv = r or Gamma)

Hence, P.V(^r)= constant is termed an **adiabatic **equation.

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Hint: first convert the given final speed (in mph) to find ft/s, then solve for the distance and acceleration.

**ANSWER**

**EXPLANATION**

First, we have to find the acceleration of the bicyclist.

To do that, we apply the formula:

[tex]a=\frac{v-u}{t}[/tex]where u = initial velocity

v = final velocity

t = time

Let us convert the speed given to feet per second. To do that, *multiply the speed by 1.46667*:

The bicyclist started from rest, so the initial speed is 0 ft/s.

Therefore, **the acceleration is**:

Now, to find the distance traveled, apply the formula:

[tex]s=ut+\frac{1}{2}at^2[/tex]Therefore, **the distance traveled is**:

Increasing the mass wouldIncreasing the mass would_______can increase or decrease the value of the gravitational force depending on the initial valuehave no effect on the gravitational forceincrease the gravitational forcedecrease the gravitational force

We will have that:

Increasing the mass would **increase the gravitational force**.

Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]

For parallel plate **capacitors **the capacitance C=Aϵ0/d

dAϵ 0

Area, A Cd/ ϵ0 = 1 * 1×[tex]10^{-3}[/tex]/8.85× [tex]10^{-12}[/tex]

= **1.13×10 8 m 2.**

The **capacitance **depending on **geometry** is given by the formula C=ϵ⋅Ad C = ϵAd. where C is the capacitance value A is the area of each plate, and d is the distance between the plates. plates, and ϵ is the dielectric constant of the material between the plates of the parallel capacitor.

The **governing equations** for **capacitor **design are C = εA/d where C is the capacitance. ε is the permittivity, a term that describes how well a dielectric holds an electric field. A is the area of the parallel plates. d is the distance between the two conductive plates. This is shown below. To calculate the total capacitance of multiple capacitors connected in this way, sum the individual capacitances.

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Ricardo, of mass 72 kg, and Carmelita, who is lighter, are enjoying Lake Merced at dusk in a 39 kg canoe. When the canoe is at rest in

the placid water, they exchange seats, which are 3.2 m apart and symmetrically located with respect to the canoe's center. Ricardo

notices that the canoe moves 46 cm horizontally relative to a pier post during the exchange and calculates Carmelita's mass. What is it?

**Ricardo **notices that the canoe moves 46 cm horizontally relative to a pier post during the exchange and the **mass **is 49 kg.

**Mass **is defined as a **measurement **of the fundamental attribute of all stuff, **inertia.**

Mass is also defined as a physical body's total **amount **of **matter**.

As per question,

Let's refer to Ricardo's mass as **MR **and Carmelita's mass as **MC**.

Let the two-person system's center of mass, which is believed to be closer to Ricardo, be **x **meters from the center of the canoe's length **L **and mass **m**.

MC(L/2 +x) = mx + MR(L/2-x).

It is derived from the **second law of parallel forces**, which states that the sum of the moments of mass moving clockwise and counterclockwise is equal.

The canoe's center has now moved twice as far from its initial location.

So, x = 46/2 = 23 cm = 0.23 m

MC = MR (L / 2x) - mx / L / 2 + x

MC = 72 ( 3.2 / 2 - 0.23 ) - 39 x 0.23 / 3.2 / 2 + 0.23

MC = 72 ( 1.6 - 0.23 ) - 39 x 0.23 / 1.6 + 0.23

MC = 72 x 1.37 - 8.97 / 1.83

MC = 98.64 - 8.97 / 1.83

MC = 49 kg

Thus, **Ricardo **notices that the canoe moves 46 cm horizontally relative to a pier post during the exchange and the **mass **is 49 kg

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In Young's double-slit experiment, two slits are separated by 5.0 mm and illuminated by light with a wavelength of 480 nm. The screen is 3.0 m from the plane of the slits. Calculate the separation between the eighth bright fringe and the third dark fringe observed with respect to the central bright fringe.

We are given the following information.

Seperation between slits: d = 5.0 mm

Wavelength of light: λ = 480 nm

Distance from the plane of slits: D = 3.0 m

We are asked to calculate the separation between the 8th bright fringe and the 3rd dark fringe observed with respect to the central bright fringe.

The position of the **8th bright fringe** is given by

The position of the **3rd dark fringe** is given by

Finally, the separation between the 8th bright fringe and the 3rd dark fringe is

[tex]\begin{gathered} x_8-x_3=2.304\times10^{-3}-7.2\times10^{-4} \\ x_8-x_3=1.584\times10^{-3}\;m \end{gathered}[/tex]Therefore, the separation between the eighth bright fringe and the third dark fringe observed with respect to the central bright fringe is **1.584×10⁻³ m**.

Aristotle's rhetorical triangle tells us that effective messages show awareness of

ethos, pathos, and logos

logic, emotion, and values

speaker, audience, and purpose

thought, voice, and opinion

Aristotle's rhetorical triangle tells us that effective messages show awareness of **ethos**, **pathos**, and **logos**. The correct answer to the question is option **A**.

**What is Aristotle's rhetorical triangle?**

**Aristotle **taught that a speaker's effective messages show awareness of the** ethos**,** pathos**, **logos** triangle, which expresses the idea that a good argument must be ethically, emotionally, and logically sound.

In summary, Aristotle's rhetorical triangle shows that the Logos, Ethos, and Pathos are very important when giving an effective message.

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The graph below shows the number of sunspots observed between 1750 and 2000.

Based on the graph, which of these statements is most likely correct about the periods 1800 to 1850 and 1900 to 1950?

A) There was decrease in global temperatures.

B) There was increase in global temperatures.

C) There was no significant change in solar activity.

D) There was no significant change in global climate.

Based on the graph, during the periods 1800-1850 and 1900-1950, there was a increase in** global temperature.**

**Sunspots** is an activity on the surface of the Sun that manifest as transient, darker-than-the-neighboring-areas spots. These parts on which it occurs have lower surface temperatures because** magnetic flux **concentrations there prevent convection from occurring.

Sunspot can increase the **temperature **of earth but by only a margin of about 0.05 to 0.1 Celsius.

As we can see from the graph that during the year 1800-1850 and 1900-1950 that number of sunspots is increasing continuously. So, there will a slight increase will be noticed in the** global temperature. **

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if a child on a skateboard has a total momentum of 86.94kgm/s and a speed of 2.3m/s, calculate the total mass of the child and skateboard

[tex]\begin{gathered} P=86.94\text{ kgm/s} \\ v=2.3\text{ m/s} \\ m=? \\ P=mv \\ Solving\text{ m} \\ m=\frac{P}{v} \\ m\frac{86.94\text{ kgm/s}}{2.3\text{ m/s}} \\ m=37.8\text{ kg} \\ Thr\text{ mass of the child and skateboard is 37.8kg } \end{gathered}[/tex]

Which of these does sound travel the fastest Through?A. steel SolidB. water LiquidC. Air gasD. Sound travels the same through all mediums

Speed of sound is maximum on solid.

Correct option.

A) steel Solid

if may 20 is a last quarter moon, when could you expect the first quarter moon to occur?

In the **early afternoon** or high in the sky around the time, the **sun** is setting.

The** crescent moon** rises around noon and sets around midnight. It can be seen near the horizon in the evening or high in the sky as the sun sets. If you live in the northern hemisphere, the first quarter moon appears as the right half of the illuminated surface. **Occurs** when the moon is at right angles to the sun as seen from Earth.

The right half of the **moon** appears bright and the left half appears dark. During the period from the new moon to the first quarter moon, the **illuminated **part of the moon grows larger day by day and continues to grow until the full moon. The first quarter is also called the crescent moon because 50% of its surface is briefly illuminated by the sun. Usually, he takes 3 nights. Each phase of the moon has a profound effect on humans and the earth.

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A parking lot is going to be 60 m wide and 240 m long. which dimensions could be used for a scale model of the lot?A. 90 in x 360 cmB. 1 m x 3 mC. 20 cm x 80 cmD. 120 cm x 480 m

**Answer:**

**C. 20 cm x 80 cm**

**Explanation:**

The dimensions of the scale model have the same ratio of the original dimensions. The ratio of the original dimenstions is

240/60 = 4

Then, the ratio for each option is

A. 360/90 = 4

B. 3/1 = 3

C. 80/20 = 4

D. 480/120 = 4

Therefore, B is not a correct option.

Additionally, we don't use A because the units for length and width are different

And we don't use D because the measures are too long for a model.

Therefore, the answer is

C. 20 cm x 80 cm

Two ways to modulate a wave are to change the wave's ___ (AM) or the wave's__ (FM).

**Answer:**

AM - amplitude modulation

FM - frequency modulation

What is the mass of a truck if it produces a force of 13,607 N while accelerating at a rate of 2.9 m/s²?

**Newton's Second Law.**

**We have the following data, provided in the exercise:**

**Mass (m) =** ?

**Force (F) =** 13607 N

**Acceleration (a) = **2.9 m/s²

*To* **calculate the mass**, *we solve the* **following formula:**

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ \frac{F}{a}=\frac{m*\not{a}}{\not{a}} } \end{gathered}$}}[/tex][tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{F}{a}=m \ \iff \ Address \ is \ changed \Rightarrow \ m=\frac{F}{a} } \end{gathered}$}}[/tex]

**We substitute the data in the clear formula.**

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ N}{2.9 \ \frac{m}{s^{2} } } } \end{gathered}$} }[/tex]

*We break down the units of* **Newton = Kg * m/s².**

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\not{\frac{m}{s^{2}} } }{2.9 \not{\frac{m}{s^{2}} } } } \end{gathered}$} }[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=4692.07 \ Kg } \end{gathered}$} }[/tex]

The mass of the truck is: 4692.07 Kilograms (Kg).a 30.0 kg child starting from rest slides down a water slide with the vertical height of 10.0 m what is the child speed (a )halfway down the slides vertical distance and (b) 3/4 of the way down

We know that

• The mass is m = 30.0 kg.

,• The vertical height is h = 10.0 m.

(a)We have to use the conservation of energy theorem, which states that mechanical energy is constant all the time. Also, halfway down means a height of 5.0 m. It's important to know that at the top the total energy is potential, while halfway is distributed as kinetic and potential, the expression below shows this

[tex]E_{p1}=E_{k1}+E_{p2}[/tex]Then, using the definition of each energy, we have

[tex]mgh_1=\frac{1}{2}mv^2+mgh_2[/tex]Now, we use the given values to find the speed.

[tex]\begin{gathered} \text{mgh}_1=m(\frac{1}{2}v^2+gh_2) \\ gh_1=\frac{1}{2}v^2+gh_2 \\ 9.81m/s^2\cdot10m=\frac{1}{2}v^2+9.81m/s^2\cdot5m \\ 98.1m^2/s^2=\frac{1}{2}v^2+49.05m^2/s^2 \\ 98.1m^2/s^2-49.05m^2/s^2=\frac{1}{2}v^2 \\ 2\cdot49.05m^2/s^2=v^2 \\ v=\sqrt[]{98.1m^2/s^2} \\ v\approx9.9m/s \end{gathered}[/tex]Therefore, the speed of the child halfway down is 9.9 meters per second.(b)In this case, we just have to use as the second height of the equation the magnitude 2.5 meters because that's 3/4 of the way down. So, let's use the same process and expression

[tex]\begin{gathered} gh_1=\frac{1}{2}v^2+gh_2 \\ 9.81m/s^2\cdot10m=\frac{1}{2}v^2+9.81m/s^2\cdot2.5m \\ v=\sqrt[]{2(98.1m^2/s^2-24.53m^2/s^2)} \\ v\approx12.1m/s \end{gathered}[/tex]Therefore, the speed of the child 3/4 of the way down is 12.1 meters per second.A chemical reaction separates water into hydrogen gas and oxygen gas. Which of the following statements is true about the mass of the water and the combined mass of the two gases

**Answer:**

The mass of the water is greater than the combined mass of the two gases

Descriptions

A. Research that is designed to describe the characteristics or behaviors of a person or particular population

B. The thing the researcher changes in the experiment

C. Research that attempts to test cause and effect between two things

D. The thing that is influenced by another variable in an experiment

E. Research that attempts to assess the relationship between two aspects of human behavior

Fill in the blank with the letter of the description that best matches the term.

Descriptive Studies

PLEASE HELP!! IF SOMEONE KNOWS THE REST PLEASE TELL ME! THANKYOU!

**Answer:**

I think it is C

**Explanation:**

A pencil is viewed through a concave lens. Which of the following best describes the image?A.RealB.InvertedC.VirtualD.Enlarged

A concave lens produces a virtual image like the one seen in the diagram (we know is virtual since it is on the same side to the original object), we also see that the image is smaller, and not inverted.

**Therefore, the only option that describes this image is C which is virtual.**

Help my hw is due by 12:00 am for final grade!!
which of the following is NOT an indication of chemical change due to application of heat it change in
In act 4 Why is Aunt Juliana Tesman dressed in mourning clothing?
Multiple gaming tournaments can be played online. In these games, players can compete with players from any part of the world. Step-by-step-explanation (Simple linear equation)In a tournament,200 points are awarded for a win, and 20points are deducted for a loss.Chetan participated in the tournament.He won two more matches than the number of matches he lost.He scored 1120 points.How many matches did he play?B. 8A. 6D. 14C. 10
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What are the nonliving parts of the ecosystem such as water, dirt, and air called?Responsesabiotic factorsabiotic factorsbiomesbiomesbiotic factorsbiotic factorsecological factors
I need questions 10 , 13 , 15 , and 16 solved with steps and graph
*THE STORY IS WHITE HERON* Novel or Short Story Title: 1. What is the title of your novel or short story? 2. Who is the protagonist of your novel or short story? Describe the protagonist.Provide a quotation from the text to support your answer.3. Who is the antagonist of your novel or short story? Describe the antagonist.Provide a quotation from the text to support your answer.4. Describe the main conflict in your novel or short story. Which of the four major types of conflict best describes the situation you described?5. Choose a short passage that develops the setting of your novel. Include the quotation and answer the associated questions in the space below.a. Quotation from the text:b. What do you see, hear, or smell due to the description you chose?
A plane flew 216 miles from Bristol airport to Leeds Bradford airport. It had an average speed of 162mph and arrived at 18:15. Work out what time the plane left Bristol airport. Give your answer using the 24 hour clock.
the national institute of cancer used fmri brain imaging to decide which potential anti-smoking advertising campaign elicited the largest amount of brain activity. this is an example of which type of marketing research?
Graph the following inequalities.4x + y 0I need TWO COORDINATES
Pre- Calculus log(x^5)=3
Solve for x12x-6 need answer please
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What is the mass of an object with a density of 1.37g/cm3 and a volume of 5.24cm3?
sofia and manuel are purchasing a home. they wish to save money for 15 years and purchase a house that has a value of $180,000 with cash. if they deposit money into an account paying 5% interest, compounded monthly, how much do they need to deposit each month in order to make the purchase?
Ian has 120 folders to file. So far, he has filed 36 of the folders. What percent of the folders does he have left to file?help pls pls pls pls pls i will give brainlliest
How does using the ocean as an energy resource interact in both positive and negative ways within each of Earth's spheres?
Describe how well you think your modeled position matches the observed position for the man.1 answer=10,543 points