**Answer:**

Electrons are transferred from atoms of sodium to atoms of phosphorus. This transfer makes the sodium atoms positive and the phosphorus atoms negative. As a result, the sodium and phosphorus atoms strongly attract each other.

**Explanation:**

REACTION: C5H12 + 8O2 5CO2 + 6H2O When 25.5 grams of C5H12 are consumed in this reaction what mass of CO2 can be produced in grams?

In order to answer this question we will need the properly balanced reaction, which the question already gave us:

C5H12 + 8 O2 -> 5 CO2 + 6 H2O

Then we need to focus on the compounds that the question is asking, which are C5H12 and 5 CO2, from the reaction we can also identify the molar ratio between both molecules, 1:5, that means that for every mole of C5H12, we will end up with 5 moles of CO2

Now let's find out how many moles of C5H12 are in 25.5 grams of it, we will use its molar mass to find the answer, molar mass is 72.15 g/mol

72.15 g = 1 mol

25.5 g = x moles

x = 0.35 moles of C5H12

Now we have 0.35 moles of C5H12, we know that molar ratio is 1:5, now let's see how many moles of CO2 we will have

1 C5H12 = 5 CO2

0.35 C5H12 = x CO2

x = 1.75 moles of CO2

And now we will do a similar step using CO2 molar mass in order to find the final mass, molar mass for CO2 is 44.01 g/mol

44.01 g = 1 mol

x grams = 1.75 moles

x = 77.02 grams of CO2

1. 10.0 grams of water in the form of a solid has a temperature of 0.0 °C. This cube of

ice is placed in a room with a temperature of 25.0 °C. The ice starts melting to form a

puddle of water. The initial 10.0 grams of water is what kind of property?

4

O

O

O

personal

intensive

extensive

chemical

The **initial 10.0 grams** of water is a kind of **intensive property.**

**What do you mean by intensive properties?**

**Intensive properties **are those properties which do not depend upon the amount of the given substance. For example **Temperature and pressure.**

Generally, **grams **are used to represent **concentrations.** Therefore, always consider **extensive.** However, in the given question, the concentration is specified i.e. means fixed. So, the 10.0 grams of water become **intensive** in the given conditions.

Hence, the answer is an** intensive property.**

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How much energy (Joules) is required to change 49.75 grams of liquid water from 95 Celsius to 105 Celsius?

The **energy** in Joules required to change 49.75 grams of **liquid ****water** from 95 Celsius to 105 Celsius is 2082.54J.

**Energy** is the ability to do work. The **energy** needed to heat a substance can be calculated using the following formula:

Q = mc∆T

Where;

Q = quantity of heatAccording to this question, 49.75 grams of **liquid water** needs to be changed from 95 Celsius to 105 Celsius. The **energy** needed can be calculated as follows:

Q = 49.75 × 4.186 × (105 - 95)

Q = 2082.54J

Therefore, 2082.54J is the **energy** required to change the **liquid** **water**.

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consider the reaction 2clf3+2nh3=n2+6hf+cl2 calculate hf for clf3 .

We can obtain the heat of **formation **required for the **chlorine tri fluorde **as -1513 kJ.

Looking at the fact that a **chemical reaction** often involves a heat change we could define the enthalpy change which is the heat change of the reaction as the energy that was **lost **or **gained **in course of a reaction.

To obtain the heat of formation of chlorine tri fluorde, let us designate it as x ;

Using the formula;

Sum of enthalpy of formation of products - Sum of enthalpy of formation of reactants

-1196 =(0 + 271 + 0) - (x + (- 46))

-1196 = 271 - x + 46

-1196 = 317 - x

x = -1196 - 317

x = -1513 kJ

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Missing parts;

Consider the reaction 2ClF3 (g) + 2NH3 (g) → 6HF (g) + N2 (g) + Cl2 (g) △H-_1196 kJ Given the following enthalpies of formation, calculate AHf for CIF3 (9) NH3 (g)- 46 kJ/mol HF 9)271 kJ/mol kJ

I have pressure of 65 kPa and starting temperature of 25°C. If I raise the temperature to 167°C, what is the new pressure? (Equation: K= 273 +°CO 90 KPaO 100 kPaO 96 kPaO 97 kPa

Answer:

**96kPa. Option C is correct**

Explanations:

According to **Gay Lussac's law**, the **pressure** of a given mass of gas is directly proportional to the t**emperature** provided that the volume is constant. Mathematically:

**Substituting the given parameters **to determine the new pressure P2

Therefore the **new pressur**e is **96kPa**

Please help me please please

Your system could **not** **cool** as effectively as it should due to **refrigerant** leakage. Your home cannot reach the target **temperature** due to your air **conditioning** system. However, it may also result in higher **monthly** **energy** costs.

**Temperature** is a unit used to represent hotness or coolness on any of a number of scales, including Celsius and **Fahrenheit**. According to temperature, heat energy will naturally move from a hotter (body with a high temp) to a colder (body with such a lower temperature) (one at a lower **temperature**)

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i need help with chemistry

**0.966 ml** concentrated acid must you add to obtain a total volume of 50.0 ml of the **dilute** **solution**.

A **diluted** **solution** is one that has a low solute content. A concentrated solution is one that contains a lot of the solute. The concentrated solution can be created by adding more solute to the **dilute** **solution**.

Considering that the moles of Nitric acid remain unchanged during the **dilution** process:

[tex]n_{H I}=n_{H I}[/tex]

Apply the following equality in terms of molarity

V[tex]_1[/tex]M[tex]_1[/tex] = V[tex]_2[/tex]M[tex]_2[/tex]

The subscript 1 accounts for the solution before the **dilution** and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

V[tex]_1[/tex]= V[tex]_2[/tex]M[tex]_2[/tex]/M[tex]_1[/tex]

= 50.0ml * 0.116 M/6.00 M

= **0.966 ml.**

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The complete question is -

You wish to make a 0.116 M nitric acid solution from a stock solution of 6.00 M nitric acid. How much concentrated acid must you add to obtain a total volume of 50.0 ml of the dilute solution ?

Ca(OH)2 is added to a large beaker of water. How is the solution different from the original water?

The solution turns blue litmus to red.

The solution turns phenolphthalein pink.

The solution has more hydrogen ions.

The solution has fewer hydroxide ions.

I know its not B

The solution is different from the original water being that the solution turns **phenolphthalein** pink (option B).

A **base** is any of a class of generally water-soluble compounds, having bitter taste, that turn red litmus blue, and react with acids to form salts.

A **base** is known to contain excessive amounts of hydroxide ions (OH-), which it releases in an aqueous solution.

**Phenolphthalein** is an indicator solution that appears colourless, however, when it is exposed to **alkaline** solution it turns pink.

This suggests that a **basic** solution turns **phenolphthalein** solution pink.

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Which tasks would Power, Structural, and Technical Systems employees most likely perform?

A. fix tractors, reassemble engines, operate bull dozers

B.package steaks, use laboratory equipment, know the standards for food storage facilities

C.track supplies, drive equipment, give advice about farm function

D.operate machinery in mines, record data on tree sizes, enforce rules and regulations

The tasks would Power, Structural, and **Technical Systems employees **most likely perform are option B. package steaks, use laboratory **equipment**, and know the standards for food **storage facilities.**

A **technological machine **is fixed of interconnected components that have been designed to satisfy a selected characteristic without, in addition, human design input. Technological structures transform, store, transport, or manage substances, energy, and/or statistics for a particular cause.

Individuals who paint in the electricity, **Structural**, and **Technical structures **pathway observe an understanding of engineering, hydraulics, pneumatics, electronics, energy, systems, and controls in the field of agriculture. They design **agricultural structures** in addition to equipment and gadget.

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Assume that a given solution contains Ag+ or Ba2+ or a mixture of both. A reasonable method for doing a qualitative analysis on this solution might be sketched out as follows : picture below

What is the precipitate formed at X in the above scheme?

b. What is the identity of cation at Y in the above scheme?

c. What are two other solutions that could be used in the above scheme rather than Na2SO4? Explain.

a) The X is **BaSO₄**, b) The cation is **Ag⁺ ions**, c) another way to separate is by adding **NaCl or NaSCN**

It is given that the solution contains Ag⁺ and Ba²⁺ ions. In addition to Na₂SO₄, Ba²⁺ ions get precipitated to give BaSO₄ leaving the cation, Ag⁺.

The reaction would be,

Ag⁺ + Ba²⁺ ------Na₂SO₄---------> BaSO₄ + Ag+

Therefore,

a) The precipitate X that is formed would be **BaSO₄** in the above scheme.

b) The cation that is left at Y is **Ag⁺.**

c) This reaction can also be carried out using **NaCl and NaSCN**. By using NaCl we could obtain, **BaCl₂** and by using NaSCN we could get **Ba(SCN)₂**. Here both precipitates are **soluble**. The respective reactions are,

Ag⁺ + Ba²⁺ ------NaCl---------> BaCl₂ + Ag+

Ag⁺ + Ba²⁺ ------NaSCN---------> Ba(SCN)₂ + Ag+

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Fill in the blanks to complete the tableCompleting the first row.

Each row is independent from the other, so we can use the same method for each one.

Le'ts give a variable for each column:

- S: Symbol

- z: Z (Atomic number)

- a: A (Mass number)

- p: No of Protons

- e: No of Electrons

- n: No of Neitrons

- c: Charge

In the symbol column, the right supercript is the charge, so since the Symbol is:

[tex]S=Mg^{2+}[/tex]The charge is 2+. We write as 2+, but in math we would write as +2, they are the same, but in different notations.

[tex]c=2+=+2[/tex]The atomic number and the symbol are always unique, so each element has always the same atomic number and the other way around too.

From a periodic table, we can see which Element corresponds to which atomic number Z.

On a periodic table, we can see that the atomic number of Mg is 12, so:

[tex]z=12[/tex]Also, the atomic number and the number of protons is always the same:

[tex]\begin{gathered} p=z \\ p=12 \end{gathered}[/tex]The mass number, a, is alwais the number of protons plus the number of neutrons:

[tex]a=p+n[/tex]Since we know that the mass number is 25 in this case, we can calculate the number of protons:

[tex]\begin{gathered} a=p+n \\ 25=12+n \\ n=25-12 \\ n=13 \end{gathered}[/tex]So it checks out with the number on the table.

Each proton has a charge of 1+ and each electron has a charge of 1-. In Math terms, we can say that each proton counts as +1 and each electron counts as -1.

Thus, the charge is the number of protons minus the number o electrons:

[tex]c=p-e[/tex]Since the charge is 2+ and there are 12 protons, we can say:

[tex]\begin{gathered} 2=12-e \\ e=12-2 \\ e=10 \end{gathered}[/tex]So, there are 10 electrons.

Putting altogether, we have:

[tex]\begin{gathered} S=Mg^{2+} \\ z=12 \\ a=25 \\ p=12 \\ e=10 \\ n=13 \\ c=2+ \end{gathered}[/tex]And, by the names:

**Symbol: Mg²⁺**

**Z: 12**

**A: 25**

**No. of Protons: 12**

**No. of Electrons: 10**

**No. of Neutrons: 13**

**Charge: 2+**

Ionic and covalent bonds help arrange atoms into unique structures for proteins like hemoglobin. Why is this necessary?

Responses

The structure of the protein allows it to carry out whatever function is needed the most.

The structure of the protein allows it to carry out whatever function is needed the most.

The bonds help hold the protein together but are unrelated to the function.

The bonds help hold the protein together but are unrelated to the function.

The ionic bonds alone in a protein help determine its function.

The ionic bonds alone in a protein help determine its function.

The structure of a protein allows it to carry out its unique function.

The structure of a protein allows it to carry out its unique function.

The reason why the **Ionic **and **covalent **bonds help arrange atoms into unique structures for proteins like hemoglobin is that the structure of a protein allows it to carry out its **unique function.**

The** covalent bond** is the kind of bond that exists between two atoms in which the electrons between the two atoms are shared. The electrons cloud of the bond lies between the two atoms. For the ionic bond, there is a transfer of the electrons from one atom to another. We ought to note that the transfer is often from the metal to the non metal.

On the other hand, it should be noted that there are various kinds of bonding that are important to be able to keep the structure and the function of the **protein**. Aside from the covalent bonds that holds the atoms together, the ionic bonds could also be involved in the dipolar interactions that are responsible for the secondary structure of the protein.

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B. The structure of a protein allows it to carry out its unique function.

ur welcum

Using the glucose data in Document A and the balanced equation for photosynthesis inDocument B, calculate how much oxygen the plant made in one day.

**The plant made in one day 0.54 moles of oxygen**.

From the balanced equation for photosynthesis, we know that 6 moles of oxygen are produced when 1 mole of glucose is produced at the same time.

So, to calculate the amount of oxygen that a plant made in one day when it produced 0.090 moles of glucose, we can use a mathematical Rule of Three:

[tex]\begin{gathered} 1\text{mol Glucose}-6\text{mol Oxygen} \\ 0.090\text{mol Glucose-x=}\frac{0.090\text{mol Glucose}\cdot6\text{mol Oxygen}}{1\text{mol Glucose}} \\ x=0.54\text{mol Oxygen} \end{gathered}[/tex]Finally, **the plant made in one day 0.54 moles of oxygen**.

Strontium metal and aqueous HCIreact to give hydrogen gas andaqueous strontium chloride. Writethe balanced chemical equation usingthe correct chemical formulas for thereactants and products and identifythe reaction type.

The metal Strontium is symbolized by Sr, and since it is a metal its oxidation number is 0, so no charge.

In this reaction, the Sr will become 2+, so, since Cl is 1-, the proportion is 1 Sr to 2 Cl, so the unbalanced reaction is:

[tex]Sr+HCl\to H_2+SrCl_2[/tex]To balance it, we need to add a coefficient of 2 on HCl, so we have 2 H on both sides and 2 Cl on both sides.

The Sr is and continue balanced.

**So, the balanced reaction is:**

As we can see, the left part has Sr alone and H with Cl, while on the right side this changes, H is alone and Sr is with Cl. This means that Cl was displaced from H to Sr, so this is a **single displacement reaction**.

A 4kg object is pushed 1 meter in 1 second. How many joules were consumed to move the object?

For the thing to move,** 2 joules **were used.

There are numerous shapes that energy can take. Examples of these energies include **gravitational energy**, **mechanical energy**, **electrical energy**, **sound energy**, **chemical energy**, **nuclear **or **atomic energy**, light energy, heat energy, and so on. Each form has the capacity to alter or change into the other forms.

**Energy **is a major factor in our daily lives because it is a fundamental need for humans. You need energy to **move**,** rise from bed**, or even merely to go down the road. Energy not only heats but also cools our man-made structures.

**formula**, joules = 1/2*kilogram*{[tex]\frac{meter}{sec}[/tex]}^2

joule = [tex]\frac{1}{2}[/tex]*4*1 = **2 joule**

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Which equations represent the conservation of matter? (choose 2)

Responses

A A + B → ABA + B , →, AB

B A + B → CA + B , →, C

C A + B + C → BC + DA + B + C , →, BC + D

D AB + CD → AC + BBAB + CD , →, AC + BB

E AB + C → AC + B

**Answer:**

AA+b Ac+b

**Explanation:**

Calculate the grams of lead (III) iodide that can be produced from 5.00 moles of potassium iodideI picked A but I’m not sure if it’s correct

Explanation:

The question gives us the following reaction:

Pb(NO3)2 + 2 KI ---> PbI2 + 2KNO3

The equation tells us that 2 moles of potassium iodide (KI) produce 1 mole of lead(II) iodide (PbI2).

So:

2 moles KI ---- 1 mole PbI2

5 moles KI ---- x moles

x = 2.5 moles

Now let's transform 2.5 moles of PbI2 into grams:

m = n*MM

MM of PbI2 = 461 g/mol

m = 2.5*461 = 1,152.5 g

Answer: alternative "D" 1.15 x 10^3 g

Identify the species oxidized, the species reduced, the oxidizing agent and the reducing agent in the following electron-transfer reaction.

Mn(s) + Pb2+(aq) Mn2+(aq) + Pb(s)

A change in the substrate's oxidation state occurs during **redox reactions. Oxidation **is the process of losing **electrons **or increasing an element's oxidation state.

Gaining electrons or lowering the **oxidation **state of an element or its constituent atoms are both examples of **reduction**.

An **oxidation-reduction (redox) reaction** is a chemical process in which two compounds exchange **electrons**. Any chemical process in which a molecule, atom, or ion suffers a change in its **oxidation number **as a result of acquiring or losing an **electron **is known as an **oxidation-reduction reaction.**

An **oxidizing agent** is a substance that "accepts" or "receives" an electron from a reducing agent in a redox chemical process. Therefore, an **oxidant **is any chemical that **oxidizes **another substance.

An **electron **is "donated" to an electron acceptor by a chemical species known as a **reducing agent.** Chemicals that are often used as reducing agents include the Earth metals, formic acid, oxalic acid, and sulfite compounds.

**Pb gets oxidized.**

**Manganese (Mn) gets reduced.**

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Use the data below to calculate ΔH°rxn for the reaction MgO(s) + CO2(g) à MgCO3(s).

ΔH°f: MgO(s) = -602 kJ mol-1

, CO2(g) = -394 kJ mol-1 and MgCO3(s) = -1096 kJ mol-

The **ΔH°rxn** for the reaction MgO(s) + CO2(g) à MgCO3(s) is -100. kJ mol-1.

**What is enthalpy ?**

**Enthalpy **is a property or state function that resembles energy; it has the same dimensions as energy and is therefore measured in joules or ergs. The value of **enthalpy **is solely dependent on the temperature, pressure, and composition of the system, not on its history.

Using ΔH° = ∑ΔfH°(products) – ∑ΔfH°(reactants), the **enthalpy change **is:

ΔH° = ΔfH°(MgCO3(s)) – [ΔfH°(MgO(s)) + ΔfH°(CO2(g))]

= (-1096 – [-394 -602]) kJ mol-1

= -100. kJ mol-1

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paragraph explain how to draw a covalent bonds

Covalent bonds are those bonds in which the atoms between which the bond is present share electrons. Each element retains its electrons but shares with the element with whom it creates the bond.

To graph a covalent bond there are different structures, for example the Lewis structure, which indicates the electrons in the form of points, then the number of points of the atom will be the valence electrons that the element has. The symbol of the element is enclosed in a circle and the electrons are drawn on the circle. The electrons that are shared overlap between the circles of both elements. In the following example you can see what I just described:

3.Two molecules of mercury oxide decompose into 2 molecules of mercury and 1 molecule of oxygen gas. Which of the following equations correctly describes this reaction?Select one:a. Ab. Bc. Cd. D

**Answer**

**Explanation**

If two molecules of mercury oxide decompose into 2 molecules of mercury and 1 molecule of oxygen gas, then the equation for the reaction is shown below

[tex]2HgO(s)\rightarrow2Hg(l)+O_2(g)[/tex]What stress would shift the equilibrium position of the following system to the left? N2O3(g) ⇌ NO(g) + NO2(g); ΔH is negativea.The forward reaction is exothermic.b.The backward reaction has a negative net enthalpy.c.The colorless gas has a higher enthalpy than the brown gas.d.The equilibrium between the two forms of the gas is disturbed at high temperatures.

**Answer**

**Explanation**

N2O3(g) ⇌ NO(g) + NO2(g); ΔH is negative

The reaction is exothermic (ΔH is negative), **an increase in the temperature will force the equilibrium to the left**, causing the system to absorb heat and thus partially offset the rise in temperature.

Therefore, the correct answer is:

**d. **The equilibrium between the two forms of the gas is disturbed at high temperatures.

Two descriptions for a sub-atomic particle are listed below:

Description 1: Can electrically attract or repel other sub-atomic particles

Description 2: Has a charge

Which sub-atomic particle or particles fit these descriptions?

a

Electrons only

b

Neutrons only

c

Electrons and protons

d

Protons and neutrons

The descriptions that the sub-atomic **particles** can electrically attract or repel other **sub-atomic **particles and has a charge best suits for electrons and protons.

**Sub-atomic** particles are the basic constituents of an atom. **Electrons**, protons and neutrons are called subatomic particles.

Electrons possess negative charge and **protons** have positive charge. Thus electrons attracts a proton and vice versa. **Neutron** is neutral and shows no attraction or repulsion.

Hence, The description that a sub-atomic particle having charge and **electrically attract** or repel other sub-atomic particle fit for both electrons and protons.

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There are **protons, neutrons**, and **electrons,** three types of **subatomic particles**. Protons and electrons, two of the subatomic particles, each have an **electrical charge** of one or the other. On the other hand, **neutrons** lack a charge.

The **fundamental feature** of matter known as **electric charge,** which is carried by some elementary particles, determines how the particles are affected by an** electric or magnetic field.**

**Protons **are **positively charged** particles that are found inside the atom's **nucleus. Neutrons** are found inside the atom's nucleus and are** neutral particles.**

**Electrons** are **negatively** charged particles that surround the nucleus by unclear paths.

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2.70 mL of 4.00 M KOH is diluted to a final volume of 100.0 mL. What is the resulting concentration?

**Answer: 0.108**

**Explanation:**

use v1s1 = v2s2

here v1 = 2.7ml s1 = 4 M v2 = 100ml s2=?

Which analogy best describes theories?

Theories are like rocks because they can change but not easilly.

Theories are like tides because they frequently go back and forth.

Theories are like time because they are eternal and never change.

Theories are like clay because they can be molded to fit changing opinions.

The **analogy** that best describes theories is that **theories** are like clay because they can be molded to fit changing opinions.

A theory is a thorough explanation of a scientific **phenomenon** that incorporates laws, hypotheses, and facts. For example, the gravitational field **hypothesis** explains why fruits fall from trees and astronauts float in space. A theory can be related to a **clay** as it can be moulded as per the observations. The more observations a theory anticipates, the more tests it passes, and the more **facts** it explains, the longer its core premises hold true.

A theory should be consistent with new **data**. If not, the theory is changed or abandoned. The more **observations** a theory anticipates, the more tests it passes, and the more facts it explains, the longer its core premises hold **true**.

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How many seconds are in72 milliseconds?Give your answer in standard form.Ent

**1) Convert milliseconds to seconds.**

1 s = 1000 ms

[tex]s=72\text{ }ms*\frac{1\text{ }s}{1000\text{ }ms}=0.072\text{ }s[/tex]*72 ms is equal to ***0.072 s.**

A vessel, divided into two parts by a partition, contains 4 mol of nitrogen gas at 5°C and 30 bar on one side and 2.5 mol of argon gas at 1°C and 20 bar on the other. If the partition is removed and the gases mix adiabatically and completely, what is the change in entropy? Assume nitrogen to be an ideal gas with CV = (5/2)R and argon to be an ideal gas with CV = (3/2)R.

If the partition is removed and the gases mix adiabatically and completely, the change in **entropy **is equal to 263 K.

**What is entropy?**

The measure of a system's chaos is called **entropy**. It is an extensive property of a thermodynamic system, which means that the amount of matter in the system affects how much it is worth. **Entropy **is frequently represented in equations by the letter S and is measured in joules per kelvin (JK%-1) or kg/m^2/s^-2K^-1. The **entropy **of a highly ordered system is low.

Lets assume nitrogen is an ideal gas with CV=5R/2

and assume argon is also an ideal gas with CV=3R/2

n₁=4 moles

n₂=2.5 moles

t₁ = 5°C, in kelvin t₁= 5+273

t₁ = 278 K

t₂=1°C, in kelvin t = 1+273

t₂= 273 K

u=пCVΔT

U(N₂)+U(Ar)=0

putting values:

4x(5R/2)x(T(final)-278) = 2.5x(3R/2)x(T(final)-273)

by simplifying:

**T(final)** = 263K

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what is the final pressure (in atm) of 5.25 L gas initially at 534 mmHg and 22 degrees celsius that is compressed to a final volume of 2.75 L at a new temperature of 15 degrees celsius?

The final **pressure** of 5.25L **gas** initially at 534 mmHg and 22 degrees celsius that is compressed to a final volume of 2.75 L is 1.31atm.

The combined **gas** law states that the ratio of the product of **pressure** and volume and the absolute temperature of a **gas** is equal to a constant.

The **pressure** of a **gas** can be calculated by using the combined **gas** law equation as follows:

P₁V₁/T₁ = P₂V₂/T₂

Where;

P₁ = initialAccording to this question, a 5.25 L **gas** initially at 534 mmHg and 22 degrees celsius is compressed to a final volume of 2.75 L at a new temperature of 15 degrees celsius. The final **pressure** can be calculated as follows;

0.703 × 5.25/295 = P₂ × 2.75/288

0.0125 = 0.00955P

P₂ = 1.31atm

Therefore, 1.31 atm is the final **pressure** of the **gas** compressed to a lower volume of 2.75L.

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How many liters of solution will be produced when diluting 1.65 L of a 0.432 M KI solution to 0.212 M KI?

All questions where they ask you about concentration or volume of a solution prepared with another solution can be solved using the following equation:

[tex]C_1V_1=C_2V_2[/tex]Where C1 is the concentration of the first solution, V1 is the volume of the first solution, C2 is the concentration of the second solution and V2 is the volume of the second solution. You only need to be careful to use the rigth units.

This particular question ask for the Volume of the second solution, V2. Then we need to solve for V2 in the previous equation:

[tex]V_2=\frac{C_1V_1}{C_2}=\frac{0.432\text{ M}\times1.65L}{0.212M}=3.36L[/tex]What is the hydrate formula for something that is 0.0243 mol Bal2 and 0.75 mol H2O?

**Answer:**

[tex]\text{BaI}_2.30H_2O[/tex]

**Explanation:**

Here, we want to get the hydrate formula

To get the hydrate formula, we need to get the number of molecules of water

Now, to get this, we have to divide the number of moles of water by the number of moles of the anhydrous solid

The number of moles of water is given as 0.75 while that of the anhydrous solid is 0.0243

Mathematically, we have it that:

[tex]\frac{0.75}{0.0243}\text{ =}30[/tex]The hydrate formula is thus:

[tex]\text{BaI}_2.30H_2O[/tex]
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