For ease of use, the** temperature **was set to zero degrees Celsius. The velocity of particles is represented by **zero** on the absolute (Kelvin) scale. **Absolute temperature** changes cause corresponding changes in pressure or volume.

**Temperature** is a physical parameter that describes how hot stuff or **radiation** is.

such as the** SI scale**; those that rely solely on purely **macroscopic** properties and **thermodynamic **principles, such as **Kelvin's** original definition; and those that are not defined by** theoretical **principles but are defined by **convenient **empirical properties of particulate matter.

A ** thermometer **is used to measure temperature.

The **coldest **a body can be conceived to be is one with an absolute zero **temperature. **It can only be approximated extremely closely, but not actually reached, in experiments.

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Which is NOT a transition metal?

a tin

b copper

c gold

d rhodium

The answer is A) Tin

Tin is a post-transition metal.

Tin is a post-transition metal.

WHAT IS THE SIZE OF MY D\

Answer:get a ruler and find out

Explanation:

measure from tip to tip and post a picture to see

**Answer:baby carrots**

**Explanation:**

measure with baby carr

compared to human cells resulting from mitosis cell division, human cells resulting from mitosis cell division would have

A. twice as many chromosomes

B. the same number of chromosomes

C. one-half the number of chromosomes

D. one-quarter as many chromosomes

Mitosis results in two identical daughter cells, whereas meiosis results in four sex cells

a cylinder contains 30.0 l of oxygen gas at a pressure of 1.9 atm and a temperature of 310 k. part a how much gas (in moles) is in the cylinder? express your answer to two significant figures. view available hint(s)

The **moles** of the gas when a cylinder contains 30.0 l of oxygen gas at a pressure of 1.9 atm and a temperature of 310 K is 2.2

The **ideal gas **equation is PV=nRT. P is the pressure, V is the volume, n is the number of moles and T is the temperature

Substituting the values, we get

1.9x30=nx0.0821x310

n=2.2(two significant figures)

An ideal gas is one that follows the ideal gas equation.It is also called the equation of state of a hypothetical ideal gas.It is an extension and generalization of Boyle's and Charles's law.To learn more about **the ideal gas** visit:

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Many communities in the United States get some of their power from hydroelectric dams. These dams work by blocking the path of a river to create a large lake with water held back by the dam. The dam can then be opened to allow water to cross over the dam. The energy from the water is captured and transformed into electrical energy. What type of energy does a hydroelectric dam capture as the water passes through?

Kinetic energy does a** **hydroelectric dam** **capture as the **water** passes through

The most common type of hydroelectric power plant is an impoundment facility and an impoundment facility is a typically a large hydropower system and the uses a dam to** store **river water in a reservoir and the water released from the reservoir flows through a turbine and spinning it and which in turn activates a generator to produce electricity and then there are many types of hydropower facilities through they are all powered by the kinetic energy of flowing water as it moves downstream

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**Answer:**

mechanical energy

**Explanation:**

smart answer :)

Which transition in an excited hydrogen atom will emit the longest wavelength of light?

A. E5 to E1

B. E4 to E1

C. E3 to E1

D. E2 to E1

The **transition **in an excited **hydrogen atom **will emit the longest wavelength of light is E2 to E1. Thus option D is correct.

**Transition **is defined as a **specific arrangement **along the reaction coordinate.

It can also be defined as the **condition **corresponding to the maximum **potential energy **along this reaction coordinate is what is meant by this term.

**d-block elements** shows transition because they behave in a way that transitions between **s-block **and** p-block **components, the d-block elements are known as transition elements.

Transition in the elements occurs when the **electrons **come under excited state and travel form **lower **energy level to **higher **energy level.

Thus, the **transition **in an excited **hydrogen atom **will emit the longest wavelength of light is E2 to E1. Thus option D is correct.

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50.0 mL of a Ba(OH)2 solution

were titrated with 66.90 mL of a

0.500 M HCl solution to reach the

equivalence point. What is the

molarity of the Ba(OH)2 solution?

According to the given statement **0.3345 M** is the **molarity** of the Ba(OH)₂ **solution**.

The quantity of a **substance** in a specific solution volume is known as its **molarity** (M). The amount of moles of a solute every litre of a solution is referred to as molarity. The molecular **concentration** of a solution is another name for molarity.

Ba(OH)₂+ 2HCl ⇒ BaCl₂ + H₂O

Ratio of moles Ba(OH)₂ ,

HCl = 1:2

Amount of HCl consumed

= 0.500/1000*66.90

= 0.03345 mol

So Ba(OH)₂ reacted = 1/2 * 0.03345 mol

If **molarity **of Ba(OH)₂ is x then

x/1000*50 = 1/2 * 0.03345

**x = 0.3345 M.**

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find values of the intrinsic carrier concentration n. for silicon at -55°c, 0°c, 20°c, 75°c, and 125°c. at each temperature, what fraction of the atoms is ionized? recall that a s

The **intrinsic carrier concentration** and the fraction of ionized atoms of silicon at -55℃, 0℃, 20℃, 75℃, 125℃ is calculated below.

The **intrinsic carrier concentration** in intrinsic material is the number of **electrons** found in the conduction band or holes in the valence band. This quantity of carriers is determined by the material's band gap as well as its temperature.

Because the number of holes equals the number of **electrons**, the concentration of each is equal to some amount, ni, and this quantity is known as the **intrinsic carrier concentration**, and the pure semiconductor material is referred to as intrinsic material.

Given:

B = 5.4 x [tex]10^{31}[/tex]

[tex]E_G[/tex] = 1.12 ev for silicon

K = 8.62 x [tex]10^{-5}[/tex]

Silicon crystal = 5 x [tex]10^{22}[/tex] atoms/[tex]cm^3[/tex]

To find:

Intrinsic carrier concentration, ni = ?

Fraction of ionized atom = ?

Formula:

[tex]ni^2 = BT^3 e^{\frac{-E_G}{KT}[/tex]

Fraction of ionized atom = ni / 5 x [tex]10^{22}[/tex]

Calculations:

(a) For -55℃:

T = -55 + 273 = 218K

ni = [tex]5.4 * 10^{31} * 218^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 218})}[/tex]

ni = 2.7018 x [tex]10^6[/tex] carriers/[tex]cm^3[/tex]

Fraction of ionized atom = 2.7018 x [tex]10^6[/tex] / 5 x [tex]10^{22}[/tex]

Fraction of ionized atom = 5.403 x [tex]10^{-17}[/tex] atoms/[tex]cm^3[/tex]

(b) For 0℃:

T = 0 + 273 = 273K

ni = [tex]5.4 * 10^{31} * 273^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 273})}[/tex]

ni = 1.53 x [tex]10^9[/tex] carriers/[tex]cm^3[/tex]

Fraction of ionized atom = 1.53 x [tex]10^9[/tex] / 5 x [tex]10^{22}[/tex]

Fraction of ionized atom = 3.07 x [tex]10^{-14}[/tex] atoms/[tex]cm^3[/tex]

(c) For 20℃:

T = 20 + 273 = 293K

ni = [tex]5.4 * 10^{31} * 293^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 293})}[/tex]

ni = 8.65 x [tex]10^9[/tex] carriers/[tex]cm^3[/tex]

Fraction of ionized atom = 8.65 x [tex]10^9[/tex] / 5 x [tex]10^{22}[/tex]

Fraction of ionized atom = 1.73 x [tex]10^{-13}[/tex] atoms/[tex]cm^3[/tex]

(d) For 75℃:

T = 75 + 273 = 348K

ni = [tex]5.4 * 10^{31} * 348^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 348})}[/tex]

ni = 3.724 x [tex]10^{11}[/tex] carriers/[tex]cm^3[/tex]

Fraction of ionized atom = 3.724 x [tex]10^{11}[/tex] / 5 x [tex]10^{22}[/tex]

Fraction of ionized atom = 7.449 x [tex]10^{-12}[/tex] atoms/[tex]cm^3[/tex]

(e) For 125℃:

T = 125 + 273 = 398K

ni = [tex]5.4 * 10^{31} * 398^3 * e^{(\frac{-1.12}{8.62 * 10^{-5} * 398})}[/tex]

ni = 4.75 x [tex]10^{12}[/tex] carriers/[tex]cm^3[/tex]

Fraction of ionized atom = 4.75 x [tex]10^{12}[/tex] / 5 x [tex]10^{22}[/tex]

Fraction of ionized atom = 9.51 x [tex]10^{-11}[/tex] atoms/[tex]cm^3[/tex]

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Calculate the % yield of the rection between 6.00 grams of salicylic acid and excess acetic anhydride to form 3.12 grams od Aspirin:

**Answer:**

You identify the limiting reactant by calculating the moles of product that can be formed from each reactant.

**Explanation: **Then you calculate the theoretical yield of product from the amount of the limiting reactant.

**EXAMPLE Aspirin is prepared by the reaction between acetic anhydride and salicylic acid.**

acetic anhydride + salicylic acid → aspirin + acetic acid

**C 4 H 6 O 3 + C 7 H 7 O 3 → C 9 H 8 O 4 + C 2 H 4 O 2 m m A m l + m B m m → m l l C m l l + m l D **

**What is the theoretical yield of aspirin ( C ) if you reacted 4.32 g of acetic anhydride ( A ) with 2.00 g of salicylic acid ( B )? **

**Solution :**

The molar masses are

**Acetic anhydride = A = C 4 H 6 O 3 = 102.1 g/mol **

**Salicylic acid = B = C 7 H 6 O 3 = 138.1 g/mol**

**Aspirin = C = C 9 H 8 O 4 = 180.2 g/mol **

Identify the limiting reactant We calculate the moles of each reactant and then use the molar ratios from the balanced equation to calculate the moles of aspirin.

Moles of aspirin from **A = 4.32 g A × 1 mol A 102.1 g A × 1 mol C 1 mol A = 0.0423 mol C **

Moles of aspirin from **B = 2.00 g B × 1 mol B 138.1 g B × 1 mol C 1 mol B = 0.0145 mol C B gives the smaller amount of aspirin, so B is the limiting reactant. **

Calculate the theoretical yield **0.0145 mol C × 180.2 g C 1 mol C = 2.61 g C**

xeof4 has one of the more interesting structures among noble gas compounds. on the basis of its symmetry, a. obtain a representation based on all the motions of the atoms in xeof4.

The molecule** xenon oxo tetrafluoride **has** five regions **of electron density as shown in the image attached.

Let us recall that a compound can be found when the atoms of elements are **combined **together. The interesting fact about the compound that we have called xenon oxo tetrafluoride is that the central atom in the compound is a **noble gas.**

We know that the noble gases are said to be unreactive. In this case, we can see from the image that is attached that there are five regions of electron density that surround the molecule and the there are no lone pairs on the **xenon **central atom.

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Why can't you use the equation Q = mc∆T to calculate how much thermal energy is needed to melt or boil a substance?

We can't you use the equation Q = mc∆T to calculate how much **thermal energy** is needed to melt or boil a substance because this equation is to calculate for heat energy transferred between two objects where m is the mass of each object and c is the specific heat capacity

Thermal energy refers to the energy contained within a** system** that is responsible for its temperature and for thermal energy for melt any substance is latent heat and during boiling of any substances the heat energy supplied is used in increasing the energy of the water molecule which changes its state from liquid to gaseous

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a sampple sand was found to contain 2.81 G of silicon and 3.20 gram of oxygen show that the law of Definite proportion is illustrate.

16:32=1:2 hence the Law of **Multiple Proportion **holds true

According to the Law of **Multiple Proportion**, the mass of one element that is combined with a fixed mass of the second element will always be ratios of whole numbers when two components combine to generate more than one compound.

For illustration, suppose there are **two molecules **of CO (carbon monoxide) and CO 2. (carbon dioxide).

CO is equal to 12g of carbon and 16g of oxygen.

CO2 is made up of **12 grams** of carbon and 32 grams of oxygen.

The two **compounds **are 16:32=1:2 in terms of the mass of oxygen.

This establishes the law of **multiple proportions**.

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The greatest about of transpiration will occur over _____________.

Group of answer choices

a mountain top covered in snow

a large river with a high discharge

the ocean

a large forest with mature trees.

The greatest about of **transpiration **will occur over a large forest with mature trees.

**Transpiration **is described because the physiological lack of water in the form of water vapor, especially from the stomata in leaves, but also thru **evaporation **from the surfaces of leaves, plants, and stems.

**Transpiration **is the system wherein plants release the water interior it inside the shape of moisture or water vapor. **Roots **eat some quantity of water from the soil and the rest evaporates inside the atmosphere. elements of plants consisting of stems, small pores on leaves, and plants evaporate the water to the environment.

Leaf **stomata **are the primary web sites of transpiration and encompass two defend cells that form a small pore on the surfaces of leaves. The defend cells control the opening and last of the stomata in reaction to various **environmental **stimuli and may alter the fee of transpiration to reduce water loss.

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True or False

1. An atom has no weight.

2An electron is the heaviest part of an atom

. 3. All protons weigh the same.

4.All atoms weigh the same.

5. All neutrons weigh the same.

6. An oxygen atom can weigh the same as a nitrogen atom

7.All oxygen atoms weigh the same.

8. To find the mass of an atom, we add the neutrons and electrons The atomic mass of Calcium is 40.08.

9.The rounded off mass is 41.

10Isotopes are atoms of the same element that have a different number of protons.

1. False, 2. True, 3. **True**, 4. False, 5. True, 6.** False**, 7. True, 8. False, 9. Incomplete and 10. True.

1. Atoms have no weight - False

**Atomic mass** is the total mass of an atom. This is roughly equal to the total number of protons and neutrons with a small addition of electrons.

2. The electron is the heaviest part of the atom - in fact

3. All protons have the same mass - True

4. All atoms have the same mass - False

The mass of each element depends on the number of protons and neutrons it contains.

5. All neutrons have the same mass. - True

6. An oxygen atom weighs as much as a nitrogen atom. - False

o2 has a **molecular weight **of 15.9994 g/mol, and the molar mass of nitrogen is 14.0067 g/mol.

7. All oxygen atoms have the same mass - True

8. If we add neutrons and electrons to find the mass of an atom, the atomic mass of calcium is 40.08 - False

The number of protons and neutrons in an element determines its mass number. Protons and neutrons are the mass numbers.

9. The circular mass is 41, which is not quite correct.

10. Isotopes are identical atoms with differing numbers of **protons**. - True

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Living things need __________ for thinking, eating and moving

**Answer:**

Living beings need survive for thinking,eating,and moving.

**Answer:**

Brain, mouth and legs

**Explanation:**

the following are needed for the above questions

when 56.6 g of calcium is reacted with nitrogen gas, 31.0 g of calcium nitride is produced. what is the percent yield of calcium nitride for this reaction? 3ca(s) n2(g)→ca3n2(s)

Calculation of **percent yield **requires the **theoretical yield **to be calculated first. Using that method, the percent yield of the reaction is 44%.

To calculate the **percent yield** of calcium nitride, we first need to calculate the **theoretical yield**. To do this, we need the molar mass of both calcium (40 g/mol) and calcium nitride (3 * 40 + 2 * 14) g/mol = 148 g/mol.

3 moles of calcium produce 1 mol of calcium nitride so the proportion we can make will look like this:

120 g of calcium : 148 g of calcium nitride = 56.6 g of calcium : X

X = 148 g of calcium nitride * 56.6 g of calcium / 120 g of calcium

X = 69.8 g of calcium nitride

This is the theoretical yield. Calculating the percent yield works like this - we divide the actual mass by the theoretical yield and then multiply that number (that is always supposed to be between 0 and 1) by 100%:

%yield = 100% * 31.0 g / 69.8 g = 44%

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i will give brainliest please help

1. A compound has an empirical formula of CO4 and a mass of 228 g/mol. What is the molecular formula?

2. What is simplest form (empirical formula) of C4H24O12?

The **molecular formula **is [tex]\rm C_2O_8[/tex]. The **empirical formula **is [tex]\rm C_2H_1_2O_6[/tex] which is the simplest from.

**Molecular formula **is defined as a **chemical formula **that gives the total number of atoms of each element in each molecule of a substance.

It can also be defined as a **formula **derived from molecules that indicates the total **number **of **individual atoms **in the molecule of a compound.

**Empirical** **formula **is defined as a **chemical formula **that depicts the simplest **elemental ratio** of a compound rather than the total number of atoms in the molecule.

**Molecular formula = n - empirical formula**

Thus, the **molecular formula **is [tex]\rm C_2O_8[/tex]. The **empirical formula **is [tex]\rm C_2H_1_2O_6[/tex] which is the simplest from.

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major difference between crystallisation and evaporation to dryness

one major clear and major difference

Difference between crystallization and evaporation to dryness : **crystallization** is the formation of solid crystal from liquid whereas **evaporation** is the formation of vapor from liquid.

**Crystallization** is defined as the the process in which pure solid separates in the form of crystal from solution .

**Evaporation to dryness** is used to separate solute thermally when soluble solid does not decompose on heating. crystallization is better than evaporation to dryness because in the process of evaporation some solid in the mixture get decomposed **leaving impurities.** during the process of evaporation.

The major difference is that in **crystallization** is the formation of solid crystal from liquid whereas **evaporation** is the formation of vapor from liquid.

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Balance the equations.

MgO + HBr → MgBr₂ + H₂O

**Answer:**

Since there is an equal number of each element in the reactants and products of MgO + 2HBr = MgBr2 + H2O, the equation is balanced.

What is the number of atoms in 12.00 g of carbon-12?

How many atoms are there in a mole (mol) of carbon-12?

**Answer: The number of atoms = Avogadro's number = 6.022 × 10²³**

**Number of atoms in a mole = Avogadro's number = 6.022 × 10²³**

**Explanation:**

1.

Mole = [tex]\frac{given mass}{molar mass}[/tex]

Also, Mole = [tex]\frac{Number of atoms/molecules/ions}{Avagadro's Number}[/tex]

∴ [tex]\frac{given mass}{molar mass}[/tex] = [tex]\frac{Number of atoms/molecules/ions}{Avagadro's Number}[/tex]

[tex]\frac{12}{12}[/tex] = [tex]\frac{number of atoms}{Avogadro's number}[/tex]

number of atoms = Avogadro's number

number of atoms = 6.022 × 10²³

2.

Mole = [tex]\frac{Number of atoms/molecules/ions}{Avagadro's Number}[/tex]

1 = [tex]\frac{Number of atoms/molecules/ions}{Avagadro's Number}[/tex]

number of atoms = Avogadro's number

number of atoms = 6.022 × 10²³

What is the atomic mass of hafnium if, out of every 100 atoms, 5 have a mass of 176, 19 have a mass of 177, 27 have a mass of 178, 14 have a mass of 179, and 35 have a mass of 180. 0?.

The **average atomic mass** of the given **isotopes **of Halfnium is 178.55 amu

The **average atomic mass** of an element is equal to the sum of its isotope masses multiplied by it's own natural abundance (the decimal associated with the percent of atoms of that element for a given isotope).

In order to determine the weighted average, we must consider the % natural abundances of each **isotope**. The atomic mass of an element is the weighted average of the atomic masses of the element's naturally occurring isotopes. Determine the average atomic mass by using atomic masses and percentage abundances of each isotope. To convert each percentage abundance to decimal form, divide it by 100. Multiply this figure by the atomic mass of the isotope. To get the a**verage atomic mass**, add the atomic masses of each isotope together.

To determine the average atomic mass of Halfnium, the mass fractions of the **isotopes **multiplied by their respected atomic masses must all be added.

Using 100 atoms as the basis, calculate the mass fractions (m1, m2,...m5):

m1 = 5/100 = 0.05

m2 = 19/100 = 0.19

m3 = 27/100 = 0.27

m4 = 14/100 = 0.14

m5 = 35/100 = 0.35

Multiplying the mass fractions with the atomic masses of the respective isotopes.

Average atomic mass of Halfnium is:

Avg = (m1 x 176) + (m2 x 177) + (m3 x 178) + (m4 x 179) + (m5 x 180)

Avg = (0.05 x 176) + (0.19 x 177) + (0.27 x 178) + (0.14 x 179) + (0.35 x 180)

Avg = 178.55 amu

Therefore, the **average atomic mass** of Halfnium based on the data for its given **isotopes **is 178.55 amu.

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a certain first order reaction has a half-life of 41.3 s. how long will it take (in s) for the reactant concentration to decrease from 6.50 m to 2.06 m? give your answer to three sig figs

The time needed to decrease reactant concentration based on its **half-life** is **68.47 seconds**.

We need to know about the **half-life **of the radioactive elements to solve this problem. The radioactive element will decay over time and follow the equation

N = No(1/2)^(t/t'')

where N is the final quantity, No is the initial quantity, λ is the decaying constant, t is time and t'' is the half-life of a radioactive element.

From the question above, we know that

t'' = 41.3 s

No = 6.5 m

N = 2.06 m

By substituting the given parameters, we can calculate the time taken

N = No(1/2)^(t / t'')

2.06 = 6.5 . (1/2)^(t / 41.3)

0.32 = (1/2)^(t / 41.3)

⁰'⁵log(0.32) = t / 41.3

1.66 = t / 41.3

t = 68.47 seconds

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The only transition metal that is a liquid at room temperature

(21 °C) is named

**Answer:**

mercury

**Explanation:**

mercury is a metal on the periodic table which is liquid at room temperature

what is the difference between an element and an isotope? an isotope is an element with a different number of electrons. an isotope is an element with a different number of neutrons. an isotope is an element with a different number of protons.

**Answer:**

different number of neutrons

in the laboratory you dilute 4.59 ml of a concentrated 6.00 m hydrobromic acid solution to a total volume of 175 ml. what is the concentration of the dilute solution?

The **concentration** of the dilute solution when in the laboratory you dilute 4.59 ml of a concentrated 6.00 m hydrobromic acid solution to a total volume of 175 ml is 0.157 M

Now, using the formula, we get

Substituting the values, we get

M=6.00

V=4.59 mL=4.59x10^-3 L

n=6.00x(4.59x10^-3L)

n=27.54x10^-3 L

The new molarity is Mnew=n/Vnew

Mnew= 27.54x10^-3 V=175 mL=175x10^-3 L

Mnew=27.54x10^-3 mol/175x10^-3 L

Mnew=0.157 M

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Geologic maps are most recognized by their _____, which represent different _____.

size, rock units

colors, rock units

contour lines, elevations

symbols, rock ages

**Geologic maps** are most recognized by their **contour lines**, which represent different **elevations**. **Option C**

This is further explained below.

What areGenerally, A **geologic map**, also known as a geological map, is a specialized map that is drawn out for the purpose of illustrating different geological phenomena.

The various rock units and **geologic layers** may be represented by different colors or symbols.

contour line: A curve along which a function has a constant value represents a contour line for a function with two variables.

This means that the curve unites points that have the same value at each point along the curve. It is a segment of the plane that is parallel to the plane that is taken from the three-dimensional graph of the function f.

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Students will design an experiment to find out if brand X fertilizer will affect the growth of Lily

plants. Remember a fair experiment only has ONE (1) Independent Variable. In this experiment,

The **independent variable** as we can see from the **experiment **that have been described in this case is the brand of **fertilizer **that was used in the study.

When we talk about an **experiment**, we are talking about the way by which the relation ship between the **dependent **and the **independent **variable could be studied. In the experiment, there is a dependent variable which would change values when the variable that is under study in the particular experiment changes value. We have to know that in the realm if science, it is only by the means of experiments that we can be able to establish cause and effect relationships.

In this case, we can see that the experiment that the students were working on has to do with trying to actually find out if brand X fertilizer will affect the growth of Lily plants. This means that they were studying the effect of a** fertilizer brand** on the growth of the crops.

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a 0.692-g sample of glucose, c6h12o6, is burned in a constant volume calorimeter. the temperature rises from 21.70 °c to 25.22 °c. the calorimeter contains 575 g of water and the bomb has a heat capacity of 650 j/k. what quantity of heat is evolved per mole of glucose?

If a 0.692-g sample of **glucose**, c6h12o6, is burned in a constant volume calorimeter, then the amount of** heat **evolved per mole of glucose is **2.88 **x [tex]10^{6}[/tex]** J/mol**

For the given reaction, the amount of heat evolved can be calculated by dividing the amount of heat evolved by the number of moles.

The formula for heat evolved is

[tex]q_{m}[/tex] = [tex]\frac{q}{n}[/tex]

Now use heat transfer equation to express q

q = [tex]mc_{w}[/tex]ΔT + [tex]c_{c}[/tex] ΔT

Where m is the mass, ΔT change of temperature and [tex]c_{w}[/tex] is the specific heat, and [tex]c_{c}[/tex] specific heat of calorimeter.

The number of moles and mass of **glucose **can be expressed as

n = [tex]m_{g} /MW[/tex]

We are given the following values:

m = 575 g

cw = 4.184 J/gK

ΔT = 25.33 − 21.70 = 3.63 K

[tex]c_{c}[/tex] = 650 J/K

MW = 180.156 g /mol

[tex]m_{g}[/tex] = 0.692 g

Now the solution will be

[tex]q_{m}[/tex] = q/n

m[tex]c_{w}[/tex]ΔT + [tex]c_{c}[/tex]ΔT/ [tex]\frac{m}{MW}[/tex]

[tex]q_{m}[/tex] = (575 g) (4.164 J/g ∘C) (3.63K) + (650 J/K)(3.63K)/[tex]\frac{0.692g}{180.56 g/mol}[/tex]

[tex]q_{m}[/tex] = 2.88 x [tex]10^{6}[/tex] J/mol

Thus the** quantity of heat** evolved per mole of **glucose** is 2.88 x [tex]10^{6}[/tex] J/mol

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Hey, this is basically almost a free point (just multiple choice of 1 pressure)

**Answer:**

1st option

**Explanation:**

At sea level, atmospheric pressure is high, and water boils at 100 °C (212 °F)

**Answer:**

the third one ;)

**Explanation:**

Calculate the volume occupied by 5.44 g of oxygen gas (O2) at a pressure of 0.881 atm and a temperature of 27.4 C

After thoroughly calculating, we have come to find that, the **volume **occupied by 5.44 g of **oxygen gas **(O2) at a **pressure **of 0.881 atm and a **temperature **of 27.4 C is 4.76 L.

The equation of state of an ideal **gas**, also known as the general **gas **equation, is the ideal **gas **law. Even though it has a number of restrictions, it is a good approximation of the behaviour of many gases under a variety of conditions. T

he empirical Boyle's law, Charles' law, Avogadro's law, and Gay-law Lussac's were all combined in Benoît Paul Émile Clapeyron's first formulation of it in 1834. Often, the empirical form of the ideal **gas **law is used:

PV is equal to nRT where n is the quantity and R is the ideal gas constant, where p, V, and T are the **pressure**, **volume**, and **temperature**. As accomplished by August Krönig in 1856 and Rudolf Clausius in 1857, it can also be derived from the microscopic kinetic theory.

To find the **volume **we will use the ideal gas law

PV = nRT

Where.

P = **pressure**

V = **volume**

n = amount of substance

R = ideal gas constant

T = **temperature**

Here, we have give **pressure **of 0.881 atm

**Temperature **of 27.4 C = (27.4+273) = 300.4 K

5.44 g of O₂ gas convert it into moles

**Mass**/Molar **mass **= No. of moles

5.44/32 = 0.17 mol

R = 0.0821 L atm K⁻¹ mol⁻¹

We need to find **volume **that is

V = nRT/P

= (0.17 × 0.0821 × 300.4)/ 0.881

= 4.76 L

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