**Answer:**

This has already been answered but here is the answer:

2.71×10 molecules of co2 * 1 Mole CO2 /6.022 *10^23 molecules of CO2

= 4.5*10^-14 Mole CO2

1 mole of CO2 has 2 mole oxygen

4.5*10^-14 Mole CO2 *2/1

**= 9.0*10^-14 Mole oxygen **

Convert 18.6 L of neon gas at STP to atoms.

1.What is the coefficient of the scientific notation answer? 2.What is the exponent of the scientific notation answer? 3.How many significant figures are there in the answer?

4.What is the right most significant figure in the answer ?

**Answer:**

See explanation

**Explanation:**

1 mole of Ne occupies 22.4 L

x moles of Ne occupies 18.6 L

x = 1 mole * 18.6 L/22.4 L

x = 0.83 moles

1 mole contains 6.02 * 10^23 atoms

0.83 moles occupies 0.83 moles * 6.02 * 10^23 atoms/1 mole

= 4.9966 * 10^23 atoms = 5.0 * 10^23 atoms

the coefficient of the scientific notation answer =5.0

the exponent of the scientific notation answer = 23

significant figures are there in the answer = 5

the right most significant figure in the answer = 1

Which a balanced chemical equation ? O C 7 H 16 +5O 2 6CO 2 +4H 2 O OB C 7 H 16 +11O 2 7CO 2 +8H 2 O C 7 H 16 +14O 2 7CO 2 +5H 2 O OD . C 7 H 16 +22O 2 14CO 2 +16H 2 O

**Answer: [tex]C_7H_{16}+11O_2\rightarrow 7CO_2+8H_2O[/tex]**

**Explanation:**

According to the** law of conservation of mass**, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation is:

[tex]C_7H_{16}+11O_2\rightarrow 7CO_2+8H_2O[/tex]

If 335 g water at 35.5C loses 5750 J of heat, what is the final temperature of the water?

**Answer:**

The final temperature is 39.58 degree Celsius

**Explanation:**

As we know

Q = m * c * change in temperature

Specific heat of water (c) = 4.2 joules per gram per Celsius degree

Substituting the given values we get -

5750 = 335 * 4.2 * (X - 35.5)

X = 39.58 degree Celsius

There are moles of carbon present in 100 g of a

compound with the following percentage composition:

C= 40.0%, H = 6.72%, O = 53.29%.

Answer: 3.33

Explanation:

The **molecular formula **of the given **composition **is C₃H₆O₃.

**Molecular formula **is defined as a compound's **chemical formula**, which counts the total number of each element present in a molecule of the compound as discrete molecules. The arrangement of atoms in a molecule in three dimensions is known as **molecular geometry**, commonly referred to as the molecular structure.

The percentage composition is

C = 40.00 %

H = 6.72 %

O = 53.29 %

Mole = 100 g

Mass of C = 40 / 100 x 100 = 40 g

mass of H = 6.72 / 100 x 100 = 6.72 g

Mass of O = 53.29 / 100 x 100 = 53.29 g

Dividing the mass with moles

C = 40 / 12 = 3.3

H = 6.72 / 1 = 6.72

O = 53.29 / 16 = 3.3

Formula = **C₃H₆O₃**

Thus, the **molecular formula **of the given **composition **is C₃H₆O₃.

To learn more about **molecular formula, **refer to the link below:

https://brainly.com/question/28647690

#SPJ2

A study was conducted to see if increasing the substrate concentration has an appreciable effect on the velocity of a chemical reaction. With a substrate concentration of 1.5 moles per liter, the reaction was run 15 times, with an average velocity of 7.5 micromoles per 30 minutes and a standard deviation of 1.5. With a substrate concentration of 2.0 moles per liter, 12 runs were made, yielding an average velocity of 8.8 micromoles per 30 minutes and a sample standard deviation of 1.2. Is there any reason to believe that this increase in substrate concentration causes an increase in the mean velocity of the reaction of more than 0.5 micromole per 30 minutes

**Answer:**

There is not enough evidence

**Explanation:**

For 1.5 moles substrate concentration per liter

Reaction ( n2 ) = 15 runs

average velocity ( x2 ) = 7.5 micromoles per 30 minutes

standard deviation ( s2 ) = 1.5

For 2.0 moles substrate concentration per liter

Reaction( n1 ) = 12 runs

average velocity ( x1 ) = 8.8 micromoles per 30 minutes

standard deviation ( s1 ) = 1.2

Show Reason to believe that this increase in substrate conc causes an increase in mean velocity

Hypothesis test

H0 : μ1 - μ2 = 0.5

H1 : μ1 - μ2 > 0.5

level of significance ( ∝ ) = 0.01

**attached below is a detailed solution to the problem **

P-value ( 0.073 ) > level of significance ( 0.01 ) hence we fail to reject the null hypothesis

hence there in not enough evidence to believe that this increase causes an increase in the mean velocity of the reaction of more than 0.5 micromole per 30 minutes

How many grams of glycerine, C3H8O3, are needed to make 100. mL of 2.60 M solution?

**Answer:**

the mass of the glycerine needed in the given solution is **23.92 g**

**Explanation:**

Given;

molarity of the solution (C₃H₈O₃), C = 2.60 M

Volume of the solution, V = 100 mL = 100 x 10⁻³ L = 0.1 M

The molarity of a solution is given as follows;

[tex]Molarity = \frac{amount \ of \ solute \ (moles)}{volume \ of \ solution \ (L)} \\\\amount \ of \ solute \ (moles) = Molarity \ \times volume \ of \ solution \ (L)\\\\amount \ of \ solute \ (moles) = 2.6 \times 0.1 \\\\amount \ of \ solute \ (moles) = 0.26 \ mole[/tex]

The molecular mass of the given solution;

molecular mass = (12 x 3) + (8 x 1) + (16 x 3)

molecular mass = 92 g/mol

The mass of the glycerine needed in the given solution is calculated as follows;

reacting mass = amount of solute (moles) x molecular mass (g/mol)

reacting mass = 0.26 x 92

reacting mass = **23.92 g**

Therefore, the mass of the glycerine needed in the given solution is **23.92 g**

Can someone please help

Answer:

5.

A. Period

B. Group

6. C

Explanation:

I am doing a break-out room and it won't let me pass I think I have all the other questions correct so this is the only one I'm not sure about.

1. figure one

2. figure two

3. figure three

4. figure two

5. figure one

**Answer:**

it goes A,C,B,C,A

**Explanation:**

Phenolphthalein indicator is??

**Answer:**

Hey mate.....

**Explanation:**

This is ur answer.....

*Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions. It belongs to the class of dyes known as phthalein dyes.*

Hope it helps!

mark me brainliest pls....

Follow me! :)

Those microscopic organisms perform what 2 processes that help pave the way for lichen by creating organic material.

**Answer:**

Decomposition pf residues and weathering of rock.

**Explanation:**

Microorganisms performs two processes such as decomposition and weathering of rock materials. These two processes make the medium suitable for the growth and development of the lichens because these processes increases nutrient and organic matter on the rock surface that is used by the lichens for its growth. In decomposition process, larger compounds are broken down into simpler substances while on the other hand, the weather of rocks causes breakdown of rock material into simpler minerals that also used by the lichens.

neeeeeeeed help with science

Answer: should be 28 degrees

Explanation:

NO FILES OR LINKS PLEASE HELPPPP IVE ASKED THIS 3 TIMES AND ALL I GET IS SCAM FILES ILL GIVE YOU BRAINLIEST PLEASE

What is the skeleton equation for

CuSO4 + 2NaOH → Cu(OH)2 + Na2SO Copper sulfate + Sodium hydroxide --> copper hydroxide + sodium sulfate

**Answer:**

*Inserting real answer*

**Explanation:**

I think CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4 is the skeleton equation.

If I am wrong I am so sorry!!!

Have a nice day! :)

Also sorry for all the fake answers you have been getting that happened to me too TnT

Light is a type of energy produced by the vibration of electrically charged particles.

True or false?

**Answer:**

**big brain**

**Explanation:**

What is the new pressure if the temperature outside is 296k and his weight causes the tire's volume to drop to 2.0 liters

**Question:**

At standard temperature and pressure, the volume of a tire is 3.5L. What is the new pressure if the temperature outside is 296k and its weight causes the volume of the gas is 2.0 L?

**Answer:**

The new pressure is: **1.896 atm**

**Explanation:**

**At standard temperature and pressure, we have:**

[tex]P_1 = 1atm[/tex]

[tex]T_1 = 273.15k[/tex]

[tex]V_1 = 3.5L[/tex]

**Outside, we have:**

[tex]T_2 = 296k[/tex]

[tex]V_2 = 2.0L[/tex]

**Required**

Determine the new pressure

**Using combined gas law, we have:**

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

**This gives:**

[tex]\frac{1 * 3.5}{273.15} =\frac{P_2*2.0}{296}[/tex]

**Solve for **[tex]P_2[/tex]

[tex]P_2 = \frac{296 * 1 * 3.5}{273.15*2.0}[/tex]

[tex]P_2 = \frac{1036}{546.30}[/tex]

[tex]P_2 \approx 1.896 atm[/tex]

Please help with these two (last question is nwse)

**Answer:**

your answer gonna be 20 miles

How many grams are in 4.5 x 10^22 molecules of water? please show dimensional analysis

Answer:

1.1grams

Explanation:

Find moles of water:

4.5x10^22/(6.02x10^23)=0.07mol

Find molar mass of the water

O=16.00g/mol

0.07x 16.00=1.1 grams

Why the colloid can't be filitred?Write it's 4 examples.

**Answer:**

Constituent substances of a colloid cannot be separated by ordinary filtration because the size of the particles in a colloid (or colloidal solution) is bigger than those in a true solution but smaller than those in suspension. It is between 1 nm to 100 nm in diameter.

ex- cheese, milk, aerosol spray, mayonnaise

Acid HX has a very large Ka. How will the relative amounts of H+ and HX

compare at equilibrium?

A)The concentration of H+ will be larger than HX

B)The concentration of HX will be larger than H+

C)The concentration of HX will be equal to H+

The right answer is A

Can you help me please..

**Answer:**

Using Charles law of Gas

**Explanation:**

Do the chemical bonds between atoms change during cellular respiration?

During cellular respiration, the carbon and hydrogen atoms change partners and bond with oxygen atoms instead. The carbon-hydrogen bonds are replaced by carbon-oxygen and hydrogen-oxygen bonds. As the electrons of these bonds "fall" toward oxygen, energy is released.

how do particles differ after a physical change?

**Answer:**

They are still the same particals just. packed together diffrently depending on what stae of matter it's in.

**Explanation:**

What is the mass of 5.6 moles of Iron (III) Oxide?

**Answer:**

312.731

**Explanation:**

it had a long answer but im sure ur teacher wanted u to round it

hope this helps!

~goldfishareswag/brianna

:)

Iron (III) oxide= Fe2O3

1) Find the gfm (gram formula mass, the gfm is the grams per mole. So, you’re pretty much finding one mole of Fe2O3) of Fe2O3

2 Fe: 2(55.845)

3 O: 3(15.9994)

=160 gfm

2) multiply gfm by mole number

160(1 mole of Fe2O3 is 160. What are 5.6 moles?)

160 x 5.6

= 896g

1) Find the gfm (gram formula mass, the gfm is the grams per mole. So, you’re pretty much finding one mole of Fe2O3) of Fe2O3

2 Fe: 2(55.845)

3 O: 3(15.9994)

=160 gfm

2) multiply gfm by mole number

160(1 mole of Fe2O3 is 160. What are 5.6 moles?)

160 x 5.6

= 896g

If you observe a Full Moon on January 12th, on what date would you observe the next New Moon?

January 19

**Explanation:**

every first 7 days of a month the moon roughly starts its full moon phase

which shows how much electron is in the outer layer

**Answer:**

is there a picture or is it multiple choice?

An organ system is formed by..

A) two or more cells working together.

B) two or more tissues working together.

C) two or more organs working together.

D) two or more organisms working together

I think it is b because it's made up out of two or more tissues

How many grams of KCl are made when 5.02 moles of

ZnCl2 react in the reaction below?

2KMnO4 + ZnCl2 → 2KCl + Zn(MnO4)2

lol pls help me

**Answer: 747.98 grams of KCl are made when 5.02 moles of [tex]ZnCl_2[/tex] react in the reaction.**

**Explanation:**

The balanced chemical equation is:

[tex]2KMnO_4+ZnCl_2\rightarrow 2KCl+Zn(MnO_4)_2[/tex]

According to stoichiometry:

1 mole of [tex]ZnCl_2[/tex] produce = 2 moles of [tex]KCl[/tex]

Thus 5.02 moles [tex]ZnCl_2[/tex] will produce =[tex]\frac{2}{1}\times 5.02=10.04[/tex] moles of [tex]KCl[/tex]

Mass of [tex]KCl=moles\times {\text {molar mass}}=10.04mol\times 74.5g/mol=747.98g[/tex]

**Thus 747.98 grams of KCl are made when 5.02 moles of [tex]ZnCl_2[/tex] react in the reaction.**

A book is pushed and released and it slides across a table for a short distance. The book quickly comes to a stop. The book originally

has kinetic energy. To what form of energy is the kinetic energy transformed?

A)

The kinetic energy is transformed into heat.

B)

The kinetic energy is transformed into chemical energy.

C)

The kinetic energy is not transformed into any other type of energy.

Eliminate

D)

The kinetic energy is transformed into electrical energy.

Law of Conservation of Energy

(58P2.c) Energy Transformation

D 149628

Regular Cals

Scientific Cals

My

**Answer:**

A

**Explanation:**

The book encountered friction which turned some of the energy into heat.

An ball with a weight of 0.5 kg is sitting on a shelf that is 3 meters high. Help me! This is 8th grade sci btw.

**Complete question:**

A ball with a weight of 0.5 kg is sitting on a shelf that is 3 meters high. What is the gravitational potential energy of the ball ?

Help me! This is 8th grade sci btw

**Answer:**

the** **gravitational potential energy of the ball is is **14.7 J.**

**Explanation:**

mass of the ball, m = 0.5 kg

height above the ground on which the ball is sitting, h = 3 m

The gravitational potential energy of the ball is calculated as follows;

P.E = mgh

P.E = 0.5 x 9.8 x 3

P.E = 14.7 J

Therefore, the** **gravitational potential energy of the ball is is **14.7 J.**

I NEED THIS LESS THAN 7 MINUTES IYS 15 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! What is the difference between a balanced equation and an unbalanced equation?

All of the answers are correct.

A balanced equation obeys the law of conservation of mass, an unbalanced equation does not. An unbalanced equation shows the conservation of mass.

Balanced equations do not show equal numbers of atoms on each side of the equation.

**Answer:**

Balanced equation have equal number of atoms of different elements in the side of reactants and products.

**Answer:**

- A balanced chemical equation has an equal numbers of atoms of different elements in the side of reactants and products.

- An unbalanced chemical equation has an unequal number of atoms of one or more elements in the reaction.

**Explanation:**

Why must the mass of reactants in a chemical reaction

always equal the mass of products?

**Answer:**

law of conservation

**Explanation:**

matter cannot be destroyed nor made

a student needs to prepare a 1h nmr sample for an organic compound soluble in chloroform (chcl3) . the student cannot use chcl3 as the solvent for the sample, but rather uses deuterated chloroform (cdcl3) because:
a type of verbal behavior in which a written verbal stimulus has point-to-point correspondence and formal similarity with a written verbal response.
Eating a well balanced diet, participating in regular physical activity, and getting enough slee each night are all practices that support what dimension of wellness?
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Design a four-bit shift register (not a universal shift register) with parallel load using D flip-flops. (See Figs. 6.2 and 6.3.) There are two control inputs: shift and load. When shift = 1, the content of the register is shifted toward Az by one position. New data are transferred into the register when load = 1 and shift = 0. If both control inputs are equal to O, the content of the register does not change. A D 4 PC D D D A C Clock Fig. 6.2 Four-bit register with parallel load SI Serial input D D D D so Serial output CLK Fig. 6.3 Four-bit shift register 6.7 Draw the logic diagram of a four-bit register with four D flip-flops and four 4 x 1 mul- tiplexers with mode selection inputs s and . The register operates according to the following function table. (HDL-see Problem 6.35(e), ().) 51 50 Register Operation 0 0 No change Clock Fig. 6.2 Four-bit register with parallel load SI SO Serial input D D D D Serial output CLK Fig. 6.3 Four-bit shift register 6.7 Draw the logic diagram of a four-bit register with four D flip-flops and four 4 x 1 mul- tiplexers with mode selection inputs s and so. The register operates according to the following function table. (HDL-see Problem 6.35(e), (O).) 51 50 0 1 0 1 0 0 1 1 Register Operation No change Complement the four outputs Clear register to 0 (synchronous with the clock) Load parallel data 6.27 Using JK flip-flops: (a) Design a counter with the following repeated binary sequence: 0, 1, 2, 3, 4, 5, 6. (b) Draw the logic diagram of the counter. 2
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