The price of one canadian dollar in US dollars is 91 **cents** or 0.91 US dollars.

It is given that the price of a US dollar is 1.10 Canadian dollars in the market.

Thus we can say that,

1.10 Canadian Dollar = 1 US Dollar

∴ 1 Canadian Dollar = [tex]\frac{1}{1.10}[/tex] US Dollars

⇒ 1 Canadian Dollar = 0.91 US Dollars

Now we know that 1 US Dollar = 100 **cents**

∴ 0.91 US Dollars = 0.91 x 100 = 91 **cents**

Hence the value of 1 Canadian Dollar is 0.91 US Dollars or 91 **cents.**

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Select the correct answer from the drop-down menu.The answer choices are in the black box.....which one is it?

**ANSWER**

**C and D**

**EXPLANATION**

**Step 1: Given that:**

**Step 2: Simplify matrix D**

**Hence, matrices C and D are equal.**

Ayuda es para mañana son similar figures

**Answer:**

2. x = 2

3. x = 43.2

4. x = 3.6

**Step-by-step explanation:**

Rewrite 4^-3 x 4 using a single positive exponent.

The** term** 4^-3 x 4 can be rewritten using a single positive **exponent** as 1/4^2.

The positive **exponent **serves as the exponents that contain a positive number, it should be noted that the exponent is the degree at the top[ of the given number which is a negative exponents and the question expect us to turn it to a **positive exponents **after simplification of the given terms which will be simplified below to the simplest expression.

To rewrite the given term so that it can have a positive exponents then it can be expressed as :

=4^-3 x 4

= 4^-2

1/4^2

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Richey bought a 35-pound bag of dog food on Monday. His dog eats an

average of 3.5 pounds a day. How many pounds will remain in the bag after 8

days? 7 pounds

7 pounds will be left

In 8 days, Richey’s dog will eat 28 pounds of dog food. 3.5 x 8 = 28. To find how much is left, subtract 28 from 35. 35-28=7 lbs

In 8 days, Richey’s dog will eat 28 pounds of dog food. 3.5 x 8 = 28. To find how much is left, subtract 28 from 35. 35-28=7 lbs

**Answer:**

**Step-by-step explanation:**

//////////////////////////////

consider the dihedral point group constructed from two generators express a 3d matrix representation for the two generators of the group in the hexagonal basis

the groups generated by two elements of order 2 are K4 and **dihedral group**.

We are given that G be a finite group with x, y belong to G have two elements of order two.

We have to prove that <x,y> is either abelian or isomorphic to a dihedral group.

<x,y> means the group **generated **by two elements of order 2.

We know that Zn is a cyclic group and number of elements of order 2 is always odd in number and generated by one element .So , given group is not isomorphic to Zn

But we are given that two elements of order 2 in given group

Therefore, group G can be K4 or dihedral group

Because the groups **generated **by two elements of order 2 are K4 and dihedral group.

We know that is abelian group of order 4 and every element of K4 is of order 2 except identity element and generated by 2 elements of order 2 and **dihedral group **can be also generated by two elements of order 2

Hence, <x,y> is isomorphic to K4 or D2.

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FRUIT Ronald buys fresh fruit from a fruit stand. Apples cost $5 per pound and peaches cost $6 per pound. He has $60 to spend. The table

shows the function relating the number of pounds of apples, x, and the number of pounds of peaches, y, Ronald could purchase.

Apples (lb) Peaches (lb)

X

y

0

1.2

3

6

7.2

12

The ?

y

10

9

7.5

5

4

0

Hintercept shows that if Ronald buys only apples, he can buy ?

intercept shows that if Ronald buys only peaches, he can buy ?

pounds. The

pounds

**Answer:**

a

**Step-by-step explanation:**

your a could be the same.

Use the rational zeros theorem to list all possible rational zeros of the following.

The given function is:

[tex]g(x)=-25x^3-5x^2-2x-1[/tex]The theorem states that the factors are p/q where p is the factors of the last term (constant term) and q is the factors of the leading coefficient.

Here the leading coefficient is -25 and the constant term is -1.

The factors are listed below:

[tex]\begin{gathered} -25\Rightarrow\pm25,\pm5,\pm1\Rightarrow q \\ -1=\pm1\Rightarrow p \end{gathered}[/tex]So the value of p/q can be the values shown below:

[tex]\frac{p}{q}\Rightarrow\pm\frac{1}{25},\pm\frac{1}{5},\pm1[/tex]**Hence the possible zeroes of the given function are:**

The following figure shows the entire graph of a relationship.

Does the graph represent a function?

Yes or no

**Answer:**

No

**Step-by-step explanation:**

The graph fails the vertical line test. More than one y-value is on one x-value.

Use the distributive property to write an equivalent expression.

9(7r−3s+10)

Thanks!

**Answer:**

63r-27s+90

**Step-by-step explanation:**

9 times 7 is 63

9 times -3 is -27

9 times 10 is 90

The figure to the right shows a square floor plan with a smaller square area that will accommodate a combination fountain and pool. The floor with the fountain-pool area removed has an area of 432 square meters and a perimeter of 90 meters. Find the dimensions of the floor and the dimensions of the square that will accommodate the fountain and pool

Considering the **area **and the **perimeter **of a **square**, it is found that:

Each length of the large square floor is of 21 meters, and each length of the small square floor is of 3 meters.

What are the area and the perimeter of a square?Supposing a square of **side length s,** the area and the perimeter are given as follows:

The **area **of the figure is given by the **subtraction **of the area of the large square, of side length x, by the area of the small square, of side length y, hence:

A = x² - y²

x² - y² = 432.

The **perimeter **of the figure is the perimeter of the square of side length s **added **to two edges of the smaller square of side length s, hence:

P = 4x + 2y

4x + 2y = 90.

Then the** system of equations **to find the dimensions is given as follows:

The **solution **of this system is given by:

The problem is completed by the image given at the end of the answer.

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solve the equation for all values of x in simplest form (x+1)^2=15

**Answer: **[tex]x=-1 \pm \sqrt{15}[/tex]

**Step-by-step explanation:**

[tex](x+1)^2 =15\\\\x+1 =\pm \sqrt{15}\\\\x=-1 \pm \sqrt{15}[/tex]

You have a $25 calling card. calls made using the card within the united states costs $10 per minute. while calls made from the us to france cost $25 per minute. write an inequality that relates the number of minutes x you can use for calls within the us and the number of minutes y you can use from de us and france

**Answer:**

**10× + 25y ≤ 25**

**Answer:**

0.1x + 0.25y ≤ 25

**Step-by-step explanation:**

A call within the US is $0.10, a call to France is $0.25, and you have $25.00. Your total amount of money spent depends on how many calls you make. Now, turn this information into an inequality.

does anyone know how to solve and find out the answer? Thank you so much if you help!

**Answer:**

perpendicular

**Step-by-step explanation:**

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - [tex]\frac{2}{3}[/tex] x + 5 ← is in slope- intercept form

with slope m = - [tex]\frac{2}{3}[/tex]

3x - 2y = 4 ( subtract 3x from both sides )

- 2y = - 3x + 4 ( divide through by - 2 )

y = [tex]\frac{3}{2}[/tex] x - 2 ← in slope- intercept form

with slope m = [tex]\frac{3}{2}[/tex]

• Parallel lines have equal slopes.

clearly the slopes are not equal, so not parallel.

• the product of the slopes of perpendicular lines = - 1

- [tex]\frac{2}{3}[/tex] × [tex]\frac{3}{2}[/tex] = - 1

then the lines are perpendicular to each other.

**Answer:**

The lines are perpendicular.

**Step-by-step explanation:**

[tex]3x -2y=4[/tex]

Step 1: Add -3x to both sides.

[tex]3x-2y+-3x=4+-3x[/tex]

[tex]-2y=-3x+4[/tex]

Step 2: Divide both sides by -2.

[tex]\frac{-2y}{-2} =\frac{-3x+4}{-2}[/tex]

[tex]y=\frac{3}{2} x-2[/tex]

Finally...

[tex]y=\frac{3}{2} x-2\neq y=-\frac{2}{3} x+5[/tex] so the lines are not parallel.

However, [tex]\frac{3}{2}[/tex] is the opposite reciprocal of [tex]-\frac{2}{3}[/tex], so, the lines are perpendicular.

(You can also try drawing the lines.)

Which equation has a graph that is parallel to the graph 2x-y = -1

The **equation** whose graph is **parallel** to that of line **2x - y = - 1 **is →

**y = - 2x - 1**

What is the general equation of straight line?

The **general equation** of straight line is -

**y = mx + c**

Given is an **equation** of line as → **2x - y = - 1**

The **equation** of the line whose graph will be** parallel** to that of the graph of line **2x - y = -1**, will have **same slope **as that of given line itself.

2x - y = - 1

y = -2x - 1

**m = -2**

The **equation** whose graph is **parallel** to that of **2x - y = -1 **is -

**y = - 2x - 1**

Therefore, the **equation** whose graph is **parallel** to that of line **2x - y = - 1 **is → **y = - 2x - 1**

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10. (2, -4); slope = -3

The equation (-4 = -3x + 2) is formed and plotted on the **graph **(Refer to the graph attached below).

So, the equation can be:

The slope is -3 and the coordinates are (2, -4):Formula: y = MX + bWhere m is the slope.From the equation:

y = MX + b-4 = -3x + 2Now, plot the equation on the graph as follows:

(Refer to the graph attached below)Therefore, the equation (-4 = -3x + 2) is formed and plotted on the **graph **(Refer to the graph attached below).

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**The correct question is given below:**From the equation and plot it on a graph when, (2, -4) and slope = -3.

A group of 40 children attended a baseball game on a field trip. Each child received either a hot dog or a bag of popcorn. Hot dogs were $2.25 and popcorn was $1.75. If the total bill was $83.50, how many hotdogs and bags of popcorn were purchased?

Write the equations for the situation above. (Use the variable x for hotdogs and y for popcorn)

**Answer:**

See Explanation

**Step-by-step explanation:**

[tex]x+y=40\\2.25x+1.75y=83.5\\[/tex]

from the first you have

[tex]h=40-p[/tex] substitute into the second:

[tex]2.25(40-p)+ 1.75x= 83.5\\90-2.25y+1.75x= 83.5[/tex]remaining

[tex]0.5y=6.5\\p= \frac{6.5}{0.5} =13\\[/tex]

substitute back into [tex]h= 40 - y\\h = 40 - 13 = 27[/tex]

Hope this helped :)

True or false

-5/-1 = 5?

(0/-4) = 0?

-3/1 = -3?

- 8/0 = 0?

**Checking if the results of the following divisions are true or false.**

**a) -5/-1 = 5 ↔ True**

*The* **fraction**, **(remembering that it is a division)**, **-5/-1** *can be simplified to 5 by* **removing the negative sign** *from ***the numerator and denominator.**

**b) (0/-4) = 0 ↔ True**

**We know*** that any* **number divided by zero**,* the* **result will always be zero.**

**c) -3/1 = -3 ↔ True**

**Any number divided by one equals the same number.**

**d) -8/0 = 0 ↔ False**

**A normal number simply cannot be divided by 0.**

*The*** three previous divisions are true**, that is,** your answers are correct.** **While the last one can't, since it can't be divided by 0**, *this one is*** false.**

HELP PLEASE!!!!!!!!!!!

What is the dimensions of a rectangle that is 32ft by 8ft after it is dilated by a scale factor of 7/8

**Dimensions **of **rectangle **after **dilation **of scale factor 7/8 will be

[tex] (\frac{7}{2},14), (\frac{-7}{2},14), (\frac{-7}{2},-14), (\frac{7}{2},-14) [/tex]

Dilation of rectangle :-**Dilation **means the area of any rectangle increases or decreases due to change in it's **dimensions **but the shape of that rectangle will **remain same**.

Now Consider the point of dilation as the center of rectangle and assume that the **center **of given rectangle is at the origin.

As given the **length **and **width **of rectangle is **32ft **and **8ft **respectively.

∴ The Dimensions of rectangle will be (4,16), (-4,16), (-4,-16) and (4,-16).

Now As the rectangle is diluted by the factor of 7/8.

So Now **New Dimensions **are **Calculated **by simply multiplying the available dimensions with the scale factor of dilation.

∴ new Dimension after dilation will be

[tex] (4(\frac{7}{8}),16(\frac{7}{8})), (-4(\frac{7}{8}),16(\frac{7}{8})), (-4(\frac{7}{8}),-16(\frac{7}{8})), (4(\frac{7}{8}),-16(\frac{7}{8})) [/tex]

∴ Dimension after dilution will be ;

[tex] (\frac{7}{2},14), (\frac{-7}{2},14), (\frac{-7}{2},-14), (\frac{7}{2},-14) [/tex]

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Please help immediately

What is the equation of the line that passes through Point (6, 0) and has a Slope of -1/2.

I know that it is f(x) = -1/2x + 3 but I need a step by step and clear explanation.

**Answer:**

[tex]y = - \frac{1}{2} x + 3[/tex]

**Step-by-step explanation:**

Please see the attached images for the full solution.

Note that when y is replaced with f(x), it is known as a **function** instead of an **equation**.

Find the slope of the line that passes through (2, 12) and (4, 3). Simplify your answer and write it as a proper fraction, improper fraction, or integer.

The **slope **of the **line **passing through the coordinates (2, 12) and (4, 3) is -9/2.

**Slope **is simply expressed as **change **in y over the **change **in x.

Slope m = ( y₂ - y₁ )/( x₂ - x₁ )

Given the data in the question;

Point 1( 2, 12 )

x₁ = 2y₁ = 12Point 2( 4,3 )

x₂ = 4y₂ = 3To determine the **slope**, plug the given x and y values into the slope formula and simplify.

Slope m = ( y₂ - y₁ )/( x₂ - x₁ )

Slope m = ( 3 - 12 )/( 4 - 2 )

Slope m = ( -9 )/( 2 )

Slope m = -9/2

Therefore, the **slope **of the **line **is -9/2.

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Please help me out with questions 20.-24.

**Answer:**

answers are in the photo

Which relation represents a function?

A and B represent a function

You get paid

$10.75 an hour at your job and the newest video game costs

$60.00 Find the inequality that represents the number of hours you will need to work in order to afford the video game. Use x as a variable

The **inequality** that represents the number of hours you will need to work in order to afford the video **game** is x ≥ 5.58.

**Inequalities are** created through the connection of two **expressions**. It should be noted that two expressions in an inequality aren't always equal. They are denoted by the symbols ≥ < > ≤

Let the number of **hours** be represented as x.

The person is paid $10.75 an hour at your **job** and the newest video **game** costs $60.00. This will be illustrated as:

10.75x ≥ 60

**Divide**

x ≥ 60 / 10.75

x ≥ 5.58

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Erica prepared 13 flower

arrangements after working 2 hours. How many hours did Erica work if she prepared 26 flower arrangements?

Erica worked 4 hours to prepare 26 **flower arrangements**.

Erica prepared 13 **flower arrangements** after working 2 hours.

Time Erica took to prepare 1 **flower arrangement** = 2 / 13 hours.

Therefore time Erica took to prepare 26 **flower arrangement** = 2/13 x 26 hours.

=4 hours.

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In the designers proposal, they state that the paths EC and DB each measure 100 feet. They also state that the garden will require 140 feet of hedges. Are their numbers reasonable?

We are given a circle whose diamter is 100 feet. To find out if 140 feet of hedges will fit into it given all the oother dimensions, we will have to calculate the lengths of the chords that correspond to the hedges.

First, let us solve for AE.

[tex]\begin{gathered} chord=2r\sin\theta \\ \\ AE=100\sin50 \\ AE=76.6 \end{gathered}[/tex]We used θ = 50 degrees because we know that the measurement of the arc is equal to the measurement of the central angle.

Now, to solve for the length of ED, we need to find out the measurement of the central angle that subtend it.

Segments AD and EC intersect, thus the following equation must be true for the angles that they form and the arcs that they subtend:

[tex]\begin{gathered} m\angle EXA=\frac{1}{2}(m\hat{AE}+m\hat{DC}) \\ \\ 70=\frac{1}{2}(50+m\hat{DC}) \\ \\ 140=(50+m\hat{DC}) \\ \\ 90=m\hat{DC} \end{gathered}[/tex]Again, using the formula for finding the length of a chord, we can now solve for the length of ED.

[tex]\begin{gathered} chord=2r\sin(\theta) \\ \\ ED=100\sin90 \\ ED=100 \end{gathered}[/tex]Finally, we need to calculate the length of BC. But we know that BC = ED because the diameters meet at a 90-degree angle and so the chords that they subtend are all congruent. You may also think of ∠BYC as being vertical to ∠EYD. So BC should be equal to ED either way. BC = 100

So the total length of the hedges is:

[tex]\begin{gathered} AE+ED+BC \\ =76.6+100+100 \\ =276.6ft \end{gathered}[/tex]**Therefore, the numbers given by the designers are not reasonable. **140 feet is too short for the hedges.

PLS HELP 9th Grade MAth

The** equation** of the given** linear function** passing through two **points** is

y = 6 -2x.

What isLet (x₁, y₁) and (x₂, y₂) be two** points** on the given** linear function** whose equation in **variables** x and y is given by** formula** below.

(y - y₁) = {(y₂ -y₁)/(x₂-x₁)} (x -x₁)

Given that f is a **linear function** ,

f(-3) = 12

f(6) = -6

⇒(x₁, y₁) = ( -3,12)

(x₂, y₂) = ( 6,-6)

Thus the** equation** of the **linear function** is :

⇒ y - 12 = { ( -6-12)/(6-(-3))} ( x - (-3))

⇒ y - 12 = { -18/ 9} ( x +3)

⇒ y - 12 = -2 ( x+3)

⇒ y = 12 -2x - 6

⇒ y = 6 -2x

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Find the area of the triangle described below. Round to the nearest hundredth.b = 20, a = 29, c = 21

**Solution**

We want to find the area of the triangle given te sides

b = 20

a = 29

c = 21

**Note: Hero formula for calculating the Area of a Triangle**

We will first find S

[tex]\begin{gathered} S=\frac{a+b+c}{2} \\ S=\frac{29+20+21}{2} \\ S=35 \end{gathered}[/tex]To find the Area

[tex]\begin{gathered} Area=\sqrt[]{S(S-a)(S-b)(S-c)} \\ Area=\sqrt[]{35(35-29)(35-20)(35-21)} \\ Area=\sqrt[]{35\times6\times15\times14} \\ Area=\sqrt[]{44100} \\ Area=210 \end{gathered}[/tex]**Therefore, the area is**

Passes to the point( -5, 6) and has a slope equal to 3

Help due tomorrow !!

The **equation of a line **that passes through the point ( -5, 6) and has a **slope** equal to 3 is y = 3x + 21

The **equation of the line** passes through the point (-5, 6) and has a **slope **equal to 3.

Therefore, the **equation of a line** can be represented as follows;

y = mx + b

where

m =Therefore,

y = 3x + b

**slope **= 3

using (-5, 6), let's find the **y-intercept**

6 = 3(-5) + b

6 = - 15 + b

b = 6 + 15

b = 21

Therefore, the** equation of the line** is y = 3x + 21

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x/x+2 - 4/x-2 algeriac equation

The **solution **of the given equation in **quadratic form **will be; (x^{2} -6x - 8)/(x^{2} -4 )

A **quadratic **equation is the second-order degree **algebraic **expression in a variable. the standard form of this **expression **is ax² + bx + c = 0 where a. b are **coefficients **and x is the variable and c is a constant.

WE have been given an **algebric equation **as;

x/x+2 - 4/x-2

Solving it;

[tex]\dfrac{x}{x+2 }- \dfrac{4}{x-2}\\\\\\\dfrac{x(x-2)}{x+2 }- \dfrac{4(x+2 )}{x-2}\\\\\\\dfrac{x(x-2)- 4(x+2 )}{(x+2 )(x-2)}\\\\\\\dfrac{x^{2} -2x- 4x - 8}{x^{2} -2^{2} }\\\\\\\dfrac{x^{2} -6x - 8}{x^{2} -4 }[/tex]

Hence, the **solution **of the given equation in **quadratic form **will be;

(x^{2} -6x - 8)/(x^{2} -4 )

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←

For the given function, find (a) f(1) (b) f(-2).

(a) f(1) =

(b) f(-2) =

For the **given** **functions** , f(1) = -3 and f(-2) = -6 .

In the question

a **graph** is given

we have to find the **value** of the **functions** f(1) and f(-2)

the value of f(1) means the value of y, when x=1 .

we see that ,

on the **graph **when x = 1 , the **value** of y = -3 .

so the value of [tex]f(1)[/tex] = -3 .

the value of f(-2) means the value of y, when x = -2 .

we see that ,

on the graph when x = -2 , the value of y = -6 .

so the value of [tex]f(-2)[/tex] = -6 .

Therefore , For the **given** **functions** , f(1) = -3 and f(-2) = -6 .

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