The correct statement is the water absorbed **energy** continuously, but the **temperature **increased only when all of the water was in one phase.

this is explained by the** latent heat of fusion. **The melting point of ice ( at which ice melts into water) is 0 degree Celcius. This temperature remains constant till all 10 g of ice melts completely and water comes in the same phase of liquid.

The latent heat of fusion, also known as enthalpy of fusion, is defined as the total amount of heat energy supplied to a solid substance to start a change in its physical state from a solid to a liquid state. Given the pressure of the environment is constant.

The correct option is (b).

The given question is incomplete, the complete question is

The image below shows how the temperature of 10 g of ice changes as energy is added. which statement is correct?

(a) The water absorbed energy continuously and temperature increases while water is changing phase.

(b) The water absorbed energy , but the temperature increased only when all of the water was in one phase.

(c) Temperature of the water remained constant.

(d) Temperature always increases.

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You push on the door and it opens explain what happens in terms of action reaction forces ￼

**Answer:**

**When you push on the door and it opens, the action-reaction forces at play are the force you exert on the door and the force the door exerts on you.**

**According to Newton's third law of motion, when two objects interact, they exert equal and opposite forces on each other. In this case, when you push on the door, you are applying force to the door. This force is then met by an equal and opposite force from the door, which pushes back against your hand.**

**The magnitude and direction of the forces depend on the relative mass and acceleration of the objects. In this case, the door is much heavier than your hand, so it requires a greater force to move it. As a result, the door exerts a greater force on your hand in the opposite direction, causing your hand to move backward.**

**Overall, the action-reaction forces at play in this situation are the force you exert on the door and the force the door exerts on you, which are equal in magnitude but opposite in direction. These forces act to accelerate the door and your hand in opposite directions, causing the door to open and your hand to move backward.**

If we assume that these pictures were taken in an area frequented by hikers, why do you think that bear activity increases as certain points during the day?

Hikers frequently take photos in the area, and **bear** behavior is generally observed during the **evening** and **morning** hours, so precautions should be taken to avoid a **bear** attack and promote safe **hiking**.

People frequently visit the **forest**, mountains, and other areas where humans and **wildlife** interact, such as the forest, where **bears**, elephants, and other **wildlife** roam freely, and hikers should be aware of this fact and take precautions, such as standing still when a **bear** approaches.

Hence, hikers frequently take photos in the area, and **bear** behavior is generally observed during the **evening** and **morning** hours, so precautions should be taken to avoid a **bear** attack and promote safe **hiking**.

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You want to investigate the bird

and his swing and how they relate to Newton's laws of

motion. List at least two questions you might ask

**Answer: Is the bird balanced or unbalanced on the swing?**

**What kind of motion is acted on the swing by the bird?**

Newton’s second law of motion on a flying chair swing ride

*The ride is powered by a motor that makes the swing ride spin around the centre axis of the ride. The chairs move in a circle at a moderate speed. The forces acting on a swing rider are the tension in the chain and the weight of the rider.*

*When the swing moves from the lowest point up to either peak, the main force acting is momentum; and when the swing falls from either peak to its lowest point, the main force acting is gravity. The movement of the pendulum is said to be simple harmonic motion because the restoring force acts directly proportional to the displacement and is directed towards the equilibrium position. Hence, the movement of the Pendulum is simple harmonic motion.*

an unsuccesstul life-historv strategv would be associated with bopulations that: decrease in size over time increase in size over time either decrease or do not change in size over time either increase or do not change in size over time.T/F

**False**. An unsuccessful life-history strategy would be associated with populations that **decrease **in size over **time**.

**Life-history** strategies are the ways in which organisms allocate their resources (such as time, energy, and nutrients) to various life-history components, such as reproduction, growth, and survival. Unsuccessful life-history strategies are those that do not result in the long-term survival and reproduction of the **organisms **following that strategy. Such strategies may result in **populations **that do not increase in size or even decrease over time.

On the other hand, successful life-history strategies are those that result in the long-term **survival **and reproduction of the organisms following that strategy. These strategies may result in populations that increase in size over time or at least remain **stable**.

It is important to note that the success or failure of a life-history strategy depends on the specific environment and conditions in which the organism is **living**. What may be a successful strategy in one environment may not be successful in another.

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2. David Wechsler took the results of IQ tests and plotted them on a bell curve. What BEST demonstrates what Wechsler learned by plotting the results on the Bell Curve?

Most scores were above average.

Most scores were below average..

O

Most scores fell in the middle of the curve with fewer outside the curve.

There was a large difference between the scores of women and men.

**Answer:**

One thing that is demonstrated by plotting the results of IQ tests on a bell curve is that **most scores fall in the middle of the curve, with fewer scores outside the curve.** This reflects the fact that IQ scores are typically distributed in a normal or bell-shaped curve, with most scores falling around the average, and fewer scores falling at the very high or very low ends of the distribution. The bell curve is a useful tool for visualizing the distribution of IQ scores, and it can help researchers and psychologists understand the typical range of scores and identify any unusual patterns or outliers. It is not accurate to say that most scores are above average or below average, or that there is a large difference between the scores of women and men. These statements do not accurately reflect the findings of IQ tests or the use of the bell curve to analyze their results.

a circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magnetic field. a field of 1.2 t is directed along the positive z-direction, which is upward.

After solving the equation the the positive z-direction is 36.88 volts are the **EMF **is the correct answer.

**Due to that,**

Radius: 15 cm = 0.15 meters

The formula for the area of a circle can be used to calculate the area of the circular loop.

**A = π r²**

A = π × 0.15²

A = 0.0708 m²

B = 1.2T magnetic field in the positive z direction

B = 1.2 •k T.

If loop is deleted from the field during the specified time period

∆t = 2.3ms = 2.3×10^-3s

The stated average EMF is what we are looking for, and it is

ε = —∆Φ/∆t

There is no further flow.

Φf = 0

When the magnetic flux is expressed as

**I = BACosΘ**

where =0 since both the **magnetic field** and the **area** are pointing in the same direction.

**I=BA Cos0**

Φi = BA

Φi = 1.2 × 0.0708

Φi = 0.0848 Vs

Then, ε = —∆Φ/∆t

ε = —(Φf — Φi) / ∆t

ε = —(0-0.0848) / (2.3×10^-3)

ε = 0.0848 / (2.3×10^-3)

ε = 36.88 V

**36.88 volts are the EMF.**

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The stone thrown with an initial velocity of 20. meters per second straight upward from the edge of a cliff 100. meters above a canyon floor. The stone just misses the cliff's edge on its way down (Neglect friction). Calculate the position of the stone 6.0 seconds after it was thrown.

The stone's greatest **height over** the cliff is 2.04s and it takes it and the stone respectively seconds to get there 20.4s

Given:

The stone's **starting velocity** is 20m

The cliff rises to a height of.100. meters

Concept:

The stone will move when it is hurled upward from the top of the cliff owing to the acceleration caused by gravity. Because the acceleration on the stone is operating in the direction opposite to its motion, the speed of the stone will decrease as it climbs upward.

When the stone reaches its highest point and briefly comes to rest, its speed will be zero.

the length of time it took the stone to stand at its tallest

The time it took the stone to reach its highest point is provided by:

0 = 20-(9.8)t

t = 20/9.81 s

= 2.04 s

Here, the stone's time, beginning velocity, ultimate velocity, acceleration, and time are all shown.

[tex]v^{2} f = vi^{2} -2gs[/tex]

Replace the values in the equation above.

The distance the stone traveled to attain its greatest height is calculated as follows:

[tex](0)^{2} = (20)^{2} - 2(9.81)s\\s = \frac{400}{19.62} m\\20.4 m[/tex]

The stone's **travel distance **is shown here.

Replace the values in the equation above.

As a result, the greatest height that the stone can reach over the cliff is 2.04 m and the time it takes to get there are both equal to 20.4 m

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according to the international phonetic alphabet (ipa), what is the label given to consonants in which there is a much wider passage of air resulting in a smooth (as opposed to turbulent) airflow?

Approximants is the name given to consonants that have a much larger air path, leading in a smooth airflow as opposed to a **turbulent airflow.**

The vocal tract is only **minimally constrained** enough to cause air to become turbulent—to produce the four English 3.43 sounds (/l/, /r/, /w/, and /y/). For English language learners working on pronunciation and accent **reduction**, these sounds can be particularly challenging.

In English, there are just four approximates, and each of them is voiced. Additionally, they are all produced the with **soft palate lifted,** making them all **oral noises**. The English version 3 are explained below.

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if you are in a low-speed collision, when your vehicle is repaired, be sure to have your replaced.

The **things **which can be replaced after the **low**-speed **collisions **are airbags, **dents **on the car, the broken mirror or any part, etc.

A **car **accident that happens while moving less than 10 **miles **per hour is referred to as a **low**-impact or low-speed **collision**. There are several situations that could result in a low-impact collision. Accidents in **crosswalks **or other pedestrian zones are only a few instances.

Here, are some things you should replace after the **collision**,

1. **Vehicle **assistance technologies

Even though your car may appear to be in good condition, it may not be performing at its best. Modern cars are equipped with a ton of high-tech features, such as several electronic sensors, cameras, and radar that constantly monitor your car.

2. **Diagnostic **error codes

The structural integrity of the car's frame, as well as the functionality of its steering and suspension components, are all thoroughly inspected. Scanners should be available to reputable shops so they may look for diagnostic trouble codes (DTCs) that may have been set off by an accident.

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A 75 kg man falls off his ladder and hangs motionless from the ceiling by a cord. Determine the net force on the man and Find the tension in the cord. (don't forget units)

PLEASE HELP MEEEEEEE PLEASE

**Answer:**

**Explanation:**

The net force on the man is the sum of all the forces acting on him. In this case, the only force acting on the man is the force of gravity, which is given by:

F = m*g

= 75 kg * 9.8 m/s^2

= 735 N

where m is the mass of the man, g is the acceleration due to gravity, and F is the force of gravity.

Since the man is motionless, the net force on him must be zero. Therefore, the tension in the cord must be equal and opposite to the force of gravity:

T = -F

= -735 N

The tension in the cord is therefore T = -735 N. The negative sign indicates that the tension is directed downward, opposite to the direction of the force of gravity.

Net Force on Man = 735 N (downward)

Tension in Cord = 735 N (upward)

Explanation: The net **force** on the man is equal to his weight (75 kg x 9.81 m/s2 = 735.75 N).

This force is directed downward. To keep the man in equilibrium, the tension in the cord must be equal in **magnitude**, but opposite in direction, so the tension is also 735.75 N, but directed upward.

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this object's brightness is 2.5 times greater today than in ptolemy's time, suggesting changes in stellar evolution 100 times larger than predicted.

This object, which is located in an asterism with Kochab and Pherkad, has a decreasing amplitude, which indicates that it has left the instability strip in **Polaris**.

The **focus **of a sentence. In most cases, the subject's verb is acting on a person, place, or thing, which is the object. The noun or pronoun that follows the verb is the simplest place to seek for the object in a short **phrase**, as you might expect.

In other words, it is **precisely **as it was before being depicted in all aspects. It is true that an object is typically—but not always—modified in some manner when it is **represented**. but by the Object in itself.

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Note that momentum can be related to kinetic energy: KE = p2m. The presence of friction in our experimental setup results in a ratio of (total moment before/total momentum after) the collision to be O a. Less than 1.0 because kinetic energy is lost to friction. O b. More than 1.0 because kinetic energy is gained in the collision due to friction. O c. equal to zero because of energy loss due to friction. O d. None of the above is correct.

The presence of friction in our experimental setup results in a ratio of (total moment before/total momentum after) the **collision** to be less than 1.0 because kinetic energy is lost to friction.

Collision is a case where one moving object or person violently collides with another.

Friction causes a constant **loss of energy** in moving objects because work is done by friction.

As we know momentum is** P = m*v** i.e. momentum (P) is directly proportional to the mass and velocity.

Due to presence of **friction**, velocity will be reduced after collision and hence the total momentum after collision will be reduced.

So,

Total momentum before collision < Total momentum after collision

Therefore, the **ratio** of total momentum before and after collision will be less than 1.0.

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Which of the following describes a natural satellite?

an object that senses radiation from celestial objects

an object that observes another planet

an object that orbits another planet

an object that records images of celestial objects

**Answer:**

An object that orbits another planet describes a natural satellite.

**Explanation:**

PLEASE HELP ME ANSWER THE PHYSICS QUESTIONS ON MY PROFILE!!!

i will give brainliest to the first to answer!!! this one and the other ones

Two freight cars, each with a mass of 291,001 kg, collide and stick together. One was initially moving at 2.4 m/s and the other was at rest. What is their final speed?

1.2m/s

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calculate combustion of methane using bomb calorimeter given data about the calorimeter and water in it

The **combustion** of **methane** can be calculated using the data from the bomb calorimeter and the amount of water in it.

First, determine the heat of the combustion of methane. This can be done by taking the heat capacity of the **calorimeter**, subtracting the heat capacity of the water, and then multiplying the resulting number by the mass of methane used.

For example, if the **heat** **capacity** of the calorimeter is 5 kcal/°C and the heat capacity of the water is 1 kcal/°C, and the mass of methane used is 2 g, the heat of combustion of methane would be (5 - 1) x 2 = 8 kcal.

Next, calculate the change in **temperature** of the water. This can be done by taking the heat of the combustion of methane and dividing it by the heat capacity of the water.

For the example above, the change in temperature of the **water** would be 8 kcal/1 kcal/°C = 8°C.

Finally, **calculate** the combustion of methane. This can be done by taking the heat of the combustion of methane and dividing it by the change in temperature of the water.

For the example above, the combustion of methane would be 8 kcal/8°C = 1 kcal/°C.

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Determine whether the Law of Sines or the Law of Cosines is needed to solve the triangle. Then solve the triangle. Round your answer to two decimal places. a= 19, b= 21. C = 75° = O Law of Sines: A = 75°, B = 48.770, = 21 O Law of Sines; A = 48.77°, B = 75°, c = 21 Law of Sines: No solution Law of Cosines: A = 48.77°, B = 56.23° c = 24.40

When we are provided either a) two angles and one side or b) two sides and an excluded angle, we utilize the** sine rule**. When we have either a) three sides or b) two sides and the included angle, the cosine rule is used.

Therefore, you either need **two sides** and an angle to solve for the remaining side or all three sides to solve for an angle. Therefore, you can't just use the rule of cosines if you have** two angles** (which allows you to figure out the third, making it technically three angles) and a side. The Law of Sines cannot be applied to triangles with two sides and an included angle or three sides.

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match the following distance on the left with the maximum speed on the right group of answer choices 2 seconds [ choose ] 3 seconds [ choose ] 4 seconds [ choose ]

Even if you are **confident** in your own driving skills, you have no control over outside elements such as other drivers' behavior, unfavorable road and weather **conditions**, or other unexpected risks.

It's best to stay 3-4 seconds behind the **automobile** in front of you to lessen the risk of a **collision**. Every driver must practice safe driving behaviors in order to reduce their chances of being involved in an accident. The "three-second rule" is a common rule that many drivers use to maintain safe following distances. It is necessary to leave three seconds of distance between your vehicle and the vehicle in front of you. The 3-second rule suggests keeping three car **lengths** between you and the car in front of you. This is also referred to as the distance.

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the equations used to describe hearing are more diverse and complex, covering a range of topics such as the physics of sound waves, the anatomy and physiology of the ear, the neural processing of sound in the brain, and the psychoacoustics of perception. these equations may include wave equations, diffusion equations, and statistical models and may be used to describe various aspects of hearing, such as the way in which sound waves are absorbed, reflected, and refracted by different materials and structures, the way in which the ear converts sound waves into electrical signals, and the way in which the brain processes and interprets these signals.

The **equations **used to describe hearing cover a range of topics and may include **wave **equations, **diffusion **equations, and **statistical **models.

**Hearing **is a complex process that involves the physics of **sound **waves, the anatomy and physiology of the ear, the neural processing of sound in the brain, and the **psychoacoustics** of perception. To understand and describe this process, a variety of equations are used. These may include wave equations, which describe the way in which sound waves are absorbed, reflected, and refracted by different **materials **and structures.

**Diffusion **equations may be used to describe the way in which sound is transmitted through different media, such as air, **water**, and bone. **Statistical **models may be used to describe the way in which the ear and brain process and interpret sound. Together, these equations help to provide a **comprehensive **understanding of the hearing process.

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of negligible mass, spring constant k and unstretched length L. First, one spring is attached to the end of the other spring and slowly lowered to its equilibrium position. The two spring stretch a total distance of X1. Next the spring are hung side by side. The block is attached to the end of the springs and again slowly lowered to its equilibrium position. The springs each stretch a distance of X2. Which of the following correctly shows the relationship between x1 and x2?

(a) X1=X2

(b)X1=â2X2

(c)X1=2X2

(d)X1=4X2

(e)X1=8X2

The **correct **option is **option (d)** X1=4X2 is the **relationship **between X1 and X2.

We get the above answer through the following method,

For case 1: two springs are connected in **series **to stretch up to a total distance of X1.

So, for the **equilibrium **position,

F= mg= k’X1

For case 2: two springs are connected in **parallel **to stretch up to an individual distance of X2

So, for equilibruim position,

F= mg= k”X2

Let n be the number of springs, which in this case is 2.

n=2.

For a series combination of springs, effective spring **constant **(k’)= [tex]\frac{k}{n}[/tex]= [tex]\frac{k}{2}[/tex]

For a parallel combination of springs, effective spring constant (k”)= nk= 2k

Now, due to the **conservation **of force, the force applied in both cases is equal

Therefore, k’X1= k”X2

=>[tex]\frac{k}{n} *[/tex]X1= 2kX2

=>X1= 4X2

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For the different values given for the radius of curvature R and sped, rank the magnitude of the force of the roller-coaster track on the bottom of each clip. Rank from largest to smallest. To rank items as equivalent, overlap them.

The magnitude of the** force **of the roller-coaster track on the bottom of each clip can be ranked from largest to smallest as follows: R = 50 m, speed = 10 m/s R = 100 m, speed = 10 m/s R = 50 m, speed = 5 m/s.

The magnitude of the force of the roller-coaster track on the bottom of a clip is determined by the** radius **of curvature of the track and the speed of the clip.

For a given radius of curvature and speed, the magnitude of the force will be larger when the radius of **curvature** is smaller and the speed is larger, and smaller when the radius of curvature is larger and the speed is smaller.

Based on this information, the magnitude of the force of the roller-coaster track on the bottom of each clip can be ranked as follows:

R = 50 m, speed = 10 m/s

R = 100 m, speed = 10 m/s

R = 50 m, speed = 5 m/s

The magnitude of the force of the roller-coaster track on the bottom of the clip with a radius of curvature of 50 m and a speed of 10 m/s will be the largest. The magnitude of the force of the roller-coaster track on the bottom of the clip with a radius of curvature of 100 m and a speed of 10 m/s will be smaller. The magnitude of the force of the roller-coaster track on the bottom of the clip with a radius of curvature of 50 m and a speed of 5 m/s will be the smallest.

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If you Heat 50 grams of cold and 50 grams of cold water how does it affect the temperature change

Yes , if we **heat **50 grams of cold sand and 50 grams of cold water the **temperature **changes according to the **density **of material i.e. if sand is denser than water than the water will get heated faster than the given cold sand.

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Which of the following methods of sound localization between the two ears can we rely on for tones of very low frequencies? -Interaural time differences -Interaural level differences -Interaural frequency differences -Interaural echo differences More than one of the above

According to Doerbecker and Ernst (1996) and Francart et al. (2011), **interaural time difference** (ITD) and **interaural level difference** (ILD) are the two **primary auditory** **cues **used by binaural hearing. The delay between each ear is known as ITD.

**What technique best localizes sound between the two ears?**

Rayleigh's view of **horizontal sound localization** has come to be known as the “duplex” theory: that sound localization at low frequencies relies on differences in phase at the two ears, or ITDs, and that high-frequency localization relies on **interaural differences in sound level** (ILDs).

**What two variables affect sound localization?**

The **variation **in the **loudness **of the sound in each ear and the time it took for the sound to reach each ear are two elements that affect how the sound is localized.

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If a wavelength of a wave increases, but the wave speed remained the same, would the frequency increase, decrease or stay the same?

If a **wavelength** of a **wave** increases, but the wave speed remained the same, the **frequency** will decrease (option B).

**Wavelength** is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.

The **wavelength** is often designated in physics as λ, and corresponds to the **velocity** of the wave divided by its **frequency** as follows:

λ = v/f

According to the above equation, the **wavelength** is inversely proportional to the **frequency** of the wave, hence, as one increases, the other decreases and vice versa.

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which set of changes will always increase the current in an electrical circuit?

**Answer:**

increasing voltage and decreasing resistance

A minimum-energy transfer orbit to an outer planet consists of putting a spacecraft on an elliptical trajectory with the departure planet corresponding to the perihelion of the ellipse, or the closest point to the Sun, and the arrival planet at the aphelion, or the farthest point from the Sun. (Assume the orbital radius of the Earth is 1.50∗108 m, and the orbital radius of Mars is 2.30∗108 m, and mass of Sun to be 2.00∗1030kg. Calculate how long spacecraft will take to arrive at Mars.

The planet that will arrive at the **aphelion**, or the Sun's farthest point from the Earth. a=(1.5e11+2.28e11)/2=1.89e11(m).

Kepler's Third Law

Use a3/T2=const with earth.

It will take 516 days for a **spaceship **to reach Mars since 1.89e11/3T is equal to 1.5e11/3365.

Because it is a fundamental human requirement, energy is crucial to our everyday **activities**. In addition to using we consume **electricity **to heat the facilities we having built, however we use it as well to cool those. For getting out of bed, you need energy.

Using a turbine generator set, **electrical **energy is transformed from mechanical energy to create electricity. Natural gas, coal, nuclear fission, biomass, petroleum, geothermal, and solar thermal all utilise the heat **generated **throughout the process to make steam.

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7. What was one advantage of the Stanford-Binet scale intelligence tests over previous ones?

The Stanford-Binet scale tests were more accurate.

The Stanford-Binet scale tests were given with paper and pencil versus conducting one-on-one interviews

The Stanford-Binet scale tests accounted for differences in social class.

The Stanford-Binet scale tests accounted for differences in test takers from different social classes.

**Answer:**

One advantage of the Stanford-Binet scale intelligence tests over previous ones is that they were given with paper and pencil, rather than conducting one-on-one interviews. This allowed for a more standardized and objective administration of the test, which helped to improve the reliability and validity of the test scores. Additionally, the Stanford-Binet scale tests were designed to account for differences in test takers from different social classes, which previous intelligence tests did not do. This made the Stanford-Binet scale tests more fair and unbiased, and allowed for more accurate comparisons between test takers.

Due to the nature of this problem, do not use rounded intermediate values in your calculations

Find the currents flowing in the circuit in the figure below. (Assume the resistances are

R1 = 20 Ω,

R2 = 6 Ω,

R3 = 15 Ω,

R4 = 10 Ω,

r1 = 0.5 Ω,

r2 = 0.25 Ω,

r3 = 0.25 Ω,

and

r4 = 0.5 Ω.)

I1 = A

I2 = A

I3 = A

The **currents flowing **in the circuit in the given figure are;

I₁ = 0.47855 A, I₂ = -0.428 A, I₃ = 1.02445 A

How to find the current in the circuit by Kirchoffs' Voltage Law?**Kirchhoff's voltage law** states that the algebraic sum of the potential differences in any loop must be equal to zero as: ΣV = 0.

Given the various **resistances** and circuit we will apply Kirchhoff's voltage law and Junction Law

Apply Kirchhoff's law to the** left side loop** to get;

E₁ + E₂ = ( r₁ + R₁ + R₄ ) I₁ + ( R₂ + r₂ ) I₃

18 + 3 = (0.5 + 20 + 10)I₁ + (6 + 0.25) I₃

21 = 30.5 I₁ + 6.25 I₃ ----( 1 )

Apply Kirchhoff's law to the** right side loop **to get;

E₃ - E₄ - E₂ = (r₃ + r₄ + R₃)I₂ - (r₂ + R₂)I₃

12 - 24 - 3 = (0.25 + 0.5 + 15) I₂ - (0.25 + 6) I₃

-15 = 15.75I₂ - 6.25 I₃ --- ( 2 )

Applying the **law of Junction** to get;

I₁ = I₂ + I₃

Put I₂ + I₃ for I₁ in eq 1 to get;

21 = 30.5(I₂ + I₃) + 6.25 I₃

21 = 30.5I₂ + 30.5I₃ + 6.25 I₃

21 = 30.5I₂ + 36.75I₃ -----(3)

Solving equations 2 and 3 simultaneously gives us;

I₁ = 0.492 A, I₂ = -0.5459 A, I₃ = 1.02445 A

Thus;

I₁ = -0.5459 + 1.02445

I₁ = 0.47855

Hence we can conclude that the **currents flowing** in the circuit are as follows : I₁ = 0.47855 A, I₂ = -0.428 A, I₃ = 1.02445 A

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In many kitchens, a microwave oven is used to cook food. The frequency of the microwaves is on the order of 1010 Hz. Are the wavelengths of these microwaves on the order of (a) kilometers, (b) meters, (c) centimeters, or (d) micrometers?

If a microwave is used to cook food, the wavelength of these microwaves are on the order of millimeters. Approximately 1010 Hz is the frequency of the **microwaves**.

A** waveform signal's** wavelength is defined as the separation between two identical locations (adjacent crests) in adjacent cycles as the signal travels through space or along a wire. This length in** wireless systems** is typically expressed in metres (m), centimeters (cm), or millimeters (mm) (mm).

UV, X, and gamma rays are examples of **shorter wavelength** and higher frequency electromagnetic waves. Microwaves, radio waves, and infrared light are examples of radio energy with** higher wavelength** and lower frequency.

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Two charged particles, q1 and q2, are located on the x-axis, with q1 at the origin and q2 initially at

x1 = 13.2 mm.

In this configuration, q1 exerts a repulsive force of 2.62 µN on q2. Particle q2 is then moved to

x2 = 17.8 mm.

What is the force (magnitude and direction) that q2 exerts on q1 at this new location? (Give the magnitude in µN.)

The **force **that q₂ exerts on q₁ at this new location is** 1.44 µN in - X axis direction.**

The definition of **force **in physics is: The push or pull on a massed object changes its velocity.

An external **force **is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. A spring balance can be used to calculate the **Force**. Newton is the SI unit of **force**.

As **electric** **force **due to point charge is inversely proportional to the square of distance.

Given that with q₁ at the origin and q₂ initially at x₁ = 13.2 mm, q₁ exerts a **repulsive force** of 2.62 µN on q₂.

Hence, with q₁ at the origin and q₂ initially at x₁ = 17.8 mm, q₁ exerts a **repulsive force** of on q₂ = 2.62 µN (13.2/17.8)²

= 1.44 µN .

So, q₂ exerts a **force **of 1.44 µN on q₁ at this new location in - X axis direction.

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**Answer:**

What is the force applied between q1 and q2?

✔ 10.8 N

In which direction does particle q2 want to go?

✔ away from particle q1, in a straight line to the right

**Explanation:**

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