By using the points (2, 30) and (4, 60) that we can see on the **graph**, we can see that the** linear equation** that models the data is:

y = 15*x

How to find the equation that models the data?A general** linear equation** is of the form:

y = a*x + b

Where a is the **slope **and b is the y-intercept.

If we know that the line passes through two points (x₁, y₁) and (x₂, y₂), the **slope **is given by:

a = (y₂ - y₁)/(x₂ - x₁)

In this case we can use two points that appear on the graph, I will use the first two ones:

(2, 30) and (4, 60)

Then the **slope **is:

a = (60 - 30)/(4 - 2) = 30/2 = 15

Thus, the line is of the form:

y = 15*x + b

To find the value of b we use the point (2, 30), replacing these values we get:

30 = 15*2 + b

30 = 30 + b

30 - 30 = b

0 = b

We conclude that the** linear equation** that models the data is y = 15*x

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The question is below:

If **function** f(x) = √(x + 1) - 5 is **translated **three (3) units to the right and two (2) units up, the equation which represents g(x) is: D. f(x) = √(x - 2) - 3

In Mathematics, the **translation** of a geometric figure to the right simply means adding a digit to the value on the x-coordinate (x-axis) of the pre-image while **translating** a geometric figure down simply means subtracting a digit from the value on the y-coordinate (y-axis) of the pre-image.

**Translating** f(x) = √(x + 1) - 5 three (3) units to the right and two (2) units up, we have:

f(x) = √(x + 1) - 5

f(x) = √(x + 1 - 3) - 5 + 2

f(x) = √(x - 2) - 3

In Geometry, g(x - 3) simply means shifting a graph three (3) units to the right while adding two (2) to the **function** simply means moving the graph up.

In this context, we can reasonably infer and logically deduce that the parent **function** f(x) was shifted 3 units to the right and 2 units up.

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can you please help me with this algebra 2 question please

If we consider a, b and c all positive constants and b > 1, a exponential growth in general is represented by a function like:

[tex]f(t)=a\cdot b^{ct}[/tex]In otherwise, a exponential decay can be represent by:

[tex]g(t)=a\cdot b^{-ct}=a\cdot(\frac{1}{b})^{ct}[/tex]Now we can check whose functions are similar to one of these:

h(x) = 3x + 1.3 is a linear function, therefore, this is neither exponential growth or decay;

f = 3*(4.2^x) is an exponential growth;

y = (5/6)*(7^x) is an exponential growth;

T = 0.6*(1.3^x) is an exponential growth;

W(x) = (1/8)*[(3/5)^x] is an exponential decay, since in this case we have 3/5 < 1.

K = 4.2*(0.28^x) is an exponential deacay by the same argument.

A combined total of $41,000 is invested in two bonds that pay 6% and 7% simple interest. The annual interest is $2,700.00. How much is invested in each bond?

**Answer**

**Amount invested at 6% interest = 17,000**

**Explanation**

The simple interest on an invested principal **(P), **at a rate, **R, **for a period of time, **T, **is given by

**Simple Interest = (PRT/100)**

Let the amount invested at **6% **be **x**

Let the amount invested at **7% **be **y**

Sum of these amounts is **$41,000**

**x + y = 41000**

Simple Interest on **x **for **1 year**

**SI = (x × 6 × 1/100) = 0.06x**

Simple interest on **y **for **1 year**

**SI = (y × 7 × 1/10) = 0.07y**

**Sum of annual interest = $2,700**

**0.06x + 0.07y = 2700**

Now, we have a simultaneous equation

**x + y = 41000**

**0.06x + 0.07y = 2700**

Solving this simultaneously,

**x = 17,000**

**y = 24,000**

**Hope this Helps!!!**

.As the operations manager of the post-sales department, you need to estimate the average duration of an on-site visit by your technical staff. Based on the information in the service call log shown, what is the average time needed for an on-site visit? Service Call Duration 45 min 55 min 1 hr 35 min 1 hr 15 min 50 min O A 40 minutes O В. 1 hour 4 minutes O С. 1 hour 20 minutes D 4 hours O E 5 hours 20 minutes

The mean (or average) is given as:

[tex]\frac{\sum ^{}_{}x_i}{n}[/tex]where xi is the value of each data and n is the total number of data. In this case we have:

[tex]\frac{45+55+95+75+50}{5}=64[/tex]**Therefore the average is 1 hour 4 minutes and the answer is B.**

Bobby read a total of 20 books over 2 months. If Bobby has read 90 books so far, how many months has he been with his book club? Solve using unit rates

**Step 1**

From the question;

[tex]\begin{gathered} Bobby\text{ reads 20 books in 2 months} \\ \end{gathered}[/tex]We are required to find how many months it will take him to read 90 books

**Step 2**

We will use the ratio below to solve the problem.

[tex]\begin{gathered} \frac{20\text{ books}}{90\text{ books}}=\frac{2months}{x} \\ x=months\text{ to read 90books} \\ x=\frac{90\times2}{20} \\ x=9\text{ months} \end{gathered}[/tex]**Answer; It will take Bobby 9months to read 90 booj**

An initial population of 350 flying squirrels triples every year. Write an exponential equation to represent the population growth of the flying squirrels after any given number of years, x.

The **exponential equation **that represents the growth of the flying squirrels is F = 350 X 3^t.

An **exponential equation **can be described as an equation with exponents. The exponent is usually a variable. An **exponential equation **exhibits a compound growth rate.

The general form of **exponential function ** is f(x) = [tex]e^{x}[/tex]

Where:

x = the variable e = constantThe population of the** bird **= present population x (1 + growth rate)^number of years

350 x (1 + 2)^t

F = 350 X 3^t

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3. The number of zeroes in the end of perfect square is never_______

*(vi) The cube of a two digit number may have seven or more digits. (vii) The cube of a single digit number may be a single digit number. Q. The number of zeroes at the end of a perfect square is always odd.*

*I** **h**o**p**e** **i**t** **w**i**l**l** **b**e** **h**e**l**p**f**u**l** **f**o**r** **y**o**u**.*

You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 165 km south and 152 km east. Mt. Rainier is located approximately 56 km east and 40 km south of JBLM. If you are flying at a constant speed of 800 km/hr, how long after you depart JBLM will you be the closest to Mt. Rainier?

For the constant **speed**, it take **5 minutes 3 seconds** after you depart JBLM will you be the closest to Mt. Rainier.

Speed:

Speed means a rate of change of **position of an object** in any direction. Speed is measured as the ratio of distance to the **time **in which the distance was covered.

Given,

You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 165 km south and 152 km east. Mt. Rainier is located approximately 56 km east and 40 km south of JBLM.

Here we need to find the time taken after you depart JBLM will you be the closest to Mt. Rainier for the constant speed of 800 km/hr.

Let us consider **+x **direction is east, and the** -y** direction is south.

We know that, JBLM is at the origin (0, 0). All distance units are presented in kilometers.

While we consider that, you are flying on line

165x + 152y = 0

We know that the slope of the line

ax + by = c

is given by -a/b, which suggests we can form the equation of a perpendicular line by swapping x and y coefficients and negating one of them.

Then, we get the equation as,

152x - 165y = c

That is **perpendicular** to the flight path.

Now we need to find c so that this is true at the coordinates of Mt. Rainier.

The perpendicular line through (56, -40) is

152x - 165y - (152(56) - 165(-40)) = 0

When we expand it then we get,

152x - 165y - (8512 + 6600 ) = 0

152x - 165y - 15112 = 0

We know that the distance in km from JBLM (0, 0) to this line is given by

So, when we apply the value of (x,y) as (0,0) then we get,

=> | 152(0) - 165(0) - 15112 |/√(152²+165²)

=> 15112/√50329

=> 15112/224.34

≈ 67.362

Therefore at the constant speed of 800 km/hr, you will have flown that 67. 362 km.

Then for one km you would take,

=> 62.076/800 hr ≈ 0.0842 hr

When we convert this then we get,

=> 0.0842 = 5 minutes 3 seconds.

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A spinner has 3 equal sections that are white, yellow, and green. Another spinner has 3 equal sections that are blue, purple, and red. How many different combinations of colors are possible if you spin each spinner once?A. 6B. 9C. 12D. 16

**ANSWER**

**EXPLANATION**

We want to find the number of different combinations of colors possible if both spinners are spun at once.

To do this, we have to find the product of the number of colors on each spinner.

That is:

[tex]\begin{gathered} 3\cdot3 \\ \Rightarrow9 \end{gathered}[/tex]The answer is **option B**.

Gina's books has 349 fewer pages than terri's. if Gina's books has 597 pages, how many pages does Terri's books have?

Gina's books has 349 fewer pages than Terri's, if Gina's books has 597 pages, Terri's books have 946 pages. In **mathematics**, an operation is function which takes zero or more input values (also called the "**operands**" or "arguments") to a well-defined output value. The number of the operands is the arity of the operation.

In mathematics, an **operation **is function which takes zero or more input values (also called the "**operands**" or "**arguments**") to a well-defined output value. The number of the operands is the **arity **of the operation.

The most commonly studied operations are the binary operations (i.e., the operations of arity 2), such as addition and **multiplication**, and the **unary operations **(i.e., the operations of arity 1), such as additive inverse and the multiplicative inverse. An operation of arity zero, or **nullary operation**, is **constant**. The mixed product is example of operation of arity 3, also called **ternary operation**.

Generally, arity is taken to be finite. However, the infinitary operations are sometimes considered, in which case "usual" operations of finite arity are called **finitary operations**.

A partial operation is defined similarly to operation, but with partial function in place of a **function**.

Gina's book = 597 pages

Terri's book= (597+349) pages

= 946 pages

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Which expression uses the commutative property of addition and the associative property of multiplication to rewrite the expression 3x(2x8) + 7 ?

7 + 3 × (2 × 8) is the expression that uses the **commutative property** of addition and the **associative property** of multiplication to rewrite the expression 3 × (2 × 8) + 7.

Given, 3 × (2 × 8) + 7

Following the application of the **Commutative property** of addition, which stipulates that altering the order of addends does not affect the result.

The expression will be,

7 + (2 × 8) × 3

Then, using the **associative principle** of multiplication, which states that how elements are arranged in a multiplication issue does not affect the product.

The expression will be,

7 + 3 × (2 × 8)

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For the following exercises, consider this scenario: There is a mound of g pounds of gravel in a quarry. Throughout the

day, 400 pounds of gravel is added to the mound. Two orders of 600 pounds are sold and the gravel is removed from

the mound. At the end of the day, the mound has 1,200 pounds of gravel.

The value of g for the given conditions is obtained from **linear equations** as 2000.

A **linear equation **in one variable has only one variable of order 1. It has the formula ax + b = 0, where x is a variable. There is only one solution to this **equation**.

The initial amount is given as g.

400 pounds is added.

2 times 600 pounds is taken out.

The remaining amount is 1200 pounds.

Form a **linear equation** from the given **constraints**.

g+400-2(600)=1200

Solve the **linear equation** using basic mathematical functions.

g+400-1200=1200

g=2400-400

g=2000

So, the value of g is obtained using the **linear equation** as 2000.

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Given g(-2) = -4 and g'(-2) = 5, find the value of h'(-2) based on the function below.

h(x) = (-2x + 6) • g(x)

**Step-by-step explanation:**

so,

h(x) = f(x) × g(x)

h'(x) = f'(x) × g(x) + f(x)×g'(x)

with f(x) = -2x + 6

f'(x) = -2

so,

h'(-2) = -2 × g(-2) + (-2×-2 + 6) × g'(x) =

= -2 × -4 + 2 × 5 = 8 + 10 = 18

Graph the solution set of the following linear equation

2x+2y<-6

Graph the inequality by finding the boundary line, then shading the appropriate area.

y < −x −3

What is the x-intercept of the following equation?15x + 5y =30

the Given

[tex]15x+5y=30[/tex]We are asked to find the x-intercept of the linear equation. This can be seen below.

**Explanation**

To find the x-intercept, we must recall that x-intercept is the point at which the graph of the equation crosses the x-axis. We can find this point by plotting the given equation.

From the graph, we can determine the x-intercept as

**Answer: (2,0)**

A fan in a baseball stadium is sitting in a seat withtheir eye level is a vertical distance of 350 ftabove level.A) When the fan is looking at home plate, theangle of depression is 30°. What is the horizontaldistance from the fan to home plate? Round to thenearest 10th. Explain two different ways todetermine this distanceB) The same fan makes eye contact with a secondfan in the stands that is seated at a lower row inthe stadium. The straight-line distance betweenthe eyes of the two fans is 300 ft and the angle ofdepression is 48°. What is the vertical distancebetween field level and the eyes of the secondfan? Round to the nearest tenth.

GIVEN:

We are told that a baseball fan is sitting at a point where his eyes are 350 feet vertical distance from the ground. When the fan is looking at the home plate the angle of depression is 30 degrees.

Required;

Find the horizontal distance from the fan to the home plate.

Step-by-step solution;

We begin by making a sketch of the scene to determine the shape and angles formed. This is shown below;

From the sketch above we can see the that the baseball fan has effectively formed a right triangle with the home plate from his position and the dimensions, that is, angles and sides, have been labeled.

We have the reference angle given as 60 degrees and the opposite is x (horizontal distance from the fan to home plate). That means the adjacent side is 350.

We can now use the following trig ratio;

[tex]tan\theta=\frac{opposite}{adjacent}[/tex][tex]tan60\degree=\frac{x}{350}[/tex]We now cross multiply;

[tex]\begin{gathered} tan60\degree\times350=x \\ \\ 1.73205080757\times350=x \\ \\ 606.217782649=x \\ \\ x=606.2ft\text{ }(rounded\text{ }to\text{ }the\text{ }nearest\text{ }tenth) \end{gathered}[/tex]A second way to determine this distance is by using the triangle formed by the angle 30 degrees, in which case the horizontal distance will be the green line as shown in the sketch above. In that case, the vertical distance of 350 feet will be the opposite while the horizontal distance will be the adjacent while the reference angle will be 30 degrees.

For the second scenario, the straight line distance between both sets of eyes is 300 feet, and the angle of depression is 48 degrees. Note that the second fan is being watched at an angle of depression of 48 degrees which means he is at a lower level.

Now we are required to determine the vertical distance between the field level and the eyes of the second fan.

Let us begin by calculating the value of x as indicated in the triangle.

We shall use the trig ratio of;

[tex]cos\theta=\frac{adjacent}{hypotenuse}[/tex][tex]cos42\degree=\frac{x}{300}[/tex]Now we cross multiply;

[tex]\begin{gathered} cos42\degree\times300=x \\ \\ 0.743144825477\times300=x \\ \\ 222.943447643=x \\ \\ x=222.9ft\text{ }(rounded\text{ }to\text{ }the\text{ }nearest\text{ }tenth) \end{gathered}[/tex]Observe carefully that the distance calculated as x (222.9 ft) is the vertical distance between both fans. If we subtract this value from 350 feet we will now derive the vertical distance from the second fan to the field level.

[tex]\begin{gathered} Vertical\text{ }distance=350-222.9 \\ Vertical\text{ }distance=127.1ft \end{gathered}[/tex]Therefore,

**ANSWER:**

Your lunch in the hospital cadet cost $6.50. Based on working 50weeks per year , how much will you spend on your lunch per year?

**Answer:**

**Step-by-step explanation:**

if they are working 7 days a week, lunch will cost $2,275

hope this helped :)

PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!ON NUMBER 4!!!!!

The absolute value **function **y = 3|x + 1| + 9 is y ≥ (x + 4)/3 when x ≥ 0 and

y > - (x - 2)/3 when x < 0.

What is the absolute value function?The absolute value function always outputs a positive value **irrespective** of the input.

Given we have to write the absolute value function as a **piecewise **function.

We know | x | = a implies x ≥ a and - x < a.

y = 3| x + 1 | + 9.

y - 9 = 3| x + 1|.

(y - 9)/3 = | x+ 1 |.

∴ (y - 9)/3 ≥ x + 1.

y/3 - 3 ≥ x + 1.

y/3 ≥ x + 4.

y ≥ (x + 4)/3.

**OR**

(y - 9)/3 = | x+ 1 |.

- (y - 9)/3 < x + 1.

-y/3 + 3 < x + 1.

-y/3 < x - 2.

-y < (x - 2)/3.

y > - (x - 2)/3.

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Determine the probability of occurence of the following single eventsA "4" appears in a single toss of a die

**SOLUTION **

The probability of an event occuring is found using the formula

[tex]\frac{possible\text{ outcome}}{\text{total possible outcome }}[/tex]There is only** "one"** 4, in a die, out of a total of **"six"** numbers labelled 1 to 6.

So, possible outcome = 1

Total possible outcome = 6, since the die was tossed once.

Probability becomes

[tex]\frac{1}{6}[/tex]**Hence the answer is **

Select all of the answer choices that are solutions to the equation2x+2y=0.Ox=0y = -1O x = 1, y = -1Ox= -2O x = -2, y = -2O x = 0, y = 0

[tex]\because2x+2y=0[/tex]

If the **sum of two terms = 0**, then the **2 terms must have the same value** but **different signs**

That means **x and y must have the same value but different signs**

Look at the given answers

The **1st, 2nd, and 4th answers are wrong** because the solution of this equation must have a value of x and a value of y together

In the 3rd answer

x = 1 and y = -1

Both have the same value and different signs

**Then 3rd answer is a solution**

In the 5th answer

x = -2 and y = -2

They have the same value with the same signs

The 5th answer is not a solution

In the last answer

x = 0 and y = 0

They have the same value but the zero has no sign

Then substitute them in the equation to check if it is solution or not

2(0)+2(0) = 0

0 + 0 = 0

The 2 sides of the equation are equal, then

**The last answer is a solution**

**The answer is the 3rd and last answers**

Describe the slope of the line.AY|(-3, 1)2|-22X-25(2,-2)

A = (-3, 1)

B = (2, -2)

First we will calculate the slope of the line

[tex]m=\frac{y2-y1}{x2-x1}[/tex][tex]m=\frac{-2-1}{2-(-3)}=\frac{-3}{5}_{}[/tex]The slope is negative

Now, we are gonna calculate the equation, with (2, -2)

[tex]b=y-mx[/tex][tex]b=-2-(-\frac{3}{5})\cdot2[/tex][tex]b=-\frac{4}{5}[/tex]If a linear function has no restrictions, the domain of the function is

The** Domain** of the** linear function** with no** restriction **is **(-∞,∞) **

A linear function is of the form f(x) = ax+ b, where a and b are** constants **, x is **independent variable **and the **graph **of such function is a **straight line.**

**Domain **of f is the** set **of all** values** of x for which **function** f is **defined.**

Given that the linear function has no **restrictions ,** means the **values** of the function can be from anywhere of** real line**.

-∞ < f(x) < ∞

⇒ -∞ < ax+ b < ∞ , where a≠0

⇒ -∞- b < ax+ b-b < ∞ -b

⇒ -∞ < ax < ∞ ( adding or subtracting anything from infinity does not

make any difference)

⇒ -∞ < x < ∞

Thus the domain of the **linear function** which has no** restriction **is **(-∞,∞)**

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nitrogen has half-life of 15 hours. how much nitrogen will remain in an 18.0 g sample after 60 hours?

If the half-life is 15 hours and there are 18 g, it means that after 15 hours,

18/2 grams would decay, leaving behind 18/2 grams

This means that 9 grams would be left.

After another 15 hours (making a total of 30 hours), 9/2 grams would decay leaving behind 9/2 grams (i.e 4.5 grams.

After another 15 hours (making a total of 45 hours), 4.5/2 grams would decay leaving behind 4.5/2 grams. Hence 2.25 grams are left

After another 15 hours (making a total of 60 hours), 2.25/2 grams would decay leaving behind 2.25/2 grams.

Hence after 60 hours, only 1.125 grams would be left

let k(x)=3h(x)+4x^4/g(x). given the following table of values, find k'(-1)

Given the following table of **values**, k'(-1) is 3.

The derivative of a function of a real variable in mathematics assesses how sensitively the function's value changes in response to changes in its argument. Calculus's core tool is the derivative. finding a function's derivative, or rate of change, in mathematics. **Differentiation** is the process of determining a function's derivative. The derivative is the rate at which x changes in relation to y when x and y are two variables.

Given Data

k(x) = -3h(x) + [tex]\frac{4x^{4} }{g(x)}[/tex]

k(x) = -3h'(x) + 4 [tex]\frac{4x^{3}g(x)-x^{4}g'(x) }{gx^{2} }[/tex]

k'(-1) = -3h'(-1) + 4 [tex]\frac{4g(-1)-g'(-1)}{g(-1^{2}) }[/tex]

k'(-1) = -3(-1) + 4(0)

k(-1) = 3 + 0

**k'(-1)** = 3

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the graph of a quadratic function is given. determine the function's equation.

[tex]f(x)=(x+2)^2\text{ + 2}[/tex]

Here, we are given a quadratic equation graph and we are tasked with getting the equation of the quadratic equation from the graph

The first thing we need to note here is the shape of the parabola.

This in the sense that if the parabola opens up or faces down

On the graph we can see that the parabola faces the positive x-direction

Generally, the equation of a quadratic graph is usually in the form below;

[tex]y=ax^2\text{ + bx + c}[/tex]So by identifying the values of a,b and c, we can get the complete equation of the graph

The above form is called the standard form while the form we have in the options is referred to as the vertex form

The vertex form can be written as;

[tex]y=a(x-h)^2\text{ + k}[/tex]Now, looking at the graph, we can see that the graph crosses the y-axis at the point y = 6

At this point, the value of x is 0

The vertex (h,k) represents the center point of the parabola

In the case of this question, the point is (-2,2)

so h =-2 and k is 2

What is left is to get a

we can obtain this from the value of y = 6 and x = 0

Thus;

6 = a(0-(-2))^2 + 2

6 = a(2)^2 + 2

6 = 4a + 2

4a = 6-2

4a = 4

a = 4/4 =1

So the equation in the vertex form is f(x) = (x + 2)^2 + 2

what's the perimeter of 3x2-1x2-4x+3 for parallelogram?

**Answer:**

**The perimeter of the parallelogram is;**

**Explanation:**

Given the figure of a parallelogram in the attached image.

With sides;

[tex]\begin{gathered} a=x^2-4x+3 \\ b=3x^2-1 \end{gathered}[/tex]The perimeter of a parallelogram can be calculated using the formula;

[tex]P=2(a+b)[/tex]substituting the given sides;

[tex]\begin{gathered} P=2(a+b) \\ P=2(x^2-4x+3+3x^2-1) \\ P=2(x^2+3x^2-4x+3-1) \\ P=2(4x^2-4x+2) \\ P=8x^2-8x+4 \end{gathered}[/tex]Therefore, **the perimeter of the parallelogram is;**

20Which equation, when paired with the equation below, will create a system of equations with infinitelymany solutions?3x - 8y = -5A. 3x+ 8y = -5B.6x+ 16y = -10C.6x- 16y = -10D. -8x+ 3y = 5

**ANSWER**

C. 6x - 16y = -10

**EXPLANATION**

An equation or a pair of equations has** infinite solutions when all numbers are solutions of the equation**(s).

The left and right hand side of the equation(s) are the same.

So, we have to look for the equation such that the case happens.

To do that, we have to simply** look for an equation that is identical to the given equation:**

3x - 8y = -5

By observing keenly, we see that **the identical one is:**

**6x - 16y = -10 **

Divide both sides by 2, we have that:

3x - 8y = -5

Let us** try to solve these equations:**

3x - 8y = -5

3x - 8y = -5

**Subtract the second from the first**:

3x - 8y = -5

- (3x - 8y = -5)

0 + 0 = 0

=> 0 = 0

We see that both sides are identical.

**So, the answer is option C.**

Find the solution of each equation if the replacement set is 10 11 12 13

[tex]\frac{b}{5}=2[/tex]

If we replace with 10:

[tex]\frac{10}{5}=2[/tex][tex]2=2[/tex]**10 is a solution.**

Let's try with 11:

[tex]\frac{11}{5}=2[/tex][tex]2.2\ne2[/tex]**11 is not a solution.**

WIth 12:

[tex]\frac{12}{5}=2[/tex][tex]2.4\ne2[/tex]**12 is not a solution**

WIth 13

[tex]\frac{13}{5}=2[/tex][tex]2.6\ne2[/tex]**13 is not a solution**.

Therefore, **the solution to this equation is 10**

16. In Barry's state, the weekly unemployment compensation is 58% of the 26-week average forthe two highest-salaried quarters. A quarter is three consecutive months. For July, August, andSeptember, Ben earned a total of $17,500. In October, November, and December, he earned atotal of $18,300. Determine Barry's weekly unemployment compensation.

~ 399.3 $ / w

. The average for the 2 highest-salaried quarters:

(17 500 $ + 18 300 $ ) / 2 = 35 800 $ / 2 = 17 900$

. The 58% compensation representing the total amount Barry will be compensated:

17 900 * 58 / 100 = 10 382 $

. The weekly compensation:

10 382 $ / 26 week ~= 399.307692 $ / w

PLEASE HELP!! I DON'T KNOW THE ANSWER BUT OF I CLOSE IT I CAN'T GET BACK IN I CAN ONLY ACCESS THIS ONE PLEASE HELP!!!!! ⚠⚠⚠⚠⚠⚠

**Answer:**

The answer is the third one.

**Step-by-step explanation:**

They show the points plotted correctly.

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