The following traits are frequently present in vulnerabilities with high scores. It was challenging to take advantage of the **weakness**. If exploited, privileges might be **increased**. Exploitation might cause a large loss of data or period of unavailability.

The criticality and vulnerability assessment tool from ABB is a structured, quick assessment **method **used to rank plant **areas**, systems, or pieces of equipment. There is never a lack of issues to tackle, but there are always restrictions on the amount of time, money, or staff available.

Therefore, A Critical **Vulnerability **is one that can be actively exploited or for which a publicly accessible attack or proof-of-concept code exists.Both techniques for displaying the **rankings **and severity of security flaws are supported by Code Insight.

Learn more about **framework **here:

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Which statement is true about how early humans met their needs?

**Answer:**

they were hunter gatherers

**Explanation:**

What is the mass of a mallard duck whose speed is 9.1 m/s and whose momentum has a magnitude of 12 kg⋅m/s?

**Answer:**

m = 1.31 kg

**Explanation:**

Given that,

The speed of duck, v = 9.1 m/s

The magnitude of momentum, p = 12 kg-m/s

We need to find the mass of the duck. We know that the momentum of an object is given by :

**p = mv**

**Where**

**m is the mass of the duck**

[tex]m=\dfrac{p}{v}\\\\m=\dfrac{12\ kg-m/s}{9.1\ m/s}\\\\m=1.31 kg[/tex]

**So, the mass of the duck is equal to 1.31 kg. **

A 3kg horizontal disk of radius 0.2m rotates about its center with an angular velocity of 50rad/s. The edge of the horizontal disk is placed in contact with a wall, and the disk comes to rest after 10s. Which of the following situations associated with linear impulse is analogous to the angular impulse that is described?

a. A 3kg block is initially at rest. An applied force of 3N is applied to the block, but the block does not move.

b. A 3kg block is initially at rest. A net force of 3N is applied to the block until it has a speed of 10m/s.

c. A 3kg block is initially traveling at 10m/s. An applied force of 3N is applied to the block in the direction of its velocity vector for 10s.

d. A 3kg block is initially traveling at 10m/s. The block encounters a 3N frictional force until the block eventually stops.

**Answer:**

D

**Explanation:**

From the information given:

The angular speed for the block [tex]\omega = 50 \ rad/s[/tex]

Disk radius (r) = 0.2 m

The block Initial velocity is:

[tex]v = r \omega \\ \\ v = (0.2 \times 50) \\ \\ v= 10 \ m/s[/tex]

Change in the block's angular speed is:

[tex]\Delta _{\omega} = \omega - 0 \\ \\ = 50 \ rad/s[/tex]

However, on the disk, moment of inertIa is:

[tex]I= mr^2 \\ \\ I = (3 \times 0.2^2) \\ \\ I = 0.12 \ kgm^2[/tex]

The time t = 10s

∴

Frictional torques by the wall on the disk is:

[tex]T = I \times (\dfrac{\Delta_{\omega}}{t}) \\ \\ = 0.12 \times (\dfrac{50}{10}) \\ \\ =0.6 \ N.m[/tex]

Finally, the frictional force is calculated as:

[tex]F = \dfrac{T}r{}[/tex]

[tex]F= \dfrac{0.6}{0.2} \\ \\ F = 3N[/tex]

Calculate the acceleration of a car if the force on the car is 450 Newtons and the mass is 1300 kilograms.

[tex] \Large {\underline { \sf {Required \; Solution :}}}[/tex]

**We**** ****have**** ****―**

We have been asked to calculate the **accele****ration**** ****of**** ****the**** ****car**.

[tex]\qquad \implies\boxed{\red{\sf{ F = ma }}}\\[/tex]

[tex] \quad \twoheadrightarrow\sf { 450 = 1300a} \\ [/tex]

[tex] \quad \twoheadrightarrow\sf {\cancel{ \dfrac{450}{1300}} = 1300a} \\ [/tex]

[tex]\quad\twoheadrightarrow\boxed{\red{\sf{0.346 \; ms^{-2} = a }}}\\[/tex]

**Therefore****,**** ****accele****ration**** ****of**** ****the**** ****car**** ****is**** ****0****.****3****4****6**** ****m****/****s²****.**

PLEASE HELP! I'LL GIVE BRAINLEST

**Answer:**

In this conversation the Neil astronaut is right

7) If someone behaves against your company's code of ethics, what should you do?

A) Ignore it and mind your own business.

B) Suggest that they talk to the human resources department.

C) Talk to them about the situation.

D) Report the problem to your supervisor

**Answer:**

D) Report the problem to your supervisor.

**Explanation:**

This is probably the most efficient way get them to stop or to get them to follow the rules <3

D. Because you should report it on how the person is acting

In the process of fluorescence, a molecule in its ground state will absorb a photon with a certain energy Eex, called the excitation energy, and then emit a photon with energy Eem, the emission energy. Obviously, the molecule cannot emit more energy than was absorbed.

a) You wrote in your notebook that you excited a fluorescent bead at λ = 640 nm and found that it fluoresced (emitted) at λ = 520 nm. Or was it the other way around? Do a calculation and see if those figures should be switched.

b) You shine a laser on your bead at the excitation wavelength. The laser has a power of 1 mW. How many photons are emitted by the laser in one second?

c) You wish to build a microscope that allows you to excite the bead at its excitation wavelength and detect the fluorescence at the emission wavelength. This requires a pair of filters, one that allows only the excitation wavelength to pass through, and the other that allows only the emission wavelength to pass through. What color will these filters appear (i.e. what color light will they transmit?) You may have to look at an electromagnetic spectrum to figure this out…

**Answer:**

a) the excitation energy is E₂ λ = 520 nm

the emission energy is E₁, λ= 640 nm

b) #_photons = 2.6 10¹⁸ photons,

c) he excitation wavelength λ = 520 nm is green, therefore the filter is also green

the emission wavelength is lam = 640 nm is orange

**Explanation:**

a) the energy of a photo is given by the planck relation

E = h f

the speed of light is

c = λ f

f = c /λ

we substitute

E = hc /λ

let's calculate the energy for the two photons

λ = 640 nm = 640 10⁻⁰ m

E₁ = 6.63 10⁻³⁴ 3 10⁸/640 10⁻⁹

E₁ = 3.1 10⁻¹⁹ J

λ = 520 nm = 520 10⁻⁹ m

E₂ = 6.63 10⁻³⁴ 3 10⁸/520 10⁻⁹

E₂ = 3.825 10⁻¹⁹ J

therefore the excitation energy is E₂ λ = 520 nm

the emission energy is E₁, λ= 640 nm

b) For this part let's use a direct proportion rule (rule of three). If a photon (lam = 520 nm) has an energy of 3.825 10⁻¹⁹ J, how many photons have an energy of E = 1 10-3 J. Remember that the power is the energy per unit of time

#_photons = 1 10⁻³ J (1 photon / 3.825 10⁻¹⁹ J)

#_photons = 2.6 10¹⁸ photons

c) the excitation wavelength λ = 520 nm is green, therefore the filter is also green

the emission wavelength is lam = 640 nm is orange

The indices of refraction for her contact lens, cornea, and the fluid behind her cornea are 1.6, 1.4, and 1.3, respectively. Light is incident from air onto her contact lens at an angle of 30 ∘∘ from the normal of the surface. At what angle is the light traveling in the fluid behind her cornea?

**Answer:**

[tex]23^{\circ}[/tex]

**Explanation:**

n = Refractive index of air = 1

[tex]n_1[/tex] = Refractive index of contact lens = 1.6

[tex]n_2[/tex] = Refractive index of cornea = 1.4

[tex]n_3[/tex] = Refractive index of fluid = 1.3

From Snell's law

[tex]n\sin30^{\circ}=n_1\sin\theta\\\Rightarrow \theta=\sin^{-1}\dfrac{1\sin30^{\circ}}{1.6}\\\Rightarrow \theta=18.21^{\circ}[/tex]

[tex]n_1\sin\theta=n_2\sin\theta_1\\\Rightarrow \theta_{1}=\sin^{-1}\dfrac{1.6\times \sin18.21^{\circ}}{1.4}\\\Rightarrow \theta_1=20.92^{\circ}[/tex]

[tex]n_2\sin\theta_1=n_3\sin\theta_3\\\Rightarrow \theta_3=\sin^{-1}\dfrac{1.4\sin20.92^{\circ}}{1.3}\\\Rightarrow \theta_3=22.62^{\circ}\approx 23^{\circ}[/tex]

**The angle is the light traveling in the fluid behind her cornea is **[tex]23^{\circ}[/tex]**.**

The **angle **is the light **traveling **in the fluid will be **23⁰. Light **is traveling in a particular direction with an angle.

"The **ratio **of the **sine **of the angle of **incidence **to the sine of the **angle **of **refraction **is a constant, for the light of a given **color **and for a given set of **media**,

The **given **data in the problem is;

**n** is the refractive index of air = 1

**n₁ ** is the refractive index of contact lens = 1.6

**n₂** is the refractive index of cornea = 1.4

n**₃** is the refractive index of fluid = 1.3

According to** Snell's law**. The formula for Snell's law is

[tex]\rm n sin30^0 = n_1 sin\theta \\\\ \theta = sin^{- 1}(\frac{1sin30^0}{1.6} )\\\\ \theta = 18.21 ^0[/tex]

For contact lenses;

[tex]\rm n_1sin\theta = n_2 sin\theta_1 \\\\ \theta_1 = sin^{-1}\frac{1.6 \times sin 18.21^0}{1.4} \\\\ \theta_1 =20.92 ^0[/tex]

For fluid;

[tex]n_2 sin\theta_1 = n_2 sin \theta_3\\\\ \theta_3 = sin^{-1}\frac{1.4 sin 20.92^0}{1.3} \\\\ \theta_3 = 22.62 ^ 0 =23^0[/tex]

Hence the **angle **is the light traveling in the fluid will be **23⁰.**

To learn more about** snell's law** refer to the link;

https://brainly.com/question/10112549

Question 8: Unspooling Thread (100 points) A 110 g spool of thread with a 4.2 cm radius is held up by a peg through its center and allowed to freely rotate. Assume the thread is ideal (i.e., it does not stretch or slip, and its mass is negligibly small). A 160 g needle is tied to the loose end of the thread. The needle is dropped, and it accelerates to the floor as the thread unwinds. Find the tension in the thread and the magnitude of the acceleration of the needle as it falls.

**Answer:**

a = 7.29 m / s², T = 0.40 N

**Explanation:**

To solve this exercise we must apply Newton's second law to each body

The needle

W -T = m a

mg - T = ma

The spool, which we will approach by a cylinder

Σ τ = I α

T R = I α

the moment of inertia of a cylinder with an axis through its center is

I = ½ M R²

angular and linear variables are related

a = α R

α = a / R

we substitute

T R = (½ M R²) a / R

T = ½ M a

we write our system of equations together

mg - T = m a

T = ½ M a

we solve

m g = (m + ½ M) a

a = [tex]\frac{m}{m + \frac{1}{2} M} \ g[/tex]

let's calculate

a = [tex]\frac{0.160}{0.160 + \frac{1}{2} 0.110} \ 9.8[/tex]

a = 7.29 m / s²

now we can look for the tension

T = ½ M a

T = ½ 0.110 7.29

T = 0.40 N

The work done is a vector quantity and SI base unit is J

**Answer:**

Is this your question? Also I think work done is a scalar quantity.

**Explanation:**

A textbook of mass 2.10 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose diameter is 0.100 m , to a hanging book with mass 3.10 kg . The system is released from rest, and the books are observed to move a distance 1.29 m over a time interval of 0.850 s . Part A What is the tension in the part of the cord attached to the textbook

**Answer:**

the tension in the part of the cord attached to the textbook is **7.4989 N**

**Explanation: **

Given the data in the question;

As illustrated in the image below;

first we determine the value of the acceleration,

along vertical direction; we use the second equation of motion;

y = ut + [tex]\frac{1}{2}[/tex]a[tex]_y[/tex]t²

we substitute;

0 m/s for u, 1.29 m for y, 0.850 s for t,

1.29 = 0×0.850 + [tex]\frac{1}{2}[/tex]×a[tex]_y[/tex]×(0.850)²

1.29 = 0.36125a[tex]_y[/tex]

a[tex]_y[/tex] = 1.29 / 0.36125

a[tex]_y[/tex] = 3.5709 m/s²

Now when the text book is moving with acceleration , the dynamic equation will be;

T₁ = m₁a[tex]_y[/tex]

where m₁ is the mass of the text book ( 2.10 kg )

a[tex]_y[/tex] is the vertical acceleration ( 3.5709 m/s² )

so we substitute

T₁ = 2.10 × 3.5709

T₁ = **7.4989 N**

Therefore, the tension in the part of the cord attached to the textbook is **7.4989 N**

Acellus

A motion sensor emits sound, and

detects an echo 0.0115 s after. A

short time later, it again emits a

sound, and hears an echo after

0.0183 s. How far has the

reflecting object moved?

Help Resources

(Speed of sound = 343 m/s)

(Unit = m)

**Answer:**

1.17m

**Explanation:**

The formula to find distance is d=vt/2

This problem is asking for how far the reflecting object has moved so you need to find the distance from the motion sensor at both times.

(343)(0.115) / (2) = 1.97

(343)(0.0183) /(2) =3.14

After that, all you have to do is find the difference so

3.14 - 1.97

= 1.17

An aircraft has to fly between two cities, one of which is 600.0 km north of the other. The pilot starts from the southern city and encounters a steady 100.0 km/h wind that blows from the northeast. The plane has a cruising speed of 236.0 km/h in still air. In what direction (relative to east) must the pilot head her plane

**Answer:**

72.57° North of east

**Explanation:**

From the given information:

We can compute the velocity plane that is related to the ground in air in the North direction as;

[tex]v^{\to} _{PG} = v \\ \\ v^{\to} _{PG,x} = 0 \\ \\ v^{\to} _{PG,y} = v[/tex]

However, the velocity of the wind-related to the ground from the NorthEast direction is;

[tex]v^{\to}_{wG}=100 \ km/h \\ \\ \text{from North East} \\ \\ v_{wG,x} = (-100 \ km/h ) cos 45 = -70.7 km/h \\ \\ v_{wG,y} = (-100 \ km/h ) sin 45 = -70.7 km/h[/tex]

Now,

Since the plane is moving with a 236 km/h speed in the Northeast direction;

Then;

[tex]v^{\to} _{pw} = 236 \ km/h \\ \\ v^{\to} _{pw.x} = (236 m/s) cos \theta \\ \\ v^{\to} _{pw,y} = (236\ m/s) sin \theta \\ \\ v_{pG,x} = v_{pw,x} + v_{w G,x} \\ \\ \implies 0 = (236 \ km/h) sin \theta -( 70.7 \ km/h) \\ \\ \implies cos \theta = \dfrac{70.7 \ km/h}{236 \ km/h} \\ \\ \theta = cos^{-1} (0.2996) \\ \\ \mathbf{\theta = 72.57}[/tex]

Protons, neutrons, electrons, and a nucleus are

It would be Atoms, they’re all made up of these tiny particles

What is characteristic of a good insulator?

A. Electrons are usually not moving at all.

B. Electrons are free to move around.

C. Electrons are semi-free to move around.

D. Electrons are tightly bound to the nuclei.

**Answer:**

D. Electrons are tightly bound to the nuclei.

**Explanation:**

In an insulator, the electrons of the outer most shell are bound with a very high electrostatic forces coming from the nucleus of each atom so electrons cannot flow around all atoms making up the material as in a conductor.

The characteristic of a good **insulator **is **Electrons **are** tightly bound **to the nuclei. **(option d)**

In a good insulator, electrons are tightly bound to the **nuclei **of their atoms. This means that they are not free to move around within the material, unlike **conductors **where electrons are relatively loosely bound and can move freely. Due to this strong binding, electrons in insulating materials cannot carry an electric charge or energy easily from one atom to another.

When an electric field is applied to an insulator, the electrons may experience a small **displacement **within their respective atoms, but they generally do not move from one atom to another or flow through the material like they would in a conductor. As a result, insulators prevent the flow of electric current and are used to isolate or protect conductive elements from **accidental **contact.

So, the correct answer is D. Electrons are tightly bound to the nuclei.

To know more about **insulator **here

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Which one of the statements below is true about mechanical waves?

They must travel in empty space.

They can travel in a vacuum.

Both sound and light are examples of mechanical waves.

They require a medium to travel through.

**Answer:**

D) Mechanical waves require a medium for transmission (wire, air, etc.) as opposed to electromagnetic which travel through empty space - light, radio, etc.)

Hydrocarbons are by-products of which of the following:

a. Fossil oils, mines and fossil fuels

b. Burning fires, water treatment plants and fossil oils

C. Combustion in fossil, lighting and exhaust fumes

d. Petrol, sea waves and combustion in vehicles

e. Burning fires and combustion in factories and vehicles

**Answer:**

A

**Explanation:**

Key word part: hydro - water

I believe the answer is A

Please give me Brainliest

I believe the answer is A

Please give me Brainliest

If a virtual image is formed 10.0 cm along the principle axis from a convex mirror of focal length-15.0 cm, how far is the object from the mirror

**Answer:**

**U****=****30cm**

**Explanation:**

All you have to do is to put

**Mirror**** ****formula**** ****,**** ****1****/****f****=****1****/****u**** ****+**** ****1****/****v**

**You**** ****should**** ****be**** ****careful**** ****in**** ****sign**** ****convention**** ****.**

** **** **** **** **** ****Virtual**** ****image**** ****is**** ****negative**** **

** **** **** **** **** ****we**** ****take**** ****focal**** ****length**** ****of**** ****convex**** ****lens**** ****negative**** ****even**** ****if**** ****its**** ****not**** ****given**** ****and**** ****so**** ****on****.****.****.**

A metal can containing condensed mushroom soup has mass 215 g, height 10.8 cm, and diameter 6.38 cm. It is placed at rest on its side at the top of a 3.00 m long incline that is at 25.0 degrees to the horizontal, and it is then released to roll straight down. Assuming mechanical energy conservation, calculate the moment of inertia of the can if it takes 1.50 s to reach the bottom of the incline. Which pieces of data, if any, are unnecessary for calculating the solution

**Answer:**

I = 1.093 x 10⁻⁴ kg.m²

Here, all the other data, namely, the height of the can, length of the inclined plane, angle of inclination, time to reach the bottom, are unnecessary.

**Explanation:**

The can which is filled with the soup can be modelled as a solid cylinder. The moment of inertia of this solid cylinder about its axis of rotation can be given by the following formula:

[tex]I = \frac{1}{2}mr^2[/tex]

where,

I = moment of inertia of can = ?

m = mass of can with soup = 215 g = 0.215 kg

r = radius of can = diameter/2 = 6.38 cm/2 = 3.19 cm = 0.0319 m

Therefore,

[tex]I = \frac{1}{2}(0.215\ kg)(0.0319\ m)^2 \\[/tex]

**I = 1.093 x 10⁻⁴ kg.m²**

**Here, all the other data, namely, the height of the can, length of the inclined plane, angle of inclination, time to reach the bottom, are unnecessary.**

Determiner l'interfrange i sur le plan d'observation π distant de L de D:

Determine the interfringe i on the observation plane π distant from L from D:

1) pour D=f

if D=f

2)pour D=2f

if D=2f

**Answer:**

can you explain in Hindi language

because i learn hindi

What is Force ?.............

**Answer:**

Push or pull of an object is considered a force. Push and pull come from the objects interacting with one another. Terms like stretch and squeeze can also be used to denote force.

In Physics, force is defined as:

The push or pull on an object with mass that causes it to change its velocity.

Force is an external agent capable of changing the state of rest or motion of a particular body. It has a magnitude and a direction. The direction towards which the force is applied is known as the direction of the force and the application of force is the point where force is applied.

Medical devices implanted inside the body are often powered using transcutaneous energy transfer (TET), a type of wireless charging using a pair of closely spaced coils. And emf is generated around a coil inside the body by varying the current through a nearby coil outside the body, producing a changing magnetic flux. Calculate the average induced emf, of each 10-turn coil has a radius of 1.50 cm and the current in the external coil varies from its maximum value of 10.0 A to zero in 6.25 x10-6s.

**Answer:**

[tex]0.475\ \text{V}[/tex]

**Explanation:**

n = Number of turns = 10

r = Radius = 1.5 cm

I = Current = 10 A

t = Time = [tex]6.25\times 10^{-6}\ \text{s}[/tex]

[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi\times 10^{-7}\ \text{H/m}[/tex]

Magnetic field is given by

[tex]B=\dfrac{\mu_0I}{2r}\\\Rightarrow B=\dfrac{4\pi 10^{-7}\times 10}{2\times 1.5\times 10^{-2}}\\\Rightarrow B=0.00042\ \text{T}[/tex]

EMF is given by

[tex]\varepsilon=\dfrac{nBA}{t}\\\Rightarrow \varepsilon=\dfrac{10\times 0.00042\times \pi (1.5\times 10^{-2})^2}{6.25\times 10^{-6}}\\\Rightarrow \varepsilon=0.475\ \text{V}[/tex]

**The average induced emf is [tex]0.475\ \text{V}[/tex].**

PROJECT: VIRTUAL LABS — CIRCUITS

Stop with that link need to stop

**Answer:**

Table A

Measuring Current as a Function of Voltage with a 20 Ω Resistor

Voltage

(V)

Current: Calculated

(A)

Current: Experimental

(A)

1 0.05 0.05

5 0.25 0.25

10 0.50 0.50

20 1.00 1.00

50 2.50 2.50

Table B

Measuring Current as a Function of Resistance at 25 V

Resistance

(Ω)

Current: Calculated

(A)

Current: Experimental

(A)

10 2.50 2.50

20 1.25 1.25

100 0.25 0.25

200 0.12 0.12

Table C

Measuring Current in a Parallel Circuit

Resistor Set

(Ω)

Total

Resistance

(Ω)

Calculated

Current

(A)

Observed

Current

(A)

Observed Current

through Each Resistor

(A)

20, 20, 20 6.67 3.75 3.74 1.25, 1.25, 1.25

20, 20, 200 9.52 2.63 2.62 1.25, 1.25, 0.12

Voltage needed to raise current to 3.75 A (20, 20, 200 resistor set):

Calculated: 35.7

Observed: 36

Table D

Calculating Power of Circuit ComponentsTeacher Guide (continued)

Observed Total Current

(A)

Current through Each Bulb

(A)

Power Usage per Bulb

(W)

2.00 0.67 6.7

**Explanation:**

got this from the teachers guide

What do meteorologists call the lines

that join places with the same

temperature?

A. isobars

B. isotherms

C. anisobars

D. anisotherms

The answer is B.isotherms

A very long straight current-carrying wire produces a magnetic field of 20 mT at a distance d from the wire. To measure a field of 5 mT due to this wire, you would have to go to a distance from the wire of A very long straight current-carrying wire produces a magnetic field of 20 mT at a distance d from the wire. To measure a field of 5 mT due to this wire, you would have to go to a distance from the wire of:_____.

a. 4d.

b. 16d.

c. 2d.

d. 8d.

**Answer:**

A. 4d

**Explanation:**

Let's begin with the formula for the magnetic field produced by a long wire.

[tex]B = \frac{\mu_0I}{2\pi d}[/tex]

So [tex]d=\frac{\mu_0 I}{2\pi B }[/tex]

at point d_{1} is

[tex]d_{1}=\frac{\mu_{0} i}{2 \pi B_{1}} \\ \frac{d_{1}}{d}=\frac{\frac{\mu_{0} i}{2 \pi B_{1}}}{\frac{\mu_{0} i}{2 \pi B}} \\ d_{2}=d\left(\frac{B}{B}\right) \\ =d\left(\frac{20 \mathrm{mT}}{5 \mathrm{mT}}\right) \\ =4 d[/tex]

Hence, option (A) is correct answer

Frequency more than 20,000 HZ

**Answer:**

dvhd

**Explanation:**

xhxjjdvcbxhjddvifidid

**Answer:**

The units of frequency are called hertz (Hz). Humans with normal hearing can hear sounds between 20 Hz and 20,000 Hz. Frequencies above 20,000 Hz are known as ultrasound

A 0.545-kg ball is hung vertically from a spring. The spring stretches by 3.56 cm from its natural length when the ball is hanging at equilibrium. A child comes along and pulls the ball down an additional 5cm, then lets go. How long (in seconds) will it take the ball to swing up and down exactly 4 times, making 4 complete oscillations before again hitting its lowest position

**Answer:**

t = 9.52 s

**Explanation:**

This is an oscillatory motion exercise, in which the angular velocity is

w = [tex]\sqrt{ \frac{k}{m} }[/tex]

Let's use hooke's law to find the spring constant, let's write the equilibrium equation

F_e - W = 0

F_e = W

k x = m g

k = [tex]\frac{m g}{x}[/tex]

k = 0.545 9.8 /0.0356

k = 150 N / m

now the angular velocity is related to the period

W = 2π / T

we substitute

4π² T² = k /m

T = 4pi² [tex]\sqrt{ \frac{m}{k} }[/tex]

we substitute

T = 4 pi² [tex]\sqrt{ \frac{0.545}{150} }[/tex]

T = 2.38 s

therefore for the spring to oscillate 4 complete periods the time is

t = 4 T

t = 4 2.38

t = 9.52 s

A certain type of laser emits light that has a frequency of 4.9 x 1014 Hz. The light, however, occurs as a series of short pulses, each lasting for a time of 2.9 x 10-11 s. The light enters a pool of water. The frequency of the light remains the same, but the speed of light slows down to 2.3 x 108 m/s. In the water, how many wavelengths are in one pulse

**Answer:**

**N = 1.42 × 10⁴ cycles**

**Explanation:**

Given that:

frequency f = 4.9 × 10¹⁴ Hz

Time = 2.9 × 10⁻¹¹ s

Speed = 2.3 × 10⁸ m/s

Recall that:

wavelength [tex]\lambda = \dfrac{c}{f} \\ \\[/tex]

Horizontal distance [tex]\Delta x = ct[/tex]

Number of wavelengths [tex](N) = \dfrac{\Delta x}{\lambda}[/tex]

[tex]N = \dfrac{ct}{c/f} \\ \\ N= ft[/tex]

N = (4.9 × 10¹⁴ cycles/s) (2.9 × 10⁻¹¹ s)

N = 14210

**N = 1.42 × 10⁴ cycles**

A 25.0kg girl pushes a 50.0kg boy so that he accelerates at 4.00m/s2. What is the force of the boy on the girl? A. 200N B. 100N C. 12.5 D. 400N

**Answer:**

a

**Explanation:**

so the answer is 200N

and I hope it is correct

using the human species as an example, explain what is meant by variation of traits

a variation of traits could be a variation of personality traits? everybody is different? what I do know Is that variation can be inherited or environmental which means that you get it from your ancestors through DNA or you get it from the environment around you

9. Calcule el valor de la fuerza que experimenta un ascensor cuando levanta 150 kg en los siguientes casos: a) Cuando asciende con una aceleracin de 4 m/s2 b) Cuando asciende con una aceleracin de 6 m/s2 c) Explique: Por qu el ascensor experimenta diferentes aceleraciones si levanta el mismo peso en ambos casos?
Find the magnitude of AB.A(-2, 6), B(1, 10)O A 2OB. 15O C.5OD 2
What is the probability of rolling a number greater than 12?
The diagram shows three touching circles.A is the centre of a circle of radius x centimeters.B and C are the centers of circles of radius 3.8 centimeters. Angle ABC = 70.Find the value of x
Which is greater -9/6 or 3/-2
2 + 1.25f = 10 - 2.75f
A scientist wanted to formulate a pill to attack a specific type of bacteria that infects the throat. Which biological component would be best to use as a model for the pills function?bacteriocytesphagocytescomplement systemantibodies
Which Factors would simplify in this expression? (x-8) 4x(x+6)x-8(x+6)(x+10) (x+10)
A reserve clause binds a professional athlete to a sports franchise even if the player does not have a contract with the team that retains the rights to the player. In other words, the player can only play for a single team and other teams may not bid for the player's services even in the absence of a contract. Major League Baseball was forced to outlaw reserve clauses in 1975. As a result of the ban, we would expect that
it earned 32000 per month has been One by fourth of his income on food 3y 10 of the remainder on house rent and 5 by 21 of the remainder on the education of children how much money is still life with him
Pick the sentence that correctly uses grammar. a. The computer corrected oneself and continued to run the program. b. The computer corrects itself and continued to run the program. c. The computer corrected itself and continued to run the program. d. none of the above
Which of the following best describes why the author includes the phrase unless you believe in objective, scientific polling (paragraph 1, sentence 4)?(A) It reveals the authors doubts about the reliability of scientific data.(B) It reinforces the authors argument that our opinions are frequentlybased on science.(C) It helps to establish the authors ironic, humorous tone.(D) It supports the authors feelings about the increasing importance oftechnology.(E) It introduces a comparison between the authors view of himselfand the way others view him.
PLEASE ANSWER! WILL GIVE BRANLIEST! I NEED HELP! NO LINKS!Which of these best describes a dangling modifier?Aa modifier that only modifies a verb or adjectiveBa modifier that modifies a word that is not in the sentenceCa modifier that modifies a word it is next toDa modifier that modifies a word it is not next to
essay on environmental sanitation
Soccer is one of the best sports to play. It teaches teamwork, encourages exercise, and develops good foot-eye coordination. Also, soccer has two seasons, unlike most other sports. You get a chance to play in the Fall and the Spring. Something else that makes soccer a really great sport to play is that there are different ways to play the sport. For example, you can play 3 on 3, or even indoor. Also, many leagues offer co-ed soccer teams in which boys and girls can play on the same team. Soccer is a great sport to play.A. Persuade the reader that soccer is a sport that everyone should play.B. Persuade the reader that 3 on 3 soccer is better than regular soccerC. Inform the reader that soccer has two seasons.D. Inform the reader that soccer requires you to have good skills.
Is the sales tax progressive, regressive or proportional? /why
Select the groups of people that rejected the Apocryphal books: Roman Catholic Church Jews of Palestine Protestant reformers Jews of Egypt multi choice
anybody know how to do this?????
Help! Il give you brainlest
At what point(s) do these graphs intersect?y = x^2 + 3x - 5y = 4x + 1Seth's solution:y = x^2 + 3x - 5y = 4x + 1x^2 + 3x - 5 = 4x + 1x^2 - x - 6 = 0(x - 3)(x + 2) = 0x = 3 and x = -2The graphs intersect at.(-20) and (3,0).Is Seth's solution correct? Explain.