[tex]\begin{gathered} m=\frac{-2}{3} \\ P(3,6) \\ y=mx+b \\ U\sin g\text{ the given data} \\ y=\frac{-2}{3}x+b \\ 6=\frac{-2}{3}(3)+b \\ 6=-2+b \\ b=6+2 \\ b=8 \\ Hence \\ \text{The equation of the line is }y=\frac{-2}{3}x+8 \end{gathered}[/tex]

Answer this please I really need you to do this

**Answer:**

x ≥ 2

**Step-by-step explanation:**

Given inequality:

[tex]-\dfrac{4(x+3)}{5} \leq 4x-12[/tex]

**Values of x less than 2**

Substitute two values where x < 2 into the inequality:

[tex]\begin{aligned}x=1 \implies -\dfrac{4(1+3)}{5} & \leq 4(1)-12\\\\ -\dfrac{4(4)}{5} & \leq 4-12\\\\ -\dfrac{16}{5} & \leq -8 \quad \Rightarrow \textsf{Not a solution}\end{aligned}[/tex]

[tex]\begin{aligned}x=0 \implies -\dfrac{4(0+3)}{5} & \leq 4(0)-12\\\\ -\dfrac{4(3)}{5} & \leq 0-12\\\\ -\dfrac{12}{5} & \leq -12 \quad \Rightarrow \textsf{Not a solution}\end{aligned}[/tex]

The values of x < 2 are not solutions to the inequality.

--------------------------------------------------------------------------------

Substitute the **value of x = 2 **into the inequality:

[tex]\begin{aligned}x=0 \implies -\dfrac{4(2+3)}{5} & \leq 4(2)-12\\\\ -\dfrac{4(5)}{5} & \leq 8-12\\\\ -\dfrac{20}{5} & \leq -4\\\\ -4 & \leq -4 \quad \Rightarrow \textsf{Yes, a solution}\end{aligned}[/tex]

The value of x = 2 is a solution to the inequality.

--------------------------------------------------------------------------------

**Values of x more than 2**

Substitute two values where x > 2 into the inequality:

[tex]\begin{aligned}x=3 \implies -\dfrac{4(3+3)}{5} & \leq 4(3)-12\\\\ -\dfrac{4(6)}{5} & \leq 12-12\\\\ -\dfrac{24}{5} & \leq 0 \quad \Rightarrow \textsf{Yes, a solution}\end{aligned}[/tex]

[tex]\begin{aligned}x=4 \implies -\dfrac{4(4+3)}{5} & \leq 4(4)-12\\\\ -\dfrac{4(7)}{5} & \leq 16-12\\\\ -\dfrac{28}{5} & \leq 4 \quad \Rightarrow \textsf{Yes, a solution}\end{aligned}[/tex]

The values of x > 2 are solutions to the inequality.

--------------------------------------------------------------------------------

Therefore, the **solution **to the inequality appears to be x ≥ 2.

To check, **solve **the **inequality**:

[tex]\begin{aligned} \implies -\dfrac{4(x+3)}{5} &\leq 4x-12\\-4(x+3) &\leq 5(4x-12)\\-4x-12 &\leq 20x-60\\ -24x & \leq-48\\x & \geq 2\end{aligned}[/tex]

When **graphing inequalities** on a number line:

To **graph **the **solution **to the **inequality **on number line, place a **closed circle** at x = 2 and shade to the **right**. (See attachment).

A ball is thrown in the air from a platform that is 96 feet above ground level with an initial vertical velocity of 32 feet per second. The height of the ball, in feet, can be represented by the function shown where t is the time, in seconds, since the ball was thrown. Rewrite the function in the form that would be best used to identify the maximum height of the ball and find Approximately when the object lands on the ground when rounded to the nearest tenth.

**Answer**:

y = -16 (x - 1)^2 + 112

The object lands on the ground in approximately 3.6s

**Explanation**:

The equation given is that of a parabola.

Now the maximum (local) point of a parabola is the vertex. Therefore, if we want to rewrite our function in the form that would be used to find the maximum height, then that **form must be the vertex form of a parabola. **

**The vertex form of a parabola is **

where (h, k) is the vertex.

The only question is, what is the vertex for our function h(t)?

Remember that if we have an equation of the form

[tex]y=ax^2+bx+c[/tex]then the x-coordinate of the vertex is

[tex]h=-\frac{b}{2a}[/tex]Now in our case b = 32 and a = -16; therefore,

[tex]h=\frac{-32}{2(16)}=1[/tex]We've found the value of the x-coordinate of the vertex. What about the y-coordinate? To get the y-coordinate, we put x = 1 into h(t) and get

[tex]k=-16(1)+32(1)+96=112[/tex]Hence, the y-coordindate is k = 112.

Therefore, the vertex of the parabola is (1, 112).

With the coordinates of the vertex in hand, we now write the equation of the parabola in vertex form.

[tex]h(t)=a(t-1)^2+112[/tex]The only problem is that we don't know what the value of **a** is. How do we find a?

Note that the point (0, 96) lies on the parabola. In other words,

[tex]h(0)=-16(0)^2+32(0)+96=96[/tex]Therefore, the vertex form of the parabola must also contain the point (0, 96).

Putting in t = 0, h = 96 into the vertex form gives

[tex]96=a(0-1)^2+112[/tex][tex]96=a+112[/tex]subtracting 112 from both sides gives

[tex]a=-16[/tex]With the value of **a** in hand, we can finally write the equation of the parabola on vertex form.

Now when does the object hit the ground? In other words, for what value of t is h(t) = 0? To find out we just have to solve the following for t.

[tex]h(t)=0.[/tex]We could either use h(t) = -16t^2 + 32t + 96 or the h(t) = -16(t - 1)^2 + 112 for the above equation. But it turns out, the vertex form is more convenient.

Thus we solve,

[tex]-16\left(t-1\right)^2+112=0[/tex]Now subtracting 112 from both sides gives

[tex]-16(t-1)^2=-112[/tex]Dividing both sides by -16 gives

[tex](t-1)^2=\frac{-112}{-16}[/tex][tex](t-1)^2=7[/tex]taking the square root of both sides gives

[tex]t-1=\pm\sqrt{7}[/tex]adding 1 to both sides gives

[tex]t=\pm\sqrt{7}+1[/tex]Hence, the two solutions we get are

[tex]t=\sqrt{7}+1=3.6[/tex][tex]t=-\sqrt{7}+1=-1.6[/tex]Now since time cannot take a negative value, **we discard the second solution** and say that** t = 3.6 is our valid solution. **

**Therefore, it takes about 3.6 seconds for the object to hit the ground. **

The turning points of the graph are (-1.73, -10.39) and (1.73, 10.39). What is the range of the Polynomial function f?

Given the turning points of the graph:

(-1.73, -10.39) and (1.73, 10.39).

Let's determine the range of the graphed function.

The range of a function is the set of all possible values of y.

The y-values are represented on the vertical axis.

From the graph, we can see the function goes up continuously and goes down continuously.

**Therefore, we can say the range of the function is real numbers.**

**Therefore, the range of the function in interval notation is:**

**(-∞, ∞)**

**ANSWER:**

**rRange: (-∞, ∞)**

The area of a triangle is 2. Two of the side lengths are 2.1 and 3.8 and the includedangle is acute. Find the measure of the included angle, to the nearest tenth of adegree.

**ANSWER**

**EXPLANATION**

The area of a triangle using two given sides and the included angle is given as:

[tex]A=\frac{1}{2}a\cdot b\cdot\sin C[/tex]where a and b are the sides and C is the included angle.

Therefore, we have to **find C** given that:

Therefore, we have that:

[tex]\begin{gathered} 2=\frac{1}{2}\cdot2.1\cdot3.8\cdot\sin C \\ \Rightarrow\sin C=\frac{2\cdot2}{2.1\cdot3.8}=0.5012 \\ \Rightarrow C=\sin ^{-1}(0.5013) \\ C=30.1\degree \end{gathered}[/tex]That is the **measure of the included angle**.

Find the equation of the line with slope −3/5 and y-intercept (0,−3).

The **equation **of the **line **will be [tex]y = -\frac{3}{5}x -3[/tex]

In the question given, It is stated that the slope of the line is **m = -3/5**, and the **y-intercept** of the line is **(0, -3)**. We have to find out the **slope-intercept **form of the line. To find out the equation of line first the **standard **equation for slope intercept form is **y = mx + b**, where m is the slope, and b is the y-intercept.

Now, we have slope **m = -3/5** and **y-intercept** is **-3**. Putting these values in the slope intercept form we get:

=> **y = mx + b**

=> [tex]y = -\frac{3}{5}x -3[/tex]

Hence, we get **equation **of line [tex]y = -\frac{3}{5}x -3[/tex]

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I don't understand this at all. Solve the equation for T1.

**Answer:**

**T1 = P2 * V2 / T2 * P1 * V1 **

Picture listed below help.

**Answer:**

Perimeter = 65.12 inches, Area = 292.48 square inches

**Step-by-step explanation:**

Perimeter:

Total perimeter = perimeter of semicircle + perimeter of rectangle (note: excluding the shared line, since that is not on the outside of the shape).

= [tex]\frac{1}{2} 2\pi r[/tex]

= [tex]\frac{1}{2} *2*3.14*8[/tex]

= 25.12

Perimeter = 25.12 + 12 + 12 + 16 = 65.12 inches

Area:

Total area = area of semicircle + area of rectangle

Area of semicircle = [tex]\frac{1}{2} \pi r^{2}[/tex]

= [tex]\frac{1}{2} *3.14* 8^{2}[/tex]

= 100.48

Area of rectangle = l * w

= 16 * 12

= 192

Total area = 100.48 + 192 = 292.48

A farmer harvested 192 pounds of Yukon Gold potatoes and 138 pounds of russet potatoes. He divided the Yukon

Gold potatoes evenly among 8 baskets. He divided the russet potatoes evenly among 6 baskets. He then filled a

sack with one basket of Yukon Gold potatoes and one basket of russet potatoes.

Which equation could be used to solve for n, the number of number of pounds of potatoes the farmer put in the

sack?

The farmer put a **total** of 47 potatoes in one sack.

Here, we are given that a farmer harvested 192 pounds of Yukon Gold potatoes and 138 pounds of russet potatoes.

He **divided** the Yukon Gold potatoes evenly among 8 baskets.

Thus, the number of pounds of potatoes in each basket = 192/8

= 24

Similarly, he divided the russet potatoes evenly among 6 baskets.

Thus, the **number** of pounds of russet potatoes in each basket = 138/6

= 23

Now, he fills a sack with one basket of Yukon Gold potatoes and one basket of russet potatoes.

n = the number of pounds of potatoes the farmer put in the sack

Thus, n = 24 + 23

n = 47

Thus, the farmer put a **total** of 47 pounds of potatoes in one sack.

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Write an equation in standard form for the line that passes through the given points.

(−4, 9), (2,−9)

So first you want to find the slope of the line: y2-y1/x2-x1

-9-9/2-(-4)

-18/6

-3

So standard form is y=Mx+b where m is the slope and b is the y-intercept

So m=-3 and b is any of the y values above

Therefore the answer is y=-3x+9

-9-9/2-(-4)

-18/6

-3

So standard form is y=Mx+b where m is the slope and b is the y-intercept

So m=-3 and b is any of the y values above

Therefore the answer is y=-3x+9

**Answer:**

3x + y = -3

**Step-by-step explanation:**

(-4, 9), (2, -9)

(x₁, y₁) (x₂, y₂)

y₂ - y₁ -9 - 9 -18 -18

m = ----------- = ----------- = ---------- = ------- = -3

x₂ - x₁ 2 - (-4) 2 + 4 6

y - y₁ = m(x - x₁)

y - 9 = -3(x - (-4)

y - 9 = -3(x + 4)

y - 9 = -3x - 12

+9 +9

---------------------

y = -3x - 3

Standard Form:

-3x + y = -3

I hope this helps!

Solve by factoring: f(x) = 2x² + 7x+6

Write the final answers in the two blanks. Do NOT write x =, just the number. If there is a fraction in your answer, write as #/#.

The **factoring** of the expression 2x² + 7x + 6 is (2x + 3)(x + 2).

It should be noted that a **factor** of a number is a number that can be multiplied with another number to get the original **number**.

In this case, 2x² + 7x - 6 will be **factored** thus:

= 2x² + 7x + 6

= 2x² + 4x + 3x + 6

= 2x(x + 2) + 3(x + 2)

= (2x + 3)(x + 2)

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Cuanto es 2 1/2 + 1 3/4 + 1/2=?

Ayudaaa

**Answer:**

2 2/4 + 1 3/4 + 2/4 = 4 3/4

4 3/4

**Answer:**

4 and 3/4

**Step-by-step explanation:**

2 1/2

+1 3/4

+ 1/2

_____

4 and 3/4

in math class, you are checking how a friend balanced an equation. what error did your friend make? explain. unbalanced equation: 16 ÷ 8 =16 ÷ 8 - 1balanced equation: 16 ÷ 8 + 1 = 1 ÷ 8 + 1

Consider the given unbalanced equation which says " 16 divided by 8 " in the Left Hand Side, while it says " 16 divided by 8 then minus one ". This can be represented as,

[tex]\frac{16}{8}=\frac{16}{8}-1[/tex]Consider two things. First, acording to BODMAS rule, division is dprferred over subtraction. Second,

can you please solve this practice problem for me I really need assistance. the original slope is blue and the parallel slope is green

**Answer:**

The original slope is 1, so the slope of the parallel line will also be 1.

uncle grandpa once said, “400 reduced by twice my age is 262.” what is his age? Show work

**Answer:**

69

**Step-by-step explanation:**

400-262=138

138÷2=69

To indirectly measure the distance across a lake, Ethan makes use of a couple

landmarks at points B and C. He measures AE, EC, and DE as marked. Find the

distance across the lake (BC), rounding your answer to the nearest hundredth of a

meter.

To the **nearest tenth**, the distance across the lake is DE = 207.68 m.

The corresponding side lengths of two** triangles** that are similar are always proportional to each other.

ΔCDE and ΔCFG are **similar** to each other

FG = 142.1 m

FC = 130 m

DF = 60 m

DC = 130 + 60 = 190 m

Therefore,

DE/FG = DC/FC

Substitute

DE/142.1 = 190/130

Cross multiply **nearest hundredth**

Therefore, applying the **similarity theorem**, the distance across the lake to the nearest hundredth is DE = 207.68 m

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A map is drawn using the scale 2cm: 100miles. On the map, Town B, is 3.5 cm from Town A and Town C is 2 cm past Town B. How many miles apart are Town A and Town C

SOLUTION

From the question, town B is 3.5cm from town A and town C is 2cm from town B. Therefore C is 5.5 cm from town A.

The scale is 2cm for every 100miles. This means 1cm for every 50 miles.

You get this by dividing 100 by 2.

Now 5.5 cm becomes 5.5 x 50 miles = 275miles.

So **town A and town C are 275 miles apart**

The quadratic function -2x ^ 2 + 4x + 6 is shown below. What are the solutions of this function? *

The solution for this **function** will be x = -1 and x = 3

**Quadratic polynomials **are those with at least one** variable** and a variable with a maximum **exponent** of two. Since the second-degree term is the highest degree term in a **quadratic function,** it is sometimes referred to as the **polynomial** of degree 2. In a quadratic function, at least one term must be of the second degree. It has qualities in **algebra.**

The given function is -2x² + 4x + 6

So, we'll employ the **middle term splitting strategy**.

-2x² + 4x + 6 = 0

- 2x² + 6x - 2x + 6 = 0

-2x ( x-3) -2 (x-3) = 0

(-2x-2) (x-3) = 0

So, the solution will be

-2x - 2 = 0

-2x = 2

x = 2/-2

x = -1

And, x-3 =0

x = 3

So, the solution of the quadratic function will be

x =-1 and x = 3

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6. Solve for x. **THINK! a) what type of angles do you have? b) what is theirrelationship (add up to 90, add up to 180, or congruent)? c) set up an equationand solve *

a) The types of angles present are:

- 1 right angle

- 1 angles of 50 degrees and 1 angle of 4x degrees

b) their relationship is add up to 90°

c) 50° + 4*x° = 90°

4*x° = 90 - 450

x° = 40/4 = 10

x = 10°

a. pi/3 b. pi/2c. 2pi/3d. 3pi/2 These are 4 options but there can be more than 2 or 3 correct answers.Find the solution of each equation the interval

[tex]\sin x\cdot\cos x-\frac{\sqrt[]{3}}{2}\cos x=0[/tex][tex]\cos x(\sin x-\frac{\sqrt[]{3}}{2})=0[/tex][tex]\begin{gathered} \cos x=0 \\ x=\frac{\pi}{2},\frac{3\pi}{2} \end{gathered}[/tex][tex]\begin{gathered} \sin x-\frac{\sqrt[]{3}}{2}=0 \\ \sin x=\frac{\sqrt[]{3}}{2} \\ x=\frac{\pi}{3} \end{gathered}[/tex]

so the answer is **pi/2, 3pi/2, and pi/3**

Hey! Can anybody help me with this?I don't need a very big explanation just a very brief explanation leading to the answer as I already kinda know this stuff. Thanks!

In an ordered pair **(x,y)**, x denotes the domain of the relation, and **y denotes the range of the relation**.

Knowing this, the three ordered pairs that will form a relation with a range of {-3, 4, 7} are

(-1, **-3**), (0, **4**), and (2,**7**).

which graph represents the equation x - 4y = -16

the given equation is

x - 4y = -16

put x = 0

0 - 4y = -16

y = 4

so at x = 0 ,, y is 4

put x = 4

4 - 4y = -16

-4y = -16- 4

y = 20/4

y = 5

so, at x = 4 the value of y is 5

**thus, the correct graph is option B**

Least squares regression line is y=4x-8 what is the best predicted value for y given x =7?

We have a regression model to predict y from the value of x.

The equation of this regression line is:

[tex]y=4x-8[/tex]We then can calculate y for x = 7 as:

[tex]y(7)=4(7)-8=28-8=20[/tex]**Answer: the predicted value of y when x = 7 is y(7) = 20**

Transit Technologies plans to produce 2-way radios that will sell for $59 per radio. They estimate fixed costs

in manufacturing the radios to be $41,500. The variable costs of producing each radio will be $14. How many

radios must the company sell to break even?

The company should must sell 923 radios to **break even**.

**Fixed cost **refer to those costs which do not vary directly with the level of output. For example salary given to staff.

**Variable cost **that cost which vary directly with the level of output..

The **selling price **of radio is $59.

Total radios sell are of value $41500. This is the fixed cost.

Let us say that they sell **x number** of radios,

As we know,

For break even point,

Total revenue = Total cost

Cost of one radio x number of radio = **fixed cost** plus **variable cost** of all radios

54x = 41500 + 14x

40x = 41500

x = 922.22~923

So, they should sell 923 radio to break even.

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B. f(x) = x² + 1

4. Evaluate f(-3).

5. Evaluate f (6).

6. Circle any ordered pairs

that are included in the

function:

(0, -1) (5, 17) ((-7,50)

0,-1 i believe that’s the answer ???

−8−x=−3(2x−4)+3x (with dcmam)

x = 10 is the **solution **to the **equation **-8 - x = -3( 2x - 4 ) + 3x using DCMAM method.

What is the solution to the given equation?

Given the **equation **in the question;

First, apply the **distributive property **to eliminate the parenthesis.

-8 - x = -3( 2x - 4 ) + 3x

-8 - x = -3×2x -3×-4 + 3x

Multiply -3 × 2x

-8 - x = -6x -3×-4 + 3x

Multiply -3 × -4

-8 - x = -6x + 12 + 3x

Next, **combine **like terms.

Add -6x and 3x

-8 - x = -3x + 12

Next, move **variable **to one side and constant terms to the other.

-x + 3x = 12 + 8

Add -x and 3x

2x = 12 + 8

Add 12 and 8

2x = 20

Divide both sides by 2

2x/2 = 20/2

x = 20/2

x = 10

Therefore, the **value** of **x **is 10.

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A mixture of 20 pounds of candy sells for $1.15. The mixture consists of chocolates worth $1.45 a pound and chocolatesworth $0.90 a pound. If x represents the pounds of $0.90 chocolates used, then which of the following represents thepounds of $1.45 chocolates used?20 - x20 xOX-20

**Answer**

**The 1.45 dollar chocolates will weigh (20 - x) pounds.**

**Explanation**

We are told that the mixture weighed **20 pounds **and one of the chocolates in the mixture weighed **x pounds.**

We are then to cslculate the weight of the other type of chocolate in the mixture.

**Total mixture = 20 pounds**

**0.90 dollar chocolate weighed x pounds**

**The 1.45 dollar chocolates will weigh (20 - x) pounds.**

**Hope this Helps!!!**

Find the dimensions of a rectangular Persian rug whose perimeter is 18 ft and whose area is 20ft^2. *Answer fill in*The Persian rug has a length (longerside) of [___]ft and a width (shorter) of [__]ft

Perimeter = 18 ft

Area = 20 ft ^2

Perimeter = 2l + 2w

Area = lw

Substitution

18 = 2l + 2w

20 = lw

Solve for l

20/w = l

18 = 2(20/w) + 2w

18 = 40/w + 2w

18w = 40 + 2w^2

2w^2 - 18w + 40 = 0

w^2 - 9w + 20 = 0

(w - 5)(w - 4) = 0

w1 = 5 w2 = 4

**Conclusion**

**width = 4 ft**

**length = 5 ft**

subtract 5x from 7x-6

We can subtract 5x from 7x - 6 like this:

7x - 6 - 5x

Now, we just have to combine like terms, in this case, the terms that have the x variable, like this:

7x - 5x - 6

2x - 6

Then, after subtracting 5x from 7x - 6 we get **2x - 6**

May u please help me with my geometry study guide Only 2 questions

**Answer:**

4.

[tex]x=AB=\frac{5\sqrt[]{2}}{2}[/tex]5.

[tex]BC=x=5\sqrt[]{3}[/tex]**Step-by-step explanation:**

**Relationships in a right triangle:**

The sine of an angle is the length of the opposite side to the angle divided by the hypotenuse.

The cosine of an angle is the length of the adjacent side to the angle divided by the hypotenuse

The tangent of an angle is the length of the opposite side to the angle divided by the length of the adjacent side to the angle.

**Question 4:**

hypotenuse is 5.

AB is adjacent to an angle of 45º. So

[tex]\sin 45^{\circ}=\frac{x}{5}^{}^{}[/tex][tex]\frac{\sqrt[]{2}}{2}=\frac{x}{5}[/tex]Applying cross multiplication:

[tex]2x=5\sqrt[]{2}[/tex][tex]x=AB=\frac{5\sqrt[]{2}}{2}[/tex]**Question 5:**

Hypotenuse is 10.

BC is opposite to an angle of 60. So

[tex]\sin 60^{\circ}=\frac{x}{10}[/tex][tex]\frac{\sqrt[]{3}}{2}=\frac{x}{10}[/tex][tex]2x=10\sqrt[]{3}[/tex][tex]x=\frac{10\sqrt[]{3}}{2}[/tex][tex]BC=x=5\sqrt[]{3}[/tex]What is the effect on the graph of f(x)=x^2 when it is transformed to h(x)=2x^2 + 15

**Answer and Explanation**:

If f(x) = x^2 is transformed to h(x)=2x^2 + 15, the below will be the effect on the its graph;

* The graph will be shifted up 15 units

*The graph will be vertically stretched since the value o

shakira starts selling various homemade crafts in her front yard each saturday morning. she can not afford an attorney and so she does not prepare any paperwork. shakira's business is most likely a(n):
Which approach to psychology emphasizes how mental processes influence behavior?
Anyone please help me this all and have solutions
A character steps out of her home and into a thick fog. based on what you know about symbolism, what might the weather reveal about the character? the character is angry about something. the character is confident about something. the character is confused about something. the character is happy about something.
How did the Bulgars, Avars, and Slavs impact the Byzantine Empire?A. They increased its prestige by taking down the western Roman Empire.B. Overall, they helped to revitalize it with new cultural vitality.C. They combined to conquer it and form a Slavic empire in its former territory.D. They significantly weakened the Byzantine Empire.
Jamal is constructing the bisector of angle ABC. He has a list of steps for the construction, but they are not inorder.
Which weather condition is most likely to occur in areas receiving little solar energy? A. evaporation B. fog C. snow D. rain
PLS HELP WILL MARK YOU BRAINLIEST!! Point B is the midpoint of AC. AB=2x and AC=3x+20.What is the value of x?x=-20x=20x=4x=6
Suppose 72% of students chose to study French their freshman year, and that meant that there were 378 such students. How many students chose not to take French their freshman year?
The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units.A solid oblique pyramid has an equilateral triangle base with a base edge length of 14 units. The base triangle is triangle A C D. The apex is point B. The angles formed with the lateral sides are 45 degrees.What is BC, the height of the pyramid?7 units7StartRoot 2 EndRoot units14 units14StartRoot 2 EndRoot units
This type of shape has irregular edge
The area of a square is 150 square feet. What is the side length of the square?
when assessing a client during the physical examination of the genitalia, the nurse palpates the scrotal contents. which finding should the nurse recognize as an indication that an infection or cysts are present?
How does the spacing of the words and the first three lines of "Latin & Soul" help convey the poem's meaning?
a. a public good is multiple choice 1 nonrival but excludable. rival but nonexcludable. rival and excludable. nonrival and nonexcludable. b. public goods are not privately provided because multiple choice 2 when goods are nonexcludable, there is too much competition for firms to earn a profit. when goods are nonrival, there is too much competition for firms to earn a profit. when goods are nonexcludable, those purchasing the good could allow others the use without requiring compensation. when goods are nonrival, those purchasing the good could allow others the use without requiring compensation.
What is the equation of the parabola with the vertex of (1,-8) that passes through (2,-6)
on a map where each unit represents one kilometer two marinas are located at p(4,2) and q(8,12). if a boat travels in a straight line from one marina to the other how far does the boat travel. Answer choices: 14 kilometers 2sqrt296 kilometer 2sqrt5 kilometers
Pls help with the question in the pic. Use context clause to find the word in the paragraph that means a refusal to buy or use something in order to bring about change.
Write the inequality shown by the shaded region in the graph with the boundary line y = -3x +5
2. A membership to the theme park is $48 per year. Marcos cancelled his membership early and is only required to pay for 0.25 of a year. How much will he need to pay?